Answer: 0.00152 km
Explanation:
The following are electronic configurations of five elements. A= 2,8,2 B= 2,8,6 C= 2,8,8 D= 2,8,7 E= 2,8,3 (a) Which element is unlikely to react with the others? (b) Which elements will react to form covalent compounds? (c) Which elements will react to form ionic solids? Give the common valency of the elements when they form ionic solids. Which of these bonds is the weakest: ionic bond; covalent bond; hydrogen bond?
(a) Element C (2,8,8) is unlikely to react with the others.
(b) Elements D (2,8,7) and E (2,8,3) will likely react to form covalent compounds.
(c) Elements A (2,8,2) and B (2,8,6) will likely react to form ionic solids.
(a) It has a complete outer electron shell (valence shell) with eight electrons, fulfilling the octet rule. This stable configuration makes element C less likely to undergo chemical reactions and form compounds.
(b) Covalent compounds involve the sharing of electrons between atoms, typically nonmetals. Both D and E have incomplete outer electron shells and can form covalent bonds by sharing electrons with other elements.
(c) Ionic compounds involve the transfer of electrons from one atom to another, typically between metals and nonmetals. When A and B form ionic solids, they will achieve a stable electron configuration by losing or gaining electrons, respectively.
Element A would lose two electrons to achieve a stable configuration, resulting in a valency of +2. Element B would gain two electrons, resulting in a valency of -2.
The weakest bond among ionic, covalent, and hydrogen bonds is the hydrogen bond. Hydrogen bonds are relatively weaker than ionic and covalent bonds. They occur when a hydrogen atom with a partial positive charge interacts with an electronegative atom, such as oxygen or nitrogen, with a partial negative charge.
Hydrogen bonds are important in various biological and chemical processes, but they are weaker compared to the strong bonds formed in ionic and covalent compounds.
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What Is the ph of a solution where [h30+]3.5*10-3=
The pH of the solution with a [H₃O⁺] concentration of 3.5 * 10^(-3) mol/L is approximately 2.456.
To determine the pH of a solution based on the concentration of H₃O⁺, you can use the equation:
pH = -log[H₃O⁺]
Given that [H₃O⁺] = 3.5 * 10^(-3) mol/L, we can substitute this value into the equation:
pH = -log(3.5 * 10^(-3))
To evaluate this using a calculator or math software:
pH ≈ -log(3.5 * 10^(-3)) ≈ -(-2.456) ≈ 2.456
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An atom of sodium-23 (Na-23) has a net charge of . Identify the number of protons, neutrons, and electrons in the atom. Then, explain how you determined the number of each type of particle. use the periodic table to help you.
Answer:
Protons - 11
Neutrons - 12
Electrons - 11
Step-by-step:
An atom of sodium-23 (Na-23) has a net charge of 0 because it is a neutral atom.
To determine the number of protons, neutrons, and electrons in Na-23, we can use its atomic number and mass number. The atomic number of sodium is 11, which means that a neutral sodium atom has 11 protons in its nucleus. The mass number of Na-23 is 23, which means that its nucleus contains 23 particles (protons and neutrons) in total.
To find the number of neutrons in Na-23, we can subtract the number of protons (which is 11) from the mass number (which is 23). Therefore, Na-23 has 23 - 11 = 12 neutrons.
Since Na-23 is a neutral atom, the number of electrons must also be 11. This is because in a neutral atom, the number of electrons is equal to the number of protons.
So to summarize, the number of protons, neutrons, and electrons in Na-23 are 11, 12, and 11, respectively. We determined the number of protons and electrons from the atomic number of sodium (which is 11), and the number of neutrons from the difference between the mass number (which is 23) and the atomic number (which is also 11).
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if 3 moes of cl reacts with 3 moles oxygen, then which substance is the limitting reactant and excess reactant
If 3 moles of cl reacts with 3 moles oxygen, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions.
To determine the limiting reactant and excess reactant, we need to compare the stoichiometry of the reaction to the given amounts of each reactant.
