Answer:
150 miles
Step-by-step explanation:
speed = 120 km per hour
1 mile = 1.6 km
speed = 120 km per hr
divide 120 with 1.6 to get in miles=120/1.6
= 75 miles per hour
speed = 75 miles per hour
So, in 1 hr, it can travel 75 miles
the distance traveled by car in 2 hours = 75 * 2 = 150
Result : Speed = 75 miles per hour , distance = 150 miles
solve this plsssssss
Let's see
LHS
(-8/9×1/-5)+(-8/9×-7/11)Keep it stay
RHS
-8/9(1/-5+-7/11)Use distributive law
(-8/9×1/-5)+(-8/9×-7/11)Hence proved
Please help, has t toy cars. Zachary has 3 times as many toy cars as Oliver. Write an expression
that shows how many toy cars Zachary has.
Answer:
z=3t
Step-by-step explanation:
multiply it by 3
The diagram shows a plan for a deck. The area of the deck is 511 ft squared what is the value of x? Show your work
Please helpp
Just have a good day
The dimension of the unknown variable x of the deck is equal to 14 feet in length.
What is a Rectangle?A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles (90°).The opposite sides of a rectangle are equal and parallel.
Given in the question is a diagram showing a plan for deck. From the data given, we can write -
Area of Deck = 511 ft.
The value of x can be found out by subtracting the area of the deck from the area of rectangle having dimensions of length 29 ft and width (16 + 4) = 20 ft. The remaining area will be equated to the sum of the area of rectangle at top right corner having dimensions of length 9 ft and width 4 ft and the area of triangle at lower right corner.
Firstly, we will find the dimensions of the triangle at the lower right. The height of the triangle will be = (20 - 9) ft = 11 ft. The base of the triangle will be = 29 - ( x + 9) ft = (20 - x) ft. Now -
[Area of Rectangle (29 x 20)] - [Area of Deck] = [Area of Rectangle (9 x 4) + Area of triangle (lower right)].
Mathematically -
580 - 511 = 9 x 4 + 1/2 × (20 - x) × 11 = 69
36 + 5.5(20 - x) = 69
36 + 110 - 5.5x = 69
146 - 69 = 5.5x
5.5x = 77
x = 14 ft
Therefore, the dimension of the unknown variable x of the deck is equal to 14 feet.
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given tan 0= -15/8 where 270º < 0 < 360°
Given tan 0 =
Find cos 0
Answer:=8/17
Step-by-step explanation:
Which of the following is NOT a characteristic of a plane?
A. thickness
B. width
C. flat surface
D. length
Answer:
A). thickness are correct
Larissa dives into a pool that is 8 feet deep. She touches the bottom of the pool with her hands 6 feet horizontally from the point at which she entered the water.
What is the approximate angle of elevation from the point on the bottom of the pool where she touched to her entry point?
36.9°
41.4°
48.6°
53.1°
Answer: 48.6°
Step-by-step explanation:
Angle of elevation = sin inverse (6/8)
= 48.6 degrees
Therefore, Option C is right answer
PLEASE HELP!!! I JUST NEED A STEP-BY-STEP!!!!!!
HINT: integrate with respect to y first (it is an easier approach)
∫∫5x sec^2(xy) dA; R={(x,y): 0 ≤ x ≤ π/6 , 0 ≤ y ≤ 2
[Answer] -5/2 ln(1/2)
Answer:
Step-by-step explanation:
[tex]=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}x\sec^2(xy)dy\\=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}\sec^2(xy)d(xy)\\=5\displaystyle\int_{0}^{\pi/6}dx\tan(xy)|_{y=0}^{y=2}[/tex]
[tex]=5\displaystyle\int_{0}^{\pi/6}\tan(2x)dx\\=-\frac{5}{2}\ln\cos(2x)|_{0}^{\pi/6}\\=-\frac{5}{2}[\ln\cos(\pi/3) - \ln\cos(0)]\\[/tex]
[tex]=-\frac{5}{2}\ln{\frac{1}{2}[/tex]
what does Y=
what does x=
Answer:
Step-by-step explanation:
The equation factors into
(x^2 + 14x + 49) =16 Factor
(x + 7)^2 = 16 Take the square root of both sides
√(x + 7)^2 = √16
x + 7 = +/- 4
x + 7 = + 4 Subtract 7 from both sides
x = 4 - 7
x = - 3
x + 7 = - 4 Subtract 7 from both sides.
x = - 4 - 7
x = - 11
x1 = -11
x2 = - 3
there were 63 fewer pears than apples in the supermarket. After 37 pears were sold, how many fewer pears than apples ?
