An unbounded problem is one for which ________. remains feasible

A. the objective is maximized or minimized by more than one combination of decision variables

B. there is no solution that simultaneously satisfies all the constraints

C. the objective can be increased or decreased to infinity or negative infinity while the solution

D. there is exactly one solution that will result in the maximum or minimum objective

Answers

Answer 1

C. the objective can be increased or decreased to infinity or negative infinity while the solution remains feasible.An unbounded problem is one for which the objective can be increased or decreased to infinity or negative infinity while the solution remains feasible.

An unbounded problem is one for which the objective can be increased or decreased to infinity or negative infinity while the solution remains feasible. This means that there may be more than one combination of decision variables that will maximize or minimize the objective, and there may not be exactly one solution that will result in the maximum or minimum objective value.

An unbounded problem is one for which the objective can be increased or decreased to infinity or negative infinity while the solution remains feasible. This means that the problem has no finite upper or lower limit and is not subject to any specific constraints. As a result, there may be more than one combination of decision variables that will maximize or minimize the objective. In addition, there may not be exactly one solution that will result in the maximum or minimum objective value, as the solution set can be infinite. Thus, it is important to keep in mind that an unbounded problem has no specific solution and that different combinations of decision variables can result in the same objective value.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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1.

[tex] \frac{3}{5} \times \frac{5}{6} = \frac{15}{30} = \frac{1}{2} [/tex]

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[tex] \frac{5}{8} \times \frac{4}{10} = \frac{20}{80} = \frac{1}{4} [/tex]

4.

[tex] \frac{5}{12} \times \frac{3}{8} = \frac{15}{96} = \frac{5}{32} [/tex]

5.

[tex] \frac{12}{20} \times \frac{5}{6} = \frac{60}{120} = \frac{1}{2} [/tex]

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[tex] \frac{4}{5} \times \frac{8}{3} = \frac{32}{15} = 2 \frac{2}{15} [/tex]

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[tex] \frac{3}{8} \times \frac{16}{7} = \frac{6}{7} [/tex]

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[tex] \frac{11}{2} \times \frac{18}{7} = \frac{198}{14} =14 \frac{1}{7} [/tex]

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Answers

Answer:

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Step-by-step explanation:

You would just set each side equal to its opposite so for x, it'll be like:

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Answers

Answer:

110 degrees

Step-by-step explanation:

Ok so no matter what the shape is, the exterior angles always have to add up to 360 degrees. Then, you can make the equation:

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Here's another way you can do it:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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