According to the given information the answer is Add masses to each car until they have the same mass, then test the carts again.
What is dynamic carts?Features three low friction ball bearing wheels and matched axles to assure their rolling along a true line without deviation to produce accurate data, and a sturdy steel body to endure rigorous handling. Each cart is around 1.5 kg in weight. The ends of the cart lift above the bed to transport a brick or any other bulk, and the cart bed is covered with a rubber pad. At one end of the cart, there is a clip where a tape can be fastened. Each cart's pins fit into the holes in the others, allowing the mass to be doubled by stacking them.
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The complete question is-
Three different dynamic carts of different masses are rolled down a ramp. The heaviest one rolls down the ramp the fastest. Before concluding that a more massive cart will roll down a ramp faster, what experiment with these three carts might you want to do?
Run an experiment with the ramp at a different angleFind a fourth cart to add to the test, then test againChange the surface of the ramp, then test the carts againAdd masses to each car until they have the same mass, then test the carts againThe centripetal force on object M as it passes
through the rest position is approximately
Since the particle always moves in a circular motion in a direction perpendicular to the radial direction.
The work done by the centripetal force in a circular motion is therefore always zero since the dot product is always zero. A force known as the centripetal force acts on a particle when it is revolving around a specific axis or point. The circular path's center is where this force is directed. The ideal decision is (d) Therefore, the body's weight will be equal to the centripetal force when the angular acceleration reaches the same level as the acceleration caused by gravity. It should be noted that for the centripetal force to equal the weight, there must be a uniform circular motion.
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You went to move a 41 kg bookcase to a different place in the living room. If you push with a force of 65 N and the bookcase accelerates at 0. 12 m/s2 what is the coefficient of kinetic friction between the bookcase and the carpet?
If you push with a force of 65 N and the bookcase accelerates at 0. 12 m/s2. The answer to the given question is A65=41×A.A=1.2m.
Explanation of the given answer:Functions and co efficients are: Ff=μkFN F f = μ k F N
The equation for kinetic friction, where FN is the object's normal force and k is the coefficient of kinetic friction.
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula which is fr = Fr/N serves as a representation of kinetic friction.
The primary distinction between static and kinetic friction is that kinetic friction occurs when there is relative motion between the surfaces, whereas static friction occurs when the surfaces are at rest.
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What is the acceleration of the particle at t 0?
The acceleration of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Acceleration is the rate of change of velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction. Acceleration of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of wee can calculate. Hence by the primary information that we have we can formerly consider that the acceleration which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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Assume air resistance is negligible unless otherwise stated. Calculate the displacement in m and velocity in m/s at the following times for a rock thrown straight down with an initial velocity of 14.4 m/s from the Verrazano Narrows bridge in New York City. The roadway of this bridge is 70.0 m above the water. (Enter the magnitudes.) (a) 0.500 s displacement m velocity m/s (b) 1.00 s displacement m velocity m/s (c) 1.50 s displacement m velocity m/s (d) 2.00 s displacement m velocity m/s (e) 2.50 s displacement m velocity m/s
Answer:
(a) 0.500 s displacement 70.0 m - 7.2 m velocity 7.2 m/s
(b) 1.00 s displacement 70.0 m - 28.8 m velocity -13.6 m/s
(c) 1.50 s displacement 70.0 m - 57.6 m velocity -20.4 m/s
(d) 2.00 s displacement 70.0 m - 92.8 m velocity -24.0 m/s
(e) 2.50 s displacement 70.0 m -134.4 m velocity -25.2 m/s
Construct the following SI derived unit, the coulomb, and define the faraday. A coulomb is a measure of and has units of: 1 A faraday is a constant and has a value of: (include units)
A coulomb is a measure of electrical charge and has units of amperes times seconds (A⋅s). A faraday is a constant equal to the magnitude of electric charge per mole of electrons of 96,485.3399 Coulombs (C).
What is magnitude?