Step-by-step explanation:
63/37 = 1.702 = 1.7
#Ihopethishleps
General solution of: (1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2]dy = 0
show two solution on your answer
nonsense answer deleted
[tex] \Large \bold{SOLUTION\ 1:} [/tex]
[tex] \small \begin{array}{l} \text{First, we need to check if the given differential} \\ \text{equation is exact.} \\ \\ (1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \quad M(x, y) dx + N(x, y) dy = 0 \end{array} [/tex]
[tex] \small \begin{array}{l l}\tt\: M(x,y) = \dfrac{1}{(1 - xy)^2}, & N(x,y) = y^2 + \dfrac{x^2}{(1-xy)^2}\\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{-2(-x)}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^2} + \dfrac{-2(-y)x^2}{(1 - xy)^3} \\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{2x}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x(1 - xy)+2x^2y}{(1 - xy)^3} \\ \\\tt \: & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^3} \end{array} [/tex]
[tex] \small \begin{array}{l} \tt\dfrac{\partial M}{\partial y} = \dfrac{\partial N}{\partial x} \implies \text{Differential equation is exact.} \\ \\\tt \dfrac{\partial F}{\partial x} = M(x, y) = \dfrac{1}{(1 - xy)^2} \\ \tt\displaystyle F(x, y) = \int \dfrac{1}{(1 - xy)^2} \partial x = -\dfrac{1}{y} \int \dfrac{1}{(1 - xy)^2}(-y)\partial x \\ \\ \tt\:F(x, y) = \dfrac{1}{y(1 - xy)} + h(y) \\ \\ \tt\dfrac{\partial F}{\partial y} = N(x, y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\\tt \dfrac{\partial}{\partial y}\left[\dfrac{1}{y(1 - xy)} + h(y)\right] = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - xy + y(-x)}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - 2xy}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} + \dfrac{1 - 2xy}{y^2(1 - xy)^2} \\ \\ \tt\:h'(y) = y^2 + \dfrac{x^2y^2 - 2xy + 1}{y^2(1-xy)^2} = y^2 + \dfrac{1}{y^2} \\ \\ h(y) = \dfrac{y^3}{3} - \dfrac{1}{y} + C \\ \\ \tt\text{Substituting to }F(x,y),\text{we get} \\ \\ \dfrac{1}{y(1 - xy)} + \dfrac{y^3}{3} - \dfrac{1}{y} = C \\ \\ \quad \quad \text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]
[tex] \Large \bold{SOLUTION\ 2:} [/tex]
[tex] \small \begin{array}{l} \tt\text{Since we already know that the equation is exact,} \\ \text{we can then continue solving for the solution by} \\ \text{inspection method or by algebraic manipulation.} \\ \\ \tt(1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + y^2 dy + \dfrac{x^2}{(1-xy)^2} dy = 0 \\ \\ \tt\dfrac{dx + x^2dy}{(1-xy)^2} + y^2 dy = 0 \\ \\ \tt\text{Divide both numerator and denominator of the} \\ \tt\text{fraction by }x^2. \end{array} [/tex]
[tex] \small \begin{array}{c}\tt \dfrac{\dfrac{1}{x^2}dx + dy}{\dfrac{(1-xy)^2}{x^2}} + y^2 dy = 0 \\ \tt\\ \tt\dfrac{\dfrac{1}{x^2}dx + dy}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt-\dfrac{\left(-\dfrac{1}{x^2}dx - dy\right)}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt\displaystyle {\large{\int}} -\frac{d\left(\dfrac{1}{x}-y\right)}{\left(\dfrac{1}{x}-y\right)^2} + \int y^2 dy = \int 0 \\ \\ \tt\implies\tt \dfrac{1}{\dfrac{1}{x}-y} + \dfrac{y^3}{3} = C \\ \\\text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]
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LMNO is a parallelogram, with and . Which statements are true about parallelogram LMNO? Select three options.
x = 11
m∠L = 22°
m∠M = 111°
m∠N = 59°
m∠O = 121°
Answer:
the answers 1, 4, and 5.
m∠N = 59° and m∠O = 121°.
Option 3 and 4 are correct.
