Across a resistor, voltage
a. drops
b. builds
c. speeds up
Answer:
drops
Explanation:
Ohm's Law states that V=I*R, where V is voltage, I is current and R is resistance. In a series circuit, the voltage drop across each resistor will be directly proportional to the size of the resistor. In a parallel circuit, the voltage drop across each resistor will be the same as the power source
Until 1979, the world's easiest driving test was administered in Egypt. To pass the test, one needed only to drive about 6 m forward, stop, and drive the same distance in reverse. Suppose that at the end of the 6 m the car's brakes are suddenly applied and the car slides to a stop. If the force required to stop the car is 6.0 X 10^3 N and the coefficient of kinetic friction between the tires and pavement is 0.77, what is the magnitude of the car's normal force? What's the car's mass?
(a) The magnitude of the car's normal force is 7,792.2 N.
(b) The mass of the car is 795.1 kg.
What is the weight of the car?
The weight of the car is calculated by applying Newton's second law of motion as shown below.
Mathematically, the formula for Newton's second law of motion is given as;
Ff = μW
where;
W is the weight of the carμ is the coefficient of kinetic friction between the tires and pavementThe weight of the car is calculated as follows;
W = Ff / μ
W = ( 6,000 N ) / ( 0.77 )
W = 7,792.2 N
Based on Newton's third law of motion, the weight of the car acting downwards is equal to normal force on the car, acting upward.
The mass of the car is calculated as follows;
W = mg
where;
m is the mass of the carg is acceleration due to gravitym = W / g
m = ( 7792.2 ) / (9.8)
m = 795.1 kg
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What is resistance? How does the resistance of a long wire compare with the resistance of a short wire? How does the resistance of a thick wire that has a large cross-sectional area compare with the resistance of a thin wire?
Answer:
The opposition offered by the conductor to the current flowing through it is known as resistance.
we know,
Resistance is directly proportional to the length of the conductor.Hence,the resistance offered by the long wire will be more than that of the short wire.
Also, Resistance is inversely proportional to the area of cross section of conductor.So,The Resistance in the thick wire will be less than that of the thin wire.
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you are in the year where the earth has no more land available for houses you decide to build an apartment up and need things to survive in each earths 5 layers (troposphere,stratosphere, mesosphere, thermosphere, exosphere) Question: what things would you need to survive the mesosphere
PLS I RLLY NEED SOME HELP
The things would which would be needed to survive the mesosphere include the following below:
Food and waterOxygen supply.What is a Mesosphere?This is refereed to as the third layer of the atmosphere which is present above the stratosphere and directly below the thermosphere.
It has a low density of gas and water vapor present in the area which is why it is no place for human life as there is a shortage of oxygen and other gases needed for some biochemical reactions in the ecosystem. This is therefore the reason why things such as food, water and oxygen supply is neeeded tio survive in the mesosphere.
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1. As air in Earth's atmosphere is heated by
the Sun, the warmer air expands and
becomes less dense than the cooler air. As a
result, the warmer air rises and the cooler
air sinks. What is the cycle of warm air
rising and cool air sinking called?
tidal current
surface current
deep current
convection current
The correct answer is D) convection current.
Convection currents are the cycle of warm air rising and cool air sinking that occurs in Earth's atmosphere (as well as in other fluids) as a result of temperature differences. When a fluid (such as air) is heated, it expands and becomes less dense, causing it to rise. When the warmer fluid cools, it contracts and becomes denser, causing it to sink. This cycle of rising and sinking creates a circular flow known as a convection current.
In a particular crash test, an automobile of mass 1759 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 12 m/s and 2.2 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Calculate the magnitude of the average force exerted on the automobile during the collision. Answer in units of N.
