1. a. Provide two independent events that you know the probability of.

b. Explain how you know these events are independent.

c. Find the probability that they both occur.

2. a. Provide two dependent events.

b. Explain how you know these events are dependent.

c. Explain why these dependent events might require a different method for calculating the probability of both events occurring.

Answers

Answer 1

Example of dependent events and independent events and their probabilities are as given below.

How to provide two independent events with known probability?

1. a. Two independent events that I know the probability of are:

Rolling a fair die and getting a 4 (probability of 1/6)

Flipping a fair coin and getting heads (probability of 1/2)

b. I know these events are independent because the outcome of one event does not affect the outcome of the other event. The outcome of rolling a die does not affect the outcome of flipping a coin, and vice versa.

c. The probability of both events occurring is (1/6) × (1/2) = 1/12

2a. Two dependent events:

i. Drawing a red card from a deck of cards and then drawing another card (without replacement)

ii. Drawing a red ace and then drawing another red card (without replacement)

b. I know these events are dependent because the outcome of the first event affects the outcome of the second event. The probability of the second event depends on the outcome of the first event.

c. These dependent events might require a different method for calculating the probability of both events occurring, such as conditional probability.

The probability of both events occurring would be P(A and B) = P(A) × P(B|A)

where P(A) is the probability of the first event and P(B|A) is the probability of the second event given that the first event has occurred.

Learn more about independent and dependent events on:

brainly.com/question/27692683

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Step-by-step explanation:

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This year, the cost of an amusement park pass is twenty percent more than last year. This year's cost is described by an expression where p is last year's cost.
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Answer:

Step-by-step explanation:

Your answer

You have already write down a expression which is p + 0.2p

So another expression can be : 1.2p

Mark it as Brainlist answer. Follow me.

Answer:

1.20p

Step-by-step explanation:

I did it, and I got it right on my test.

Hope this helps :)

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Domain: {-3}
Range: {8, 7, 6, 5}
This is not a function.

A store sells hardcover books for $8 and paperback books for $5. You buy 9 books, represented by the equation x+y=9, where x is the number of hardcover books and y is the number of paperback books. The equation 8x+5y=51 represents the total cost. How many of each type of book did you buy?

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Answer:

Step-by-step explanation:

x+y = 9

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8x + 5y = 51

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Two hardcover books and seven paperback books.

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Step-by-step explanation:

huh what you are trying to say

Which statement below is represented by the correct ratio? Choose all that apply.
"For every 4 boys in Mr. Washington's class, there are 3 girls." The ratio of boys to girls is 3:4.
"For every 10 minutes of reading, I can finish 15 pages of my book." The ratio of minutes reading to finished pages is 2.3.
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Answer:

Step-by-step explanation:

Its basic all you do is multiply 4 x 3 and you get 12 ywwww!!!!!!!!!

Suppose a university is divided into three campuses: the Main campus, the Downtown campus, and the Bay Area campus. The Main campus has 60% of the university's students, the Downtown campus has 25%, and the Bay Area has the rest. At the Main campus, 12% of the students are statistics majors. At the Downtown campus, 4% of the students are statistics majors. Finally, at the Bay Area campus, 1% of the students are statistics majors.

Required:
a. What proportion of students at the university are statistics majors?
b. Of all statistics majors at the university, what proportion are at the Main campus?

Answers

Answer:

a) 0.0835 = 8.35% of students at the university are statistics majors

b) 0.8623 = 86.23% are at the Main campus

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

This is used for item b.

a. What proportion of students at the university are statistics majors?

12% of 60%(At the main campus).

4% of 25%(Downtown campus).

The rest is 100 - 60 + 25) = 15%.

1% of 15%(Bay Area Campus). Si

[tex]p = 0.12*0.6 + 0.04*0.25 + 0.01*0.15 = 0.0835[/tex]

0.0835 = 8.35% of students at the university are statistics majors.

b. Of all statistics majors at the university, what proportion are at the Main campus?

Using conditional probability to find the percentage.

Event A: Statistics majors, so [tex]P(A) = 0.0835[/tex]

Event B: Main Campus

Intersection of A and B:

12% of 60%. So

[tex]P(A \cap B) = 0.12*0.6 = 0.072[/tex]

Percentage:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.072}{0.0835} = 0.8623[/tex]

0.8623 = 86.23% are at the Main campus

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True

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Because I did this.

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Answer:

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Step-by-step explanation:

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