The balanced chemical equation for the reaction between chlorine (Cl2) and oxygen (O2) can be represented as follows:
2Cl2 + O2 → 2Cl2O
According to the balanced equation, it requires 2 moles of chlorine (Cl2) to react with 1 mole of oxygen (O2) to produce 2 moles of chlorine oxide (Cl2O).
Given that we have 3 moles of chlorine (Cl2) and 3 moles of oxygen (O2), we can determine the limiting reactant by comparing the ratio of moles between the two reactants.
The ratio of Cl2 to O2 required for complete reaction is 2:1. However, since we have equal amounts of Cl2 and O2 (both 3 moles), neither reactant is present in excess.
Therefore, in this scenario, there is no limiting reactant or excess reactant because the reactants are in stoichiometric proportions. All of the chlorine and oxygen will be consumed in the reaction, resulting in the complete conversion to chlorine oxide (Cl2O).
It's important to note that if the amounts of Cl2 and O2 were different, the reactant present in lesser quantity would be the limiting reactant, and the reactant in greater quantity would be the excess reactant.
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5. An alcoholic drink containing 216.0 g of H2O and 9.2 g of ethanol (C2H5OH) is bottled by adding CO2. If the mole fraction of water is 0.9 what approximate mass of CO2 is dissolved in it?
The approximate mass of CO2 dissolved in the alcoholic drink is 832.5 grams.
To calculate the approximate mass of CO2 dissolved in the alcoholic drink, we need to consider the mole fraction of water and the composition of the solution.First, let's determine the number of moles of water and ethanol in the solution:
Molar mass of H2O = 18.02 g/mol
Number of moles of H2O = mass of H2O / molar mass of H2O = 216.0 g / 18.02 g/mol = 11.994 mol
Molar mass of C2H5OH = 46.07 g/mol
Number of moles of C2H5OH = mass of C2H5OH / molar mass of C2H5OH = 9.2 g / 46.07 g/mol = 0.1998 mol
Next, we can calculate the mole fraction of ethanol:
Mole fraction of ethanol = (moles of C2H5OH) / (moles of H2O + moles of C2H5OH) = 0.1998 mol / (11.994 mol + 0.1998 mol) = 0.0164
Since the mole fraction of water is given as 0.9, we can calculate the mole fraction of CO2:
Mole fraction of CO2 = 1 - (mole fraction of water + mole fraction of ethanol) = 1 - (0.9 + 0.0164) = 0.0836
Now, we need to determine the mass of CO2 dissolved in the solution. Assuming ideal behavior, we can use Raoult's law to calculate the approximate mass of CO2:
Mass of CO2 = (mole fraction of CO2) * (molar mass of CO2) * (total mass of the solution)
= 0.0836 * 44.01 g/mol * (216.0 g + 9.2 g)
= 0.0836 * 44.01 g/mol * 225.2 g
≈ 832.5 g
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Please answer part C (the answers for other parts are in the screenshots).
Part C: What is the activation energy of the reaction? Express your answer numerically in kilojoules per mole
The formula for the activation energy was used to obtain;
a. The result is -2.11 * 10^-4 K
b. The result is -3.29
What is the activation energy?The bare minimum of energy required to start a chemical reaction is referred to as activation energy. For a reaction to move from the reactants to the products, the energy barrier must be broken.
To break existing bonds and generate new ones, reactant molecules must collide with enough force and in the proper direction during a chemical reaction. The energy needed to dissolve these bonds and start the atoms moving around to generate the products is known as the activation energy.
We know that we can use the formula;
1/T2 - 1/T1
= 1/318 - 1/298
= -2.11 * 10^-4 K
Again;
ln(k1/k2) = ln(0.1/2.70)
= -3.29
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Draw the orbital Diagram
The orbital diagram of the compound has been shown in the image attached.
What is the orbital diagram of a molecule?
The configuration of the molecular orbitals (MOs) within a molecule is shown in an orbital diagram of the molecule. Atomic orbitals from different molecules' individual atoms overlap to create molecular orbitals. According to the rules of quantum physics, electrons can fill these molecular orbitals.
