Choose the correct condensed structure from the name: hexene.
O CH3​CHCHCHCH3​
O CHCCH2​CH3​
O CH3​CH2​CH2​CH2​CH2​CH3​
O CH3​CH2​CHCHCH2​CH3​

the de Broglie wavelength of the electron moving at a velocity of 3. 0 × 107 m/s is 2.4×10∧-11nm

lambda = h/mv

The de Broglie wavelength is defined as follows: lambda = h/mv, wherein the greek letter lambda represents the wavelength, h is Planck's consistent, m is the particle's mass and v is its pace. One may also explicit mv as the particle's momentum

according to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all the gadgets in quantum mechanics which determines the chance density of locating the item at a given factor of the configuration area. The de Broglie wavelength of a particle is inversely proportional to its momentum

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Explanation:

The alimentary canal is the long tube of organs - including stomaches and intestines

Answer: digestive strat.

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Answer:

Ethylene oxide

Explanation:

Ethylene oxide is an organic compound with the formula C2H4O. It is a cyclic either and the simplest epoxied: a three-membraned ring consisting of one oxygen atom and two carbon atoms!

The equivalent of 5.690 × 10³ miles in metres is 9157167 metres. Details about metres and miles can be found below.

Miles and metres are both units for measuring distance between two bodies or locations.

However, they can be converted interchangeably as follows:

1 mile = 1609.34 metres

According to this question, 5.690 × 10³ miles can be converted to metres as follows;

5.690 × 10³ × 1609.34 = 9157167 metres.

Therefore, the equivalent of 5.690 × 10³ miles in metres is 9157167 metres.

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Answer:

60 g / mole

Explanation:

120 g  / 2 mole   = 60  g/mole

Taking into account the definition of mole or molar fraction, the mole fraction of N₂ in the mixture is 0.79.

The molar fraction is used to express the concentration of a solute in a solution and expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute(s) and solvent.

The mole fraction "x" of the elements in a compound is defined as a ratio between the number of moles of each of the different elements present in the compound and the total number of moles of them:

x=number of moles of the solute÷ total number of moles

In this case, you know that:

Replacing in the definition of mole fraction:

x=2.11 moles÷ 2.67 moles

Solving:

x= 0.79

Finally, the mole fraction of N₂ in the mixture is 0.79.

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Mass after 60 years:

2 kg of cesium-137 will remain after 60.0 years.

What is Half-life?

The duration needed for a quantity to decrease to half of its initial value is known as the half-life.

Given:

N0 = is the initial amount of cesium-137 = 8.0 Kg

N = is the amount remaining after a time =  Unknown

t =  Duration of cesium-137 decay in 8.0 Kg = 60 years

t1/2 = half-life of cesium-137 = 30.0 years

Formula = N/No = (1/2)^t/t1/2

After putting the value:

N/8= (1/2)^60/30

N/8= (1/2)^2

N/8= 1/4

4N= 8

N= 8/4

N= 2 Kg

As a result, 2 Kg of cesium-137 will be present after 60 years.

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An alginic acid is bio polymer.  The two modified carbohydrate units make up the basic building block of this polymer are guluronic acid ( G) and mannuronic acid (M).

Alginic acid is a biopolymer formed from chain of polyuronic acid. Alginic acid is polysaccharide found in brown algae. Alginic acid is also known as Algin. it is linear co-polymer.

Polysaccharides  are found in the food and it is most abundant carbohydrates. It is long chains of monosachharides. Polysaccharides  is formed by glycosidic linkage or bonds .

Example of polysaccharides are cellulose , starch , glucogen.

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Combustion of hydrogen produces electricity:

It would power a 100-watt (W) light bulb in 27.66 min.

Calculation:

At STP conditions, we know that 1 mole of any gas is contained in 22.4L.

So let's make the operation:

The volume of one mole of gas at STP is 22.4 L

Then, 13.0 L may be the volume for (13.0) /22.4  = 0.58 moles.

The total energy is released = 0.58 x 286 kJ

Total energy = 165.98 kJ

Energy = Power x time

Time = energy / power

where power = 100W = 100 J/s

Therefore, Time = 165.98 kJ/ 100J/s = 1659.8 sec

Time = 1659.8 sec / 60 min = 27.66 min

∴ Time = 27.66 min

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The answer is hydroxides.

