Consider the following intermediate chemical equations.

3 equations. 1: upper C solid plus upper o subscript 2 gas right arrow upper C upper O subscript 2 gas Delta H 1 equals negative 393.5 kilojoules. 2: 2 upper C upper O gas plus upper O subscript 2 gas right arrow 2 upper C upper O subscript 2 gas Delta H 2 equals negative 566.0 kilojoules. 3: 2 upper H subscript 2 upper o gas right arrow 2 upper H subscript 2 gas plus upper O subscript 2 gas delta H 3 equals 483.6 kilojoules.

The overall chemical equation is Upper C (s) plus upper H subscript 2 upper O (g) right arrow upper C upper o (g) plus upper H subscript 2 (g).. To calculate the final enthalpy of the overall chemical equation, which step must occur?
Reverse the first equation, and change the sign of the enthalpy. Then, add.
Reverse the second equation, and change the sign of the enthalpy. Then, add.
Multiply the first equation by three, and triple the enthalpy. Then, add.
Divide the third equation by two, and double the enthalpy. Then, add.

Answer

5.6 L

Explanation:

whatever you start with, you end with the same amount.

(LAW OF CONSERVATION)

The amount of oxygen and gasoline that can be produced is 5.6 liters

The question above is answered with the law of conversation of mass. This law of conversation of mass states that  no form of energy can be destroyed, instead it is changed from one form to another type of form.

In this law, it is expected that you end with the same amount you started with. According to the question above, since the amount that you started  with is 5.6 liters then you will end with 5.6 liters also.

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10.6 mol NO

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Stoichiometry

Step 1: Define

[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O

[Given] 13.2 mol O₂

Step 2: Identify Conversions

[RxN] 5 mol O₂ → 4 mol NO

Step 3: Stoich

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

10.56 mol NO ≈ 10.6 mol NO

Answer:

The enthalpy of solution for AgNO3 is positive because the temperature of the solution decreases (the dissolution is endothermic). Hsol = Hsolute + Hsolvent + HmixHsolute and Hsolvent are endothermic because energy is required to overcome intermolecular forces and separate solute and solvent particles.

Answer:

the enthalpy of solution for agno3 is positive because the temperature of the solution decreases. (the dissolution is endothermic.)

Delta H sol=delta HSolute +delta H solvent +delta H mix

HSolute and H solvent are endothermic because energy is required to overcome intermolecular forces and separate solute and solvent particles.

H mix is exothermic because energy is released when intermolecular forces form between solute and solvent particles.

if the overall enthalpy of solution is positive, then HSolute + H solvent must be larger in magnitude than H mix.

Explanation:

correct on edge2021

d. all of the above

AnswerD:

Explanation:

Answer:

ok

Explanation:

Answer: While the mass number is the sum of the protons and neutrons in an atom, the atomic number is only the number of protons. The atomic number is the value found associated with an element on the periodic table because it is the key to the element's identity.

MARK ME BRAINLIST

Answer:

No, It would be a unsaturated solution

Explanation:

The solubility of a compound gives us information about how a compound may dissolve or not in a determinate solvent.

In this case we have Z, which in 25 °C the solubility of this compound is 40g/100 mL water. This means that if we have 60 g of Z and try to dissolve it in 100 mL of water, only 40 g of Z will solve and the remaining 20 g will be in the water as precipitate or remaining solid.

Now if you just put 40 g of Z in 100 mL water, it will dissolve completely in water, and in this case, we have a saturated solution. A saturated solution is when you dissolve a determinated quantity of a solute in a determinated quantity of solvent, without remaining of solid or excess of solvent.

According to this explanation, we now have 120 g of Z. To make a saturated solution of Z with this quantity, well, let's do math. If 40 g dissolves in 100 mL, then 80 g would be 200 mL and 120 g would have to be 300 mL of water. But in this case, we have 450 mL of water, we have more than 300 mL, an excess of water, so, the 120 g will dissolve but it's dissolved in more than the needed quantity to be a saturated solution, therefore, we have an unsaturated solution of Z (more solvent than the needed).

Hope this helps.

Answer:

Cu3PO4

Explanation:

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, Cu[tex]_3[/tex]PO[tex]_4[/tex] is the formula for copper(I) phosphate(v).

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond. Cu[tex]_3[/tex]PO[tex]_4[/tex] is the formula for copper(I) phosphate(v). Cu[tex]_3[/tex]PO[tex]_4[/tex] is an ionic compound with cation Cu⁺¹ and anion as PO₄³⁻.

Therefore, Cu[tex]_3[/tex]PO[tex]_4[/tex] is the formula for copper(I) phosphate(v).

To learn more about chemical compound, here:

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Answer:

electrical --> thermal --> light

Explanation:

Answer:

electrical--> thermal--> light

Answer:

[NaOH] = 0.1 Molar ... Note => the brackets around formula;i.e., "[ ]" is generally accepted in the chemistry community as concentration in Molar terms.

Explanation:

The metathesis rxn, or double replacement rxn, equation is:

(Molarity x Volume) of acid = (Molarity x Volume) of base, or

(M·V)acid = (M·V)base => M(base) = M·V(acid)/V(base)

= 0.1M × 18.3ml / 20ml = 0.0915M(base) = 0.1M (1 sig-fig) = [NaOH]

Answer:

The sign of change of heat of solution is positive

Explanation:

The dissolution of AgNO3 in water is represented by the equation;

AgNO3(s) --------> Ag^+(aq) + NO3^-(aq)

We can see from the question that as the temperature was increased from 10° to 20°C the solubility of the solute increased from  170g to 222g per 100g of H2O.

This implies that the solubility of the solute increases with increase in temperature.

If a reaction moves in the forward direction when the temperature is increased, then the reaction is endothermic. If the reaction is endothermic, the sign of change of heat of solution is positive.

