The actual free energy change at 298 K when the pressure of SO2 is 120 atm and O2 is 3.1 x 10^-3 atm is +172.93 kJ/mol. Option (b) is the correct answer.
To calculate the standard free energy change for the given reaction, we need to use the standard free energy of formation values for the reactants and products. The reaction can be written as:
2 PbO (s) + 2 SO2 (g) → 2 PbS (s) + 3 O2 (g)
The standard free energy change for this reaction can be calculated as:
ΔG° = ΣnΔGf°(products) - ΣmΔGf°(reactants)
where n and m are the stoichiometric coefficients of the products and reactants, respectively, and ΔGf° is the standard free energy of formation.
Using the given values for the standard free energy of formation, we can calculate ΔG° as:
ΔG° = [2ΔGf°(PbS) + 3ΔGf°(O2)] - [2ΔGf°(PbO) + 2ΔGf°(SO2)]
= [2(-82.5) + 3(0)] - [2(-217.6) + 2(-300.4)]
= -165 + 835.2 - (-435.2)
= -165 + 835.2 + 435.2
= 1105.4 kJ/mol
Now, we need to calculate the actual free energy change at 298 K when the pressure of SO2 is 120 atm and O2 is 3.1 x 10^-3 atm. For this, we can use the following equation:ΔG = ΔG° + RTln(Q)
where R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin (298 K), and Q is the reaction quotient.
The reaction quotient can be calculated using the given pressures of SO2 and O2:
Q = (PSO2)^2 / PO2^3.
Substituting the values, we get:
Q = (120)^2 / (3.1 x 10^-3)^3
Q = 2.36 x 10^22
Now, substituting all the values in the above equation, we get:
ΔG = 1105.4 kJ/mol + (8.314 J/mol K x 298 K x ln(2.36 x 10^22))
= 1105.4 kJ/mol + (61473 J/mol)
= 172.93 kJ/mol
Therefore, the actual free energy change at 298 K when the pressure of SO2 is 120 atm and O2 is 3.1 x 10^-3 atm is +172.93 kJ/mol. Option (b) is the correct answer.
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Consider the following reaction: 2 PbO (s) + 2 SO2 (g) -> 2 PbS (s) + 3 O2 (g). To calculate the Gibbs free energy change (ΔG) at 298 K, we need the standard Gibbs free energy change (ΔG°) and the partial pressures of the gases involved.
ΔG = ΔG° + RT ln(Q)
where R is the gas constant (8.314 J/mol·K), T is the temperature (298 K), and Q is the reaction quotient.
Given ΔG° = -780.8 kJ/mol and partial pressures: SO2 = 120 atm, O2 = 3.1 x 10^-2 atm.
First, we need to calculate Q using partial pressures:
Q = (P_PbS^2 * P_O2^3) / (P_PbO^2 * P_SO2^2)
As PbO and PbS are solids, their activities are considered to be 1.
Q = (1^2 * (3.1 x 10^-2)^3) / (1^2 * (120)^2) = 2.828 x 10^-11
Now, calculate ΔG using the equation above:
ΔG = -780.8 kJ/mol + (8.314 J/mol·K * 298 K * ln(2.828 x 10^-11))
ΔG = -780.8 kJ/mol + 0.646 kJ/mol = -780.154 kJ/mol
The closest answer to the calculated ΔG is option (b) +646 kJ, although there might be some discrepancies in the provided data.
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Please show all work:
If 40.0 grams of magnesium is reacted with an excess of nitric acid, HNO 3 , how many
grams of hydrogen gas will be produced?
3.3 g of hydrogen gas will be produced.
What is Stoichiometry ?Stoichiometry helps to measure quantitative relationships between the amounts of products and reactants that are given in a reaction.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
Mg + 2HNO₃ → Mg(NO₃)₂ + H₂
According to Stoichiometry
[tex]40.9\ \text{g Mg} \times \frac{1\ \text{mol Mg}}{24.31\ \text{g Mg}} \times \frac{1\ \text{mol}\ H_2}{1\ \text{mol Mg}} \times \frac{2.02\ g\ H_2}{1\ \text{mol}\ H_2}[/tex]
= 3.3 g H₂
Thus from the above conclusion we can say that 3.3 g of hydrogen gas will be produced.