Magnitude is a measure of the size or scale of an object or event. It is often used to describe the intensity or severity of a phenomenon, such as earthquakes and hurricanes. It is usually expressed as a number on a logarithmic scale. In astronomy, magnitude is used to measure the brightness of stars and other celestial bodies. On Earth, magnitude is often used to measure the size of earthquakes and other seismic events. Magnitudes are typically expressed as a number on a logarithmic scale, with a greater magnitude indicating a larger size or scale of the event. Magnitudes can also be used to measure the intensity of light, sound, and other forms of energy.
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Please help
How does sound move from the source to the receiver? (a slinky moving back and forth)
Answer:
through a chain reaction of particle collisions in a medium.
Explanation:
A point particle of charge -5.40 nC is located at the origin of a Cartesian coordinate system. Determine the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge.
The magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is 918.7 N/C.
Given that,
Charge on point particle Q = -5.4 nC = -5.4 × 10⁻⁹ C
Distance from the charge r = 23 cm = 23 × 10⁻² m
The relation between distance charge and electric field is known to be,
E = 1/4πε₀ × Q/r² = 9 × 10⁹ × (-5.4 × 10⁻⁹)/(23 × 10⁻²)² = (9 × 5.4)× 10⁴/(23)² = 918.7 N/C
Thus, the magnitude of the electric field due to this charge at a distance of 23.0 cm from the charge is calculated to be 918.7 N/C.
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the first artificial satellite to orbit the earth was sputnik 1, launched october 4, 1957. the mass of sputnik 1 was 83.5 kg, and its distances from the center of the earth at apogee and perigee were 7300 km and 6610 km, respectively. find the difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee
The difference in gravitational potential energy for sputnik 1 as it moved from apogee to perigee is 193 kJ.
The gravitational potential energy of an object in orbit around the Earth can be calculated using the equation:
U = -GMm/r
where U is the gravitational potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the object.
The difference in gravitational potential energy as the satellite moves from apogee to perigee can be found by calculating the potential energy at each point and subtracting the two values:
U(apogee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (7300 x 10^3 m)
U(perigee) = -(6.67 x 10^-11 N*(m^2)/(kg^2)) * (5.972 x 10^24 kg) * (83.5 kg) / (6610 x 10^3 m)
U(apogee) = -1.865 x 10^5 J
U(perigee) = -2.058 x 10^5 J
The difference in gravitational potential energy is:
= U(perigee) - U(apogee)
= -2.058 x 10^5 J - (-1.865 x 10^5 J)
= 193 x 10^3 J
So, the difference in gravitational potential energy for Sputnik 1 as it moved from apogee to perigee is 193 kJ.
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Seismic-wave velocity can change (increase or decrease) as the waves pass through different rock types.
Yes, seismic-wave velocity can change as the waves pass through different rock types.
Rocks with high porosity and permeability tend to have lower seismic-wave velocities because the pores contain fluid that can dampen the energy of the seismic waves, while rocks with high compaction and densities tend to have higher seismic-wave velocities. Additionally, changes in temperature and pressure can also affect seismic-wave velocity.
What are seismic sounders?Seismic sounders are seismic instruments that use a wide range of sound frequencies to measure the Earth's subsurface structure, composition, and its response to seismic waves generated from a source.
They are used in the exploration of oil, gas and mineral resources and for investigating earthquake and volcanic processes.
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two blocks are connected by a string of negligible mass that passes over massless pulleys
If two blocks are connected by a string of negligible mass that passes over massless pulleys, the system can be analyzed using the principles of Newton's second law and the conservation of energy.
In this scenario, the net force acting on each block is the tension in the string, which is equal in magnitude for both blocks.
Therefore, if the blocks have different masses, they will have different accelerations.
In this scenario, the mechanical energy of the system is the sum of the gravitational potential energy and the kinetic energy of the blocks. If the pulleys are massless and frictionless, then the mechanical energy of the system will be conserved.