Each chemical orbital is depicted in an orbital diagram by a line or a box, and the electrons are shown as arrows. The arrow's direction—upward for "spin up" and downward for "spin down"—indicates the spin of the electron.
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What masses of potassium chloride and water are needed to make 300. g of 8.50% KCl solution?
We need 25.5 g of KCl and 274.5 g of water to make 300. g of 8.50% KCl solution.
To find the masses of potassium chloride (KCl) and water needed, we need to use the concentration of the solution and the total mass of the solution.
We need to find the mass of KCl in the solution. We know that the solution is 8.50% KCl by mass, so:
mass of KCl = 8.50% x 300. g = 25.5 g
We can find the mass of water in the solution by subtracting the mass of KCl from the total mass of the solution:
mass of water = 300. g - 25.5 g = 274.5 g
To create 300 g of 8.50% KCl solution, we need 25.5 g of KCl and 274.5 g of water.
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8. Which statement is best supported by the data shown?
A) An iron nail contains fluorite.
B) A streak plate is composed of quartz.
C) Topaz is harder than a steel file.
D) Apatite is softer than a copper penny.
The statement that is best supported by the data shown is this: C) Topaz is harder than a steel file.
What is the best supporting statement?The best supporting statement is the one that shows that Topaz has a higher hardness rating when compared to a steel file.
In the depiction, Topaz is shown as having a hardness rating of 8 while the steel file has an approximate hardness of 6.5. So, the right conclusion to reach is that Topaz is harder than a steel file.
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I need help with this please fast
4) The volume of the HCl used is 9.500 mL while the volume of the NaOH used is 3.800 mL.
5) Molarity of sodium hydroxide is obtained from; Molarity of HCl * 1/2
What is titration?By reacting an unknown component with a known quantity of a different chemical known as a titrant, titration is a laboratory procedure used to measure the concentration of an unknown substance, often a solute dissolved in a liquid.
The endpoint of a titration can be detected in a number of ways, depending on the specific titration being performed.
4)
Volume of the Acid used = Initial reading - Final reading = 25.00 - 15.50 = 9.500 mL
Volume of the base used = 8.80 - 5.00 = 3.800 mL
5)
We know that the mole ratio is 1:2 and the implication of this is that the set up to obtain the molarity of the sodium hydroxide solution is Molarity of HCl * 1/2
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LHow many grams of lead (II) sulfate will precipitate out of solution when 90.0 mL of a 0.10M lead (II)
nitrate solution reacts with an excess of sulfuric acid? Nitric acid is another product of this reaction.
___Pb(NO3)2+____H2SO4–>____PbSO4+____HNO3
Answer: 2.73 g PbSO4
Explanation:
1) solvefor moles Pb(no3)2
0.10 M X 0.09 L =0.009 moles Pb(NO3)2
2) stoichiometry from balanced chemical equation
___Pb(NO3)2 + ___H2SO4---> PbSO4 + ___2 HNO3
0.009 moles Pb(NO3)2 X (1 mole PbSO4 / 1 mole Pb(NO3)2) X (303.2516 g PBSO4/ 1mole PbSO4) = 2.73 g PbSO4
An aqueous solution of ________ will produce a basic solution.
NaClO4
Na2SO3
NaNO3
LiBr
NH4I
Answer:
Explanation:
NH4I NH4 is ammonium thus a base. All other bases end with OH except ammonia which is NH3
How are alleles and traits related?
A. Traits are segments of DNA that code for alleles, which are the
observable characteristics in an organism.
B. Alleles are the inherited characteristics that are seen through
different gene combinations.
C. Traits are characteristics inherited from parents, while alleles are
caused by the environment.
O D. Alleles are distinct versions of genes, and they code for traits,
which are distinct forms of characteristics.
Alleles and traits related as D. Alleles are distinct versions of genes, and they code for traits, which are distinct forms of characteristics.
