22. Chris bought a new car for $12,500. He made a $3,000 down payment and financed the rest at an annual interest rate of 14.5% for 36 months (3 years). How much less would his total interest be for the same loan for 24 months (2 years)? A. $1,387.50 B. $1,377.50 C. $1,367.50 D. $1,357.50​

Answer:

361

Step-by-step explanation:

discriminant = b² - 4ac

= (21)² - 4(1)(20)

= 441 - 80

= 361

Answer:

18/19= X/37 because 18 and x are both between 72 and 45 degrees

Multiply 18 and 37 then divide by 19 to get answer

Step-by-step explanation:

Step-by-step explanation:

2y - x = 6

2y = x + 6

y = (x + 6) / 2

the slope is 1 and the y int is 3

The answers to the questions are

a. From the table the probability of having 6 girls in 8 birth is given as

0.109.

b. The probability of 6 or more girls in 8 births

p(6) + p(7) + p(8)

= 0.109 + 0.016 + 0.002

= 0.127

c. The result from b is the relevant factor given that it includes the probability of getting 6, 7 and 8 girls.

D. No six is not a significantly high number of girls in 8 births. This conclusion is from the fact that 0.109 is greater than 0.05.

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Answer: A. x = 4

Step-by-step explanation:

Substituting 4 for x..

(4+7)^2 = 121

(11)^2 = 121

11 * 11 = 121

The graph that represents the given line with slope and y-intercept is as attached below.

We are given the equation;

x - y - 3 = 0

Now, the standard way we should put the equation would be in slope intercept form which is; y = mx + c

where;

m is slope

c is y-intercept

Thus, our equation can be rearranged to get;

y = x - 3

Thus, y-intercept is c = -3

The graph that represents the given line is as attached below.

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The standard deviation of the number of defective candles in the group is 0.9277.

When a random variable X follows a binomial distribution, with the sample size n, and the proportion of success is p, then the standard deviation is calculated as:

σ = √{np(1-p)}.

In the question, we are given that off the production line, there is a 2.2% chance that a candle is defective.

We are asked if the company selected 40 candles off the line, then what is the standard deviation of the number of defective candles in the group.

Assuming the occurrence of a defective bulb as success, we get the proportion of success, p = 2.2% or 0.022, and the sample size, n = 40.

Thus, we can calculate the standard deviation of the number of defective candles in the group as:

σ = √{np(1-p),

or, σ = √{40*0.022*(1 - 0.022)} = √0.86064 = 0.9277.

Thus, the standard deviation of the number of defective candles in the group is 0.9277.

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The correct equation of 146 ÷ 7 = 20857 is 146.0 ÷ 7.0 = 20.857

The equation is given as:

146 ÷ 7 = 20857

The above equation is wrong.

The equation can be rewritten as:

146.0 ÷ 7.0 = 20857

The significant digits in 146.0 and 7.0 are 3 and 1, respectively.

3 - 1 = 2

This means that

So, the decimal place in the result must be after the second digit.

So, we have:

146.0 ÷ 7.0 = 20.857

Using the above highlights, we have:

146 ÷ 0.7 = 208.57

1.46 ÷ 7 = 0.20857

14.6 ÷ 0.7 = 20.857

1460 ÷ 70 = 20.857

The reasoning behind the above equations is that the decimal position in the results is dependent on the decimal positions in the dividend and divisor

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The total number of snakes in the zoo is 10.

The number of snake can be found using ratio as follows:

The animals in the zoo are lions, tigers and snakes and he has them in the ratio of 5 : 3 : 2. The total animal is 50 animals.

Therefore,

total snakes = 2 / 10 × 50

total snakes = 100 / 10

total snakes = 10

Therefore, the total number of snakes in the zoo is 10.

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Using Green's Theorem to evaluate the given line integral with the given conditions and vertices gives us; -30

The line integral of a vector-valued function along the edges of a rectangle or any other closed curve can be found by converting the line integral into a double integral. We apply Green's theorem to do this. The resulting double integral is integrated over the two-dimensional region bounded by the same closed curve.

Green's Theorem can be applied as follows:

∮_c (P.dx + Q.dy) = ∫∫_R ((dQ/dx) - (dP/dy))dA

The vertices of the rectangle (1,1), (3,1), (1,4), and (3,4).

Applying Green's Theorem to the given function gives;

∮_c (ln x + y) dx - x² dy

= ∫14∫13 Dx(-x2) -Dy(ln(x) +y) dx dy

= ∫₁⁴∫₁³ (-2x - 1) dx dy

= -3·[x² +x]₁³

= -30

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[tex]nPr = \frac{n!}{(n - r)!} [/tex]

[tex]5P2 = \frac{5!}{(5 - 2)!} = \frac{5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} = 20[/tex]

Step-by-step explanation:

the formula for the height in a right-angled triangle is

h = sqrt(p×q)

p and q being the segments of the Hypotenuse left and right from the point, where the height intersects with the Hypotenuse.

so, in our case

12 = sqrt(16×(x-16))

let's square this to eliminate the square root :

144 = 16×(x - 16) = 16x - 256

400 = 16x

x = 25

Using right triangle relations, we will get:

We assume that bot triangles are equivalent, then the angle B will be the same as the angle Z.

Now remember the relations:

If we step on angle B, we have:

Replacing that, we get:

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Answer: A and H

Step-by-step explanation:

y=x+1 is shaded below and dotted, so [tex]y < x+1 \implies x-y > -1[/tex].

Also, y=-2 is dotted and shaded above, so it represents [tex]y > -2[/tex]

The decomposition of the partial fraction is [tex]\frac{4ax-a^2}{(x+ 2a)(x-a)} = \frac{A}{x + 2a} + \frac{B}{x - a}[/tex]

The expression is given as:

[tex]\frac{4ax-a^2}{x^2+ax-2a^2}[/tex]

Expand the denominator

[tex]\frac{4ax-a^2}{x^2- ax+2ax-2a^2}[/tex]

Factorize

[tex]\frac{4ax-a^2}{x(x- a)+2a(x-a)}[/tex]

Factor out x - a

[tex]\frac{4ax-a^2}{(x+ 2a)(x-a)}[/tex]

The denominator of the partial fraction is a product of two linear factors.

So, the decomposition can be represented as:

[tex]\frac{4ax-a^2}{(x+ 2a)(x-a)} = \frac{A}{x + 2a} + \frac{B}{x - a}[/tex]

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Answer:

C

Step-by-step explanation:

y = (x - 2)² = x² - 4x + 4 → (1)

x + y - 2 = 0 → (2)

substitute y = x² - 4x + 4 into (2)

x + x² - 4x + 4 - 2 = 0

x² - 3x + 2 = 0

(x - 1)(x - 2) = 0

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2

substitute these values into (2) and solve for y

x = 1 : 1 + y - 2 = 0 ⇒ y - 1 = 0 ⇒ y = 1 ⇒ (1, 1 )

x = 2 : 2 + y - 2 = 0 ⇒ y + 0 = 0 ⇒ y = 0 ⇒ (2, 0 )

the line intersects curve C at 2 points (1, 1 ) and (2, 0 )

The  bottom cutoff for receiving an A grade is 88.

The bottom cutoff for receiving an A grade is found as follows:

The mean of the distribution = 75

The standard deviation = 9

The z-score for the 93% = 1.476

The score for an A grade, x = mean + z-score * standard deviation

Score for an A grade, x = 75 + 1.476 * 9

Score for an A grade, x = 88

In conclusion, the minimum score for an A grade is obtained from the mean, the z-score and the standard deviation.

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Answer:

  A.  -∞ < y < 2

Step-by-step explanation:

The range is the vertical extent of the graph.

The arrow pointing down tells you the graph extends toward -∞.

The arrow pointing right suggests that y=2 is a horizontal asymptote. A graph will approach, but never cross, an asymptote. Thus, we can conclude y < 2.

The range is the set of values that lie between the limits:

  -∞ < y < 2

Answer:

1.The center of the circle lies on the x-axis

2.The radius of the circle is 3 units.

3.The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.