In summary, the two blocks will move together with the same acceleration if the pulleys are massless and frictionless.
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For the segment AB in the bacterium's trajectory, calculate the x component of its velocity.
Express your answer in micrometers per second
UABx = 2o pm/s
For segment AB in the bacterium's trajectory, The x component of its velocity is 3.92m/s.
[tex]AB_X = 50um AB_Y = 10um[/tex]
[tex]AB =\sqrt{50^{2}+ 10^{2} } = 50.99um[/tex]
[tex]t = \frac{AB}{20} = 2.55[/tex]
[tex]V_ABY = \frac{AB_Y}{T}[/tex]
[tex]\frac{10}{2.55}[/tex] [tex]= 3.92m/s[/tex]
Speed is the directional pace of an item in motion as an illustration of its fee of change in position as discovered from a specific body of reference and as measured with the aid of a selected well-known time (e.g. 60 km/h northbound). speed is an essential idea in kinematics, the department of classical mechanics that describes the motion of our bodies.
Velocity is a physical vector quantity; both importance and route are had to define it. The scalar absolute value (significance) of velocity is known as pace, being a coherent derived unit whose amount is measured within the SI (metric system) as meters per 2d (m/s or m⋅s−1). as an example, "5 meters per 2d" is a scalar, whereas "5 meters in step with 2nd east" is a vector. If there's an exchange in speed, direction, or each, then the object is stated to be present process an acceleration.
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A 600 g steel block rotates on a steel table (μk = 0.6) while attached to a 1.0 m long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.2 N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 50 N. If the block starts from rest, how many revolutions does it make before the tube breaks?
If the block starts from rest, then revolutions that it make before the tube breaks is 0.947 rotations.
What is meant by revolution?When object turns around an internal axis, it is called a rotation. When object circles an external axis, it is called revolution.
Given mass of block = 600 g = 0.6 kg ; Radius of rotation = 1.0 m-long
Given thrust force of 4.2 N
The maximum tension is 50 N.
As thrust is perpendicular to the tube. So, tangential component of the thrust force is Ft=4.2 N and radial component Fr=0
As we know, α = F/m r
= 4.2/0.6 * 1
α = 7 rad/s²
As, m r ω²= 50 N
ω² = 50/ 0.6 * 1.0
ω = 9.128 rad/s
Ф = ω² - ω0²/2α
= (9.128² - 0)/2 * 7
Ф = 5.951 rad
As 1 Radians = 0.1592 Rotations,
5.951 rad = 0.947 rotations.
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Which of the following best defines the term “climate”?
A: the weather patterns that are occurring right now
B: the specific weather patterns for a local region or city
C: the temperature readings for the past 30 years or more
D:he average conditions of the atmosphere for a large region for the past 30 years or more
The statement that best defines climate is as follows: the average conditions of the atmosphere for a large region for the past 30 years or more (option D).
What is climate?Climate is the long-term manifestations of weather and other atmospheric conditions in a given area or country.
Climate is now usually represented by the statistical summary of its weather conditions during a period long enough to ensure that representative values are obtained (generally 30 years).
A description of a climate includes information on, e.g. the average temperature in different seasons, rainfall, and sunshine.
Therefore, option D correctly describes climate.
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A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 110,000 kg of scrap metal into it. (a) What is the final velocity of the loaded freight car
The freight car which is being dumped into the metal scrap has the final velocity of 0.18 m/s.
In this problem, we use the principle of conservation of linear momentum.
Given that,
Mass of the freight car m₁ = 30,000 kg
Mass of the hopper m₂ = 110,000 kg
Velocity of the freight car u₁ = 0.85 m/s
Velocity of the hopper u₂ = 0
Let the velocity of the loaded freight car = v
We need to find out v.
m₁ u₁ + m₂ u₂ = ( m₁ + m₂) v
After putting the values into the equation above, we have,
30,000 × 0.85 + 110,000 × 0 = (30,000 + 110,000) v
140,000 v = 25500
v = 0.18 m/s
Thus, the required velocity of the loaded freight car is calculated to be 0.18 m/s.