Answer:

KCl

Explanation:

hope this is correct and helps i did this last year in chem :)

[tex]\mathrm{KCl}[/tex]

Answer:

The designs ensure that the experimental.

Explanation:

Scientific research refers to the-fact finding inquiry to answer the questions related to natural processes. A hypothesis is a situation or an assumption that needs to be proved by applying scientific produces. Experimental design refers to the methodology, which is applied to conduct research.

The designs ensure that the experimental data support the hypothesis is the true statement regarding experimental designs that are used in scientific research because an experimental design should be concerned with the fact that it is relevant or appropriate to prove a hypothesis.

Answer:

its c. the designs follow a general method that is familiar to all scientists

Explanation:

Answer:

it should be the second one :)

Explanation:

Explanation:

Specific heat capacity of gold (S)

= 0.126 J /kg°C

mass (m) = 350 g = 0.35 kg

difference in temperature (dt)

= 88.5°C - 24.6°C

= 63.9° C

Now

Energy released (Q)

= m*s*dt

= 0.35 * 0.126 * 63.9

= 2.81799 Joule

Hope it will help :)

Molecular formula

hope that helps^^

Answer:c

Explanation:

Answer: In empty space, electromagnetic radiation will fly. Some kind of material must pass across most other forms of waves. In order to be heard, for instance, sound waves require either a gas, solid, or liquid to travel through.

Answer:

Reflection-energy waves bouncing off the surface of an object

Explanation:

Answer:

The dissolution of sodium chloride involves three steps. During the process energy changes occur in:

1. breaking apart the hydrogen bonds between water molecules,

2. breaking apart the electrostatic bonds between sodium and chloride ions, and

3. when bonds are formed between water molecules and aqueous ions in solution.

Since the energy used to break apart the hydrogen bonds between water molecules and the energy used to break apart the electrostatic bonds between sodium and chloride ions, is greater than the energy released when bonds are formed between water molecules and aqueous ions in solution, the dissolution of sodium chloride is endothermic.

Explanation:

The heat of solution or enthalpy of solution/dissolution, is the enthalpy change that occurs with the dissolution of a solute in a solvent at constant pressure, resulting in infinite dilution. Its unit is kJ/mol for reactions taking place under standard conditions (298.15 K and 1 atm).

The process of dissolution occurs in three energy-dependent steps:  

1. The breaking of bonds within the solute. For example, electrostatic forces of attraction between two oppositely-charged ions. This process is endothermic.

2. The endothermic process of breaking of intermolecular forces within the solvent, e.g. hydrogen bonds in water.

3. The exothermic process of the formation of new solute-solvent bonds in solution.

The sum of the energies involved in these three steps gives the enthalpy of dissolution of a solute. The overall process of dissolution can either endothermic or exothermic depending on the amount of energy used or released in breaking and making bonds. If more energy is released in making than is used in breaking bonds, it is exothermic.  However, if more energy is used in breaking bonds than is released in making bonds, dissolution is then endothermic.

For example, considering the dissolution of sodium chloride. During the process the energy used to break apart the hydrogen bonds between water molecules and the energy used to break apart the electrostatic bonds between sodium and chloride ions, is greater than the energy released when bonds are formed between water molecules and aqueous ions in solution. Therefore, the dissolution of sodium chloride is endothermic.

Answer:

D or C.

Explanation:

Sorry if its wrong

Answer:

A. Rocks along the coast are broken up by waves crashing into the shore.

Explanation:

Answer:

D

Explanation:

Option D is the correct Lewis structure of ozone.

Ozone is known to be an allotrope of oxygen which has three atoms of oxygen.

In the Lewis structure of ozone, one pair of oxygen is actually double-bonded while the other is single-bonded. In this structure, two oxygen atoms carry charges. In the drawing the Lewis structure of ozone, we discover that one oxygen atom of the ozone has a -1 charge and while another oxygen atom of the ozone has a +1 charge.

78 L Cl₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

280 g Cl₂

Step 2: Identify Conversions

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.90 g/mol

[STP] 1 mol = 22.4 L

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

78.4981 L Cl₂ ≈ 78 L Cl₂

Answer:

210 microliters of drug are needed to fill the capsule

Explanation:

As given in the question

1 liter is equal to [tex]10^6[/tex] micro liters

Volume of Capsule [tex]= 210[/tex] cubic millimeter

1 cubic millimeter  [tex]= 10^{-3}[/tex] cubic meter

1 cubic meter [tex]= 10^3[/tex] liters

1 micro liter [tex]= 10^{-6}[/tex] micro liters

Converting [tex]210[/tex] cubic millimeter to micro liter

[tex]= 210 * (10^{-3})^3 * 10^3 \\= 210 * 10^{-6}\\= 210[/tex]micro liters

Answer:

This is a typical stoichiometry question.To answer this question you want to get a relationship between

N

a

2

O and NaOH.

So you can get a relationship between the moles of

N

a

2

O

and moles of NaOH by the concept of stoichiometry.

N

a

2

O +

H

2

O ----------------> 2 NaOH.

According to above balanced equation we can have the stoichiometry relationship between

N

a

2

O and NaOH. as 1:2

It means 1 moles of

N

a

2

O is required to react with one mol of

H

2

O to produce 2 moles of NaOH.

in terms of mass 1 mole of

N

a

2

O has mass 62 g on reaction with water produces 2 moles of NaOH or 80 g of NaOH.

62 g of

N

a

2

O produces 80 g of NaOH.

1g of NaOH is produced from 62/80 g of

N

a

2

O

1.6 x

10

2

g of NaOH will require 62 x 1.6 x

10

2

g / 80 of

N

a

2

O

124g of

N

a

2

O.

Explanation: