Answer:
[tex]T_f=25.0\°C[/tex]
Explanation:
Hello.
In this case, considering that the sample of hot copper is submerged into the water and the container is isolated, the heat lost by the copper is gained by the water so we can write:
[tex]Q_{Cu}=-Q_w[/tex]
In terms of mass, specific heat and temperature we write:
[tex]m_{Cu}C_{Cu}(T_f-T_{Cu})=-m_wC_w(T_f-T_w)[/tex]
Whereas the final temperature is the same for both copper and water because they are in contact until thermal equilibrium is reached. In such a way, the required maximum temperature no more than the equilibrium temperature and is computed as shown below:
[tex]T_f=\frac{m_{Cu}C_{Cu}T_{Cu}+m_wC_wT_w}{m_{Cu}C_{Cu}+m_wC_w}[/tex]
Thus, plugging the given data in the formula, we obtain:
[tex]T_f=\frac{10.3g*0.385\frac{J}{g\°C}*100\°C +47.0g*4.184\frac{J}{g\°C}*23.5\°C }{10.3g*0.385\frac{J}{g\°C}+47.0g*4.184\frac{J}{g\°C}}\\\\T_f=25.0\°C[/tex]
Which is a small change considering the initial one, because the mass of water is greater than the mass of copper as well as for the specific heats.
Best regards!
The maximum temperature of the water in the insulated container after the copper metal is added is 25 °C
From the question given above above, the following data were obtained:
Mass of water (Mᵥᵥ) = 47 g
Temperature of water (Tᵥᵥ) = 23.5°C
Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC
Mass of copper (M꜀) = 10.3 g
Temperature of copper (M꜀) = 100 °C
Specific heat capacity of copper (C꜀) = 0.385 J/gºC
Equilibrium temperature (Tₑ) =?The equilibrium temperature of the mixture can be obtained as follow:
Heat loss by copper = Heat gained by water
Q꜀ = Qᵥᵥ
M꜀C꜀(M꜀ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ– Mᵥᵥ)
10.3 × 0.385 (100 – Tₑ) = 47 × 4.184 (Tₑ – 23.5)
3.9655 (100 – Tₑ) = 196.648 (Tₑ – 23.5)
Clear bracket
396.55 – 3.9655Tₑ = 196.648Tₑ – 4621.228
Collect like terms
396.55 + 4621.228 = 196.648Tₑ + 3.9655Tₑ
5017.778 = 200.6135Tₑ
Divide both side by 200.6135
Tₑ = 5017.778 / 200.613
Tₑ = 25 °CThus, the equilibrium temperature of the mixture is 25 °C. Therefore, the maximum temperature of the water in the insulated container is 25 °C
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Which is a chemical property of milk
A. Milk has a ph ranging from 6.4 to 6.8
B. Milk spoils when left unrefrigerated
C. Milk boils at about 212F
D. Milk curdles when mixed with vinegar
Answer:
C. Milk boils at about 212F
Explanation:
The principal constituents of milk are water, fat, proteins, lactose (milk sugar) and minerals (salts). Milk also contains trace amounts of other substances such as pigments, enzymes, vitamins, phospholipids (substances with fatlike properties), and gases.
Which is not the name of a family on the periodic table
a) Halogens
b) Noble Gases
c) Alkali Earth Metals
d) Actinides
;
Explanation: Look at the scrrn shot and you can see what is on there or not. :)))))
Actinides are not the name of the family of the periodic table.
Explanation:
In the modern periodic table :
Elements are arranged on the basis of their atomic numbersThere are 18 groups(vertical groups) and 7 periods (horizontal rows)Groups are also called families of the periodic table.Metals are present from the middle to the left-hand side of the periodic tableNonmetals are present on the upper right-hand side of the periodic tableMetalloids divide the periodic table in a zig-zag line with nonmetals on the right and metals on the left.The alkali metals are present under group 1The alkaline earth metals are present under group 2The noble gases are present under group 18The halogens are present under group 17The elements in separate two horizontal rows in the bottom are lanthanides and actinides.So, from this, we can conclude that actinides are not the name of the family of the periodic table.
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10. Predict the mass of nitrogen dioxide produced if 2.30 L of ammonia are allowed to react
with excess oxygen gas at STP?
Answer:
Mass of nitrogen dioxide produced = 4.6 g
Explanation:
Given data:
Volume of ammonia = 2.30 L
Mass of nitrogen dioxide produced = ?
Solution:
Chemical equation:
4NH₃ + 7O₂ → 4NO₂ + 6H₂O
Number of moles of ammonia at STP:
PV = nRT
n = PV/RT
n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K
n = 2.30 atm .L / 22.414 atm.L/mol
n = 0.1 mol
Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.
NH₃ : NO₂
4 : 4
0.1 : 0.1
Mass of NO₂:
Mass = number of moles × molar mass
Mass = 0.1 mol × 46 g/mol
Mass = 4.6 g
Calcium reacts with sulfur forming calcium sulfide. What is the theoretical yield (g) of CaS(s) that could be prepared from 7.19 g of Ca(s) and 2.67 g of sulfur(s)? Enter your answer with two decimal places. Do not type units with your answer.
Answer:
The theoretical yield of CaS is 6.01 g.
Explanation:
The balanced reaction is given as:
[tex]Ca+S\rightarrow CaS[/tex]
The molar mass of Ca and S is 40.08 and 32.065 g/mol respectively.
Number of moles = [tex]\frac{Mass}{Molar Mass}[/tex]
So, 7.19 g of Ca contains [tex](\frac{7.19}{40.08})[/tex] mol of Ca or 0.179 mol of Ca
Also, 2.67 g of S contains [tex](\frac{2.67}{32.065})[/tex] mol of S or 0.0833 mol of S
According to the balanced equation:
1 mol of Ca produces 1 mol of CaS
So, 0.179 mol of Ca produces 0.179 mol of CaS
According to the balanced equation:
1 mol of S produces 1 mol of CaS
So, 0.0833 mol of S produces 0.0833 mol of CaS
As the least number of mol of CaS (product) is produced from S , therefore, S is the limiting reactant.
So, thoretically, 0.0833 mol of CaS is produced.
The molar mass of CaS is 72.143 g/mol.
So, the mass of 0.0833 mol of CaS is [tex](0.0833\times 72.143)[/tex] g or 6.01 g
Hence, the theoretical yield of CaS is 6.01 g.
Members of which group easily lose an electron to form a +1 cation?
halogens
alkaline earth metals
noble gases
alkali metal
The alkali metals easily loose an electron and form a +1 cation.
The periodic table is arranged in groups and periods. The elements in the same group have the same number of valence electrons and similar chemical reactivity. This is why groups of elements are also called families of elements.
The group of the periodic table which its members easily loose electrons and form a +1 cation are the alkali metals.
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Element X
Is a Solid at room temperature
Is a metalloid and semiconductor of heat and
electricity
Reacts with Oxygen to form XO2,
compounds and with chlorine to form XCI4,
compounds
Has an average atomic mass that is 2.34
times greater than the standard for atomic
mass(Carbon-12)
You need to make an aqueous solution of 0.192 M barium sulfide for an experiment in lab, using a 500 mL volumetric flask. How much solid barium sulfide should you add?
Answer:
Explanation:
Molecular weight of barium sulphide = 169
500 mL of .192 M barium sulfide = .5 x .192 moles of barium sulphide
= .096 moles of barium sulfide
= .096 x 169 gram of barium sulfide
= 16.22 grams of barium sulfide .
We shall have to add 16.22 gram .
All elements in the same group
Answer:
The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements. Every element in the first column (group one) has one electron in its outer shell.
Explanation:
I'm not really sure what the question is but I hope this helps.
what is the chimestry
the coefficient of 02 is needed to balance the equation C3h8+O2+3co2+4H20
Answer:The anwser is 5
Explanation:
A rook is dropped into a graduated cylinder filled with 35 mL of water.
What is the volume of the rock? (Hint: 1 ml water = 1 cm?)
40 cm
O 14 cm
O 5 cm
O 35 cm
Answer:
5 cm³.
Explanation:
The following data were obtained from the question:
Volume of water = 35 mL
Volume of water + Rock = 40 mL
Volume of rock =.?
