8:11
GCSE Science - Physics
22 of 25
14 67%
A cat accelerates from rest to 10 m/s
when it sees a dog. This takes 2
the cat?
seconds What is the acceleration of the cat ?

Answers

Answer 1

the acceleration of the cat is 5m/s square

Answer 2
To find the acceleration of the cat, you can use the formula a = (v-u)/t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time it takes for the acceleration to occur.

In this case, the initial velocity (u) is 0 m/s (since the cat starts at rest), the final velocity (v) is 10 m/s, and the time (t) is 2 seconds. Plugging these values into the formula, we get:

a = (10 m/s - 0 m/s) / 2 s
= 10 m/s / 2 s
= 5 m/s^2

So the acceleration of the cat is 5 m/s^2.

Related Questions

Write words with a similar meaning to the given words for old, stubble and room help me?pls ​

Answers

Answer:

Old = senior. geriatric. senescent. unyoung. over-the-hill.

Stubble= bristles

whiskersdesigner stubblehairfacial hairbeardfive o'clock shadowFeedback

a boy of 40kg and a girl of a mass an unknown mass plays on a seesaw of negligible weigh. If the boy sits 300cm from the pivot and the girl sits 400m from the pivot what is the mass of the girl in order for the seesaw to be in equilibrium

Answers

The mass of the girl is 30 kg  in order for the seesaw to be in equilibrium.

What is seesaw?

A particular kind of lever is a seesaw, which has a long beam coupled to a pivot known as the fulcrum.

As soon as you sit on one side of the beam and apply weight on one end, the beam falls to the ground. This is because the weight of your body is being pulled down by the force of gravity, along with the beam.

Let the  mass of the girl = m kg

In equilibrium;

40 kg × 300 cm = m × 400 cm

⇒ m = 30 kg.

Hence,  the mass of the girl is 30 kg.

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At what separation will two charges, each of magnitude 6.0 μC, exert a force of 0.70 N on each other?

Answers

At separation  of 1470 meters, the two charges exert a force of 0.70 N on each other.

What is electric force?

Electric force is the interaction between any two charged objects that can be either attractive or repelling. Newton's rules of motion, which apply to all forces, explain how each one affects the target body and how it does so. The electric force is one of the many forces that operate on objects.

We know that electric force can be mathematically defined as:

F = kQq/r²

0.70 = 9.0 × 10⁹ × (6.0×10⁻⁹)²/r²

r = 1.47 meter.

Hence, the separation between two charges is 1.47 meters.

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The coyote, whose mass is 20kg is chasing the roadrunner when the coyote accidentally runs off the edge of the cliff and plummets to the ground 30m below. What force does the ground exert on the coyote as he makes a coyote-shaped dent 0.420m deep in the ground.

Answers

The force is 196 N (20kg x 9.8 m/s2)

What is force ?

Force is an action or influence that causes an object to change its state of motion or rest. Force can be exerted by a single object or by two or more objects interacting with each other. Examples of force include friction, gravity, magnetism, electricity, and pressure. The magnitude of a force is usually measured in newtons (N) and is determined by the amount of mass and acceleration of the object it is acting upon.

The force exerted on the coyote by the ground is equal to the mass of the coyote multiplied by the acceleration due to gravity, which is 9.8 m/s2.

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8. If the m<5 is 63°, find the
measure of <3.

Answers

The statement indicates that angle 3 seems to have a 117 degree measurement.

Short answer: What is measure?

Compare of an untold amount with a fixed quantity that is known or A attribute of an item or event is measured when a number is assigned to it so that it may be compared to other things or occurrences.

Briefing:

An angle is the figure produced by two photons that must intersect at a shared terminal in geometry. The symbol should indicate an angle.

The sum of the two degrees is 180 degrees but since radius 5 is 63 degrees.

Angle 3 is therefore = 180 - 63 = 117 degrees.

Consequently, angle 3 has a measure of 117 degrees.

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The sum of the x components of vectors A and B in (Figure 1 ) is
-5
4
14
6
Vectors A and B are shown in a tip to tail arrangement. Vector A begins at the origin (0,0) and ends at the x y coordinate (9,3). Vector B begins at the tip of vector A and ends at the x y coordinate (4,6).

Answers

The resultant (x,y) coordinate of vector B is  (- 5, 3) and that of A is (9,3). Then, the sum of x components of vector A and B is 4.

What are vectors ?

Vectors are physical quantities having both magnitude and direction. For example force, velocity, displacement etc .are vector quantities. Coordinates are used to describe the position of these vectors.

The coordinates of tail of  the vector A is (0, 0) and the head is (9,3)

Then the coordinate of A is (9 -0, 3-0) = (9,3)

Similarly, the tail coordinate of B is (9,3) and head is (4,6). The coordinates of B vector is (4-9, 6-3) = (-5, 3)

Now the sum of x components of A and B is = - 5 + 9 = 4.

Therefore, option b is correct.

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A 25 kg box of roofing shingles is lifted 15 meters vertically to the top of a roof. How much work is done on the box?

Answers

Important Formulas:

[tex]F=ma[/tex]

force(measured in newtons) = mass(measured in kg) * acceleration(measured in m/s^2)

[tex]w=Fd[/tex]

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

__________________________________________________________

Given:

[tex]m=25kg[/tex]

[tex]d=15m[/tex]

[tex]w=?[/tex]

We know that the acceleration due to gravity is 9.8 m/s^2.

__________________________________________________________

Finding force:

[tex]F=ma[/tex]

[tex]F=25\times9.8[/tex]

[tex]F=245N[/tex]

__________________________________________________________

Finding work:

[tex]w=Fd[/tex]

[tex]w=245\times15[/tex]

__________________________________________________________

[tex]\fbox{w = 3675 Joules}[/tex]

a car with mass m1=1000kg moving at speed v1=6m/s hits a stationary truck with mass m2=5000kg. The impact is absolutely inelastic. Determine the speed of both car and truck immediately after the impact

Answers

Impact Speed means the maximum speed of impact tested upon the bumper of the vehicle pursuant to sections 581.6 and 581.7 of part 581 of title 49 of the Code of Federal Regulations.

In an inelastic collision, what occurs when two objects collide?An inelastic collision occurs when items cling together after impact and kinetic energy is not preserved. Because of this violation of conservation, the forces between colliding objects may convert kinetic energy to other types of energy, such as potential energy or thermal energy.To calculate the momentum of either individual vehicle, divide the total system momentum by two (approx. 11 200 kg*m/s). Once the momentum of the individual automobiles is known, the after-collision velocity may be calculated by simply dividing momentum by mass (v=p/m).

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A iguana runs back and forth along the ground. The horizontal position of the iguana in meters over time is shown
What is the displacement of the iguana between 3 s and 6 s?
m
What is the distance traveled by the iguana between 3 s and 6 s?

Answers

The displacement of the iguana between 3 s and 6 s  is 6.71 meters.

The distance traveled by the iguana between 3 s and 6 s is  8.08 meters.

What are distance and displacement?

Distance is the sum of an object's movements, regardless of direction.

The term "displacement" refers to a shift in an object's position.

According to the graph:

The displacement of the iguana between 3 s and 6 s

= √{ (3-6)²+(6-0)²} meters

= 6.71 meters.

The distance traveled by the iguana between 3 s and 6 s

= [ √{ (3-5)²+(6-6)²} +√{ (5-6)²+(6-0)²}] meters

= [2+ 6.08] meters

= 8.08 meters.

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A 500-mm-long, 16-mm-diameter rod made of a homogenous,
isotropic material is observed to increase in length by 300 mm, and
to decrease in diameter by 2.4 mm when subjected to an axial 12-
kN load. Determine the modulus of elasticity and Poisson's ratio of
the material. [20 marks]

Answers

The material has a Poisson's ratio and a modulus of elasticity of 0.25. Y=2G(1+) is the correct relationship between the Young's modulus (Y), the shear modulus (G), and the Poisson's ratio ().

What are elastic modulus and Poisson's ratio?

The bulk modulus, also known as the elastic modulus K, is related to the Poisson's ratio; G as the modulus of shear; and E, Young's modulus, by the following (for isotropic solids whose properties are non-directional). The stiffness is measured by the elastic moduli. They are stress-to-strain ratios.

Determine the rod's stress level.

Determine the longitudinal strain by multiplying F A 12 by (0.016) = 59.683 MPa.

