The single cable will pull upward on the sign with a force of 38.3 N.
What is single cable?Single cable is a type of cable that is composed of a single electrical conductor. It is most commonly used in low voltage applications such as wiring for computers and domestic appliances. Single cable is typically insulated with rubber, PVC or other insulating materials. The insulator protects the conductor from short circuits and other electrical hazards.
This is because the sign is supported symmetrically by two cables, which means that the total downward force on the sign is equal to the total upward force. Since the two cables make an angle of 1.0 degrees with the horizontal, the total downward force on the sign is equal to the combined weight of the sign (38.3 N) and the two cables pulling down on it. Therefore, the single cable must pull up with a force of 38.3 N in order to keep the sign in equilibrium.
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A hairdryer has a power of 1000W and was used for half an hour, how much did it cost with the energy price being 14p/kWh?
Answer:
12hp and 132 ml
Explanation:
12+ 132.00=12asd
While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run, 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s² Answer in units of J.- answer :7100J part 2 of 2 What is his final velocity? Answer in units of m/s.
Answer:
12.3 m/s
Explanation:
To calculate the final velocity of Ben, we can use the equation KE = 1/2mv^2, where KE is the kinetic energy and m is the mass of Ben. Inserting the given values, we get:
7100 = 1/2 (63.2 kg) v^2
Therefore, v^2 = 7100/31.6
v = √(7100/31.6)
v = 12.3 m/s
*NOTE* The answers in this question are
NOT realistic. Don't second guess yourself!
A pitcher claims he can throw a 0.151 kg
baseball with as much momentum as a 3.22 g bullet moving with a speed of 1.90312 x
10° m/s.
What must be its speed if the pitcher's claim is valid?
Answer in units of m/s. Answer in units of ms.
004 (part 2 of 3) 1.0 points
What is the kinetic energy of the bullet?
Answer in units of J. Answer in units of J.
005 (part 3 of 3) 1.0 points
What is the kinetic energy of the ball?
Answer in units of J. Answer in units of J
Answer: It is not clear what is the power of 10 in the speed of the bullet but here is a general procedure for the question.
Explanation:
[tex]P_{bullet}=(3.22*10^{-3}kg)*(10^{?}m/s)\\P_{baseball}=P_{bullet}\\[/tex]
Therefore we can write:
[tex](0.151*10^{-3} kg)*v_{baseball}=(3.22*10^{-3}kg)*(10^{?}m/s)[/tex]
From this using the relationship:
[tex]v_{baseball}=\frac{(3.22*10^{-3}kg)*(10^?m/s)}{0.151*10^{-3}kg}[/tex]
I cannot give a precise answer since power of then for speed of the bullet is not clear. But using the above equation you can reach the answer. General form of the equation is therefore:
[tex]v_{baseball}=\frac{P_{bullet}}{m_{baseball}}[/tex]
Where m is the mass of the ball which is 0.151 g.
A 6 kg bowling ball is lifted 1.2 m into a storage rack. The acceleration of gravity is 9.8 m/s². Calculate the increase in the ball's potential energy. Answer in units of J.
Answer:
70.56 J
Explanation:
The increase in potential energy of the ball can be calculated using the formula:
PE = mgh
where:
PE is the increase in potential energy
m is the mass of the ball (6 kg)
g is the acceleration of gravity (9.8 m/s²)
h is the height the ball is lifted (1.2 m)
Substituting in the values, we get:
PE = (6 kg)(9.8 m/s²)(1.2 m)
This simplifies to:
PE = 70.56 J
So the increase in the ball's potential energy is 70.56 J.
what change do you need to make when comparing objects going upward against gravity versus downward with gravity?
A. Different amount of time in motion
B. Different length of displacement
C. Different sign + or - on the acceleration
D. Different changes to velocity
If an object is working against gravity, that means gravity must have the opposite sign of the object (this is why we see objects slow down at their peak height and return to us if we throw them in the air!). If the object is working with gravity, though, they must both be moving in the same direction, therefore gravitational acceleration would be the same sign as the velocity (positive or negative depending on how you define your axes).
Therefore, your answer should be C. Different sign + or - on the acceleration.
