Answer:
58.50
Step-by-step explanation:
C.$58.50
|| ▼ Answer ▼ ||
|| ✪ Solution ✪ ||
Step 1:
In this question, we are given the following:
A teenager puts $50 into an investment account in January.
If by December the balance in the account increases by 17%,
what is the amount of money in the account in December?
Step 2:
In this case, we are going to use:
[tex]Amount=Principal~(~1+\frac{Rate}{100})^{n}[/tex]
Here, Principal = $ [tex]50[/tex]
Rate = 17%
[tex]^{n}(Time)=~From~January~to~December=12=months=1~year[/tex]
Then, we have that:
[tex]Amount=50~(~1+\frac{17}{100})^{1}[/tex]
[tex]Amount=50~(~1+0.17~)^{1}[/tex]
[tex]Amount=50~(~1.17)[/tex]
[tex]Amount=[/tex] $ 58.50 (Option B)
CONCLUSION:
The amount of money in the account in December = $ 58. 50 ( OPTION B )
Hope this helps!
If you have any queries please ask.
There are 10 students in Class 1 and 40 students in Class 2.
All 50 students sit a test.
The mean score for the students in Class 1 was 80%
The mean score for the students in Class 2 was 70%
Find the mean score of all the students.
Answer:
72%
Step-by-step explanation:
We have 10 sudents in class 1 and 40 in the other for a total of 50 students.
The 10 in class 1 had a mean of 80 so we do 80x10=800
The mean of the class of 40 is 70, so we do 40x70=2800
we add both of those together to get 3600 then we divide that by 50 because there are 50 students in total.
3600/50=72.
Ashley is riding her bike to train for a triathlon and so far has traveled 96 miles.
She is riding at an average rate of 15 miles per hour.
Calculate the time that she has been riding her bike in hours.
Answer:
hours
Note: Write the answer in decimal form.
Answer:
6.4
Step-by-step explanation:
she has been riding her bike for 6.4 hours.
Please help!
consider the function f(x)=-(x+2)^2+4
2 + 4.
a) in what form is this quadratic function written? _________________________
b) list the values of the following parameters
a = ______
h = ______
k = ______
vertex = ___________
c) what will the a parameter do to this function?
Answer:
Below,
Step-by-step explanation:
f(x)=-(x+2)^2+4
(a) Vertex form
(b) a = -1 , h = -2 and k = 4.
vertex = (-2, 4)
(c) The value of a, -1 will invert it vertically or we can describe it as a reflection in the line y = 4. The graph will change from a U shape to a ∩ shape.
About 11,000 species of Lepidoptera (butterflies and moths) have been identified in the United States. Only 679 of them are butterflies. What is the percentage of the Lepidoptera species in the United States are butterflies?
*Science+Math*
Answer:
total no. of butterflies=11000
no.of butterflies=679
percentage of butterflies=?
Percentage of butterflies= (11000/679) percent..
= 16.20 percentage
therefore 16.20 percentage butterflies are in US
A small class has 9 students, 3 of whom are girls and 6 of whom are boys. The teacher is going to choose two of the students at random. What is the probability that the first student chosen will be a boy and the second will be a girl? Write your ansuer as a fraction in simplest form.
subtract, need help again! thanks a lot.