The volume of the rock can be obtained as follow:
Volume of rock = (Volume of water + Rock) – (Volume of water)
Volume of rock = 40 – 35
Volume of rock = 5 mL
Finally, we shall convert 5 mL to cm³. This can be obtained as illustrated below:
1 mL = 1 cm³
Therefore,
5 mL = 5 cm³
Thus, the volume of the rock is 5 cm³.
sulphur is non metal why
Answer:
Sulfur is characterized as a non-metal because it is consistent with the 3 physical properties listed for nonmetals. It is a poor conductor of heat and electricity because the electrons are not free to move.
Explanation:
Which of the following molecules may show a pure rotational microwave absorption spectrum: (i) H2, (ii) HCl, (iii) CH4, (iv) CH3Cl, (v) CH2Cl2?
Answer:
Explanation:
H₂ , HCl , CH₃Cl , CH₂Cl₂ ---- Yes
CH₄ ------ No .
Symmetric molecules do not have rotational microwave absorption spectrum because they do not possess permanent dipole moment so they lack polarisability .
The pure rotational microwave absorption spectrum has been possessed by HCl and [tex]\rm \bold{CH_3Cl}[/tex].
Pure rotational microwave absorption has been consisted of the molecules having dipole and polarizability. The molecules that show the spectrum and dipole are diatomic molecules, linear molecules, spherical molecules.
(i) The hydrogen has been a diatomic molecule with symmetry thus not showing a pure rotational microwave absorption spectrum.
(ii) The HCl being a linear molecule possesses a pure rotational microwave absorption spectrum.
(iii) [tex]\rm CH_4[/tex] molecule has symmetry, thus will not possess a pure rotational microwave absorption spectrum.
(iv) [tex]\rm CH_3Cl[/tex] molecule has no symmetry, and thus possesses a pure rotational microwave absorption spectrum.
(v) [tex]\rm CH_2Cl_2[/tex] molecule with the presence of symmetry, thus lacks a pure rotational microwave absorption spectrum.
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2. What is the purpose of subscripts?
3. What is the difference between monatomic and polyatomic ions?
4. How do the names of monatomic anions end?
5. When are Roman numerals used in cation names ?
2. Chemical formulas are used to describe the types of atoms and their numbers in an element or compound. The atoms of each element are represented by one or two different letters. When more than one atom of a specific element is found in a molecule, a subscript is used to indicate this in the chemical formula.
3. The main difference between monatomic and polyatomic ions is that monatomic ions are composed of single atoms whereas polyatomic ions are composed of two or more atoms per ion.
4. These are nonmetal elements which have accepted extra electrons. These ions are relatively few in number and are listed below. Monatomic anions are named by taking the root of the element name and applying an -ide ending. Other important simple anions.
5. This is indicated by assigning a Roman numeral after the metal. The Roman numeral denotes the charge and the oxidation state of the transition metal ion. For example, iron can form two common ions, Fe2+ and Fe3+. To distinguish the difference, Fe2+ would be named iron (II) and Fe3+ would be named iron (III).
HELP ME ASAP!
Under the Law of Multiple Proportions, Carbon Dioxide has a ratio of 2.666 g
Oxygen for every 1 g Carbon. Given this, how much oxygen is present in a sample
of carbon dioxide that has 16 g of carbon?
Answer:
In carbon dioxide, on the right, there is 2.666 g of oxygen for every gram of carbon. So the ratio of oxygen in the two compounds is 1:2, a small whole number ratio
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Given the mass of carbon on the periodic table (12.01 amu), which isotope do you think is the most abundant? Explain WHY in complete sentences. *
Answer:
Carbon-12
Explanation:
Carbon-12 is a carbon with 6 protons and 6 neutrons. Since the AMU for an element is calculated by averaging all naturally occurring isotopes, we can see that 12 in the most abundant. (Since 12.01 is very close to 12, the only reason it is not exactly 12 is because there are other isotopes like carbon-13 or carbon-14 but in low amounts)
Scientists are experimenting with pure samples of isotope X which is radioactive. The sample has a mass of 20. Grams. The half-life was measured to be 232 seconds. There is a second sample that weighs 80 grams. What is the half-life of the second sample
Answer:
Explanation:
Half life of radioactive materials do not depend upon the mass of the material . It only depends upon the nature of radioactive materials . The half life of 20 g is 232 seconds . That means 20 gram will be reduced to 10 gram in 232 seconds .