I hope this helps!
2. How much work is done in lifting 214kg from the floor to a shelf at a height of 6m?
Answer:
12583.2 J or 12.5832 KJ
Explanation:
Work done can be expressed as force multiplied by displacement, or
W = Fs
In this case, we can calculate the force by using F = mg.
m is the mass, 214 kg, and g is gravitational acceleration, which is 9.8 m/s/s.
So, we Calculate 214 * 9.8 to get 2097.2
The displacement is 6m.
So, by doing W = Fs, we get
2097.2 * 6 = 12583.2 Joules
three way to calculate average are
A 68.2 kg high jumper leaves the ground with a vertical velocity of 8 m/s. How high can he jump? The acceleration of gravity is 9.8 m/s². Answer in units of m.
What will be the linear expansion of a piece of wrought iron 8 feet long if it’s temp is raised 70 degrees F?
The linear expansion of the wrought iron is 0.0038 feet.
What is the linear expansion of the wrought iron?
The linear expansion of the wrought iron is the increase in length of the wrought iron due to change or increase in temperature.
Mathematically, the formula for the linear expansion of metals is given as;
ΔL = αLΔθ
where;
ΔL is the linear expansion of the metalα is the coefficient of thermal expansion of the metalL is the original length of the metalΔθ is the change in temperature of the metalThe coefficient of thermal expansion of wrought iron = 0.0000067 / ⁰F
The linear expansion of the wrought iron is calculated as follows;
ΔL = αLΔθ
ΔL = ( 0.0000067/ ⁰F x 8 ft x 70 ⁰F )
ΔL = 0.0038 ft
Thus, the linear expansion of the wrought iron is a function of the increase in temperature of the iron and the original length of the iron.
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If a vehicle goes from 15.0 km/h to 28.0 km/h in 4.60 seconds, how far will it have traveled?
Answer:
To find the distance the vehicle traveled, you will need to find the average speed of the vehicle over the 4.60 seconds and multiply that by the time traveled.
The average speed of the vehicle can be found by adding the initial speed and the final speed, and then dividing by 2: (15.0 + 28.0) / 2 = 21.5 km/h.
The distance traveled can be found by multiplying the average speed by the time traveled: 21.5 km/h * 4.60 s = 98.7 km.
So, the vehicle will have traveled 98.7 km.
Explanation:
Three point charges are arranged at the corners of a square of side L as shown in Fig. What is the potential at the fourth corner (point A), taking V=0 at a great distance?
Thus the electric field at the fourth corner of the square of side L is E4 = kQ.[2/a² + 1/a√2].
What is Electric field strength?Electric field strength is a quantitative expression of the intensity of an electric field in an electric circuit at a particular location and time. The standard unit of the electric field strength is the volt per meter (V/m or V·m⁻¹). An electric field strength of 1 V/m represents a potential difference of about 1V between the two points which are separated by 1 meter distance.
We are given that:
Number of point charges = 3
Here, we shall use the superposition principle to calculate the net electric field at the fourth point, so
E4 = E1 + E2 + E3
E4 = kQ/a² + kQ/√(2a²) + kQ/a²
E4 = kQ [1/a² + 1/√(2a²) + 1/a²]
E4 = kQ [2/a² + 1/a√2]Thus the electric field at the fourth corner is E4 = kQ [2/a² + 1/a√2].
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Please help with this
A unit vector must have length equal to 1. By calculating the length of (1, 1), we discover that (12 + 12) = 2 = 1.414, which is not the same as 1, is the length.
How do you write unit vector notation?I,J notation is a way to describe a vector. In Cartesian coordinates, a unit vector is a vector with length 1. The unit vectors along the axis are denoted by the letters I and j, respectively. The form ai+bj an I + b j can be used to represent any two-dimensional vector.Numerous operations, including addition, subtraction, and vector multiplication, can be carried out with the aid of the vector form of representation. A=xi+yj+zk is the vector form of the cartesian representation of the three points (x, y, and z). A is equal to x I y j, and z k.Vy = Vyj, Vz = Vz k, and Vx = Vxî. V = Vx + Vy + Vz = Vxî+ Vyj+ Vz k is the result of applying the triangle rule to vector addition twice. The unit vector notation is used in this situation.To learn more about vector refer to:
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How long does it take the Earth to spin on its axis once?