[tex]\quad\qquad\qquad\huge\underline{\boxed{\sf Aηswer☂ }}[/tex]
Here's the solution ~
# First[tex]\qquad \sf \dashrightarrow \: \sqrt{8} - \sqrt{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: ( \sqrt{2 \times 2 \times 2} )- \sqrt{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2\sqrt{ 2} - \sqrt{2} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt{ 2} [/tex]
# Second[tex]\qquad \sf \dashrightarrow \: \sqrt[3]{24} - \sqrt[3]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: (\sqrt[3]{2 \times 2 \times 2 \times 3}) - \sqrt[3]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2\sqrt[3]{3} - \sqrt[3]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt[3]{3} [/tex]
# Third[tex]\qquad \sf \dashrightarrow \: \sqrt[]{125} - \sqrt{45} [/tex]
[tex]\qquad \sf \dashrightarrow \: \sqrt[]{5 \times 5 \times 5} - \sqrt{3 \times 3 \times 5} [/tex]
[tex]\qquad \sf \dashrightarrow \: 5 \: \sqrt[]{5 } - 3\sqrt{ 5} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2 \: \sqrt[]{5 } [/tex]
# Fourth[tex]\qquad \sf \dashrightarrow \: \: \sqrt[5]{96 } - \sqrt[5]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: \sqrt[5]{2 {}^{5} \times 3} - \sqrt[5]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: 2\sqrt[5]{3} - \sqrt[5]{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: \sqrt[5]{3} [/tex]
# Fifth[tex]\qquad \sf \dashrightarrow \: \: \sqrt[]{75} - \sqrt{27} [/tex]
[tex]\qquad \sf \dashrightarrow \: \: \sqrt[]{3 \times 5 \times 5} - \sqrt{3 \times 3 \times3} [/tex]
[tex]\qquad \sf \dashrightarrow \: 5 \sqrt{3} - 3 \sqrt{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: 2 \sqrt{3} [/tex]
15 points do all pls
Keeram ordered 15 1/2 kg of juniper berries for her store. But 2/7 of them arrived bruised and mushy how many kg of useable berries did she receive?
Answer:
11.07~
Step-by-step explanation:
2/7 of 15.5 is 4.42857142857 which we can round to 4.43. We can then just do 15.5-4.43 to get our answer of 11.07.
Events that cannot happen at the same time are called?
HELP!! I’m in class I just need help with the fill in blanks segment help me please
Answer:
First Blank: “controlled” Second Blank: "a Different" Third Blank: "the same" Last Blank: "Height of the ramp"
Step-by-step explanation:
Help please I would appreciate
Answer:
66 (no other answer)
Step-by-step explanation:
The number can be divided by 2 so its even. Its a multiple of 11. It is between 20 and 79. it is a multiple of 3.
write the standard form of the equation of the circle with the given center and radius. Center (2.-1), r= √3
Answer:
(x-2)^2 + (y+1)^2 = 3
Step-by-step explanation:
That is the standard equation for a circle given h,k center and r
10. Jacinto Corado rented a minivan for 4 days in Tampa, Florida, for
$88.00 a day plus $0.20 a mile for all miles over 200. He drove 75, 120,
85, and 140 miles on the days rented. He paid a CDW fee of $18.50 per
day and $61.83 for gasoline.
Answer:
$531.83
Step-by-step explanation:
88*4=352
75+120+85+140=420. Take away the 200 he was allowed. Leaves 220
220*.20 =44
18.50*4=74
gas is set at 61.83
Sum each of those.
352+44+74+61.83= $531.83
What property of operations is used to show that 12x + 6y is equivalent to(2x + y)?
Answer:
Distributive property. When you factor out a GCF, from 12x + 6y, you would get 6(2x+y).
Step-by-step explanation:
12x + 6y is equivalent to 2x + y using the distributive property of multiplication over addition.
What is Number system?A number system is defined as a system of writing to express numbers.
The distributive property states that a(b + c) = ab + ac, where a, b, and c are any real numbers.
We can apply this property to the expression 2x + y by multiplying 2x by 6 and y by 6, giving:
12x + 6y = 6(2x) + 6(y)
Then, we can use the distributive property again to simplify the expression inside the parentheses:
6(2x) + 6(y) = 6(2x + y)
Substituting this expression back into the original equation, we get:
12x + 6y = 6(2x + y)
Simplifying further by dividing both sides by 6, we obtain:
2x + y = 12x/6 + 6y/6
2x + y = 2x + y
Therefore, we have shown that 12x + 6y is equivalent to 2x + y using the distributive property of multiplication over addition.
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solve pls brainliest
Hi again! The answer is 200 students
Would you like me to help explain so you can do these questions on your own? :)
I NEED HELP PLEASEEEEEEEEEEE
The measures of heights (in inches) of a class of students are shown. 60, 60,54, 62, 62, 57,58, 65, 54,67, 63,57, 62, 54, 72, 66, 54, 69, 55, 61 Find the mean, median, mode, range, and standard deviation of the heights.b. A new student who is 7 feet tall joins your class. How would you expect this student’s height to affect the measures in part (a)?