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Conclusion: why do you think it is important to record your data with all the decimals provided by the instruments even if they are zero? How does this help with data analysis?
H. If you had 64 amu of ch4, how many molecules would this be? i. If you had 64 g of ch4, how many moles would this be?
The number of molecules and number of moles of [tex]CH_{4}[/tex] is 4 moles and 24.088×[tex]10^{23}[/tex] molecules.
Calculation,
Atomic mass of carbon is 12 u and H is 1 u
So, molar mass of [tex]CH_{4}[/tex] = 12 + 1×4 = 16 u = 16 g/mole
Number of moles = given mass / molar mass = 64 g/ 16 g/mol = 4 moles
1 moles of substance contains 6 .022 ×[tex]10^{23}[/tex] molecules.
So, number of molecules in 3 moles of methane = 4×6.022 ×[tex]10^{23}[/tex]
number of molecules in 3 moles of methane = 24.088×[tex]10^{23}[/tex] molecules.
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Describe the scale used to measure the basicity of a substance. Demonstrate how you could differentiate a weak base from a strong one. (10
points)
Answer:
The pH scale is used to measure the acidity or basicity of a substance.
Explanation:
pH stands for potential hydrogen. It ranges from 0 to 14, 7 being neutral. The pH of water is 7 i.e. it is neither acidic nor basic. 0 to 7 shows acidic behavior while 7 to 14 shows basic behavior.
Experiment:
Dip the pH paper in the liquid and wait for ten seconds. The pH strip starts to discolor.
For a strong acid the strip will turn red.
For a weak acid the strip will become pale red.
To find the correct pH value we can compare it with the indicator scale present on the pH scale box.
The scale used to measure the basicity of a substance is called the pH scale.
What is the pH scale?The pH scale is a logarithmic scale that ranges from 0 to 14 and is used to determine the acidity or basicity of a solution. A pH value of 7 is considered neutral, values below 7 are acidic, and values above 7 are basic.
To differentiate a weak base from a strong one, you can perform the following experiments:
pH Measurement: Measure the pH of the solution containing the base using a pH meter or pH indicator paper. A strong base will have a higher pH value, typically around 12-14, indicating a highly basic solution. A weak base will have a lower pH value, closer to 7, indicating a less basic or slightly basic solution.
Conductivity Test: Dissolve a small amount of the base in water and measure its electrical conductivity using a conductivity meter. Strong bases are good electrolytes and will conduct electricity well, resulting in a high conductivity. Weak bases, on the other hand, are poor electrolytes and will exhibit lower conductivity.
Reaction with Acids: Add a few drops of a strong acid, such as hydrochloric acid (HCl), to a solution containing the base. Strong bases will rapidly and completely neutralize the acid, resulting in a significant increase in pH. Weak bases, however, will only partially neutralize the acid, leading to a smaller increase in pH.
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A welding torch requires 4122.8l of ethylene gas at 0.64 atm what will be the pressure of the gas if ethylene is supplied by a 51.6 l tank
The pressure of the gas if ethylene is supplied by a 51.6 l tank is 51.1355atm
The final pressure of the gas can be calculated by using the formula given by Boyle's law,
P1V1 = P2V2
What is Boyle's law?
Boyle's law relates the compression and expansion of gas at a constant temperature. It states that, At constant temperature the pressure exerted by a gas is inversely proportional to the volume of the given mass of gas.
P1V1 = P2V2
where,
P1 is the initial pressure
V1 is the initial volume
P2 is the final pressure and
V2 is the final volume.
Given data:Initial volume V1= 4122.8L
Initial pressure P1= 0.64atm
Final volume V2= 51.6L
Final pressure P2= ?
0.64*4122.8= P2*51.6
P2= 2638.592/51.6
P2= 51.1355atm
Hence the final pressure of the gas is 51.1355atm
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The procedure calls for 2.0 ml of concentrated nitric acid. how many moles is this?