Alleles and traits are closely related in terms of genetics and inheritance. Alleles are alternative forms of a gene that occupy the same locus on a chromosome. They represent different variations of a specific gene. Traits, on the other hand, are the observable characteristics or features of an organism that are determined by the combination of alleles.
Each individual inherits two alleles for a particular gene, one from each parent. These alleles can be the same (homozygous) or different (heterozygous). The combination of alleles determines the expression of traits in an organism. For example, in the case of eye color, the gene may have alleles for blue and brown eye color. An individual may inherit two blue alleles (homozygous), resulting in the trait of blue eyes, or they may inherit one blue and one brown allele (heterozygous), resulting in the trait of brown eyes. In summary, alleles are distinct versions of genes, and they code for the different variations of traits or characteristics that are observed in organisms. The correct answer is D. Alleles are distinct versions of genes, and they code for traits, which are distinct forms of characteristics.
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To prepare zinc sulphate eye drops APF (Australian Pharmaceutical Formulary), the following ingredients are provided:
1) chlorobutol aqueous solution (0.67% w/v),
2) zinc sulphate monohydrate,
3) boric acid powder,
4) glycol aqueous solution (50% w/v)
Calculate the amount of each ingredients needed to prepare 70 mL of zinc sulphate eye drops APF. Show your working.
To prepare 70 mL of zinc sulfate eyedrops APF, you would need the following ingredients:
Zinc sulfate monohydrate: 0.07 g
Chlorobutol aqueous solution: 10.45 mL
Boric acid powder: 0.7 g
Glycol aqueous solution: 0.14 mL
To calculate the amount of each ingredient needed to prepare 70 mL of zinc sulfate eye drops APF, we'll follow these steps:
Step 1: Determine the concentration of zinc sulfate needed. Since the recipe doesn't specify the concentration, we'll assume a standard concentration of 0.1% w/v.
Step 2: Calculate the amount of zinc sulfate required. The desired concentration is 0.1% w/v, and we need to prepare 70 mL of the eye drops. Therefore, the amount of zinc sulfate needed can be calculated as follows:
Amount of zinc sulfate (g) = (Desired concentration (g/100 mL) * Volume (mL))/100
= (0.1 * 70)/100
= 0.07 g
Step 3: Determine the amounts of other ingredients based on the provided ratios. The chlorobutol solution is at a concentration of 0.67% w/v, so we need to calculate the volume required using the ratio:
Volume of chlorobutol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of chlorobutol (%)
= (0.07 * 100)/0.67
= 10.45 mL
The boric acid powder doesn't specify the concentration, so we'll assume it to be 1% w/v. Using the same logic, we can calculate the amount of boric acid powder required:
Amount of boric acid powder (g) = (Desired concentration (g/100 mL) * Volume (mL))/100
= (1 * 70)/100
= 0.7 g
Finally, the glycol solution is at a concentration of 50% w/v, so the volume required can be calculated as:
Volume of glycol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of glycol (%)
= (0.07 * 100)/50
= 0.14 mL
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Which number is the same as 2.5
10-3?
The number that is the same as the exponentiation given as follows: 2.5 × 10-³ is 0.0025.
What is exponentiation?Exponentiation is the process of calculating a power by multiplying together a number of equal factors, where the exponent specifies the number of factors to multiply.
For example, if 10 is multiplied three times, then it can be written as "10 raised to 3" which means 10³. In this case, 10 is the base, and 3 is the exponent.
Therefore, a number 0.0025 can be written in exponentiation as 2.5 × 10-³ by counting the number of zeros forward.
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chemical reaction for copper carbonate
Answer:
copper cu++
carbonate co3--
reaction=cuco3
an isomer of C3H7O undergoes one step oxidation reaction. Answer the following questions due to this reaction.
a) Write a full symbol equation for this reaction b) Name the proper reagent and catalyst for this reaction.
c) Why do you think there is no need to remove the product from the reaction vessel?