Answer:

(1 , 6)

Step-by-step explanation:

the center of the circle is the midpoint of the diameter

Which is the point of coordinates:

[tex](\frac{-3+5}{2} ,\frac{5+7}{2} )[/tex]

Then the center is the point :

[tex](1 , 6)[/tex]

[tex] \huge\mathbb{ \underline{SOLUTION :}}[/tex]

Given:

[tex]\longrightarrow\bold{(-3,5)}[/tex]

[tex]\longrightarrow\bold{(5, 7)}[/tex]

Calculate the average value between the x-coordinates of the diameter and do the same for the y-coordinates:

[tex]\longrightarrow\sf{C_x=\dfrac{-3+5}{2} = \dfrac{2}{2} =1}[/tex]

[tex]\longrightarrow\sf{C_y= \dfrac{5+7}{2} = \dfrac{12}{2} = 6 }[/tex]

[tex]\huge \mathbb{ \underline{ANSWER:}}[/tex]

[tex]\longrightarrow\sf{=(1,6)}[/tex]

The amount of qts to use for 15 gals is 0.6qts

Proportion and ratio

Ratio are written as quotient of 2 integers

Given that 2 qts for every 50 gal of water, this is written as;

2qts = 50 gals

In order to calculate for 15gal, we will have:

x = 15gals

Take the ratio

2/x = 50/15

50x = 30

x = 3/5

x = 0.6qts

Hence the amount of qts to use for 15 gals is 0.6qts

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Answer:

120°

Step-by-step explanation:

Angles in a quadrilateral add to 360°, so

90+90+x+2x=360

180+3x=360

3x=180

x=60

So, angle R measures 120°.

Answer:

31 3/4 %

Step-by-step explanation:

There are 100 squares so each square is a percent.  There at 31 full squares colored and it looks like 3/4 of 1 square.

Hello!

We are going to solve the question with our given functions.

We were given:

Those are our two given functions, we will use those to solve for (f + g)(x).

Keep in mind that (f + g)(x) could also be written as f(x) + g(x)

With this knowledge, we can solve our question.

Solve:

(ƒ + g)(x) = f(x) + g(x)

Plug in our f(x) and g(x) functions and solve.

f(x) + g(x) = |2x +1| + 3 - 2

Simplify.

|2x +1| + 3 - 2

|2x +1| + 1

Since we can't simplify this any further, the above will be our answer.

(f + g)(x) = |2x +1| + 1

Answer:

|2x +1| + 1

The number of unique passwords is 5400

The characteristics of the password are given as:

Since the characters in the password must unique, we have the following possibilities

So, the number of unique passwords is

Password = 5 * 10 * 4 * 9 * 3

Evaluate the product

Password = 5400

Hence, the number of unique passwords is 5400

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Answer:

13 pieces

Step-by-step explanation:

First we convert 4m into cm :

1m = 100cm

4m = 400cm

Now we need to figure out how many 30s go into 400 :

400 ÷ 30 = 13 remainder 10

So 13 pieces can be cut from the ribbon

Hope this helped and have a good day  

Answer:

13

Step-by-step explanation:

4 meters is equal to 400 centimeters.

400/30 =  13 1/3

You don't want partial pieces, so your answer is 13

The future values of Ashley's periodic deposits under the five scenarios are stated in the deposit table as follows:

Item     Initial       Periodic      Deposit    Interest    Future Value    Interest

         Deposit     Deposit        Period        Rate                                    ($)

a.      $10,000     $10,000     6 months        5%        $61,774.51      $1,774.51

b.     $10,000     $10,000     3 months        5%      $30,502.78       $502.78

c.      $10,000    $10,000     6 months        5%        $51,774.51     $1,522.42

d.    $20,000    $10,000      6 months       5%        $72,201.71     $2,201.71

e.   $10,000     $10,000     6 months       5%/6%  $60,803.78       $803.78

The future value of a periodic investment represents the present value of cash flows compounded at an interest rate into the future.

The future value is computed using the FV formula or factor.

It can also be computed using an online finance calculator as follows:

Periodic Deposit = $10,000

Investment period = 6 months

Interest rate = 5% compounded monthly

N (# of periods) = 6 months

I/Y (Interest per year) = 5%

PV (Present Value) = $0

PMT (Periodic Payment) = $10,000

Results:

FV = $61,774.51

Sum of all periodic payments = $60,000 ($10,000 x 6)

Total Interest = $1,774.51

c) Interest on $10,000 for 3 months is $1,522.42 ($1,774.51 - $252.09).

d)                             Future Value      Interest

5% with $20,000   $82,285.04    $2,285.04

5% with  $10,000     (10,083.33)          (83.33)

Total for 6 months   $72,201.71     $2,201.71

e)                            Future Value       Interest

5% for 3 months    $30,502.78       $502.78

6% for 3 months     $30,301.00       $301.00

Total for 6 months $60,803.78      $803.78

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