Explanation:
it takes the earth 24 hours to spin on it's axis once
If an object is moving and the sum of all the vector forces on it is zero, then the object will:
accelerate at a constant rate
come to rest
move at a constant speed
none of the previous
If an object is moving and the sum of all the vector forces on it is zero, then the object will move at a constant speed. The correct option is c.
What is vector force?A force's magnitude and direction are both represented by a force vector. This contrasts with expressing the force's magnitude alone, which is known as a scalar quantity.
Typically, a vector is represented by an arrow that points in the direction of the force and has a length proportionate to the strength of the force.
Therefore, the correct option is c, move at a constant speed.
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Gravity on earth is 9.8
Jaydens mass is 50 kilograms his weight is
An object with a weigh of 170 N on Earth is brought to planet Oobla. Where it has a weight of 360 N. What is the gravitational field strength on Oobla
The gravitational field strength on Oobla is 20.75 m/s².
What is gravitational field strength?The gravitational field is the gravitational force exerted per unit mass on a small mass at a point in the field.
To calculate the gravitational field strength on Ooobla, we use the formula below
Formula:
W/g = W'/g'................. Equation 1Where:
W = Weight of the object on Earthg = Gravitational field strength on the Earthg' = Gravitational field strength on the OoblaW' = Weight of the object on OoblaFrom the question,
Given;
W = 170 Ng = 9.8 m/s²W' = 360 NSubstitute these values into equation 1 and solve for g'
170/9.8 = 360/g'g' = 360×9.8/170g' = 20.75 m/s²Hence, the gravitational field strength is 20.75 m/s².
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Hi can anyone please help me with this question? i just cant seem to do it.. Thanksss
Newtons Universal Gravitational Law.
Bill gates a billionaire and space-X CEO, send Robin, 65kg, to planet Gidz. Gidz has a very weak gravitational attraction, of 1.56 N/Kg. Planet GIdz has a radius of 6.35 x 10^11 m.
i. determine the mass of planet Gidz.
Answer:
F = G M m / R^2 = m a
G M / R^2 = a
M = a R^2 / G
M = 1.56 N/kg * 6.35 m^2 / 6.67E10-11 N-m^2 / kg^2
M = 1.56 * 6.35 / 6.67E-11 kg
M = 1.49 * 10^11 kg
a stage light uses a white lamp wgat color of light will be seen when
a yellow filter is used
an orange filter is used
Answer:
Explanation:
When a yellow filter is used, the stage light will appear yellow because the filter absorbs all colors of light except for yellow, which it allows through. When an orange filter is used, the stage light will appear orange for the same reason.
It is important to note that the color of the lamp itself will not change, but the light that is seen by the observer will appear to be the color of the filter due to the absorption and transmission properties of the filte
A 42 kg cart is pushed forward with a total force of 225 Newtons. What is the work done if the cart moves forward 12 meters
Important Formulas:
[tex]w=Fd[/tex]
work(measured in joules) = force(measured in newtons) * distance(measured in meters)
__________________________________________________________
Given:
[tex]m=42kg[/tex]
[tex]F=225N[/tex]
[tex]d=12m[/tex]
[tex]w=Fd[/tex]
__________________________________________________________
Finding work:
[tex]w=Fd[/tex]
[tex]w=225\times12[/tex]
__________________________________________________________
[tex]\fbox{w = 2700 Joules}[/tex]
One of the largest organ pipes is in the auditorium organ in the convention hall in
Atlantic City, New Jersey. The pipe is 38.6 ft long and produces a sound with a
wavelength of about 10.6 m. If the speed of sound in air is 346 m/s, what is the
frequency of this sound?
Among electromagnetic waves, UV rays are most dangerous because exposure to these radiation cause serious problems in living organism. Thus the frequency of sound wave is 0.135 s⁻¹.
What is electromagnetic wave?Electromagnetic wave is a wave which contain two component one is electric component and other is magnetic component. The electric and magnetic component are perpendicular to each other. There are so many wave that comes under electromagnetic wave like infrared wave , radio wave, light wave.