Based on the data provided about the collision;
the magnitude of the impulse due to the collision is 21105.8 kg.m/sthe magnitude of the average force exerted on the automobile during the collision is 191870.91 NWhat is the magnitude of the impulse due to the collision of the vehicle with the wall?The magnitude of the impulse due to the collision of the vehicle with the wall is calculated using the formula of the impulse on an object given below as follows:
Impulse = change in momentum
Change in momentum = m(v - u)
where;
m is mass
v is the final velocity
u is the initial velocity
Impulse = 1759 (12 - 22)
Impulse = 21105.8 kg.m/s
The average force on the automobile will be:
Force = impulse/time
Force = 21105.8 / 0.11
Force = 191870.91 N
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A snowboarder on a slope starts from rest and reaches a speed of 3.4 m/s after 7.3 s.
The acceleration of the snowboarder is 0.466 m/s².
What is acceleration?Acceleration is the rate of change of velocity.
To calculate the acceleration of the snowboarder, we use the formula below.
Formula:
a = (v-u)/t........................ Equation 1Where:
a = Accelerationv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 3.4 m/su = 0 m/st = 7.3 sSusbtitute these values into equation 1
a = (3.4-0)/7.3a = 0.466 m/s²Hence, the acceleration is 0.466 m/s².
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An 80-kg man balances the boy on a teeter-totter as shown. What is the approximate mass of the boy? What, approximately, is the magnitude of the downward force exerted on the fulcrum? Ignore the weight of the board.
I know the first answer is 20 kg and the second answer is 1000N. Have no idea how to get these answers though. Please help? Will rate!!
The boy weighs at about 80 kg. When, as illustrated, a N 784 guy balances the youngster on a teeter-totter.
What is ideal interpretation of mass?A way to determine how much material, in mass, makes up a physical body.
In classical mechanics, an object's mass is essential to Newton's equations of motion because it affects the force required to accelerate it and, subsequently, how much inertia it has.
Language expert Peter Trudgill claims that the name "Tittermatorter" from the Norfolk language is its origin. Trudgill can trace all of his great-great-grandparents to a tiny region of eastern Norfolk.
As per the question:
Weight is come under gravity and become force
80g = mg
m = 80
Force = 80(9.8) = 784N
Thus, the answer is 784N.
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What is the average time for the toy car to move 1.0 m on cement?
Answer:
24.4
Explanation:
you would add all the numbers , 25.5+24.4+24.2= 73.1/3=24.36 and you round up you get 24.4
Please need help ASAP, ASAP
If force is doubled, acceleration will also be doubled.
Newton’s second law of motion, unlike the first law of motion, pertains to the behaviour of objects for which all existing forces are unbalanced. The second law of motion is more quantitative and is used extensively to calculate what happens in situations involving a force.It states that: Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body. This means that as the force acting upon an object is increased, the acceleration of the object is increased.In this given question, force is doubled. We know that force is directly proportional to acceleration. As we increase the force on an object the acceleration increases proportionally. Therefore, if you double the force you double the acceleration.
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Why was Silent Spring so influential at the time?
The book provided inspiration to those suffering from pesticide exposure.
It was the first book to bring awareness to global warming issues.
It was the first book that discussed the benefits of the Endangered Species Act.
It was the first time that the public was being made aware of the long-term impacts of pollution.
The reason that Silent Spring was so influential at the time is option D: It was the first time that the public was being made aware of the long-term impacts of pollution.
What is the book about?Silent Spring, a book written by Rachel Carson and published in 1962, was influential at the time because it was the first book to bring awareness to the negative impacts of pesticides on the environment and human health.
Therefore, The book provided evidence and detailed accounts of the harmful effects of pesticides on wildlife and ecosystems, and it argued that the widespread use of pesticides was unsustainable and could have long-term consequences for the environment and human health.
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The planet Mars has a mass that is 0.11 times Earth’s mass and a radius that is
0.54 times Earth’s radius. a) How much would a 60.0-kg astronaut weigh if
she were to stand on the surface of Mars?
How much force is needed to accelerate a 100 kilogram car 5 meters per second?
The force needed to accelerate the mass of 100 kg is 500 N.
What is force?Force is the product of mass and acceleration. The S.I unit of force is Newton (N).