What is a parallelogram?A parallelogram is a geometric object with sides that are parallel to one another in two dimensions. It is a form of polygon with four sides (sometimes known as a quadrilateral) in which each parallel pair of sides have the same length. A parallelogram has adjacent angles that add up to 180 degrees. You must have studied a variety of 2D shapes and sizes in geometry, including circles, squares, rectangles, rhombuses, etc. Each of these forms has a unique set of characteristics.
As per the given data:
LMNO is a parallelogram
The sum of adjacent angles in a parallelogram is always equal to 180°
11x + 6x - 7 = 180
17x = 187
x = 11
m∠L = m∠N {opposite angles in a parallelogram are equal}
m∠N = 6x - 7 = 6(11) - 7 m∠N
m∠L = 59°
m∠M = m∠O {opposite angles in a parallelogram are equal}
m∠M = 11x = 11(11) = 121°
m∠O = 121°
Hence, m∠N = 59° and m∠O = 121°.
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Solve the simultaneous equations
.
3x + y = 10
y = 2 - x
X =
y =
Step-by-step explanation:
please mark me as brainlest
Answer:
3x + (2 - x) = 10
3x + 2 - x = 10
2x + 2 = 10
2x = 10 - 2
2x = 8
x = 8/2
x = 4
y = 2 - x
y = 2 - 4
y = -2
What is the inverse of 2x-3?
Step-by-step explanation:
the inverse of 2x-3 is
[tex] \frac{1}{2x - 3} [/tex]
if this helped pls give brainliest
What is the length for X
Answer:
x = 5
Step-by-step explanation:
3^2 + 4^2 = x^2
9 + 16 = x^2
25
Now we need to find the square root of 25 :)
The answer is 5
X = 5
Have a great day!!
Please rate and mark brainliest!!
Find the average of this set of numbers.16, 20, 30, 30
A) 14
B) 15
C) 25
D) none of the above
Answer:
D) none of the above
Step-by-step explanation:
16+20+30+30=96
96/4 =24
I’m stuck pls help me
Answer:
B and E
Step-by-step explanation:
There are only 7 days left until the launch of our new product and we only have $668 left and Ira promotion budget we need to spend $85 on the last day can you please calculate how many dollars we can spend on the remaining days
Answer:
97.16
Step-by-step explanation:
in total, you have $668.00.
To reserve enough for the last day, you need to subtract the last day's budget:
This means that, for the remaining 6 days in the week, you have $583.00.
Assuming an equal amount is being spent each day, you can calculate the daily budget by dividing the remaining total by the number of days left.
To avoid going over budget, you can spend $97.16 per day for the other six days.
Find the exact value of sin(255∘)
Check the picture below.
[tex]\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}[/tex]
What is the value of the expression (–5) -3?
1. Apply the negative exponents rule:
1
(−5)3
2. Expand the power:
1
(−5)(−5)(−5)
3. Simplify:
1
x
What is the value of x?
x =
Answer:
15 :)
Step-by-step explanation:
brainliest please
Answer:
The answer is -125
Proof:
Find the equation of the line with slope m=53 that contains the point (−6,−12).
.................................................................................
find the square root of 576 and do it in factorizing method and your answer is going to be in index form
Answer:
24.
Step-by-step explanation:
Solution,
By Prime Factorisation method,
576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
576 = (2)² × (2)² × (2)² × (3)²
Now,
By Taking square roots on both the sides,
√576 = √ (2)² × (2)² × (2)² × (3)²
√576 = 2 × 2 × 2 × 3
√576 = 24.
Order the measures of mass from least to greatest.
Answer:
18 grams,160 grams,2,100 grams,2 kilograms,17 kilograms,208 kilograms.
The measure from least to greatest is 18 gm < 10 gm< 17 Kg < 2Kg < 2300 gm < 208 Kg.
What is Ascending Order?The arrangement of numbers or other things in increasing order from least to greatest is known as ascending order. Ascending order is demonstrated by numbers on a number line, which are listed from left to right.
Given:
18gm, 17 Kg, 100 gm, 2 Kg, 2300 gm, 208 Kg
Converting all the units into gram we have
18 , 1700, 100, 2000, 2300, 208000
So, the mass from least to greatest.
18 < 100 < 1700< 2000< 2300 < 208000
Hence, 18 gm < 10 gm< 17 Kg < 2Kg < 2300 gm < 208 Kg.
