The magnetic field in the regions are (a) B = (μ₀ * I) / (2πr) for r ≤ r1 , (b) B = 0 for r2 ≥ r ≥ r1 ,(c) B = (μ₀ * I ) / ( 2πr ) r3, for ≥ r ≥ r2 , (d) B = 0 for r ≥ r3.
To determine the magnetic field of the coaxial cable, we can use Ampere's law, which says that the magnetic field around the closed loop is equal to the free space permittivity (μ₀) of the total current in the loop.
(a) For the region r ≤ r1 (inside the conductor), the magnetic field can be visualized using a circular ring in the middle of the electric field. Since the currents are equal to the cross section of the conductor, the current through the loop is I. According to Ampere's law, the magnetic field (B) in the inner conductor is given by B = (μ₀ * I) / (2πr).
(b) In the region r2 ≥ r ≥ r1 (between inner and outer conductors), the magnetic field is zero.
This is because the magnetic field produced by the current in the outer conductor cancels the magnetic field produced by the inner conductor, and as a result, there is no net magnetic field in the field.
(c) For the r3 ≥ r ≥ r2 (inside outer conductor) region, we can still use the circle between the power lines. Since the currents are equal to the cross-sectional area of the conductor, the current through the loop is also I. Using Ampere's law, the internal magnetic field is given by B = (μ₀ * I) / (2πr). because no current flow creates a magnetic field.
In summary:
(a) B = (μ₀ * I) / (2πr) for r ≤ r1
(b) B = 0 for r2 ≥ r ≥ r1
(c) B = (μ₀ * I ) / ( 2πr ) r3
for ≥ r ≥ r2
(d) B = 0 for r ≥ r3
These equations give the magnetic field effect according to the current distribution for different regions of the coaxial cable.
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100 kg ball is initially traveling at 10 m/s. If the ball experiences a constant external force that increases the ba
velocity to 15 m/s, what is the net impulse that acted on the ball?
the net impulse that acted on the ball =500 N.s if 100 kg ball is initially traveling at 10 m/s. If the ball experiences a constant external force that increases the ba velocity to 15 m/s .
What is an example for force?The normal force acts in a direction normal to the surface interaction between objects. Friction is a force that opposes motion on surfaces. Other examples of non-fundamental forces include the elastic force, tension, and frame-dependent forces .
What does it mean to force someone?to make someone do something that they do not want to do, for example by using or threatening to use violence. force someone to do something: He claims that police officers forced him to sign a confession.
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When do a 1000kg car and a 2000kg truck have the same momentum?
When a car has double the speed of the truck
Momentum is calculated by multiplying the mass by the velocity. And we have masses of 1000 kg and 2000 kg and to make the momentum equal velocity needs to be inversely proportional.
Let the velocity of the car be x m/s
momentum (p) = mass * velocity
then momentum is 1000*x
1000x kgm/s
So lets the velocity of the truck be y m/s
the momentum of the truck will be 2000*y
so 2000y kgm/s
by the condition 1000x = 2000y
so on solving
x= y/2
which shows the car has double the velocity of the truck.
So we can conclude to greater momentum we need either velocity or mass needs to be greater or both can be also large to get higher momentum.
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The displacement of a 500 g mass, undergoing simple harmonic motion, is defined by the function.
When the displacement of a 500 g mass, undergoing simple harmonic motion, is defined by the function : x=-3.5sin(π/2t+(5π)/4).The maximum potential energy is 7.56J
What is simple harmonic motion?Simple harmonic motion, or SHM, is a particular form of periodic motion of a body that results from a dynamic equilibrium between an inertial force that is proportional to the body's acceleration away from the static equilibrium position and a restoring force on the moving object which is directly proportional to the magnitude of the object's displacement and applies towards the object's equilibrium position.
Solution:Given :
k = 1.234N/m
x=3.5
Now by applying the value of spring constant, we can find the maximum potential energy.
PE=[tex]\frac{1}{2} kx^{2}[/tex]
PE=1/2*1.234*3.5^2
PE=7.56J
Hence, The maximum potential energy is 7.56J
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The complete question is :
The displacement of a 500 g mass, undergoing simple harmonic motion, is defined by the function :
x=-3.5sin(π/2t+(5π)/4)
Find maximum potential energy.