Answer:
ρHNO₃= 1.51 g/cm3
ρ = m/V
m = ρ x V
m = (1.51 g/cm3)(2 cm3)= 3.02 g de HNO₃
n = m/PM = 3.02 g/63.01 g/mol = 0.0479 mol de HNO₃
Explanation:
2 mL of concentrated nitric acid equals 0.0479 mol
Consider the following intermediate chemical equations.
CH₂(g) → C(s) + 2H₂(g)
ΔΗ, = 74.6KJ
CCl4(g) →C(s) + 2Cl₂(g)
AH₂ = 95.7 kJ
H₂(g) + Cl₂(g) → 2HCl(g)
AH₂=-92.3 KJ
What is the enthalpy of the overall chemical reaction CH4(g)+4Cl₂(g) → CCl4(g) + 4HCI(g)?
O-205.7 kJ
O-113.4 kJ
O-14.3 kJ
O 78.0 kJ
Based on the calculations, the enthalpy of the overall chemical reaction is equal to: C. -14.3 kJ.
What is a chemical reaction?A chemical reaction can be defined as a chemical process that involves the continuous transformation (rearrangement) of the ionic, atomic or molecular structure of a chemical element by breaking down and forming chemical bonds, in order to produce a new chemical compound while new bonds are formed.
What is a chemical equation?A chemical equation can be defined as a group of chemical symbols that is typically used in chemistry to represent the chemical reaction between two (2) or more chemical elements.
Mathematically, an expression for enthalpy of the overall chemical reaction is given by:
ΔHrxn = (n × ΔH₃) + (-n × ΔH₁) + (n × ΔH₂)
Where:
n represents the number of moles.
Substituting the given points into the formula, we have;
ΔHrxn = (2 × ΔH₃) + (-1 × ΔH₁) + (1 × ΔH₂)
ΔHrxn = (2 × (-92.3)) + (-1 × (-74.6)) + (1 × (-95.7))
ΔHrxn = -184.6 + 74.6 + 95.7
ΔHrxn = -14.3 kJ.
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Name the following ether: OCH2CH3
A. ethyl benzyl ether
B. methyl phenyl ether
C. ethyl phenyl ether
D. ethyl propyl ether
The name of the given ether is ethyl benzyl ether .
What are ethers?Ethers are organic compounds formed when nan oxygen atom is bonded to two alkyl or aryl groups.
Ethers usually have relatively high boiling points as a result of the central oxygen atom. An example of an ether, is ethyl propyl ether
The name of the given ether is ethyl benzyl ether as it has a benzyl and ethyl group attached to the oxygen atom.
In conclusion, ethers are characterized by an oxygen atom bonded to two alkyl or aryl groups.
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In the redox reaction below, which is the reducing agent?
MnO2(s) + 4H+(aq) + 2Cl–(aq) Right arrow. Mn2+(aq) + 2H2O(l) + Cl2(g)
CI–
CI2
Mn2+
MnO2
In the following redox reaction, the reducing agent is MnO2 (option D). Details about reducing agent can be found below.
What is a reducing agent?A reducing agent in a redox reaction is any substance that reduces, or donates electrons to another, hence, it becomes oxidized.
According to this question, a redox reaction is given as follows: MnO2(s) + 4H+(aq) + 2Cl–(aq) = Mn2+(aq) + 2H2O(l) + Cl2(g)
As shown in the equation, MnO2 is oxidized into Mn2+, therefore, it is the reducing agent.
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6) What is the pH of a solution with [H3O+] = 1 × 10-9 M?
A) 1.0 × 10-5
B) -9.0
C) 5.0
D) -5.0
E) 9.0
Answer:
E) 9.0
Explanation:
pH = -log [1×10^-9] = 9
A generic element, Q, has two isotopes, 195Q and 190Q, and an average atomic mass of 191.86 amu. The natural abundances of the two isotopes are 38% 195Q and 62% 190Q. The isotopic mass of 195Q is 194.96 amu. What is the isotopic mass of 190Q
A generic element, Q, has two isotopes, 195Q and 190Q, and an average atomic mass of 191.86 amu. The natural abundances of the two isotopes are 38% 195Q and 62% 190Q. The isotopic mass of 195Q is 194.96 amu. the isotopic mass of 190Q is 186.80.