Determine the lateral strain by elongating Or 30010-3 = L mm 500 mm = = 0.0006.

-2.410-3 mm 16 mm Elateral = = -0.00015 d Determine the material's young's modulus.

& Long 59.683 MPa 0.0006 E = 99.471 GPa  100 GPa

Determine the material's poisson's ratio. & the lateral lengthens by -0.00015 0.0006 = 0.25.

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The monster wants to make himself known to the family in the cottage in chapters 9-12 of Frankenstein. He decides he can't do that until he masters something. What skill
must he master?
A. How to dress properly
B. Language
C. The rules of etiquette
D. Music

Answers

Answer:

c

Explanation:

A man drags a 10.0 kg bag of mulch at a constant speed applying a 22.5 N force at a 32-degree angle. What is the friction force acting on the bag?

Answers

The

friction

force acting on the bag is 4.36µ.

What is friction force?

The

force

preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.

Given,

Force =F=22.5 n

Mass=m= 10 kg

mu=µ=?                            

(1N= 1kg m/s²)

Gravitational force =g= 9.81 m/s²

As we know,

F= µ*m*g

µ= m*g/F

  = 10*9.81/ 22.5

µ= 4.36 .

Therefore, the friction force acting on the bag is 4.36.

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The bag is subject to a friction force of 4.36. A man applies a 22.5 N force at a 32° angle while dragging a 10.0 kilogram bag of mulch at a steady speed.

How much friction is there?

Friction refers to the force that resists hard surface, fluid layering, and materials ingredients from gliding past one another. Friction lessens a machine's mechanical advantage, or, to put it another way, friction decreases the output to input ratio.

Force = 22.5 N

Mass  = 10 kg

⇒ mu     = µ (1N= 1kg m/s²)

⇒ g        = 9.81 m/s²

As we know, F= µ × m × g

⇒ µ = (m × g)/F

⇒ (10 × 9.81)/ 22.5

⇒ µ = 4.36 .

Therefore, the friction force acting on the bag is 4.36.

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A force of 7.36 N acts on a(n) 2.1 kg object for 24.7 s. What is the object’s change in momentum? What is its change in velocity? Answer in units of N · s

Answers

Based on the data given:

the change in momentum of the object is 181.8 N.sthe change in velocity, Δv = 86.6 m/s

What is the change in the momentum of a body?

The change in momentum of the object equals the impulse experienced by the object

Mathematically,

Impulse = change in momentum

Impulse = F • t

change in momentum = m • Δ v

F • t = m • Δ v

where

F is the force

t is the time the force acts

m is the mass of the object

Δv is the change in velocity

For the given values:

change in momentum of the object = 7.36 * 24.7

change in momentum = 181.8 N.s

Change in velocity, Δv = change in momentum / mass

Change in velocity, Δv =  181.8 / 2.1

Change in velocity, Δv = 86.6 m/s

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An object with a weigh of 170 N on Earth is brought to planet Oobla. Where it has a weight of 360 N. What is the gravitational field strength on Oobla

Answers

The gravitational field strength on Oobla is 20.75 m/s².

What is gravitational field strength?

The gravitational field is the gravitational force exerted per unit mass on a small mass at a point in the field.

To calculate the gravitational field strength on Ooobla, we use the formula below

Formula:

W/g = W'/g'................. Equation 1

Where:

W = Weight of the object on Earthg = Gravitational field strength on the Earthg' = Gravitational field strength on the OoblaW' = Weight of the object on Oobla

From the question,

Given;

W = 170 Ng = 9.8 m/s²W' = 360 N

Substitute these values into equation 1 and solve for g'

170/9.8 = 360/g'g' = 360×9.8/170g' = 20.75 m/s²

Hence, the gravitational field strength is 20.75 m/s².

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While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run, 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s² Answer in units of J.- answer :7100J part 2 of 2 What is his final velocity? Answer in units of m/s.​

Answers

Answer:

12.3 m/s

Explanation:

To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:

7100 = 1/2 (63.2 kg) v^2

Therefore, v^2 = 7100/31.6

v = √(7100/31.6)

v = 12.3 m/s

A force of 50N applied to the end of a lever moves that end a certain distance if the other end of the lever is moved half as far how much force does it exert?