I need help on how to do the graph
Some general tips for creating graphs include:
1. Choose the type of graph that best illustrates your data.
2. Organize your data in a way that makes sense and is easy to read.
3. Label your graph clearly so readers can understand what the graph is trying to convey.
4. Use colors and symbols to make the graph more visually appealing.
5. Use a grid to ensure that the graph lines are straight and even.
6. Double-check your graph to make sure all of the data is accurate.
What is graph?
Graph is a pictorial representation of data or information. It is a way of visually displaying data points in a way that is easy to understand and interpret. By using graphs, we can compare different sets of data, identify relationships between different data points, and easily spot trends and patterns.
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A 3.0-kg mass moving in the positive
x
direction with a speed of 10
m/s collides with a 6.0-kg mass initially at rest. After the collision, the
speed of the 3.0-kg mass is 8.0 m/s, and its velocity vector makes an
angle of 35 with the positive
x axis. What is the magnitude of the
velocity of the 6.0-kg mass after the collision?
The 3.0 kg mass is moving at a speed of 8.0 m/s after the collision, and its velocity creates a 35° angle with the pos x axis.
What occurs during a collision?In a collision, two forces with opposite directions and equal magnitudes act on each object, accelerating them simultaneously. Each object feels the same acceleration in collisions with objects of equal mass.
How do you spot a collision?A collision occurs when both the vertical and horizontal edges cross. When comparing the right and left sides of two objects, we determine that whether right side of both the second object is stronger than that of the left side that of the first, and vice versa for something like the vertical axis.
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An airplane flies from Milwaukee to Chicago a distance of 130 km and is in the air for 20 minutes. What is the average velocity?
A chain of metal links with total mass m = 5 kg is coiled up in a tight ball on a low-friction table. You pull on a link at one end of the chain with a constant force F = 64 N. Eventually the chain straightens out to its full length L = 0.8 m, and you keep pulling until you have pulled your end of the chain a total distance d = 3.2 m (diagram is not to scale). m ------- 1000000000000000 T> (a) Consider the point particle system: What is the speed of the chain at this instant? V = m/s (b) Consider the extended system: What is the change in energy of the chain? AE = joules (c) In straightening out, the links of the chain bang against each other, and their temperature rises. Assume that the process is so fast that there is insufficient time for significant thermal transfer of energy from the chain to the table, and ignore the small amount of energy radiated away as sound produced in the collisions among the links. Calculate the increase in thermal energy of the chain. AEthermal =
The speed of the chain at this instant is 8.47 m/s. The change in energy of the chain is 204.8J. The increase in thermal energy of the chain is 25.6J.
Acceleration(a) of Centre of mass = F/m = 64/5 = 12.8 m/s2
a) v2 = u2 + 2as,....(1)
It defines the direction of the movement of the body or the object. Speed is primarily a scalar quantity. Velocity is essentially a vector quantity. It is the rate of change of distance. It is the rate of change of displacement.v is final velocity of centre of mass,
u is the initial velocity of centre of mass,
s is the displacement of centre of mass
s = d - L/2 = 3.2 - 0.4 = 2.8m
using equation 1,
V = [tex]=\sqrt{2as} =\sqrt{2*12.8*2.8}=8.47 m/s.[/tex]
Therefore, the speed of the chain at this instant is 8.47 m/s.
2. Change in energy = Total Work Done = Force*Displacement of point on which force is applied = 64*3.2 = 204.8J
Therefore, the change in energy of the chain is 204.8J
3. Change in Thermal Energy = Change in Energy - Change in Kinetic Energy = 204.8 - 0.5*m*v2
Change in Thermal Energy = 204.8 - 0.5*5*8.47*8.47 = 25.6J
Therefore, the increase in thermal energy of the chain is 25.6J.
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which of the following situations would sonar be most practical?
Measuring the distance between objects in the ocean
Observing internal organs
Determining the frequency of sounds
Dampening the intensity of sounds
The situations that sonar be most practical is option A: Measuring the distance between objects in the ocean.
What is the distance about?Sonar, short for sound navigation and ranging, is a technology that uses sound waves to determine the distance and location of objects in the ocean.