What do you mean by Isotopes?Isotopes are two or more atom types that share the same atomic number (number of protons in their nuclei), location in the periodic table, and chemical element but have distinct nucleon numbers (mass numbers) as a result of having a different number of neutrons in their nuclei. Although the chemical properties of each isotope of a given element are nearly identical, they differ in their atomic weights and physical characteristics.
191.86 =(62% x 194.96 + 38% x X )
where, X is the mass of other Isotope.
X = (191.86 - 120.8752)/0 .38
= 186.80
Parent and Daughter IsotopesThe initial radioisotope and the isotope that results from radioactive decay may not be the same. The atoms created by the reaction are known as daughter isotopes, whereas the original isotope is known as the parent isotope. It's possible to get different kinds of daughter isotopes.
As an illustration, the uranium atom is the parent isotope and the thorium atom is the daughter isotope when U-238 decays into Th-234.
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Which state of matter is being described below?
It cannot be squashed easily, spreads out slowly, is of medium density & flows to
fill up space
A. Plasma
B. Liquid
C. Gas
D. Solid
Answer:
C. Gas
Explanation:
I think this is the right answer because it fits the description
You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. Write the conversion factor (including units) inherent in each mass percent composition. (a) Water is 11.19% hydrogen by mass. (b) Fructose, also known as fruit sugar, is
You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚ 100 g H₂O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol
What is the Mass Percent ?The percent by mass of each element present in a compound is called Mass Percent.
(a) Water is 11.19% hydrogen by mass.
Here it is given mass of hydrogen is 11.19 %. That means 11.19 % of solute should be added in 100 g H₂O.
(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.
Here it is given mass of oxygen is 53.29 %. That means in 53.29% of solute should be added in 100 g fructose.
(c) Octane, a component of gasoline, is 84.12% carbon by mass.
Here it is given mass of carbon is 84.12 %. That means in 84.29% of solute should be added in 100 g Octane.
(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.
Here it is given mass of carbon is 52.14 %. That means in 52.14% of solute should be added in 100 g Ethanol.
Thus from the above conclusion we can say that You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. The conversion factor in each mass percent composition are (a) 11.19 g H‚100 g H2O (b) 53.29 g O‚100 g fructose (c) 84.12 g C‚100 g octane (d) 52.14 g C‚100 g ethanol
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: You can use mass percent composition as a conversion factor between grams of a constituent element and grams of the compound. Write the conversion factor (including units) inherent in each mass percent composition.
(a) Water is 11.19% hydrogen by mass.
(b) Fructose, also known as fruit sugar, is 53.29% oxygen by mass.
(c) Octane, a component of gasoline, is 84.12% carbon by mass.
(d) Ethanol, the alcohol in alcoholic beverages, is 52.14% carbon by mass.
What are the correct half reactions for the following reaction:
Zn + 2 HCI -> H₂ +zncl2
Answer:
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g)
Explanation:
The equation Zn + 2 HCI -> H₂ +zncl2 on reduction and oxidation, it results as below;
2H+ + 2e- => H2 ; reductionZn => Zn²+ + 2e- ; oxidationThe equations above are half cell.
On combination of the above half cell reaction equations gives;
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).
Therefore, the half reaction equation for Zn + 2 HCI -> H₂ +zncl2 is given by;
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).
For what mechanistic reason does g1 of lactase first act as a brønsted acid during catalysis?.
Glucose becomes a better leaving group.
In a manner similar to how protonation of an alcohol makes it easier to substitute a -OH group, glucose becomes a better leaving group when the oxygen atom is protonated.
What is Bronsted acid-base theory?A substance that releases or donates hydrogen ions during a chemical reaction is referred to as a Bronsted-Lowry acid. A Bronsted-Lowry base, on the other hand, takes hydrogen ions. Another way to look at it is that a base accepts protons whereas a Bronsted-Lowry acid donates them. Amphoteric species are those that, depending on the circumstance, can either give or take protons.