The specific equation depends on the isomer and the oxidizing agent used. An example of a general oxidation reaction could be:
C₃H₇OH + [O] → C₃H₆O + H₂O
Common oxidizing agents for organic compounds include potassium permanganate (KMnO₄), potassium dichromate (K₂Cr₂O₇), or hydrogen peroxide (H₂O₂).
Whether or not the product needs to be removed from the reaction vessel depends on the specific reaction and its desired outcome. In some cases, the product may be of interest for further reactions or analysis, and therefore, it would be retained in the reaction vessel.
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27. Which is true about scientific theories? (2 points)
They are the result of a single experiment.
They are the results of many experiments over a long period of time.
O They are proposed by scientists who wish to investigate a new topic.
They are only based on the most recent evidence.
Answer:
hey are the results of many experiments over a long period of time.
Explanation:
The relative formula masses (Mr) are: CaCo3 = 100; CaO =56 ; Co2=44
describe how this experiment could be used to provide evidence for the law of conservation of mass.
[6 marks]
include your answer:
-method
-which measurements should eb taken
-how the student could show evidence for the conservation for mass
The law of conservation of mass states that in a chemical reaction, the total mass of the reactants is equal to the total mass of the products. An experiment involving the thermal decomposition of calcium carbonate ([tex]CaCO_3[/tex]) can provide evidence for this law.
Method:
A sample of calcium carbonate is heated strongly in a crucible or test tube, causing it to decompose into calcium oxide (CaO) and carbon dioxide ([tex]CO_2[/tex]) gases. The reaction can be represented by the following chemical equation:
[tex]CaCO_3(s) = CaO(s) + CO_2(g)[/tex]
Measurements:
The mass of the empty crucible or test tube is first measured and recorded. A known mass of calcium carbonate is added to the crucible or test tube, and the combined mass is measured and recorded. The crucible or test tube containing the calcium carbonate is then heated strongly, and the mass of the products (calcium oxide and carbon dioxide) is measured and recorded.
Evidence for conservation of mass:
If the law of conservation of mass is true, the total mass of the products should be equal to the total mass of the reactants. In this experiment, the mass of the calcium oxide and carbon dioxide produced should add up to the mass of the calcium carbonate that was originally used.
To show evidence for the conservation of mass, the student could calculate the mass of the products by subtracting the mass of the empty crucible or test tube and the mass of the remaining calcium oxide (if any) from the combined mass of the crucible or test tube and the calcium carbonate.
If the calculated mass of the products is equal to the mass of the reactants, then the law of conservation of mass has been demonstrated.
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How many grams of NaOH are needed to make 100. mL of solution with a concentration of 1.5 M?
To create 100 mL of solution with a concentration of 1.5 M, 6.00 grams of NaOH are required.
The amount of NaOH needed to make 100. mL of solution with a concentration of 1.5 M can be calculated using the formula:
mass = molarity x volume x molar mass
where:
molarity = 1.5 M (given)
volume = 100. mL = 0.1 L (given)
molar mass of NaOH = 40.00 g/mol (from periodic table)
Substituting the values, we get:
mass = 1.5 mol/L x 0.1 L x 40.00 g/mol
mass = 6.00 g
Therefore, 6.00 grams of NaOH are needed to make 100. mL of solution with a concentration of 1.5 M.
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Imagine that the earth's axis of rotation changed so that the same spot (red circle) received the same amount of light in the winter and in the summer. What effect might that change have on the temperature in that spot?
Answer: the temperature would increase
Explanation:
because if one spot on the earth got the same amount of light through the summer and winter it would have a severe amount of drought and nothing to cool it down since all off it evaperated
Energy
4p
3d
4s
3p
3s
2p
2s
1s
Answer:
Energy
4p ⇵ ⇵ ⇵
3d ⇵ ⇵ ⇵ ⇵ ⇵
4s ⇵
3p ⇵ ⇵ ⇵
3s ⇵
2p ⇵ ⇵ ⇵
2s ⇵
1s ⇵
Suppose you were doing a titration where you start out with a basic solution of around 8.0 and you expect to keep adding an acid until the mixture has a pH of 3.0. Based on the indicator chart which pH indicator would be the best one to use. Describe the color change that would be observed
Based on the indicator chart, the pH indicator that would be the best one to use would be Thymol Blue.