Half life of 80 gram is also 232 seconds . So , 80 gram will be reduced to 40 gram in 232 second .
Balance the equations by inserting coefficients as needed.
equation 1:
PCl_{3} + Cl_{2} -> PCl_{5}
PCl3+Cl2⟶PCl5
equation 2:
Mg_{3}N_{2} + HCl -> MgCl_{2} + NH_{3}
Mg3N2+HCl⟶MgCl2+NH3
Answer:
first one is already balanced
2. MgN2+6HCl->3MgCl2+2NH3
Explanation:
To balance the equations, we need to ensure that the same number of each type of atom is present on both sides of the equation. Here's how we can balance the given equations:
Equation 1: PCl₃ + Cl₂ -> PCl₅
In this equation, there are 1 phosphorus (P) atom, 3 chlorine (Cl) atoms, and 5 chlorine (Cl) atoms. To balance the equation, we can put a coefficient of 2 in front of PCl₃ to have 2 phosphorus atoms, and a coefficient of 5 in front of Cl₂ to have 10 chlorine atoms:
2PCl₃ + 5Cl₂ -> PCl₅
Now the equation is balanced with 2 phosphorus atoms and 10 chlorine atoms on both sides.
Equation 2: Mg₃N₂ + HCl -> MgCl₂ + NH₃
In this equation, there are 3 magnesium (Mg) atoms, 2 nitrogen (N) atoms, 2 hydrogen (H) atoms, and 1 chlorine (Cl) atom.
To balance the equation, we can put a coefficient of 3 in front of HCl to have 3 hydrogen atoms, and a coefficient of 2 in front of NH3 to have 2 nitrogen atoms:
Mg₃N₂ + 3HCl -> MgCl₂ + 2NH₃
Now the equation is balanced with 3 magnesium atoms, 2 nitrogen atoms, 6 hydrogen atoms, and 2 chlorine atoms on both sides.
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________ and ________ fibres are obtained from animals
Answer:
Explanation:
Silk and wool
Answer:
silk and wool fibers are obtained from animals
Explanation:
good luck :)
i’m so lost please help
C=4
D=-19
Explanation:
2exp-25/5exp-7= 4exp-19
A chemist prepares a solution of silver(II) oxide by measuring out 0.0013 of silver(II) oxide into a 100 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's silver(II) oxide solution. Be sure your answer has the correct number of significant digits.
Answer:
1.3x10⁻⁸ mol/L
Explanation:
0.0013μmol, Calculate concentration in mol/L
To obtain concentration in mol/L we need to convert the μmoles to moles and mL to liters:
Moles silver(II) oxide:
0.0013μmol × (1mol / 1x10⁶μmol) = 1.3x10⁻⁹ moles
Liters solution:
100mL * (1L / 1000mL) = 0.1L
That means concentration in mol/L is:
1.3x10⁻⁹ moles / 0.1L =
1.3x10⁻⁸ mol/L1. Determine the electron-domain geometry and molecular geometry for each of the following.a. SBr2b. PI4+c. IBr2−2. The following three compounds all have the same general formula, XF4. Compare the electron-domain geometries of these three compounds and explain what characteristic(s) of the central atom causes differences in geometry.a. SiF4:b. SeF4:c. XeF4:
Answer:
SBr2
Electron geometry-tetrahedral; molecular geometry-trigonal pyramidal
PI4+
Electron geometry-tetrahedral; moleculargeometry-tetrahedralr
IBr2
Electron geometry - tetrahedral ; molecular shape - bent
Explanation:
We have to carefully consider the issues in question 2.
First of all, the compound SiF4 is an AX4 molecule so both it's electron domain geometry and molecular geometry are tetrahedral. The molecule has no lone pairs.
For SeF4, the compound is a molecule of the type AX4E, its molecular geometry is trigonal bipyramid but its molecular geometry is see-saw because of the presence of a lone pair of electrons on the central atom, selenium.
For XeF4, the electron domain geometry is octahedral but its molecular geometry is square planar. The molecule is of the type AX4E2 and the two lone pairs are positioned above and below the plane of the square.
Describe the changes and challenges that today’s immigrant children experience
Explanation:
It can be a demanding undertaking to reach adulthood as the offspring of mothers who immigrated to america. In the u.s, something many see as a land of opportunities relative to the world they left behind, parents frequently place heavy pressure on their kids to excel.