Every Bronsted-Lowry acid gives a species that is its conjugate base a proton in exchange for the species' support. Each base in the Bronsted-Lowry system similarly accepts a proton from its conjugate acid.
I understand the question you are looking for is this:
For what mechanistic reason does G1 of lactase first act as a Bronsted acid during catalysis?
A) G1 becomes a better nucleophile
B) G2 becomes a better nucleophile
C) Glucose becomes a better leaving group.
D) Galactose becomes a better leaving group.
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7. A spontaneous reaction occurs when the sign of free energy IS
O A. positive.
O B. zero,
• C. negative.
O D. neutral.
Answer:
positive
Explanation:
5.18 L of nitrogen gas at 76.0°C are cooled to 6.0°C at constant pressure. Calculate the new volume of
the gas.
(write your answer in this space with sig digs and units - submit your work in the work space provided)
Answer:
0.409 L
Explanation:
Because you are dealing with volume and temperature, you need to use the Charles' Law equation:
V₁ / T₁ = V₂ / T₂
In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature.
V₁ = 5.18 L V₂ = ? L
T₁ = 76.0 °C T₂ = 6.0 °C
V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation
5.18 L / 76.0 °C = V₂ / 6.0 °C <----- Insert values
0.06815789 = V₂ / 6.0 °C <----- Simplify left side
0.409 L = V₂ <----- Multiply both sides by 6.0
What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?
Based on the mole ratio, the mass of oxygen reacting is 45.8 g.
What mass of oxygen reacts during the reaction?The incomplete combustion of propane with oxygen produces carbon (ii) oxide and water.
The mole ratio of propane to oxygen according to the equation of the reaction is 2 : 7.
Molar mass of propane = 44 g/mol
Molar mass of oxygen = 32 g/mol
moles in 18.0 g = 18/44 mole
Mass of oxygen reacting = 18/44 * 7/2 * 32 = 45.8
In conclusion, incomplete combustion of propane produces carbon (ii) oxide.
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A mole is a name for a specific number of things. What is the value of a mole? write the number using scientific notation. By what other name is it known? (2 points)
The value of a mole is 6.022 ×[tex]10^{23}[/tex]. The other name of mole is Avogadro's number.
The mole is define as 6.022 ×[tex]10^{23}[/tex] of the chemical unit like atoms , molecules, ions or others.It is very convenient unit because of huge numbers o f atoms, molecules or others. This is very important unit used by chemist.
One mole = atomic Mass of atoms / molecular mass of molecule
Example: one mole of sodium = 23 g = atomic mass
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1. You have learned that alkyl iodides may be prepared by SN2 replacement of other leaving groups, or by treatment of alcohols or ethers with co centrated hydriodic acid (HI). A milder method for preparation of alkyl iodides from alcohols is shown below:
Imidazole's cyclic structure is aromatic and the lone pair present at the N₁ atom available for donation. hence, according to question N₁ is the most basic atom in the structure.
What is resonating structure?Two π bonds (between C₂-C₃ and N₁-C₅), as well as one lone pair on N₄, can interact with one another to generate a delocalized π system in the cyclic structure.This delocalization is intriguing since it has the same number of delocalized electrons as benzene—six.As a result, imidazole, like benzene, has a closed, delocalized ring with six π electrons. So, like benzene, it is regarded as an aromatic chemical with resonance stability.N₄ is neutral since it cannot be donated because it needs to use its lone pair to be aromatic.On the other hand, N₁ already forms a π connection, which helps the system become delocalized.N₁ is sp² hybridized and has a trigonal planar basic form. Its lone pair cannot communicate with the delocalized π system since it is pointed away from the cyclic structure.Know more about Resonating structure
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What is the smallest whole-number coefficient for h₂s when the equation h₂s mno₄⁻ → mn²⁺ so₄²⁻ is balanced in acidic solution?
The lowest smallest whole-number coefficient for H₂S is 5. Option C
What is the smallest whole-number coefficient for H₂S?Now we know that a redox reaction is one in which there is a loss and gain of electrons One specie is oxidized (looses electrons) while another specie is reduced (gains electrons). The electrons must be transferred leading to an increase in oxidation number of one specie and a decrease in the oxidation number of another.