Answers

The force exerted at other end is 100N.

Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.Mathematically, the above statement is expressed as follows:

                              W = (F cos θ) d = F. d

Where,

W is the work done by the force.

F is the force, d is the displacement caused by force

θ is the angle between the force vector and the displacement vector

Let , F' = Force exerted on ladder at other end

       d' = distance moved = d/2 (given)

i.e.  W = F'd' and W = Fd

Using these two equations we get, F'd' = Fd

i.e. F' = Fd/d'

Given, F = 50N and d' = d/2

Putting these values in above equation we get, F' = 100N

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Which of the following best explains the cause and effect relationship between convection currents in the mantle and the movement of tectonic plates?

A. The tectonic plates will heat up the mantle due to being closer to the surface of the earth and sun. The less dense particles in the mantle fall and cool toward the core, driving the convection cycle.

B. The tectonic plates drive the convection cycles in the mantle. As the plates move apart or push together, particles in the mantle will be thrust toward the core.

C. The heat from the core will make the particles in the mantle more dense and rise, causing plates in the
lithosphere to move in the opposite direction of the convection current.

D. The heat from the core will make particles in the mantle less dense and rise, causing plates in the
lithosphere to move in the direction of the convection current.

Answers

C) The mantle's particles will become more dense and rise as a result of the core heat, causing the lithosphere's plates to move in the opposite direction of the convection current.

How does the mantle's density change as it heats up?

Convection Currents The lithosphere becomes denser than the surrounding magma and sinks back toward the core as the heated mantle transfers heat energy to it.

How does heat travel from the core to the crust in the mantle?

Conduction from the core directly heats the lower mantle. As atoms collide, heat is transferred in conduction. Convection is the movement of warm and cool materials upward and downward. Material that is hot rises to the surface through conduction.

When the mantle rises, what takes place?

“hot spots," which are non-plate tectonic volcanic regions, are probably caused by mantle plumes. A diapir is formed when a mantle plume reaches the upper mantle. Volcanic eruptions are sparked by the heat generated by this molten material in the asthenosphere and lithosphere.

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A 62.3 kg base runner begins his slide into second base while moving at a speed of 4.49 m/s. He slides so that his speed is zero just as he reaches the base. The acceleration of gravity is 9.8 m/s². What is the magnitude of the mechanical energy lost due to friction acting on the run- ner?​

Answers

Answer:

628 J

Explanation:

ME = PE + KE

PE = mgh = 0,  because h = 0

KEi (initial KE) = 1/2mv² = 1/2(62.3 kg)(4.49 m/s)² = 628 J

KEf (final KE) = 0, because v-final = 0

All the initial ME, which is all KE, converts to thermal E due to friction

This theory of motivation focuses on finding the right level of stimulation. An organism tries to find behaviors that actually increase arousal because everything else bores them.
*
2 points
Cognitive Theory
Hierarchy of Needs
Drive-Reduction Model
Optimal Arousal Theory

Answers

Optimal Arousal theory focuses on finding the right level of stimulation.

What is Optimal Arousal theory?

William James (1842–1910), frequently referred to as the father of psychology in the United States, made significant contributions to early studies on motivation.

James proposed a number of instincts that help with survival as the driving forces behind conduct . An instinct is a species-specific pattern of behavior that is not taught, according to biology.

But there was a lot of disagreement over what exactly constitutes instinct among James's contemporaries. James postulated a number of unique human instincts, although many of his contemporaries had different lists.

Therefore, Optimal Arousal theory  focuses on finding the right level of stimulation.

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i understand how something about the pod could have affected its velocity change.
yes or not yet.
EXPLAIN your answer choice.

Answers

A stronger force can cause a greater change in an object's velocity. The correct option is yes

What caused the pod to change direction?

The force exerted by the thrusters caused the pod to change direction. The thrusters on the ACM pod exerted the same strength force as thrusters on other pods on other missions. If the same strength force is exerted on two objects but the objects have different masses the object with less mass will have a greater change in velocity.

Therefore pod would have had to have a lighter mass meaning a smaller amount of force would have had to be exerted onto the pod making it move in the opposite direction.