The color change would be from light blue to yellow to orange.
Why is this pH indicator best ?Thymol blue would be best because it would show you where your starting point is and then when you reach the desired pH value of 3. 0. Looking at the indicator chart, Thymol blue has a color of light blue between 8. 0 and 9. 0 so you will know you are at 8. 0 when the reaction starts.
As you add more acid, the color would move to yellow to let you know that it is getting more acidic. Once it reaches orange, the titration should stop.
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2 NaN3 → 2 Na + 3 N
Given 9.98 grams of N2, how many moles of NaN3 are produced?
0.238 moles of NaN₃ are produced from 9.98 grams of N₂.
What is the moles of NaN₃ produced?The moles of he mass of NaN₃ produced
The balanced equation for the reaction is:
2 NaN₃ → 2 Na + 3 N₂
The molar ratio between NaN₃ and N₂ is 2:3, which means that for every 2 moles of NaN₃, 3 moles of N₂ are produced.
The mole ratio is used to determine how many moles of NaN₃ are produced from 9.98 grams of N₂.
First, we need to convert the mass of N₂ to moles:
moles of N₂ = mass of N2 / molar mass of N₂
moles of N₂ = 9.98 g / 28.02 g/mol
moles of N₂ = 0.356 mol
moles of NaN₃ = (2/3) * moles of N₂
moles of NaN₃ = (2/3) * 0.356 mol
moles of NaN₃ = 0.238 mol
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Write the chemical formula for this molecule from the picture.
I understand there are 4 Hydrogens
2 Carbons, and 1 Sulfur, but I have no clue how to format it
Answer:
[tex]C_{2}H_{2}S[/tex]
Name a liquid substance that could be used in the laboratory for dissolving dry mortar on floor tiles
One liquid substance that could be used in the laboratory for dissolving dry mortar on floor tiles is hydrochloric acid (HCl). Hydrochloric acid is a strong acid commonly used in laboratories for various purposes, including cleaning and dissolving mineral deposits.
When dry mortar, which is primarily composed of cement, hardens on floor tiles, it can be challenging to remove using traditional cleaning methods. However, hydrochloric acid can effectively dissolve and break down the cementitious components of the mortar.
It is important to note that when using hydrochloric acid, proper safety precautions should be followed, such as wearing protective gloves, goggles, and working in a well-ventilated area.
Additionally, it is crucial to dilute the hydrochloric acid to an appropriate concentration for the specific task, as using it undiluted can cause damage to the tiles or other surfaces.
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An ideal gaseous reaction (which is a hypothetical gaseous reaction that conforms to the laws governing gas behavior) occurs at a constant pressure of 35.0 atm and releases 71.8 kJ of heat. Before the reaction, the volume of the system was 7.00 L
After the reaction, the volume of the system was 2.60 L Calculate the total internal energy change, ΔE , in kilojoules.
Express your answer with the appropriate units.
When, the volume of the system was 2.60 L. Then, the total internal energy change is -71.8 kJ.
We can use the first law of thermodynamics to find the total internal energy change;
[tex]Δ_{E}[/tex] = q + w
where q is the heat transferred to or from the system and w is the work done on or by the system. At constant pressure, work done is given by;
w = -P[tex]Δ_{V}[/tex]
where P is pressure and [tex]Δ_{V}[/tex] is change in volume.