To calculate the amount of force needed to accelerate the mass of 100 kg, we use the formula below.
Formula:
F = ma.................. Equation 1Where:
F = Forcem = Mass a = AccelerationFrom the question,
Given:
m = 100 kga = 5 m/s²Substitute these values into equation 1
F = 100×5F = 500 NHence, the force is 500 N.
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3. An electron moves along the trajectory from i to f as shown.
a) Does the electric potential energy increase, decrease or stay the same? Explain.
b) Is the electron's speed at f greater than, less than or equal to its speed at i? Explain.
Answer:
decrease
Explanation:
this is for part a
What kind of nuclear reaction is seen in 30Y0Zr+e?
→40
OA. Beta decay
OB. Alpha decay
OC. Nuclear fusion
D. Nuclear fission
Beta decay is seen in the nuclear reaction: ⁹⁰₃₉Y → ⁹⁰₄₀Zr + ⁰₋₁e. Hence, option (A) is correct.
What is Beta (β) decay?A proton can change into a neutron or vice versa inside the radioactive sample's nucleus through a process known as beta decay.
The radioactive sample's nucleus can approach the ideal neutron/proton ratio as closely as feasible through processes like beta decay and alpha decay. The nucleus releases a beta particle during this process, which can either be an electron or a positron.
As electron releases here, it is a Beta (β) decay.
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A 10 kg box is on an inclined plane that is 40 degrees above the horizontal. It is sliding
down with a constant velocity.
a. Draw a free body diagram with Fg, FN, F₂ and Ff.
b. What is the weight of the box?
What is the normal force of the box?
c. What is the force of friction acting on the box?
d. What is the net force acting on the box?
A horizontal force of 10.0 N is acting on a 10 kg box that is sliding to the right along the floor with velocity v.
What are the assumptions for drawing a free-body diagram?Most people make the common assumptions of rigid body action and ignoring air resistance and friction. In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation.
The specific situation and the presumptions used will determine how many forces and moments are displayed. Most people make the common assumptions of rigid body action and ignoring air resistance and friction.
In statics, all forces and moments must balance to zero; if they don't, the body is accelerating and the laws of statics do not apply, according to the physical interpretation. The resultant forces and moments in dynamics can have non-zero values.
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The first scientist misidentified the fossil as that of a big cat. What body structure did he use to make his observations?
1. What happens when a cold piece of metal is placed in hot water?
a. heat will flow from the metal to the water
b. temperature will flow from the water to the metal
c. temperature will flow from the metal to the water
d. heat will flow from the water to the metal
2. How do the molecules differ in a cup of hot water and a cup of cold water?
a. In the cold water, the molecules are moving faster than in the hot water.
b. In the hot water, the molecules are moving faster than in the cold water.
c. In the cold water, there are more molecules.
d. In the hot water, there are more molecules.
When a cold piece of metal is placed in hot water, heat will flow from the water to the metal.
The correct option is D.
The molecules in a cup of hot water differ from the molecules in a cup of cold water in that, in the hot water, the molecules are moving faster than in the cold water.
The correct option is B.
What is heat energy?Heat energy is a type of energy that is transmitted between systems or objects with various temperatures. Heat energy is also known as thermal energy.
The direction of the flow of heat energy is from the high-temperature system to the low-temperature system.
For example, heat energy will flow from hot water to a cold piece of metal; placed inside it.
The molecules of a hotter body have more kinetic energy than the molecules of a colder body.
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How does the horizontal velocity of a projectile affect the velocity at which it falls?
A. faster horizontal objects fall slower
B. slower horizontal objects fall slower
C. No horizontal motion means the object will not fall
D. Horizontal motion does not have an effect on how an object will fall
The same resultant force acts on objects 1 and 2. Object 1 accelerates at 2m/s² and Object 2 accelerates at 5m/s². Which object has the greater mass?