Therefore, It works by emitting a sound wave and measuring the time it takes for the wave to bounce back, which allows the system to calculate the distance to the object. This technology is commonly used in navigation, search and rescue, and underwater mapping.
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Which type of force does a window washer want acting on him when trying to keep the same position?
A. Large
B. Small
C. Balanced
D. Unbalanced
Balanced force does a window washer want acting on him when trying to keep the same position.
What is force?
Force is an external influence that is capable of changing the motion of a body, either by a push or pull, or by causing a change in the shape or direction of the body. Force is a vector quantity, meaning it has both magnitude and direction. It can be a result of either physical contact, like pushing or pulling, or a non-contact force, such as gravity, magnetism, or electricity. Force is a fundamental concept in physics and its effects are studied in numerous fields, from mechanics to thermodynamics. Force can be used to move objects, cause objects to change shape, or cause objects to accelerate. It is a powerful tool for understanding physical phenomena.
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An external force of 34.0 N acts on a system for 12.0 s in the negative x direction. What is the impulse delivered to
the system?
Answer:
90. 6
Explanation:
An external force of 25 N acts on a system for 10 s.
Frank pushes with a force of 620 N on a filing cabinet with a mass of 60 g. The cabinet doesn’t move.
What can be inferred?
When Frank exerts push with a force of 620 N over a filing cabinet with a mass of 60 g. The cabinet doesn’t move. it can be inferred that The static friction force of the floor and cabinet is greater than 620 N.
What is static friction?A type of force which holds an object at the state of rest is termed as static friction. we can define the static friction as The resistance person feel when he attempts to move a stationary object over a surface without actually causing any relative motion between his body and the surface they are moving the object across.To know more about static friction visit
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The complete question is :
Frank pushes with a force of 620 N on a filing cabinet with a mass of 60 g. The cabinet doesn't move.
What can be inferred?
A. There are no other forces acting on the filing cabinet.
B. The static friction force of the floor and cabinet is greater than 620 N.
C. The net force of the cabinet is greater than 620 N.
D. The friction force of the floor and cabinet is less than 620 N.
Solve the following question using the concepts of work and energy: A giant alien invader is devastating humanity and having a nice day when he sees Captain America 100 m away holding an ice cream. He decides to attack Captain America because the ice cream looks quite tasty. The alien has a mass of 6.32x104 kg and is moving with a constant velocity of 26 m/s forward. To save Captain America, The Hulk rushes over and pushes back on the alien, which results in a net backward force of 2.43x105 N on the alien. If the alien was 100 m away from Captain America when The Hulk started to push, will Captain America survive? What distance does the Hulk take to stop the alien?
Yes, Captain America will survive.
The distance the Hulk takes to stop the alien is 87.9 m.
What is the distance travelled by Hulk?
The distance travelled by the Hulk is calculated by applying the principle of work-energy theorem.
Work done by Hulk = Kinetic energy of the alien
Fd = K.E
Fd = ¹/₂mv²
where;
f is the resultant force of Hulkd is the distance travelled by Hulkv is the velocity of the alienm is mass of the aliend = ( mv² ) / ( 2F )
The distance travelled by Hulk is calculated as;
d = ( 6.32 x 10⁴ x 26² ) / ( 2 x 2.43 x 10⁵ )
d = 87.9 m
Hence, Captain America will survive since the distance travelled by Hulk when he is pushing the alien back is 87.9 m, which is less than 100 m where Captain America is.
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school cafeteria has thick padding installed along the walls and portions of the ceiling to reduce echoes. Which statement best explains the wave property this padding is taking advantage of?
Refraction, because refracted waves have a lower intensity
Reflection, because reflected waves have a higher intensity
Absorption, because absorbed waves go into the media
Transmission, because transmitted waves move through media
The wave property this padding is taking advantage is reflection, because reflected waves have a higher intensity.
option B is the correct answer.
What is refection of wave?
The reflection of a wave occurs when a travelling hits a hard surface and it is directed backwards.
Also, the reflection of a wave is a process by which a wave, whether light, sound, infrared, or radio waves, hits an object and bounces off it.
An example of reflection of wave is echo.
An echo is a sound caused by the reflection of sound waves from a surface back to the listener.