Answer:Compute the variance: 49+25+16+9+1+16+36+648=27.
The variance is a measure of the dispersion and its value is lower for tightly grouped data than for widely spread data. In the example above, the variance is 27. What does it mean to say that tightly grouped data will have a low variance? You can probably already imagine that the size of the variance also depends on the size of the data itself. Below we see ways that mathematicians have tried to standardize the variance.
Step-by-step explanation:
Find the derivative of following function.
[tex]\\ \rm\rightarrowtail y=\dfrac{cos^2x-3\sqrt{x}+6}{sin^2x+6}\times \dfrac{tan^2x+5x}{cosec^2x+3}[/tex]
Make sure you include proper explanation and all steps .
Wrong answers aren't tolerated.
Spam/short/irrelevant answers will be deleted so don't do time pass if you don't know
[tex]\boxed{\pink{\mathscr{All\:the\:best}}}[/tex]
Answer:
[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]
General Formulas and Concepts:
Calculus
Differentiation
DerivativesDerivative NotationDerivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]
Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]
Derivative Rule [Basic Power Rule]:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]:
[tex]\displaystyle (uv)' = u'v + uv'[/tex]
Derivative Rule [Quotient Rule]:
[tex]\displaystyle \bigg( \frac{u}{v} \bigg)' = \frac{vu' - uv'}{v^2}[/tex]
Derivative Rule [Chain Rule]:
[tex]\displaystyle [u(v)]' = u'(v)v'[/tex]
Step-by-step explanation:
*Note:
Since the answering box is way too small for this problem, there will be limited explanation.
Step 1: Define
Identify.
[tex]\displaystyle y = \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \times \frac{\tan^2 x + 5x}{\csc^2 x + 3}[/tex]
Step 2: Differentiate
We can differentiate this function with the use of the given derivative rules and properties.
Applying Product Rule:
[tex]\displaystyle y' = \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) '[/tex]
Differentiating the first portion using Quotient Rule:
[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( \cos^2 x - 3\sqrt{x} + 6 \big)' \big( \sin^2 x + 6 \big) - \big( \sin^2 x + 6 \big)' \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]
Apply Derivative Rules and Properties, namely the Chain Rule:
[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]
Differentiating the second portion using Quotient Rule again:
[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( \tan^2 x + 5x \big)' \big( \csc^2 x + 3 \big) - \big( \csc^2 x + 3 \big)' \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]
Apply Derivative Rules and Properties, namely the Chain Rule again:
[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]
Substitute in derivatives:
[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2} \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]
Simplify:
[tex]\displaystyle y' = \frac{\big( \tan^2 x + 5x \big) \bigg[ \big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - 2 \sin x \cos x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \bigg]}{\big( \sin^2 x + 6 \big)^2 \big( \csc^2 x + 3 \big)} + \frac{\big( \cos^2 x - 3\sqrt{x} +6 \big) \bigg[ \big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) + 2 \csc^2 x \cot x \big( \tan^2 x + 5x \big) \bigg] }{\big( \csc^2 x + 3 \big)^2 \big( \sin^2 x + 6 \big)}[/tex]
We can rewrite the differential by factoring and common mathematical properties to obtain our final answer:
[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]
∴ we have found our derivative.
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---
Topic: Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
You are painting the outside wall of a large building. The wall has a width of 60.11 meters, and a height of 79.88 meters. You need to estimate the total area of the wall, so you know how much paint to buy. Which number below is the best estimate?
A. 4,800 m2
B. 4,400 m2
C. 5,200 m2
D. 5,300 m2
Answer: A) 4,800 m2
60.11m x 79.88= 4801.5868
Answer:
A. 4,800 m²
Step-by-step explanation:
Given :
=> width of wall is 60.11 meters.
=> height of wall is 79.88 meters.