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A jug containing water at 26° C while another contains water at 82°C,if a patient wish to bath with water 40°C , the ratio of the mass of hot water to that of cold water is_​

Answers

Answer:2:7

Explanation:

Quantity of heat energy before mixing= Quantity of heat energy after mixing

M1. S1.T1+ M2.S2.T2= M.S3.T3

Let, .

M1 = mass of cold water

M2 = mass of hot water

S1=S2=S3=S

M=M1+M2

T1=28,T2=82,T3= 40

M1.28 + M2.82= (M1+M2)40

M1.28 + M2.82= M1 40+M2.40

M2.82 -M2.40= M2.40–M1.28

M2.42= M1. 12

M2/M1= 12/42= 2/7

Or

M2: M1= 2:7

Find the location of the CM of a system of three particles arranged such that two of the particles with mass m are separated by distance I along the y-axis. The third mass 2m lies on the x-axis and is separated by a distance I from one of the masses. ​

Answers

Answer:

CM of a system ( 0.5l , 0.25l )

Explanation:

x = (m1.x1 +m2.x2 +m3.x3) / ( m1 + m2 +m3)

x = ( m x 0 + m x 0 + 2m x l ) / ( m+m+2m)

x = 2m x l / 4m

x = 0.5 l

y = (m1 x y1 +m2 x y2 +m3 x y3) / ( m1 + m2 +m3)

y = (m x 0) + m x l + 2m x 0 ) / ( m + m + 2m )

y = m x l / 4m

y = 0.25 l

A man is attempting to train his dog. He is pulling on the dog with a force of 52.4 Newtons at an angle of 35.1 degrees above the horziontal. Fimd the X and Y component of the applied Force

Answers

The formula for the horizontal component (Fx), which is the angle the force makes with the horizontal, is Ftens•cosine(). Ftens• sine() can be used to compute the upward component (Fy), where is the angle that the force produces with the horizontal.

What is the force's horizontal component?

The portion of a force that works horizontally with regard to a body is known as its horizontal component. Its vertical component is known as its vertical component.

Why is moving the box with the rope horizontal easier?

The pulling of the box is with the rope horizontal. When the rope is angled Because Is less than, the horizontal component (= F cos ) is less. As a result, it is the proper response.

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This theory of motivation focuses on finding the right level of stimulation. An organism tries to find behaviors that actually increase arousal because everything else bores them.
*
2 points
Cognitive Theory
Hierarchy of Needs
Drive-Reduction Model
Optimal Arousal Theory

Answers

Optimal Arousal theory  focuses on finding the right level of stimulation.

What is Optimal Arousal theory?

William James (1842–1910), frequently referred to as the father of psychology in the United States, made significant contributions to early studies on motivation.

James proposed a number of instincts that help with survival as the driving forces behind conduct . An instinct is a species-specific pattern of behavior that is not taught, according to biology.

But there was a lot of disagreement over what exactly constitutes instinct among James's contemporaries. James postulated a number of unique human instincts, although many of his contemporaries had different lists.

Therefore, Optimal Arousal theory  focuses on finding the right level of stimulation.

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Helen is para sailing. She sits in a seat harness which is attached by a tow rope toba speedboat. The rope makes an angle of 59.9* with the horziontal and has a tension of 364N. Determine the horziontal and vertical component of the tension force

Answers

To find the horizontal and vertical components of the tension force in para sailing, we can use the basic trigonometric ratios of sine, cosine and tangent.

How to use trigonometric ratios ?First, given the rope's angle (59.9 degrees) and the tension force (364 N), we can apply the following formula to determine the tension force's horizontal component (Fx): Fx = Tension force x cos(angle) = 364 N x cos (59.9).Next, we can use the angle of the rope and the tension force to find the vertical component (Fy) of the tension force using the formula: Fy = Tension force x sin(angle) = 364 N x sin(59.9)You must convert the angle to radians because these calculations, as you should be aware, employ radians rather than degrees.As a result, the tension force's horizontal component has the following formula: Fx = 364N x cos(59.9) = 225.98N roughly.Additionally, the vertical component of the tension force is roughly 318.6N, or Fy = 364N x sin(59.9)According to these calculations, the tension force has two components: a horizontal component that is 225.98 N and a vertical component that is 318 N.

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Equilibrium exists in a system where three forces are acting concurrently on an object. If the system includes a 5.0-newton force due north and a 2.0-newton force due south, the third force must be?