The elements of the group IA are termed as alkali metals, because their hydroxides are alkaline.

The value of ΔS° for reaction  is - 22.2 J/K.mol

[tex]SO_{2}(s)+NO_{2} (g)[/tex] → [tex]SO_{3}(g)+NO(g)[/tex]

Calculation,

Given value of S°(J/K.mol) for

[tex]SO_{2}(s)[/tex] = 248.5

[tex]NO_{2} (g)[/tex] = 240.5

[tex]NO(g)[/tex] = 210.6

[tex]SO_{3}(g)[/tex] = 256.2

Formula used:

ΔS° (Reaction) =  ∑S°(Product) - ∑S°(Reactant)

ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol

The change in stander entropy of reaction is  - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.

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The liberated electron will have 10.28 eV kinetic energy.

Given that light of frequency 3.62 × [tex]10^{15}[/tex] Hz strikes a surface of copper metal with work function([tex]W_{0}[/tex]  = 4.70 eV).

The incident (photon) energy given as hf (Planck's Constant time's frequency) minus the energy that "binds" the electron to the metal (the work function) will equal the maximum kinetic energy of the emitted electron.

K.E. = hf − ϕ

Where K = Kinetic energy

h = Planck's constant = 6.62607015 × [tex]10^{-34}[/tex] J s

f = frequency = 3.62 × [tex]10^{15}[/tex] Hz

ϕ = 4.70 eV = 4.7 × 1.6 × [tex]10^{-19}[/tex] = 7.52 × [tex]10^{-19}[/tex]

K.E. = 6.62607015 × [tex]10^{-34}[/tex] × 3.62 × [tex]10^{15}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 6.62607015 × 3.62 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

       = 23.98 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]

K.E. = 16.46 × [tex]10^{-19}[/tex] J = 10.28 eV

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The example that shows the correct way to set up the calculation will be the second example.

Mathematically:

  Number of moles = mass/molar mass

In this case, mass = 23.4 g and molar mass = 110.98 g/mol

Number of moles = 23.4/110.98 = 0.21 moles

Thus, the second example is the correct way.

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The soft ionization technique that uses a UV-absorbing compound upon which the analyte of interest is placed and eventually vaporized into a plume of ions directed into the mass analyzer is matrix-assisted laser desorption ionization.

Soft Ionizer produces less fragment ions. Soft ionizer produce the molecular ions or a quasi molecular ion. This technique not fragment the macromolecules into the more smaller charged particles.

Thus from the above conclusion we can say that The soft ionization technique that uses a UV-absorbing compound upon which the analyte of interest is placed and eventually vaporized into a plume of ions directed into the mass analyzer is matrix-assisted laser desorption ionization.

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Answer:

1.3 x10^-16

Explanation: answered it in your comments! :)

When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

The Baeyer-villiger oxidation would seem to be a chemical reaction that uses peroxy acids using peroxides as the oxidant to transform a ketone into an ester or a lactone from such a cyclic ketone.

The main product produced by the Baeyer-Villiger oxidation of camphor using m-CPBA in buffer conditions could be created as a result of the migration of a tertiary bridgehead carbon as opposed to a methylene group.

By the reaction between 3-methyl-2-butanone with m-CPBA , will form isopropyl acetate and methyl isobutyrate.

It reaction can be shown as:

Therefore, when 3-methyl-2-butanone undergoes a Baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.

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1.98 moles of Magnesium oxide were formed.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now write the balanced chemical equation

2Mg + O₂ → 2MgO

(2 × 24)          2 × (24 + 16)

48 g of Mg gives 80 g of MgO

To find the number of moles use the expression

Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

                              = [tex]\frac{80}{40.3}[/tex]

                              = 1.98 mole

Thus from the above conclusion we can say that 1.98 moles of Magnesium oxide were formed.

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Lead is a naturally occurring metal found in the environment as well as manufactured in products. The major source of this metal has historically been fuels in on-road motor vehicles such as cars and trucks, and industrial sources.