Answer:
Object 1
Explanation:
Newton's 2nd Law: F = ma, therefore m = F/a
This shows that mass is inversely proportional to acceleration. Because the resultant force (F) is held constant in this problem, the lower the acceleration, the greater the mass. Therefore, the object that accelerates at 2 m/s² has the greater mass. In other words, if the net force on both objects is the same, the object with the slower acceleration has the greater mass.
4. How many excess electrons does a balloon that was rubbed on a child's hair and
now has a charge of 4.0 x 107 Coulombs?
The number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.
What is electrons?Electrons are particles of matter that carry a negative electrical charge. Electrons are the smallest particles in the atom and are responsible for most of the atom's mass. Electrons orbit around the nucleus of the atom and are held together by the electromagnetic force. Electrons have a property called spin, which can have a value of either +1/2 or -1/2. Electrons are found in all elements and are important in chemical reactions as they are able to move around and form bonds with other atoms. Electrons are also important in electricity and magnetism.
The number of excess electrons on the balloon is equal to the charge of the balloon divided by the charge of an electron. Since the charge of an electron is 1.60 x 10-19 Coulombs, the number of excess electrons is 4.0 x 107 Coulombs divided by 1.60 x 10-19 Coulombs, which is 2.5 x 1026 electrons.
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both of yall are right and wrong its b and d
Answer:
Yup
Explanation:
The linear impulse delivered by the hit of a boxer is 194 N · s during the 0.416 s of contact. What is the magnitude of the average force exerted on the glove by the other boxer? Answer in units of N.
The magnitude of the average force exerted on the glove by the other boxer is 466.3 N.
What is the relationship between force and impulse?The force that acts on a body is defined as an agent that causes a change in the position or the state of an object.
Force can be defined as a push or pull agent.
The impulse that acts on a body is the product of the force that acts on that body and the time in which it acts.
Hence, the relationship between force and impulse is given below:
Force = Impulse/time
The force exerted on the glove by the other boxer is calculated using the formula above as follows:
Force = 194 / 0.416
Force = 466.3 N
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Sarita Has power of 480 watt. Calculate the amount of mass lifted by her up to 10 Metres in 12 SECONDS?
Answer:
58.7g (answer might differ a little if the answer treats g as 10 instead of 9.81ms-2)
Explanation:
First, apply the formula Energy = Power x Time
Power -> 480W (given)
Time -> 12 seconds (given)
Hence,
Energy = (480 x 12) J (SI units of energy is in Joules, J)
= 5760 J
Since Sarita lifts up the mass, the energy we have calculated above is gravitational potential energy.
That means 5760 J of gravitational potential energy.
Recall that another formula for gravitational potential energy (GPE) is
GPE = mgh (where h is the height lifted, mass is the mass and g is the gravitational constant of 9.81ms-2)
h = 10 metres (given)
Therefore,
5760 = m x 9.81 x 10
98.1m = 5760
m = 58.71559g
Hence, mass lifted is 58.7g (in 3sf)
Periodic motion
This question is about the stretching of springs
The diagram below shows an unblocked spring of length 100 mm
hanging suspended from a clamp. When an object of mass 50g is
hung on the spring, it becomes 180 mm long.
The spring constant K=50N/m
100 mm
50g
1- Calculate x in (mm) then convert it to meter
X is the distance that the spring is stretched from its
equilibrium position.
2- Use Hooke's law to calculate the restoring force of the spring
Hooke's law :
F=-K.X
The value of x is 0.04m and restoring force is 9 N
(a) From the figure, the spring force balances force due to gravity.
So, [tex]\frac{1}{2} kX^{2} = mg[/tex]
Where, k = spring constant = 50N/m
X = compressed distance = L+x = 0.1+x
m = mass = 50 g = 0.05Kg
g = acceleration due to gravity = 10
Putting these values in above equation, we get: x= 0.04m
(b) Using Hooke's law, F = kx
Where, k = spring constant =50N/m
x = distance = 180mm = 0.18 m
Putting these values in above equation, we get restoring force F = 9N
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A blue whale with a mass of 1.90 X 10^5 kg was caught in 1947. What is the magnitude of the minimum force needed to move the whale along a horizontal ramp if the coefficient of static friction between the ramp's surface and the whale is 0.460?