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A 64 g plastic ball is moving to the left at 24 m/s . How much work must be done on the ball to cause it to move to the right at 24 m/s
The ball requires a total of zero work to go to the right at 24 m/s.
Take into account the ball's kinetic energy.
Vi = -24 ms-1 for the initial velocity
Final velocity: vf = +24ms⁻¹
K = 12mvf²- 12mvi² = 12m(vf² - vi²) = 12m(242 - 242) = 0,
meaning that the ball does not undergo any effort.
As an alternative, think about the effort made to stop the ball.
W1 = ½m(0 – 24²) = 0.5 × 0.06 × –576 = –17.28J
Work required to accelerate the ball from rest to +24 milliseconds per second was W2 = 12m(242 - 0) = 0.5 0.06 576 = +17.28 J.
Therefore, the sum of the work is W = W1 + W2 = -17.28 + 17.28 = 0 J.
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Define the following
a. Velocity:
b. Inertia:
c.Speed:
e Force:
f. Balanced force:
g. Net force:
h. Displacement:
Answer:
Explanation:
a.speed with direction associated
b.the ability to resist motion
c.The rate of change of position of an object
e.any influence object's motion
f.forces cancel out, create equilibrium
g.total force acting on an object
h. change in position of an object (total distance from starting point)
two objects gravitationally attract with a force of 36 N if the distance between the two objects centers is decreased by a factor of threee then the new force of attraction is
The new force of attraction is 324N if the distance between the centres of the two objects is reduced by a factor of 3e.
The equation for the force of gravitational attraction between two objects is: F = G*(m1*m2)/r^2 Where F is the force of attraction, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers. If the distance between the two objects' centers is decreased by a factor of three, the new force of attraction will be: F' = G*(m1*m2)/(r/3)^2The ratio of the new force of attraction to the original force of attraction is:
F'/F = (r/3)^2 If we substitute in the original force of attraction, we have:
F'/36 = (r/3)^2 = F' = 36 * (r/3)^2
As we decrease the distance by a factor of 3, the new force of attraction will increase by a factor of 9.
F' = 36*9 = 324 N
Therefore, the new force of attraction is 324 N.
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anthony walks to the pizza place for lunch. he walks 1 km east then 2 km south and then 1 km east again. what distance did he cover and what was his displacement
Answer:
3 km displacement
Explanation:
I'm pretty sure that's the answer, I'm so sorry if it's not
What is the vertical acceleration of a dart that is launched horizontally with an initial velocity of 2.3 m/s
With merely a 2. 3 m/s beginning velocity, a horizontally dart launch accelerates upward at a rate of -9.8 m/s².
Describe the concept of acceleration:The rate at which speed and distance for velocity vary over time is known as acceleration. Anything is said to have been accelerated when it goes quicker or slower in a single direction.
What is an efficient case of acceleration?When an item accelerates positively, it moves more quickly than it did before. In the first instance, the moving automobile showed positive acceleration. The acceleration is accelerating in a way that is comparable with the direction in which the vehicle is speeding up and velocomotion is accelerated in a route that is compatible with the direction in which the vehicle is
Let's say a body of mass (m) is shot from a height (h) above surface of the planet. As it descends at a faster rate, it eventually reaches the ground.
Under the influence of gravity, which is acting at a distance r from the earth's core, the body begins to accelerate in that direction.
Then, ma = GMm/r²
a = GM/r²
Therefore, the value of the acceleration due to gravity (g) = GM/r2.
Any object freely falling to the surface of the earth has acceleration due to gravity is 9.8m/s².
The earth's gravitational attraction is felt by the object if it shifts away from the planet's surface. Dart's vertical acceleration is therefore equivalent to -g.
As a result, the dart's vertical acceleration is equivalent to -9.8m/s2.