The area of the wall is = length × breadth
=> 60.11×79.88
=> 4,801.5868m²
Approx. 4,800
Ben and Cam are scuba diving. Ben is 15.8 meters below the surface of the water. Cam is 4.2 meters below
Ben. Andrew is a further 16 meters.
Part 1 Write an expression That'll allow you to find Andrew's depth.
Part 2: What's Andrew's depth?
Answer:
27.6
Step-by-step explanation:
1) Say bens depth is x
Cam's depth is x + 4.2
Andrew's depth is x + 4.2 + 16 or x + 11.8
1) andrew's depth = x + 11.8, where x is 15.8.
Therefore, his depth is 27.6 meters.
Isolate the variable to find the solution of the equation. 6. 2w = 18. 6 w = 3 w = 12. 4 w = 24. 8 w = 115. 32.
An equation is formed of two equal expressions. The solution of the equation is w=3.
What is an equation?An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
In order to solve the equation, we need to isolate the variable in the following manner, therefore, the solution of the equation can be written as,
[tex]6.2w=18.6[/tex]
Divide both sides of the equation by 6.2,
[tex]6.2w=18.6\\\\\dfrac{6.2w}{6.2}=\dfrac{18.6}{6.2}\\\\w = 3[/tex]
Hence, the solution of the equation is w=3.
Learn more about Equation:
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I need help please provide the steps
Answer:
1/[tex]\sqrt{2}[/tex] - 1/4
Step-by-step explanation:
We can write 2[tex]\sqrt{8}[/tex] as 2*[tex]\sqrt{4}[/tex]*[tex]\sqrt{2}[/tex]
That becomes 4[tex]\sqrt{2}[/tex], since the square root of 4 is 2 (±2, to be exact)
(4/(4[tex]\sqrt{2}[/tex]) - ( [tex]\sqrt{2}[/tex]/4[tex]\sqrt{2}[/tex])
1/[tex]\sqrt{2}[/tex] - 1/4
Exactly 150 years ago, students planted a tree in front of their school. Since then, the tree has grown 21 meters taller and the distance around the trunk has increased by 3 meters. Use pencil and paper. Describe how you can use this information to find at least two different unit rates. Then find these unit rates.
Answer: There are 2 different unit rates here:
The increase of the tree's height per year
The increase of the tree's trunk per year
Rate of tree's height per year
= 33m / 150 years = 0.22m per year.
Rate of tree's trunk per year
= 3m / 150 years = 0.02m per year.
If you have 19 cups full of water and 45 gallons of water. what does the gallon equals to how many cups of water?
Answer:
45 divide by 19 =2 r 7 thanks
solve pls brainliest
Answer:
a) 441 gallons
b) -243 fish
Step-by-step explanation:
For a), multiply the 7 gallons of water by the 63 minutes to get 441 total gallons of water added
For b), multiply the 27 fish by 9 days to find the total decrease in fish, which is -243 fish.
Hopefully this helps - let me know if you have any questions!
Which expression is equivalent to 3 square root of x^5 y
[tex] \sqrt[3]{ {x}^{5}y } = {x}^{ \frac{5}{3} } {y}^{ \frac{1}{3} } \\ [/tex]
Thus the second option is the correct answer
Anona poured 5.6 cups of
water into her dog's water bowl
this morning. If her dog drinks 27 fluid ounces of the water,
how many fluid ounces of water
will be left in the bowl?
Answer:
Step-by-step explanation: 5.6 would be the add on to 27 so since it included the key word '' left'' you'd substract the two and you'd get your answer, just use calculator. You got this!!!
Go sub to clan fbib !!!!!
HELP GUYS ASAP THIS QUESTION IS DUE SOLVE
The diameter of a cylinder is 1 yd. The height is 12 ydof the cylinder? Find the volume of the cylinder.
Answer:
the volume should be 9.42
Simplify 6-2a
Thank you
Answer:
4a because first, do 6 - 2 which is 4 and combine with a.
Please mark brainliest, thanks!
please help me here?
Answer:
$90
Step-by-step explanation:
12 * 4 = 48
48 + (12*3.5) = 90
answer is $90