Using the given values, we have:
q = -71.8 kJ (since heat is released)
P = 35.0 atm = 3.56×10⁶ Pa (using the conversion factor 1 atm = 101325 Pa)
[tex]Δ_{V}[/tex] = 7.00 L - 2.60 L = 4.40 L = 4.40×10⁻³ m³ (using the conversion factor 1 L = 10⁻³ m³)
Therefore,
w = -P[tex]Δ_{V}[/tex]= -(3.56×10⁶ Pa)(4.40×10⁻³ m³) = -15.7 J
= -1.57×10⁻² kJ
Thus, the total internal energy change is;
[tex]Δ_{E}[/tex] = q + w = (-71.8 kJ) + (-1.57×10⁻² kJ)
= -71.8 kJ - 1.57×10⁻² kJ
= -71.8 kJ
Therefore, the total internal energy change is -71.8 kJ.
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How many How many molecules are there in 265 grams of FeF^3?
a. 1.1 x 1023
b. 1.3 x 1023
c. 1.4 x 1024
d. 2.8 x1024
2. How many molecules are there in 98 grams of FeF^3?
a. 1.4 x 1023
b. 5.2 x 1023
c. 1.4 x 1024
d. 5.2 x 1024
3. How many atoms are there in 6.2 grams of silver?
a. 1.2 x 1022
b. 3.5 x1022
c. 1.2 x1023
d. 3.5 x 1023
4. How many atoms are there in 54.2 grams of Manganese?
a. 5.9 x 1023
b. 1.3 x 1024
c. 5.9 x1024
d. 1.3 x 1025
. How many molecules are there in 250 grams of Cu(NO3)2?
a. 8.0 x 1022
b. 1.4 x 1023
c. 8.0 x 1023
d. 1.4 x 1024
How many grams are in 6.2 × 1024 molecules of water?
a. 16.5 grams
b. 18.5 grams
c. 165.3 grams
d. 185.3 grams
7. How many grams are in 2.3 x 1023 molecules of NO3?
a. 23.7 grams
b. 46. 2 grams
c. 237 grams d.
d. 462 grams
8. How many grams are in 9.7 x 1023 atoms of selenium?
a. 12.7 grams
b. 62.3 grams
c. 127.3 grams
d. 623 grams
9. How many grams are in 3.4 x 1024 atoms of osmium?
a. 52.2 grams
b. 107.4 grams
c. 203.7 grams
d. 410. 1 grams
10. How many grams are in 11 x 1022 molecules of oxygen?
a. 2.9 grams
b. 5.8 grams
c. 0.3 grams
d. 0.6 grams
The masses, moles, and number of molecules are as follows:
1. c. 1.4 x 10²⁴
2. b. 4.214 x 10²³ molecules
3. a. 1.2 x 10²²
4. a. 5.9 x 10²³
5. c. 8.0 x 10²³
6. d. 185.3 grams.
7. a. 23.7 grams
8. c. 127.3 grams
9. No answer in the option
10. a. 2.9 grams
What is the number of molecules?To determine the number of molecules in 265 grams of FeF₃:
First, calculate the number of moles of FeF₃:
moles = mass / molar mass
moles = 265 g / 139.839 g/mol
moles = 1.8939 mol
number of molecules = moles * Avogadro's number
number of molecules = 1.8939 mol * 6.022 x 10²³ molecules/mol
number of molecules = 1.138 x 10²⁴ molecules
2. To determine the number of molecules in 98 grams of FeF₃:
moles = 98 g / 139.839 g/mol = 0.7001 mol
number of molecules = 0.7001 mol * 6.022 x 10²³ molecules/mol
number of molecules = 4.214 x 10²³ molecules
3. To determine the number of atoms in 6.2 grams of silver:
moles = 6.2 g / 107.8682 g/mol = 0.0574 mol
number of atoms = 0.0574 mol * 6.022 x 10²³ atoms/mol
number of atoms = 3.457 x 10²² atoms
4. To determine the number of atoms in 54.2 grams of Manganese:
moles = 54.2 g / 54.938045 g/mol = 0.9876 mol
number of atoms = 0.9876 mol * 6.022 x 10²³ atoms/mol
number of atoms = 5.947 x 10²³ atoms
5. To determine the number of molecules in 250 grams of Cu(NO₃)₂:
moles = 250 g / (63.546 g/mol + 2 * 14.007 g/mol + 6 * 16.00 g/mol) = 250 g / 187.56 g/mol = 1.333 mol
number of molecules = 1.333 mol * 6.022 x 10^23 molecules/mol
number of molecules = 8.027 x 10^23 molecules
6. To determine the mass in grams of 6.2 x 10²⁴ molecules of water:
moles = (6.2 x 10²⁴ molecules) / (6.022 x 10²³ molecules/mol)
moles = 10.29 mol
mass = moles * molar mass
mass = 10.29 mol * 18.00 g/mol)
mass = 185.3 grams