Thus, to reduce the echo of a sound wave, the school cafeteria had thick padding installed along the walls and portions of the ceiling.
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During solar maximum more UV radiation reaches Earth and we experience atmospheric cooling.
A. True
B. False
Answer:
should be false (F)
you don't have to, but I'd like brainliest if you can.
Explanation:
Analyze the IR spectra for both t-butanol and 1-butanol.
If the reactions were successful what do you expect to see in the IR of the product compared to the starting material?
If the reactions were successful then we can see the reactions involved O-H groups of the alcohols then the O-H stretching will not be observed in the product.
Analysis of IR spectrum of 1-butanol:
There are sp3 C-H stretching and CH2 bending modes at 2900 and 1500 cm-1 and there is a C-O stretching mode near 1050 cm-1. There is a very large peak around 3400 cm-1. O-H peaks are usually very broad due to H -bonding.The rounded shape O-H stretching modes occurs because of hydrogen bonding between different hydroxy groups.
Because protons are shared to varying extent with neighboring oxygens, the covalent O-H bonds in alcohol all vibrate at slightly different frequencies and show up at slightly different positions in the IR spectrum.
Instead of seeing one sharp peak, the entire range is observed as a whole lot of them merged into one broad peak. Since C-H bonds don't hydrogen bond very well, hence this phenomenon is not observed for C-H stretching.
Analysis of IR spectrum of tertiary-butyl alcohol:
There are sp3 C-H stretching and alkane C-H bending modes at 2900 and 1500 cm-1 and there is a strong C-O stretching mode near 1200 cm-1 indicative of tertiary C-O, there is a broad peak around 3400 cm-1 indicative of H bonding.
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Air flows steadily along a streamline from point (1) to point (2) with negligible viscous effects. The following conditions are measured: At point (1) z1 = 2 m and p1 = 0 kPa; at point (2) z2 = 10 m, p2 = 20 N/m2 and V2 = 0. Determine the velocity at point (1). Also calculate the change in each form of energy in the Bernoulli equation and describe, in words, the energy gain or loss by each form as the air flows from point (1) to point (2).
The velocity of the air flow at point (1) is 13.8 m/sec. The gravitational potential energy is increasing from point(1) to point(2) by 94.176 joules. The pressure head increased by 1.7 m of air column. Kinetic energy head is decreased by 9.71 m of air column.
Datum head at point (1), z₁ = 2 m
Datum head at point (2), z₂ = 10 m
Pressure at point(1) p₁ = 0 kpa
Pressure at point(2) p₂ = 20 N/m²
Velocity at point(2) v₂ = 0
Velocity at point(1) v₁ = ?
The density of air, ρ = 1.2 kg/m³
By applying Bernoulli's equation,
z₁ + p₁/ρg + v₁²/2g = z₂ + p₂/ρg + v₂²/2g
2 + 0 + v₁²/2g = 10 + 20/(1.2×9.81) + 0
v₁²/2g = 10 + 1.7 - 2
v₁² = 9.7×2×9.81
v₁² = 190.314
v₁ = 13.8 m/sec
Change in gravitational potential energy(ρgΔh) = 1.2×9.81×(10-2)
= 94.176 Joules
Increase in the pressure head = p₂/ρg - p₁/ρg
= 1.7 - 0
= 1.7 m (of air column)
Change in the kinetic energy head = v₂²/2g - v₁²/2g
= 0 - v₁²/2g
= - (13.8×13.8)/(2×9.81)
= -9.71 m (of air column)
Negative sign indicates that the kinetic energy head is decreasing.
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Convert 1.5 days to s
Convert 5.2 ft to m
Convert 3600 s to hr
Convert 10.2 m to ft
Convert 305 g to kg
Convert 180 pm to m
Convert 73 kg to g
Convert 1,366 s to min
Convert 86,000 m to km
Please answer these and SHOW ALL WORK, please please please show ALL WORK. Need this done right now please help! Thank you so much!
Although this computation is essentially based on a mathematical formalism or equation that integrates components, conversion factors are frequently employed to convert one type of measure into another.
A chemical equation is what?The term "chemical equation" is frequently used in everyday chemistry. French chemist Jean Beguin established the first empirical formula in 1615. A chemical equation merely refers to a premise of a molecular reaction's process using symbols and figures.