There is a relation between frequency of wave, and wavelength of wave
Mathematically,
speed=distance/time
where,
ν=frequency of light
c is speed of light that is 3×10⁸m/s
λ is the wavelength of light=4.5x10² nm= 10.6 m
Substituting all the values
346 m/s =11.76m÷ t
t=0.033= 0.135 s⁻¹
Thus the frequency of sound wave is 0.135 s⁻¹.
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A satellite’s speed is
5,000 m/s. After 1 min, it is 10,000 m/s.
What is the satellite’s acceleration?
Acceleration = (change in speed) / (time for the change)
Change in speed = (10,000 m/s) - (5,000 m/s)
Change in speed = 5,000 m/s
Time for the change = 1 minute
Time for the change = 60 sec
Acceleration = (5,000 m/s) / (60 s)
Acceleration = 83-1/3 m/s²
Please give me the answer to this question
There is not enough information to determine the work done. Option iv
What is the work done?Let us note that we say that there is work done when the force that has been applied moves a distance in the direction of the force. In this case, we have been told that there is the combination of the works that is done by the object.
Now, we also have to note that we do not have other information to determine the work done such as the magnetic feild and the mass of the electron. All these are lacking in the question.
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A horse trots past you and then a fencepost that is 36m away from you. It takes the horse 11.0 sec to make this trot. What is the average velocity of the horse?
As the horse trots a fencepost that is 36m away from you in 11.0 second, the average velocity of the horse is 3.27 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
A horse trots past you and then a fencepost that is 36m away from you.
Time taken to make this trot = 11.0 second.
Hence, the average velocity of the horse is = total distance travelled/time interval
= 36/11.0 m/s
= 3.27 m/s.
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A longitudinal wave is shown. An illustration of a horizontal spring. In the spring are areas where the rings are closer together and areas where the rings are further apart. The area where the rings are closer together is labeled A, the area where the rings are further apart is labeled B, the height of the spring is labeled C and the distance between adjacent areas where the rings are closer together is labeled D. Which label identifies a rarefaction? A B C D
Answer:
Explanation:
The label that identifies a rarefaction in a longitudinal wave is B.
In a longitudinal wave, such as a wave in a spring, a rarefaction is an area where the particles of the medium are farther apart than they are in the rest of the wave. This is in contrast to a compression, which is an area where the particles of the medium are closer together than they are in the rest of the wave.
In the given illustration, the area where the rings are further apart is labeled B, so B is the label that identifies a rarefaction. The area where the rings are closer together, labeled A, is a compression. The height of the spring, labeled C, does not correspond to a rarefaction or a compression, and the distance between adjacent areas where the rings are closer together, labeled D, is not related to the concept of rarefactions or compressions.
Answer:
wavelength - C
rarefractions - B
compressions - A
Explanation:
correct on EDGE 2023
a defender running away from a goalkeeper at 5m/s is hit in the back by the goal kick. the ball stops dead and the players speed increases to 5.5m/s if the ball had a mass of 500g and the player mass is 70k how fast was the ball moving?
The goal kick strikes a defender racing at 5 m/s away from a goalkeeper in the back. The ball was moving at a speed of 70 m/s if it weighed 500g and the player's mass was 70k.
Why does the goalie in a football game pull his hands back after holding the ball that has been shot towards the goal?The goalkeeper extends the amount of time he has to hold the ball by pulling his hands back. He lessens the force (rate of change of momentum) the football exerts on him by lengthening the time.
Write the formula for momentum and define it.A vector quantity, momentum. A body's momentum is equal to P=m.v if it is travelling at a speed of v while having mass m. P=mv describes the magnitude of the momentum. Because momentum is a function of mass and velocity, its unit is the product of those two quantities.
By using conservation of momentum,
Initial momentum = Final momentum
(5 x 70) + (v x 0.5) = (5.5 x 70) + (0 x 0.5)
350 + 0.5v = 385 + 0
0.5v = 35
v = 70 m/s
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convert 22.0m/s² to km/min²
22.0m/s² is equal to 78.98 km/min². Since 1 m/s² = 3.59 km/m². If we multiply 22 by this number, we get the accurate answer, according to the conversion table.