Now the reduction half equation is;
MnO4^-(aq) + 8H^+(aq) + 5e^- ----> Mn^2+(aq) + 4H2O (l)
The oxidation half equation is;
H2S(aq) ----> S^2-(aq) + 2H^+(aq) + 2e^-
Multiplying the reduction half equation by 2 and the oxidation half equation is 5
2MnO4^-(aq) + 16H^+(aq) + 10e^- ----> 2Mn^2+(aq) + 8H2O (l)
And;
5H2S(aq) ----> 5S^2-(aq) + 10H^+(aq) + 10e^-
The overall balanced reaction equation is;
2MnO4^-(aq) + 6H^+(aq) + 5H2S(aq) ----> 2Mn^2+(aq) + 8H2O (l) + 5S^2-(aq)
Thus the lowest smallest whole-number coefficient for H₂S is 5.
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If 10.0 moles of sulfur dioxide react with excess chlorine gas, what is the theoretical yield (in grams) of CI2O produced?
Answer:
869 g Cl₂O
Explanation:
To find the theoretical yield of Cl₂O, you need to (1) convert moles SO₂ to moles Cl₂O (via mole-to-mole ratio from reaction coefficients) and then (2) convert moles Cl₂O to grams Cl₂O (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs of the given amount (10.0 moles).
1 SO₂ (g) + 2 Cl₂ (g) ----> 1 SOCl₂ (g) + 1 Cl₂O (g)
Molar Mass (Cl₂O): 2(35.453 g/mol) + 15.998 g/mol
Molar Mass (Cl₂O): 86.904 g/mol
10.0 moles SO₂ 1 mole Cl₂O 86.904 g
------------------------ x ---------------------- x ------------------ = 869 g Cl₂O
1 mole SO₂ 1 mole
In a mining community, groups of dead fish appear in a local river every few weeks. These fish kills coincide with incidents of mining waste dumped into the river. Which of the following components is an abiotic factor causing these fish kills?
Human activities
Biodiversity in the river
Water pollution
Overfishing
In a mining community, water pollution kills the fish in local river.
How does mining affect the rivers?Large amounts of water are frequently used in mining, which has the potential to contaminate local groundwater, rivers, streams, and other water sources. A community's ability to grow its own food may be hampered by mining since it consumes grazing or agricultural land and pollutes the soil and the environment.
Metals that leach from the rock also contaminate nearby water sources when they do so. chemical processing pollution: When minerals are extracted from their ores using cyanide or sulfuric acid and water, the runoff pollutes the rivers in the area.
Through erosion and sedimentation, dewatering of wetlands, diverting and channelizing streams, and poisoning surface water and aquifers with harmful chemicals, surface mining can have an impact on fish and aquatic resources.
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Answer:
a
Explanation:
Zinc Sulfide reacts with oxygen according to the reaction:
2ZnS (s) + 3 O2(g) 2 ZnO (s) +2 SO2 (g)
A reaction mixture contains 4.2 moles of zinc sulfide and 6.8 moles of oxygen. Once the reaction occurred as a completely as possible, what amount in moles is left of the excess reactant?
The amount in moles of the excess reactant left is 0.5 mole
Balanced equation2ZnS (s) + 3O₂(g) --> 2ZnO (s) + 2SO₂(g)
From the balanced equation,
2 moles of ZnS reacted with 3 moles of O₂
How to determine the excess reactantFrom the balanced equation,
2 moles of ZnS reacted with 3 moles of O₂
Therefore,
4.2 moles of ZnS will react with =(4.2 × 3) / 2 = 6.3 moles of O₂
From the calculations made above, we can see that only 6.3 moles of O₂ out of 6.8 moles given, is required to react completely with 4.2 moles of ZnS.
Thus, ZnS is the limiting reactant and O₂ is the excess reactant.