7. To determine the mass in grams of 2.3 x 10²³ molecules of NO₃:
moles = (2.3 x 10²³ molecules) / (6.022 x 10²³ molecules/mol)
moles = 0.382 mol
mass = moles * molar mass
mass = 0.382 mol * (14.007 g/mol + 3 * 16.00 g/mol) = 23.7 grams
8. To determine the mass in grams of 9.7 x 10²³ atoms of selenium:
moles = (9.7 x 10²³ atoms) / (6.022 x 10²³ atoms/mol)
moles = 1.61 mol
mass = moles * molar mass
mass = 1.61 mol * 78.9718 g/mol = 127.3 grams
9. To determine the mass in grams of 3.4 x 10²⁴ atoms of osmium:
moles = (3.4 x 10²⁴ atoms) / (6.022 x 10²³ atoms/mol)
moles = 5.64 mol
mass = moles * molar mass
mass = 5.64 mol * 190.23 g/mol
mass = 1074.8 grams
10. To determine the mass in grams of 11 x 10²² molecules of oxygen:
moles = (11 x 10^22 molecules) / (6.022 x 10²³ molecules/mol)
moles = 0.182 mol
mass = moles * molar mass
mass = 0.182 mol * 16.00 g/mol
mass = 2.9 grams
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Next the students place waxed paper in front of the light instead of the plastic.
Material Waxed Paper
Photograph of Screen Very blurry white image on gray background.
Does the waxed paper affect how the light hits the screen? Explain your response.
Yes, the waxed paper does affect how the light hits the screen. Waxed paper is a translucent material that diffuses light as it passes through.
When light passes through the waxed paper, it scatters in various directions due to the irregularities and texture of the paper's surface. This scattering of light results in a blurry white image on a gray background when the photograph is taken.
Compared to plastic, which is typically more transparent and smooth, waxed paper has a rougher surface and contains wax coatings that further contribute to light scattering. This diffusion of light reduces the sharpness and clarity of the image projected onto the screen.
The scattered light rays create a more diffused and less defined image, leading to a blurry appearance in the photograph.Therefore, the use of waxed paper instead of plastic alters the behavior of light, causing the light to scatter and resulting in a blurry white image on a gray background when projected onto the screen.
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Which of the following statements regarding the skeletal structure of the organic molecule shown
below is/are true?
K
2
3
H
H
I. A sp² hybrid orbital on C-1 overlaps with a sp hybrid orbital on C-2 to form the sigma
bond between
C-1 and C-2.
II. The bonds between C-2 and C-3 are formed from overlap of sp hybrid orbitals.
III. There are 10 sigma bonds in this molecule.
IV. The bond angle about C-2 is 109.5⁰.
V. The lone pair on the nitrogen atom is in a sp² orbital.
A sp² hybrid orbital on C-1 overlaps with a sp hybrid orbital on C-2 to form the sigma bond between C-1 and C-2. This statement regarding the skeletal structure of the organic molecule true. The correct option is option A.
In general, molecules containing carbon (C) are referred to as organic compounds. Carbon atoms serve as the primary structural framework for the enormous diversity of naturally occurring compounds. Organic substances play a critical role in the existence of all life forms on Earth (and perhaps elsewhere in the universe). A sp² hybrid orbital on C-1 overlaps with a sp hybrid orbital on C-2 to form the sigma bond between C-1 and C-2.
Therefore, the correct option is option A.
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