What is the acceleration unit in the SI?Acceleration is measured in meters per second2 (m/s2). Newton's Second Law, which states that "The acceleration of an object is exactly proportional to the net force acting on it and inversely proportionate to its mass," connects force (F), mass (m), and acceleration (g).
The SI unit is what?The Système International unit, or SI unit, is an acronym for the French phrase for system international. The metric system that serves as the industry standard for measurements is called the International System of Units (SI). In the advancement of science and technology, SI units are essential.
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Which ideas did you include in your answer? Check all that apply.
Scientists use relative and absolute dating to determine age of rocks.
Scientists can organize the rocks layers based on their age on the geologic time scale.
The type of rocks and the fossils in the rock layers tell scientists about Earth’s history.
By contrasting a fossil with related rocks and fossils of known ages, relative dating can estimate the fossil's age.
By utilising radiometric dating to track the isotope decay inside the fossil or, more frequently, the rocks it is linked with, absolute dating may pinpoint an object's exact age.
What are the benefits of using relative and absolute dating of rocks?It is possible to identify whether one artefact, fossil, or stratigraphic layer is older than another using relative dating, which does not provide particular dates.
Absolute dating techniques offer more precise dates and times of origin, such as a range in age in years.
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5.33 A constant force F= (4.70-379, 2.09) N. acts on an object of mass 180 kg, causing a displacement of that object by F= (4.25, 3.69-245) m What is the total work done by this force
The total work done by this force is 28.9-1457.86 N m.
What is total work?Total work is the sum of all the energy expended in completing a job or task. It is the amount of effort and energy expended to accomplish a goal or complete a task. Total work can be calculated by adding up all of the individual components of the job or task, such as time, effort, and materials.
The total work done by this force can be calculated using the formula W = F * Δx, where F is the force vector, and Δx is the displacement vector. In this case, the total work done is:
W = (4.70-379, 2.09) * (4.25, 3.69-245) = (19.9-944.81, 8.00-513.05) N m
Therefore, the total work done is 28.9-1457.86 N m.
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As a warehouse worker pushes a crate across a concrete floor, the force he
applies is not perfectly horizontal, as shown in the image below. If the
coefficient of kinetic friction between the crate and concrete floor is 0.5, what
is the net force on the crate?
Pushing Force
350 N
Weight
460 N
OA. 95 N
OB. 115 N
O C. 130 N
OD. 145 N
10⁰
-Friction Force
2
The crate will be under a net force of 95 N. Resolving the force in the x-direction yields the net force on the crate: F = 300 cos 10° - N F= 295.44-196.45, F= 95.
How do you calculate the frictional force?The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.
What are the friction laws?The friction of a moving item is inversely proportional to the normal force and runs perpendicular to it. The type of surface the thing comes into touch with determines the amount of friction it experiences. As long as there is a point of contact, friction does not depend on the area of contact.
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what is the atmosphere pressure on earth will support a column of mercury about 760 mm high, since the atmosphere pressure on the surface of the planet venus is 9200 kpa (1330 pal) , about 91 times that of earth about how tall a mercury column could venus’s atmosphere support ?
The atmospheric pressure on earth is 1 atm. This pressure is equivalent to the mercuric pressure of 760 mmHg. The atmospheric pressure on the surface of Venus is 9200 kpa which is equivalent to 69017 mmHg.
What is atmospheric pressure?Pressure is the force acting per unit area. In the atmosphere, the gaseous particles and dust exerts a pressure in the atmosphere. The atmospheric pressure depends on the temperature.
There are various units for pressure. Normally the atmospheric pressure is expressed in atm unit. The mmHg pressure is based on the raise in mercuric level with respect to increase in pressure.
1 mmHg = 0.0013133 atm
hence, 760 mmHg = 1 atm
On the surface of Venus, the pressure is 9200 kilopascal.
1 mmHg = 0.133 KPa
then 9200 KPa = 9200/0.133 = 69017 mmHg pressure.
Therefore, height of mercuric column will be 69017 mm in Venus surface.
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