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Stephen has to drive 8 miles south and 3 miles east to get to work.What is his distance and displacement?
Since the displacement is a vector quantity, the distance is 11 miles while displacement is 8.5 miles
What is Displacement ?Displacement is a distance travelled in a specific direction. Distance is a scalar quantity while displacement is a vector quantity.
Given that Stephen has to drive 8 miles south and 3 miles east to get to work.
His distance will be 8 miles + 3 miles = 11 miles
While his displacement can be calculated by using Pythagoras theorem. That is,
Displacement D = √(8² + 3²)
D = √(64 + 9)
D = √73
D = 8.5 miles
Therefore, his distance is 11 miles and his displacement is 8.5 miles.
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What causes diffusion in cells?
The causes diffusion in cells are, temperature, area of interaction, the size of the concentration gradient.
1) Temperature, The rate of diffusion increases as temperature rises.
2) Area of Interaction: The rate of diffusion increases as the surface area of interacting molecules increases.
3) The Size of the Concentration Gradient: The rate of diffusion is higher the greater the concentration gradient between the regions.
Higher the rate of diffusion, the more concentration between the locations. The movement is forced because of the increased pressure that the higher concentration creates. The movement of molecules from a location of higher concentration to a region of lower concentration can be used to define diffusion. The continuous motion (or kinetic energy) of atoms in matter is the primary cause of diffusion.
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can u pls solve this question thank u!! i having my physics paper tomorrow!!
Answer:
13.875Ω & 5Ω
Explanation:
in the first diagram:-
R = Rs + Rp + Rs'
Rp => [tex]\frac{1}{7} + \frac{1}{1} = \frac{1+7}{7} = \frac{8}{7} \\[/tex]
Rp = [tex]\frac{7}{8}[/tex] = 0.875
4 + 0.875 + 9 = 13.875Ω
in the second diagram:-
R= Rp + Rs + Rp'
Rp => 1/6 + 1/3 = 1+2/6 = 3/6 => 2
Rp' => 1/3+1/3+1/3 = 3/3 => 1
R = 2 + 2 + 1 = 5 Ω
Write down whether quantity of potential kinetic and total energy
Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
What is Potential energy?The earth can pull you down through the force of gravity while doing work in the process, being at the top of a stairwell gives you more potential energy than standing at the bottom.
Two magnets have more potential energy when they are held apart than when they are near to one another. They will migrate near each other and begin working if you let them go.
The force acting on the two objects affects the potential energy formula. P.E. = mgh, where m is the mass in kilograms and g is the acceleration due to gravity, is the formula for gravitational force.
Therefore, Potential energy is the power that a thing possesses as a result of where it is in relation to other objects.
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What is the velocity of the particle at time t 0?
The velocity of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
Velocity is the rate of change of velocity. At any point on a trajectory, the magnitude of the velocity is given by the rate of change of velocity in both magnitude and direction. Velocity of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of we can calculate. Hence by the primary information that we have we can formerly consider that the velocity which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.
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A ball is tossed straight up from the surface of a small spherical asteroid with no atmosphere. The ball goes to a height equal to the asteroid's radius and then falls straight down toward the surface of the asteroid. What forces if any act on the ball while it is on the way up?
a. only a decreasing gravitational forces acts downward
b. only an increasing gravitational force that acts downwards.
c. only a constant gravitational force that acts downwards
d. Both a constant gravitational force that acts downwards and a decreasing force that acts upwards.
e. No forces act on the ball
'Only a decreasing gravitational force that acts downward' act on the ball while it is on the way up.
What is gravitational force?
Gravitational force is the force of attraction between two objects that have mass. It is the force of gravity that causes objects to be pulled towards each other. The strength of the force depends on the mass of the objects and the distance between them.
Since the ball is moving away from the Earth, the gravitational force between the two objects is decreasing. The ball does not experience any upward force and thus the only force acting on it is the decreasing gravitational force that acts downward.