These same relatives can know only conjectural English, whereas their offspring rapidly become fluent, requiring the children to take on adult roles as parents need to connect with outside the environment of the family.
Which of the three crowns was made of gold? Explain:
Answer:
I need more context. Maybe add a picture.
Explanation:
Answer:
Crown B
Explanation:
because the density of gold is 19.3 and the density of the crown is 19.29.
Rank these systems in order of decreasing entropy. Rank from highest to lowest entropy.
a. 1 mol carbon tetrafluoride gas at 273k 40L
b. 1 mol krypton gas at 273K 40L
c. 1/2 mol krypton gas at 100k 20L
d. 1 mol krypton gas at 273K 20L
e. 1/2 mol krypton liquid at 100K
f. 1 mol fluorine gas 273 K 40L
g. 1/2 mol krypton gas at 273K 20L
Answer:
The answer is "order will be A > F > B> D > G > C > E".
Explanation:
Entropy is disunity, the greater the lack of organization the entropy. When two gases use the same moles, then more entropy is achieved for a larger number of atoms in the molecule (even with more macrostates). Its smaller your volume the less the molecules may circulate, reducing as well as the amount of potential different countries and thus the entropy. Molecules or atoms in colder gas are much less active so they do not actually take so many various energy states and therefore less entropy. In colder gas. A liquid is requested more so than gas and its randomness decreases.__________ have the lowest ionization energies of the groups listed
PLZ HELP I'LL AWARD BRAINLIEST
Answer: have the lowest ionization energies of the groups listed
PLZ HELP I'LL AWARD BRAINLIEST
Explanation:
Pls help, and fast plsssssssss
Answer:
The cell on the left is animal, The cell on the right is a plant cell.
Explanation:
1: cell membrane
2: chloroplast
3: cell wall
4: vacuole
5: mitochondria
6:nucleus
7: lysosome
8: cytoplasm
Things to remember, only plant cells have cell walls. Plant cells are the only ones that have chloroplast.
7. The equation below represents a chemical reaction that occurs in living cells.
CH,26 + 602
6CO2 + 6H,0 + energy
How many atoms are represented in the reactants of this equation?
A=6
B=12
C=24
D=36
Answer:
D
Explanation:
Because i just added all of numbers up
C. 24 if the zero after the 6H, is supposed to be a zero however if it wasnt and u were trying to say h2o it'd be 36
Calculate the mass in grams for 3.28 moles of O2? Please show your work to receive credit.
Answer:
105 g O₂
Explanation:
Step 1: Define
Molar Mass O - 16.00 g/mol
Molar Mass O₂ - 2(16.00) = 32.00 g/mol
Step 2: Use Dimensional Analysis
[tex]3.28 \hspace{3} mol \hspace{3} O_2(\frac{32 \hspace{3} g \hspace{3} O_2}{1 \hspace{3} mol \hspace{3} O_2} )[/tex] = 104.96 g O₂
Step 3: Simplify
We are given 3 sig figs.
104.96 g O₂ ≈ 105 g O₂
Electrolysis of water produces its constituent elements, hydrogen and oxygen. This process is represented by the following balanced chemical equation:
2 H2O(l) → 2 H2(g) + O2(g).
If 8.05 grams of oxygen gas was produced in the reaction, how many molecules of water were decomposed?
Do enter the coefficient of the answer only. Do NOT include the unit in final answer.
_______________________________ × 1023 H2O molecules.
Answer:
3.011 × 10²³
Explanation:
Given data:
Mass of oxygen produced = 8.05 g
Molecules of water decomposed = ?
Solution:
Balance chemical equation:
2H₂O → 2H₂ + O₂
Number of moles of oxygen produced:
Number of moles = mass/molar mass
Number of moles = 8.05 g/ 32 g/mol
Number of moles = 0.25 mol
Now we will compare the moles of water with oxygen.
O₂ : H₂O
1 : 2
0.25 : 2×0.25 =0.5 mol
0.5 moles of water were decomposed.
Molecules of water decomposed:
1 mole = 6.022× 10²³ molecules of water
0.5 mol ×6.022× 10²³ molecules of water/ 1mol
3.011 × 10²³ molecules of water