1.5 days = 129600 second
5.2 ft = 1.58496 meters
3600 s = 1 hour
10.2 m = 33 ft 5.57 in
305 g = 0.305 Kg
180 pm = 0.00000000018 m
73 kg = 73000 g
1,366 s = 22.76666667 min
86,000 m= 86 km
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in trial 1 of an experiment, a cart moves with speed v0 on a frictionless, horizontal track and collides elastically with another cart that is initially at rest. in trial 2, the setup is identical except that the carts stick together during the collision. how does the speed of the two-cart system’s center of mass change, if at all, during the collision in each trial?
In trial 1, the speed of the center of mass does not change, while in trial 2, the speed of the center of mass decreases.
In trial 1, the carts collide elastically, which means that the total kinetic energy of the system is conserved during the collision. The two carts will bounce off each other with the same kinetic energy that they had before the collision. Since the center of mass is a point of reference for the total kinetic energy of a system, and its speed is related to its kinetic energy, the speed of the center of mass does not change during the collision. The final kinetic energy of the two-cart system after the collision is the same as the initial kinetic energy. The two carts will move away from each other with the same speed they had before the collision.
In trial 2, the collision is inelastic, which means that some of the kinetic energy is converted into internal energy, this causes the total kinetic energy of the two-cart system to decrease. Since the center of mass is a point of reference for the total kinetic energy of a system, and speed is related to kinetic energy, the decrease in total kinetic energy causes a decrease in the speed of the center of mass. As the carts stick together after the collision, the final speed of the two-cart system is lower than the initial speed. The final speed of the two-cart system after the collision is slower than the initial speed of the first cart.
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Your question seems to be incomplete, but I assume the question was:
"In trial 1 of an experiment, a cart moves with speed v0 on a frictionless, horizontal track and collides elastically with another cart that is initially at rest. In trial 2, the setup is identical except that the carts stick together during the collision. How does the speed of the two-cart system's center of mass change, if at all, during the collision in each trial?"
What is true of low resistance wires
Answer:
A. The shorter a wire is, the lower resistance it will have.
Natural gas-fired generation of power is among the primary sources of energy production in NC. Explain what it is.
energy the top states in the nation for nuclear power electricity production is North Carolina. The contributions of natural gas-fired energy over the previous ten years.
What is the primary energy source in North Carolina?nuclear energy Nuclear energy contributed for 33% of North Carolina's net generation in 2021, placing the state in the top five states for production. North Carolina was one of the top ten states in 2020 for both total annual motor fuel spending and petroleum consumption.
What is the main source of production of primary energy?one of the main ways to produce energy is through the combustion of natural gas. Describe it in detail.Sunlight is the principal energy source on Earth's surface and can.As the effects of global warming worsen, North Carolina must go nuclear. Nuclear energy will become the best solution for clean, dependable, and economical electricity, and recent state legislation compels Duke Energy to dramatically cut carbon emissions by 2030.
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A 10-kg object is near a planet's surface, where the gravitational field strength is 4 n/kg. With what force is the planet attracted to the 10-kg object?.
The force with which the planet is attracted to the 10 kg object is calculated to be 4 N.
Given that,
Mass of object = 10 kg
Gravitational field strength = 4 N/kg
Now, let us determine with what force the planet is attracted to the 10 kg object,
Mathematically, the force with respect to the gravitational field strength is given by the formula,
Force = mass × gravitational field strength
Force = 10 × 4
Force = 40 newton
We can conclude that the force with which the planet is attracted to the 10 kg object is 4 Newton.
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A mixture of gasoline vapor and air is placed in an engine cylinder. The piston has an area of 7.4 × 10^−3 m^2 and is displaced inward by 7.2 × 10^−2 m. If 9.5 × 10^5 Pa of pressure is placed on the piston, how much work is done during this process? Is work being done on or by the gas mixture?
The work done during the process is 506.2 J.
What is the work done during the process?
The work done during the process is calculated by applying the following equation.