How to determine the mole of the excess reactant remainingThe excess reactant is O₂. Thus the mole remaining after the reaction can be obtained as illustrated below:
Mole of O₂ given = 6.8 molesMole of O₂ that reacted = 6.3 molesMole of O₂ remaining =?Mole of O₂ remaining = (Mole of O₂ given) - (Mole of O₂ that reacted)
Mole of O₂ remaining = 6.8 - 6.3
Mole of O₂ remaining = 0.5 mole
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What mass of oxygen reacts during the incomplete combustion of 18.0 g of propane?
Answer:
66 grams of carbon dioxide
C3H8+5O2=3CO2+4H2O
Which molecules are types of lipids?
Answer: The answer is fatty acids and triglycerides
Explanation:
The combining power of an element is called ?
A. coefficient
B.subscript
C.periodicity
D.valence number
Answer:
D
Explanation:
Valency is the combining power of an element
Liquids A and B form an ideal solution. The vapor pressure of pure A is 0.700 atm at the normal boiling point of a solution prepared from 0.250 mole of B and 0.650 mole of A. What is the vapor pressure of pure B at this temperature
The vapor pressure of pure B is 1.77atm
Given:-
Vapor pressure of Pure A = 0.700atm
Mole of A = 0.650mole
Mole of B = 0.250mole
Dalton's law of partial pressures states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressures of all of the constituent gases.
So, Ptotal = [tex]P_A + P_B[/tex]
According to Raoult's law, a solvent's partial vapor pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapor pressure times the mole fraction present in the solution.
So, Ptotal = [tex]X_AP_A + X_BP_B[/tex]
Ptotal = 1atm
1atm = (0.650/0.650+0.250 X 0.700atm) + 0.250/0.650+0.250 X [tex]P_B[/tex]
1atm = 0.722 X 0.700atm + 0.278 X [tex]P_B[/tex]
1atm = 0.506atm + 0.278 X [tex]P_B[/tex]
1atm - 0.506atm = 0.278 X [tex]P_B[/tex]
0.494atm = 0.278 X [tex]P_B[/tex]
[tex]P_B[/tex] = 0.494atm / 0.278
[tex]P_B[/tex] = 1.77atm
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What is the name of the amide bond between amino acids?
a. polyamide bond
b. polyamine bond
c. polyamino acids bond
d. protein bond
e. peptide bond
The name of the amide bond between amino acids will be peptide bond.
Peptide bonds are amide-type covalent bonds that form bonds that connect two adjacent alpha-amino acids throughout peptide or protein chains, starting at C1 of one as well as [tex]N_{2}[/tex] of another.
The substances are known as amino acids, or the "building blocks of proteins," and play a variety of vital functions in the human body. Humans require them for essential functions like producing hormones, neurotransmitters, even proteins. In meals high in protein like meat, fish, as well as soybeans, amino acids could be concentrated.
Therefore, the name of the amide bond between amino acids will be peptide bond.
Hence, the correct answer will be option (e)
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You have two buffered solutions. Buffered solution 1 consists of 5.0 M HOAc and 5.0 M NaOAc; buffered solution 2 is made of 0.050 M HOAc and 0.050 M NaOAc. How do the pHs of the buffered solutions compare
The pH of buffered solution is:
The two buffered solutions have 'equal' pH values.
Comparison between two buffer solutions:
To compare the pH of two different buffer solutions with different concentrations, Henderson-Hasselbalch equation is used.
pH = pKa + log [tex]\frac{Salt}{Acid}[/tex]
pKa of HOAc = 4.76
In solution 1:
Concentration of salt= 5 M
Concentration of acid= 5 M
Putting the values in the equation,
pH = 4.76 + log [tex]\frac{5}{5}[/tex]
pH = 4.76 + log1
pH = 4.76
In solution 2:
Concentration of salt= 0.050 M
Concentration of acid= 0.050 M
Putting the values in the equation,
pH = 4.76 + log[tex]\frac{0.050}{0.050}[/tex]
pH = 4.76 + log1
pH = 4.76
As the ratio [tex]log\frac{salt}{acid}[/tex] is the same for the different solutions.
Therefore, the pH of the solution remains the same in both the buffer solutions even if the two solutions have different concentrations.
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