Both naturally occurring in the environment and used in manufactured goods are the metal lead. In the past, industrial sources and fuels used in on-road motor vehicles (such as cars and trucks) have been the main sources of lead emissions. Lead emissions from the transportation industry rapidly reduced by 95% between 1980 and 1999 thanks to regulatory measures in the U.S. to remove lead from gasoline for on-road motor vehicles, while lead levels in the air decreased by 94% over the same period. The areas closest to lead smelters typically have the greatest airborne lead concentrations today. Today, the processing of ores and metals as well as piston-engine aircraft using leaded aviation gasoline are the main sources of lead emissions into the atmosphere.

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The same solvent as the liquid in the original mixture should be used to wash the solid material collected from a filtration.

The solid material which is collected from the filtration is washed by that solvent in which that solid material is dissolved. Generally methanol solvent is used to wash the solid material collected from a filtration.

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Metal that won't be oxidized:

Metal that will not be able to oxidize by any of the other metals is gold.

What causes oxidation to happen?

This chemical reaction might take place in the air or after the metal has been in contact with acids or water. The most prevalent example is corrosion of steel, which occurs when the iron molecules on the surface of steel change into iron oxides, most frequently Fe2O3 and Fe3O4.

If you've ever seen a rusted-out vehicle or corroded metal bits, you've witnessed oxidation in action.

Metals that don't oxidize:

In their native condition, noble metals like platinum or gold resist oxidation. Ruthenium, rhodium, palladium, silver, osmium, and iridium are more examples of these metals. Humans have developed a wide variety of corrosion-resistant alloys, including brass and stainless steel.

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Answer:

Medicinal Chemistry

Explanation:

Medicinal Chemistry deals with the development, design and production of medicines.

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A hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D

The hydrogen bond is one that is responsible for association in molecules. It occurs when hydrogen is covalently bonded to a highly electronegative element such as oxygen, nitrogen or Sulphur.

Thus, a hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D

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The state of the balloon:

When the balloon is submerged in the beaker, the amount of water in the beaker will get reduced.  

What is Osmosis:    

Based on the concentration of solutes on both sides of the membrane, water will flow through a permeable membrane in a specific direction.

Hypertonic solution:

It means that there are more solutes present in the surrounding environment than in the cell itself.

Hypotonic solution:

In a hypotonic solution, the concentration of solutes inside the cell is higher than that outside the cell.

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The complete reaction equation is [tex]3Fe + 4H_2O -- > Fe_3O_4 + 4H_2[/tex]

They are reactions in which one of the elements in a reactant is displaced by another element in the product.

In the reaction leading to the production of [tex]Fe_3O_4[/tex], Fe displaced H atoms from [tex]H_2O[/tex].

Thus, the equation of the reaction is as follows:

[tex]3Fe + 4H_2O -- > Fe_3O_4 + 4H_2[/tex]

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Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

It is a device that can measure heats of combustion, used in various applications such as calculating the calorific value of foods and fuels.

A sample of propane is burned in a bomb calorimeter with a mass (m) of 1.350 kg and a specific heat (c) of 5.82 J/g.°C. All the energy released by the propane is absorbed by the bomb calorimeter.

If the temperature rises by 2.87 °C (ΔT), we can calculate the energy released (Q) using the following expression.

Q = c × m × ΔT = 5.82 J/g.°C × 1,350 g × 2.87 °C × (1 kJ/1000 J)

Q =  22.5 kJ

Propane is burned in a 1.350-kg bomb calorimeter with a specific heat of 5.82 J/g.°C. For a temperature rise of 2.87 °C, the energy released is 22.5 kJ.

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Answer:

22.5 kj

Explanation:

18 g of silicon-32 will be present in 800 years.

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and it's given by

                              [tex]N(t) = N_0 (\frac{1}{2}) ^\frac{t}{t_\frac{1}{2} }[/tex]

where,

[tex]N(t) =[/tex] quantity of the substance remaining

[tex]N_0 =[/tex]  the initial quantity of the substance

[tex]t =[/tex]  time elapsed

[tex]t_1_/_2 =[/tex] the half-life of the substance

From the given information we know:

The initial quantity of silicon-32 is 40 g.

The time elapsed is 800 years.

The half-life of silicone-32 is 710 years.

So, using the calculation above, we can determine how much silicon-32 is left.

                  [tex]N(t) = 40 (\frac{1}{2}) ^\frac{800}{710} \\N(t) = 40 (\frac{1}{2}) ^\frac{80}{71} \\\\N(t) = 18 g[/tex]

Therefore,18 g of silicon-32 will be present in 800 years.

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