W = PΔV
W = P ( Vf - Vi )
where;
P is the constant pressure of the systemVf final volume of the systemVi is the initial volume of the systemThe final volume of the system is calculated as follows;
Vf = A x h
Vf = 7.4 x 10⁻³ m² x 7.2 x 10⁻² m
Vf = 5.33 x 10⁻⁴ m³
W = 9.5 x 10⁵ Pa x ( 5.33 x 10⁻⁴ m³ - 0 )
W = 506.2 J
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(c) Assume that, at t = 0 s, the horizontal position of the box is x = 0 and it has a vertical position of y = 0. Derive an equation that describes the vertical position y of the box as a function of the horizontal position of x of the box.
The horizontal displacement of a projectile can be found using the equation for displacement with a constant acceleration of zero: = .
What is the horizontal displacement of a projectile?A projectile's horizontal velocity is constant (a never changing in value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion is unrelated to its horizontal motion. A projectile's horizontal displacement is influenced by its starting horizontal speed and distance travelled. A projectile's vertical displacement is determined by three factors: time, gravity's acceleration, and its starting vertical velocity. Vertical lines move up and down and are in the form of x = a where a represents the shared x-coordinate, whereas horizontal lines go left and right and are in the form of y = b where b represents the y-intercept.To learn more about horizontal displacement refer to:
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A 3000kg train car become attached to a 2000kg train car at the tockyard. The 3000kg train car ha a velocity of 5. 0m/ but the 2000kg train car i initially motionle. After they couple, what i the peed of thee car combined?
The speed of the combined train cars after they couple cannot be determined from the information given. The velocity of an object is determined by its speed in a given direction, but it is not specified in which direction the train cars are moving.
Additionally, the concept of momentum must be considered to calculate the final velocity of the combined train cars.
The principle of conservation of momentum states that the total momentum of a closed system (in this case the train cars) remains constant unless acted upon by an external force. Therefore, we would need to know the initial momentum of each train car and the external forces acting on the system in order to calculate the final velocity of the combined train cars.
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What is the MLA citation formula?
The basic formula for the MLA citation is: Last Name, First Name. Title of Book. City of Publication, Publisher, Publication Date, Location (pages, paragraphs, URL or DOI).
MLA Style defines guidelines for formatting manuscripts and citing research in writing. MLA Style also specifies writers with a system for referencing their sources through parenthetical citation in their essays and Works Cited page.
MLA citation arrange entries in alphabetical order by the first author's last name or the title of the work when there is no author, in each entry. Then, continue with the numbering convention used throughout the paper by including the last name and the page number in the upper right-hand corner of the Works Cited pages.
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How much work is done on a box that is pushed 9 meters across a horizontal floor by a force of 3000N?
The amount of work done by a box that is pushed 9 meters across a horizontal floor by a force of 3000N is 27000J.
How to calculate work?Work in physics refers to the measure of energy expended in moving an object; most commonly, force times distance.
It is said that no work is done if the object does not move. The work done on an object can be calculated by multiplying the force of the object by its distance as follows:
W = F × d
W = 3000N × 9m
Work done = 27,000J
Therefore, 27,000Joules is the work done on the box.
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How many criteria must a substance meet in order to be considered a mineral
A car changes velocity from 60 km/h to 40 km/h in 0.4 h. What is the car's acceleration? Is the car accelerating or decelerating?
Answer:
The car is decelerating because speed is decreasing and you also get the answer in negative
Explanation:
acceleration= change in speed(final speed-initial speed)/time
final speed=40km/h
initial speed=60km/h
40-60/0.4
-20/0.4= -50km/h^2
Which is an example of why impuise is so important?
Elevators being hoisted up by a pulley
Using nylon ropes in rock climbing
Running a race around a track
Plane taking off from a runway
Impulse is important because it is the force that changes an object's momentum.
What is momentum?Momentum is a physical concept that describes the movement of an object due to the product of its mass and velocity. Momentum is a vector quantity, meaning it has both a magnitude and a direction. In classical mechanics, momentum is conserved, meaning that the total momentum of a system remains constant over time.
In the examples given, impulse is what allows the elevator to be hoisted up, the nylon ropes to hold a climber's weight, the runner to move around the track, and the plane to take off from the runway. Without impulse, none of these activities would be possible.
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Please explain how to do this
slope is zero therefore velocity will be 0 at B to C .