Determine the percent yield for the reaction between 46.5 g of
ZnS and 13.3 g of oxygen if 18.l4 g of ZnO is recovered along with an unknown quantity of sulfur
dioxide.
please show work thank you

Answers

Answer 1
Found an answer sheet :)
Determine The Percent Yield For The Reaction Between 46.5 G Of ZnS And 13.3 G Of Oxygen If 18.l4 G Of
Answer 2

The percentage yield of the reaction has been 46.74%.

Percentage yield can be given as the ratio of the actual yield to the theoretical yield.

For the theoretical yield, the balanced equation will be:

[tex]\rm 2\;ZnS\;+\;3\;O_2\;\rightarrow\;2\;ZnO\;+\;2\;SO_2[/tex]

Thus, 2 moles of ZnS will give 2 moles of ZnO.

The moles of 46.5 g ZnS:

Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]

ZnS = [tex]\rm \dfrac{46.5}{97.474}[/tex]

ZnS = 0.477 mol

The moles of 13.3 grams Oxygen:

Oxygen = [tex]\rm \dfrac{13.3}{32}[/tex]

Oxygen = 0.415 mol.

The moles of 18.14 grams ZnO:

ZnO = [tex]\rm \dfrac{18.14}{81.38}[/tex]

ZnO = 0.222 mol

According to the balanced chemical equation,

2 moles ZnO = 2 moles ZnS

0.222 mol ZnO = 0.222 mol ZnS

2 moles ZnO = 3 moles Oxygen

0.222 mol ZnO = 0.334 mol of Oxygen

Since, both the reactants are in enough concentration,

The theoretical yield can be calculated with any of the reactants. The theoretical yield of ZnO from 46.5 grams of ZnS can be given as:

1 mole ZnS = 1 mol ZnO

0.477 mol of ZnS = 0.477 mol of ZnO.

The mass of 0.477 mol of ZnO:

Mass = moles [tex]\times[/tex] molecular weight

Mass of ZnO = 0.477 [tex]\times[/tex] 81.38

Mass of ZnO = 38.818 grams.

The theoretical yield of ZnO = 38.818 g.

The actual yield of ZnO = 18.14 g.

Percentage yield = [tex]\rm \dfrac{18.14}{38.81}\;\times\;100[/tex]

Percentage yield = 46.74 %

The percentage yield of the reaction has been 46.74%.

For more information about the percentage yield, refer to the link:

https://brainly.com/question/11715808


Related Questions

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Answer:

8.

Explanation:

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16 - 8 = 8

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Answers

Answer:

The answer to your question is A.

D. Protective coloration.  Protective coloration, also known as "crypsis," is a defense mechanism used by animals to avoid detection by predators or prey.

An illustration of protective coloration, which is a sort of camouflage, is how white arctic hares blend in with the white snow around them. Animals use protective coloration, commonly referred to as "crypsis," as a defensive strategy to evade being seen by predators or prey.

In this instance, the white arctic hares' fur is the same shade as that of their snowy environment. Their chances of survival are increased by this merging, which enables them to remain unnoticed and effectively hidden from predators like polar foxes or birds of prey. They have a better chance of escaping or avoiding detection when they are well-camouflaged, making it difficult for predators to see them against the white background.

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Answer:

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In a chemical reaction
1 point
The atoms of the reactants unbond, rearrange and then rebond to form the products
Some atoms disappear while others multiply to form the products
The atoms of the reactants always stay together to form the products
New atoms are formed which combine to make the products

Answers

Answer:

A) The atoms of the reactants unbond, rearrange and then rebond to form the products

Explanation:

Using method of elimination:

A) The atoms of the reactants unbond, rearrange and then rebond to form the products

This is the correct option. Chemical reactions involves breaking and forming of new bonds.

B) Some atoms disappear while others multiply to form the products

This option is incorrect. Atoms do not disappear

C) The atoms of the reactants always stay together to form the products

This option is incorrect. The bonds between the atoms in the reactants must first be broken before products can be formed.

D) New atoms are formed which combine to make the products

This option is incorrect. Atoms do not just form out of nowhere.

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Answers

Answer:

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Explanation:

Answer:

No

Explanation:

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Answers

Answer:

Area of rectangular poster = [tex]\frac{3}{16}[/tex] yard²

Explanation:

P.S - The exact question is -

Given - A rectangular poster is [tex]\frac{1}{4}[/tex] yard wide and [tex]\frac{3}{4}[/tex] yard tall.

To find - What is its area ?

Proof -

We know that ,

The area of rectangle = Length × Breadth

Here,

Given that,

Length of rectangle = [tex]\frac{3}{4}[/tex] yard

Breadth of rectangle = [tex]\frac{1}{4}[/tex] yard

∴ we get

Area of rectangular poster = [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{4}[/tex]  yard²

                                          = [tex]\frac{3}{16}[/tex] yard²

⇒Area of rectangular poster = [tex]\frac{3}{16}[/tex] yard²

In a chemical reaction*
1 point
The atoms of the reactants unbond, rearrange, and then rebond to form the products
Some atoms disappear while others multiply to form the products
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New atoms are formed which combine to make the products

Answers

Answer:

1st one is correct

The atom of the reactants unbound , rearrange, and then rebond to form the product

hope it helps

In a chemical reaction, the atoms of the reactants unbond, rearrange, and then rebond to form the products. Therefore, option A is correct.

What is chemical reaction ?

Chemical reaction, the transformation of one or more chemicals the reactants into one or more distinct compounds, the products. Chemical elements or chemical compounds make up substances.

Combustion reaction, decomposition reaction, neutralization reaction, redox reaction, precipitation or double-displacement reaction, and synthesis reaction are some of the numerous types of reactions.

In a chemical reaction, bonds between molecules of the reactant are broken and new bonds between molecules of the product are established to create a new substance.

A chemical equation is nothing more than a mathematical statement that represents how reactants form products.

Thus, option A is correct.

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https://brainly.com/question/3461108

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M
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=
M
b
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Determine the percent yield for the reaction between 98.7 g of
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Answers

Convert 98.7 g Sb2S3 to mols.
Convert mols Sb2S3 to mols Sb4O6 using the coefficients in the balanced equation.
Convert mols Sb4O6 to grams Sb4O6. (This is the theoretical yield.)
Convert grams Sb4O6 to percent Sb4O6.
%Sb4O6 = [72.4/theoretical yield]*100


So basically your answer is 85.5%

The percent yield of the reaction would be 85.64%

Percent Yield

From the balanced equation of the reaction:

[tex]9 O_2 + 2 Sb_2S_3 ---> 6 SO_2 + Sb_4O_6[/tex]

Mole ratio of Sb2S3 to Sb4O6 is 2:1

Mole of 98.7g Sb2S3 = 98.7/339.7

                                   = 0.29 moles

Equivalent mole of Sb4O6 = 0.29/2

                                            = 0.145 moles

Mass of 0.145 Sb4O6 = 0.145 x 583

                                     = 84.535 g

Percent yield = yield/theoretical yield x 100

                       = 72.4/84.535 x 100

                        = 85.64%

More on percent yield can be found here: https://brainly.com/question/2506978?referrer=searchResults

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