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Help picture below problem 3
angle ksp+61=108(being straight angle)
or,angle ksp=180-61
angle ksp=119
Diego's soccer team played in a tournament. The tournament started at 8:07 A.M. It ended at 3:44 P.M. How long did the soccer tournament last?
Answer:
Step-by-step explanation:
7 hours and 37 minuties
Answer:
5 hours
Step-by-step explanation:
it lasted 5 hours for the tournament
Oxygen flows through one tube into a liter flask filled with air, and the mixture of oxygen and air (considered well stirred) escapes through another tube. Assuming that air contains 4% oxygen, what percentage of oxygen will the flask contain after 5 L have passed through the intake tube?
The amount of oxygen in the flask through the intake tube illustrates proportions
The flask 99.35% will contain of oxygen after 5L have passed through the intake tube
How to calculate the percentage of oxygen?
To do this, we make use of the following representations
P for the proportion of oxygenV for te volume of oxygenx for the proportion of oxygen in the flask after 5 L passed throughSo. we have the following derivative
dP = dV - P * dV
Divide through by dV
dP/dV = 1 - P
Next, we set up the integral
[tex]\int\limits^x_{0.040} \frac {1}{1 - P}dP= \int\limits^5_0 {dV}[/tex]
Integrate both sides
[tex]-\ln(|P - 1|)|\limits^x_{0.04} = 5[/tex]
Expand
-ln(|x - 1|) + ln(|0.04 - 1|) = 5
Evaluate the difference
-ln(|x - 1|) + ln(|-0.96|) = 5
Express as a fraction
ln(0.96/|x - 1|) = 5
Express both sides as exponents with a base of 2
e^ln(0.96/|x - 1|) = e^5
Solve for x
x = 1 - 0.96/e^5
Evaluate the difference
x = 0.9935
Express as percentage
x = 99.35%
Hence, the flask 99.35% will contain of oxygen after 5L have passed through the intake tube
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How do you graph y=3x-2
Answer:
The graph should look almost exactly like this. I used a virtual graphing chart to assist, since it is capable of showing more than paper alone.
Answer:
Here is your answer.
Step-by-step explanation:
8. Anita recorded the amount of rainfall in
her area each day for 14 days. What was
the total amount of rainfall in the 14 days?
A 40 cm
B 36 cm
C 13.5 cm
D 12.5 cm
How to determine the total amount of rainfall
From the dot plot, we have the following frequency table
Rainfall Frequency
0 4
1/8 5
1/4 1
3/8 2
1/2 1
1 1/4 1
= 3/8 inches
A study was designed to investigate the effects of two variables(1) a student's level of mathematical anxiety and (2) teaching methodon a student's achievement in a mathematics course. Students who had a low level of mathematical anxiety were taught using the traditional expository method. These students obtained a mean score of 440 with a standard deviation of on a standardized test. Assuming no information concerning the shape of the distribution is known, what percentage of the students scored between 360 and 520 ?
Using Chebyshev's Theorem, considering a standard deviation of 40, we have that at least 75% of the students scored between 360 and 520.
What does Chebyshev’s Theorem state?When we have no information about the population distribution, Chebyshev's Theorem is used. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.At least 89% of the measures are within 3 standard deviations of the mean.An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].In this problem, considering a standard deviation of 40, we have that:
440 - 2 x 40 = 360.
440 + 2 x 30 = 520.
Within 2 standard deviations of the mean, no information about the distribution, hence, at least 75% of the students scored between 360 and 520.
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The polygon given below is a regular pentagon.
A. 54°
B. 108°
C. 135°
D. 540°
Answer:
Step-by-step explanation:
In a regular pentagon, all the angles and sides are equal. So, to find an angle, divide 540 by 5.
Sum of all angles of regular pentagon = 540
measurement of one angle = 540 ÷ 5
= 108°
∠N = 108°
Answer:
B
Step-by-step explanation:
Solve the following equation for p: 6/p=x+a
[tex]\dfrac 6p = x+a\\\\\implies \dfrac 6p \times\dfrac 16 = (x+a) \times\dfrac 16 ~~~~~~;\left[\text{Multiply both sides by}~ \dfrac 16 \right]\\\\\implies \dfrac 1p = \dfrac{x+a}6\\\\\implies p= \dfrac{6}{x+a}~~~~~~~~~~~~~~~~~~~~;[\text{Cross multiply}][/tex]