The minimum force needed to move the whale along a horizontal ramp, given that the whale has a mass of 1.90×10⁵ Kg is 856520 N
How do I determine the force needed to move the whale?We'll begin by listing out the given parameters from the question. This is shown below:
Mass of whale (m) = 1.90×10⁵ KgCoefficient of static friction (μ) = 0.460Force needed (F) = ?To obtain the force needed to move the whale, we shall first obtain the normal reaction. This is shown below:
Mass of whale (m) = 1.90×10⁵ KgAcceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = ?N = mg
N = 1.90×10⁵ × 9.8
N = 1862000 N
Finally, we shall determine the force needed. Details below:
Coefficient of static friction (μ) = 0.460Normal reaction (N) = 1862000 NForce needed (F) = ?F = μN
F = μN
F = 0.460 × 1862000
F = 856520 N
Thus, we can conclude that the force needed is 856520 N
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Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.
To solve this we must be knowing each and every concept related to interval. Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as below.
What is interval?An interval is any set of numbers that fall between two distinct integers. This range includes all real values that fall between those two. All real numbers that lie in any 2 of a set's numbers are collectively referred to as an interval within mathematics.
For instance, the set of integers x fulfilling 0 x 1 is the interval consisting of 0, 1, and all numbers in between. a snapshot graph of wave on a string moving toward one another at 1 m/s at time t = 0 s.
At time t = 0,Y₀= 0 cm
At At time t =1, Y₁= 0 cm
At time t = 2, Y₂= 0 cm
At time t =3, Y₃= 0 cm
At time t =4, Y₄= 0 cm
At time t = 5 ,Y₅=0 cm
At time t = 6, Y₆= 0 cm
Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as above.
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Find the full load primary and secondary current of a 230/115V, 2kVA transformer.
The full load primary current of a 230/115V, 2kVA transformer can be calculated using the formula:
I_primary = (2kVA * 1000 VA/kVA) / (230V)
I_primary = 8.7V
The full load secondary current of the transformer can be calculated using the formula:
I_secondary = (2kVA * 1000 VA/kVA) / (115V)
I_secondary = 17.4V
Therefore, the full-load primary current of the transformer is approximately 8.7V, and the full-load secondary current is approximately 17.4V. It is important to note that these values are based on the assumption that the transformer is operating at its full load capacity. If the transformer is operating at a lower load, the primary and secondary currents will be correspondingly lower.
A car accelerates from the rest at 1.5 m/s^2 for 10 sec. What made the car move?
Accelerating linearly is simple.
What is Acceleration?When the velocity vector length of an object moving in a straight line changes in response to changes in the object's speed (speed being the magnitude of the velocity vector), we have acceleration. Increasing speed is frequently referred to as "positive acceleration" and decreasing speed as "negative acceleration."
A particle's acceleration is the rate at which its velocity changes over time. The term "constant acceleration" refers to the pace at which a particle's velocity changes.
We shall measure acceleration in metres per second per second because our basic units are metres and seconds.
Therefore, Accelerating linearly is simple.
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The same 42 kg cart is pushed forward with a force of 180 Newtons. How far will it go if a total of 2500 Joules of work are done on the cart?
Important Formulas:
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]m=42kg[/tex]
[tex]F=180N[/tex]
[tex]w=2500J[/tex]
[tex]d=?[/tex]
__________________________________________________________
Rearranging work formula to make distance the subject:
[tex]w=Fd[/tex]
[tex]\dfrac{w}{F} =\dfrac{Fd}{F}[/tex]
[tex]d=\dfrac{w}{F}[/tex]
__________________________________________________________
Finding distance:
[tex]d=\dfrac{w}{F}[/tex]
[tex]d=\dfrac{2500}{180}[/tex]
__________________________________________________________
[tex]\fbox{d = 13.89 meters}[/tex]