a sinusoidal electromagnetic wave has rms electric field 800 n/c. what is the intensity of the wave? (c = 3.00 × 108 m/s, μ0 = 4π × 10-7 t ∙ m/a, ε0 = 8.85 × 10-12 c2/n ∙ m2)

Answers

Answer 1

The intensity of the wave is 1.92 x [tex]10^{-5[/tex] W/[tex]m^2[/tex].

The intensity (I) of an electromagnetic wave is defined as the average power per unit area that it carries.

The relationship between the intensity and the RMS electric field (E) of a sinusoidal electromagnetic wave is given by:

I = (1/2) x [tex]\epsilon_0[/tex] x c x [tex]E^2[/tex]

where [tex]\epsilon_0[/tex] is the vacuum permittivity and c is the speed of light in vacuum.

Substituting the given values, we have:

I = [tex](1/2) \times (8.85 \times 10^{-12}) \times (3.00 \times 10^8) \times (800 \times 10^{-9})^2[/tex]

I = 9.44 × [tex]10^{-5} W/m^2[/tex]

Therefore, the intensity of the wave is 9.44 × [tex]10^{-5[/tex] W/[tex]m^2[/tex]

It is important to note that the intensity of an electromagnetic wave depends on the square of the amplitude of its electric field.

Therefore, doubling the RMS electric field of the wave will result in a four-fold increase in its intensity.

Conversely, reducing the electric field amplitude by a factor of 2 will result in a reduction of the wave's intensity by a factor of 4.

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Answer 2

The intensity (I) of an electromagnetic wave is defined as the average power (P) per unit area (A) of the wave, and can be calculated using the following formula:

I = P/A

We can also express the power of an electromagnetic wave in terms of the electric field (E) and magnetic field (B) amplitudes, using the following relationship:

P = (1/2)ε0cE^2

where ε0 is the permittivity of free space, c is the speed of light, and E is the root-mean-square (rms) electric field amplitude.

Since we are given the rms electric field amplitude, we can use the above equation to calculate the power of the wave:

P = (1/2)ε0cE^2 = (1/2)(8.85 × 10^-12 c^2/n ∙ m^2)(3.00 × 10^8 m/s)(800 × 10^-9 V/m)^2 = 0.095 W/m^2

Next, we can calculate the intensity by dividing the power by the area through which the wave is passing. Since the area of a sphere of radius r is 4πr^2, and the wave is assumed to be spreading out uniformly in all directions, we can take the area to be that of a sphere with radius r = 1 meter:

A = 4πr^2 = 4π(1 m)^2 = 12.57 m^2

Therefore, the intensity of the wave is:

I = P/A = 0.095 W/m^2 ÷ 12.57 m^2 = 7.57 × 10^-3 W/m^2

So the intensity of the wave is 7.57 × 10^-3 W/m^2.

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Credits to ocean service

Explanation:

Hope this helps



The seed planted at extreme cold or in the region of frozen ice do not germinate, why?​

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Answer:

yes

The the seed planted at Extreme cold or in the region of frozen I did not germinate because the amount of moisture of the seed is too high which results in lack of air of the sea in the frozen ice

In fact, a soil temperature below 50°F might be problematic for many garden plants. Seeds will quickly absorb water at 40°C, but they won't begin to grow. This presents a risk for rot and disease, which may cause damping-off or subpar growth.

What is germination of seed?

The formation of the seedling is the consequence of germination, which is often the growth of a plant inside a seed. It is also the process of the seed's metabolic machinery being reactivated, which causes the radicle and plumule to emerge. A vascular plant's seed is a little bundle that develops in a fruit or cone as the result of the union of the male and female reproductive cells.

Given the need for particular internal or external stimuli to resume growth, dormant seeds are viable seeds that do not germinate. When the right circumstances are present, the seed starts to germinate and the embryo starts to grow again, eventually becoming a seedling.

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this is in order.

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work out

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Answers

Explanation:

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Assignments
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Hello there!

I hope you and your family are staying safe and healthy during this unprecendented time.

A) What is the work done?

Answer: We need to use the formula

[tex]w=-F_f(d)[/tex]

[tex]w=-(35)(20)[/tex]

[tex]w=-700J[/tex]

B) What is the work done on the cart by the gravitational force?  

Alright, we know that the gravitional force is perpendicular to the diplacement. Therefore, we gonna use the following formula:

[tex]w=Fdcos90[/tex]

[tex]w=0[/tex]

C) What is the work done on the cart by the shopper?

This is the easier part, since we already know that the work done by the shopper is the same as the work done by the friction force

[tex]W shopper + W friction = 0\\W shopper = W-friction \\W shopper = 700J[/tex]

D) Find the force the shopper exerts, using energy considerations.

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Answer:

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Answer:

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Answer:

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D. 90 degrees

Hope this helped !

Answer:

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