Hence, Option A is correct.
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A meter‑long wire of mass 185 g is attached to a 60. 0 Hz mechanical wave oscillator operating at 139 W. The far end of the wire is strung over a frictionless, massless pulley, and a 306 g mass is hung from it. When the oscillator is turned on, it produces a sinusoidal wave in the wire. Calculate the amplitude of oscillation of the wire. Use the value 9. 81 m/s2 for the acceleration due to gravity
The tension in the wire is 2.99986 N. The amplitude of the oscillation of the wire is approximately 0.01067 meters.
The tension (T) can be calculated using the equation:
T = m × g
T = 0.306 × 9.81
T = 2.99986 N
The linear mass density (μ) of the wire is given by the mass per unit length of the wire. It is calculated as:
μ = m(wire) ÷ L(wire)
μ = 0.185 ÷ 1
μ = 0.185 kg/m
The speed (v) of the wave on the wire can be determined using the equation:
v = √(T ÷ μ)
v = √(2.99986 ÷ 0.185 )
v = 7.351 m/s
The power (P) transmitted by the wave is related to the amplitude (A) and the speed (v) of the wave through the equation:
P = 2π² × μ × v × A² × f²
A² = P ÷ (2π² × μ × v × f²)
A² = 139 ÷ (2π² × 0.185 × 7.351 × (60.0)²)
A² = 1.138 × 10⁻⁴
A = √(1.138 × 10⁻⁴)
A = 0.01067 m
Therefore, The amplitude of the oscillation of the wire is approximately 0.01067 meters.
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A proton moves perpendicular to a uniform magnetic field B at 2.20 107 m/s and experiences an acceleration of 1.60 1013 m/s2 in the x direction when its velocity is in the z direction. Determine the magnitude and direction of the field.
The magnitude of the magnetic field is 7.27 x 10-6 T and its direction is perpendicular to the velocity of the proton.
The force experienced by a charged particle in a magnetic field is given by the equation F = q(v x B), where F is the force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.
Given the information provided in the question, we can set up the following equation:
1.60 1013 m/s2 = (q)(2.20 107 m/s) x B
To find the magnitude of the magnetic field, we can divide both sides of the equation by the velocity:
B = 7.27 x 10-6 T
To find the direction of the magnetic field, we know that the force on the proton is perpendicular to its velocity and the direction of the magnetic field. The direction of the magnetic field can be found using the right-hand rule which states that if you point your fingers in the direction of the velocity and then curl them in the direction of the force, your thumb will point in the direction of the magnetic field.
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What is the difference between active and passive flexibility?
The difference between active flexibility and passive flexibility is that in active flexibility, we rely on our own muscle power to reach the end range, but in passive flexibility, we rely on an external push to reach the end range.
According to the findings of recent studies, active flexibility has a stronger connection to a person's level of sporting performance than passive flexibility does. The ability to build active flexibility is more difficult to achieve than passive flexibility. Active flexibility involves passive flexibility in addition to muscle strength in order to be able to retain and maintain the initial extended position.
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When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. What is the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d?
plsss help
According to Newton's law of gravitation, the new gravitational force will be F/9
Newton's Law of GravitationIt states that, the force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. That is,
F = GMm/d²
Where
M = mass of the earthm = mass of the satelliteG = universal gravitational constantThe magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d can be expresses as follow
f = GMm/(3d)²
f = GMm/9d²
f = GMm/d² × 1/9
Since GMm/d² = F
f = F × 1/9
f = F/9
Therefore, the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d is F/9 Newton
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a force of 15 N is used to push a box along the floor a distance of 3 meters. find the amount of work done
Answer:
The amount of work done is 45 J.
Explanation:
We know that the force applied is 15N. The amount of displacement experienced by the box is 3 metres along the floor.
Thus, F= 15N
D= 3 metres
The formula for calculating work done is W= F×D
Thus, W=15×3
W=45J
Thus, the amount of work done is 45J.