Answers

The third force must be 3.0 newtons due north in order for equilibrium to exist in the system.

Why should equilibrium exist in system?This is so because the total of all the forces acting on the object equals the net force acting on it. The net force in this situation is 3.0 newtons due north and is calculated by subtracting the 5.0 newton force due north from the 2.0 newton force due south.In equilibrium, the net force on an object is zero.A chemical reaction is said to be in a state of north equilibrium when the reactant and product concentrations remain stable throughout time. The concentrations of the reactants and products stay unchanged, and the rate of the forward reaction is equal to the rate of the reverse reaction.

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A rock is thrown horizontally of a bridge at 8.00 m/s. It hits the water's surface below 3.4 seconds later. How high is the bridge? How far from the bridge does it hit the water?

I was provided with the equations:
x= v * t and y= (Vi * t)1/2 * a * t^2

Answers

Answer:

56.7m

Explanation:

horizontal velocity does not matter in this situation because it stays constant (no unbalanced force acting upon it)

a=9.81m/s^2              

t=3.4s

Vi=0m/s

d=Vi*t+1/2at^2

d=1/2at^2

d=1/2*9.81m/s^2*(3.4s)^2

d=4.905m/s^2*11.56s^2

d=56.7m

a) What is the magnitude of the force F⃗ on the −10 nC charge in (Figure 1)? Express your answer using two significant figures.

b) What is the direction of the force F⃗ on the −10 nC charge in (Figure 1)? Give your answer as an angle measured cw or ccw (specify which) from the +x-axis. Express your answer in degrees. Enter a positive value if the angle is counterclockwise and negative value if the angle is clockwise.

Answers

a) The magnitude of the force F on the −10 nC charge is  0.00134 Newton.

b) The direction of the force F on the −10 nC charge is 41.99° with horizontal line.

What is electric force?

Electric force is the attractive or repulsive interaction between any two charged things.

a) the magnitude of the force F on the −10 nC charge = √{k (q₁Q/r₁²)²+(q₂Q/r₂²)²}

= kQ √( (q₁/r₁²)²+ (q₂/r₂²)²}

= 9×10⁹×10×10⁻⁹ √{ (1×10⁻⁹/(0.01)²)² +(10×10⁻⁹/(0.03)²)² }

= 0.00134 Newton.

b)  the direction of the force F on the −10 nC charge

= tan⁻¹( (1×10⁻⁹/(0.01)²) ÷(10×10⁻⁹/(0.03)²) )

= 41.99°

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What does a step-down transformer change in an alternating current?

Answers

Answer: A step-down transformer changes the magnitude of the voltage in an alternating current (AC) electrical signal. It reduces the voltage of the AC signal by using a winding ratio between the primary (input) and secondary (output) coils that is less than 1:1.

Explanation: For example, if the winding ratio of a step-down transformer is 1:0.5, the output voltage of the secondary coil will be half the magnitude of the input voltage of the primary coil. In this case, the transformer would change the AC voltage from a higher value to a lower value.

The transformer does not change the frequency of the AC signal, which is determined by the source of the electrical power. The transformer also does not change the waveform of the AC signal, which is typically a sinusoidal wave.

Rank the images showing the highest electric potential 1 energy to the lowest electric potential energy 4.

Answers

Answer:

3rd image, 2nd image, 1st image, 4th image

Explanation:

Not an easy question, tricky one

Electric potential energy is proportional to the magnitude of the charges (the higher the charges, the stronger the Electric potential energy(EPE)) and inversely proportional to the distance between the charges(the longer the distance, the smaller the EPE).  U = kQq/r

EPE is positive in this case due to unlike charges.

Between distance and magnitude of the charges, magnitude of charges play a more significant effect than distance (due to Qq , both the magnitude of Q and q affect the EPE)

Hence. zoom in on the magnitude first.

3rd image has the largest + and -, hence greatest magnitude of charges, therefore highest EPE.

Between 1st and 2nd images, charges have the same magnitude, distance now comes to play. Distance between the charges is smaller for image 2 and the charges experience greater EPE. 1st image, the charges are further, hence smaller EPE.

For the fourth image, the magnitude of the charges is the smallest, hence smallest EPE.

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