draw the structure of the product of the enamine formed between cyclohexanone and dimethylamine.

Answer:

Molarity = 1.28

Explanation:

[tex]m= n/v[/tex]

M = molar concentration

n = moles of solute

v = liters of solution

Molarity = moles of solute / litres of solution.

]

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The theoretical yield of H₂S is 13.5 g.

The percent yield is 75.5 %.

The equation of the reaction is given below:

Moles of FeS reacting = mass/molar mass

Molar mass of FeS = 88 g/mol

Moles of FeS reacting = 35/88 = 0.398 moles

Moles of H₂S produced = 0.398 moles

Molar mass of H₂S = 34 g/mol

Mass of H₂S produced = 0.398 * 34 = 13.5 g

Theoretical yield of H₂S is 13.5 g.

Actual yield of H₂S = 10.2 g

Percent yield = 10.2/13.5 * 100%

Percent yield = 75.5 %

In conclusion, the actual yield is less than the theoretical yield.

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The functional group would be the aromatic ring.

Functional groups in organic compounds are a group of atoms that gives the compound a distinctive chemical property or properties.

The major functional groups include Hydroxyl, sulfhydryl, carbonyl, carboxyl, amino, and phosphate groups. Aromatic rings are also considered a functional group.

Functional groups are made up of atoms of elements that are covalently linked to each other. The functional group as a whole is also covalently linked to the rest of the molecule.

Functional groups influence molecules to behave in a particular way when it comes to chemical reactions.

Looking at the image (see the attached), none of the side chains qualify as functional groups except the mother chain which is an aromatic ring.

Thus, the only functional group remains the aromatic ring.

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The enthalpy change of the reaction:  A + 2B → C is determined as follows: ΔH = ΔH₁ +  ΔH₂; option C

Enthalpy change refers to the change in heat content as reactant molecules combine to form products.

The enthalpy change of a multistep reaction is calculated from by summing the enthalpy changes of the intermediate steps that leads to the overall reaction.

Thus, the enthalpy change of the reaction:  A + 2B → C is determined as follows:

ΔH = ΔH₁ +  ΔH₂

In conclusion, the enthalpy change of the reaction is determined from the summation of the enthalpy changes that occur in the intermediate steps.

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Answer:

a. 54 calories burnt

b. multiplied by 9

Answer:

298-273 = 25°C is correct answer!

Answer:

121 g/mol

Explanation:

To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 1.00 atm                         R = 0.0821 L*atm/mol*K

V = 1.00 L                             T = 25.0. °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = (24.478115)n

0.0409 = n

Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.

0.0409 moles           ? grams           4.95 grams
----------------------  x  ------------------  =   ------------------
        1 L                       1 mole                     1 L

? g/mol = 121 g/mol

**note: I am not 100% confident on this answer

The mass of 36-6-18 fertilizer fertilizer required is 536 lb.

The mass of nitrogen fertilizer required for the acre of land is determined as follows:

Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.

Mass of Nitrogen required per acre = 193 lbs

Mass of fertilizer required = 193 * 100/36

Mass of fertilizer required  = 536 lb of fertilizer.

In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.

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Taking into account the definition of dilution, the initial volume needed to prepare each of the diluted solution is 145.59 mL.

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

17% (m/v)× Vi= 7.5% (m/v)× 330 mL

Solving:

Vi= (7.5% (m/v)× 330 mL)÷ 17% (m/v)

Vi= 145.59 mL

In summary, the initial volume needed to prepare each of the diluted solution is 145.59 mL.

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[tex]K_{sp}[/tex] of the compound is found to be  5.04 ×[tex]10^{-10}[/tex].

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = [tex][A^{+} ]^{a}[/tex] [tex][B^{-} ]^{b}[/tex]

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × [tex]10^{-2}[/tex] g/L

molar mass = 288 g/ mol

∴ s= 3.60 × [tex]10^{-2}[/tex] g/L ÷ 288 g/ mol = 1.25 ×[tex]10^{-4}[/tex] mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

[tex]K_{sp}[/tex] =[ [tex]M^{+3}[/tex]] [ [tex]X^{-1}[/tex][tex]]^{3}[/tex] = solubility product

∴ [tex]K_{sp}[/tex] =[tex][s]^{} [3s]^{3}[/tex]

∴ [tex]K_{sp}[/tex] = 3 [tex]s^{4}[/tex]

∴ [tex]K_{sp}[/tex] = 3 × (3.60 × [tex]10^{-2}[/tex] [tex])^{4}[/tex]

∴ [tex]K_{sp}[/tex] = 503.8848 ×[tex]10^{-8}[/tex]  = 5.04 ×[tex]10^{-10}[/tex]

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The mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.

The number of moles of a substance can be calculated stoichiometrically as follows:

According to this question, sodium azide decomposes to produce sodium and nitrogen gas as follows:

2NaN3 → 2Na + 3N2

2 moles of sodium azide produces 3 moles of N2

This means that 0.016 moles of N2 will be produced by 0.016 × 2/3 = 0.011moles of NaN3.

Therefore, the mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.

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When 67 g of water is heated from its melting point to its boiling point, it takes 28006 J of heat.

The following formula is frequently used to describe the connection between these four values.

q = msΔT

where, q = the amount of heat emitted or absorbed by the thing

m =  the object's mass = 67 gm

s =  a specific heat capacity of the substance = 4.18  J/gC

ΔT = the resultant change in the object's temperature = 373.15 -273.15K= 100 k

q = 67 * 4.18 * 100 J

⇒q = 28006 J

Therefore it is concluded that 67 g of water takes 28006 J of heat from its melting point to reach its boiling point.

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Answer:

2.30 moles MgCl₂

Explanation:

First, you need to balance the chemical equation. An equation is balanced when there is an equal amount of each element on both sides of the reaction. These values can be modified by adding coefficients in front of the molecules.

The unbalanced equation:

Mg (s) + HCl (aq) ---> MgCl₂ (s) + H₂ (g)

Reactants: 1 magnesium, 1 hydrogen, 1 chlorine

Products: 1 magnesium, 2 hydrogen, 2 chlorine

The balanced equation:

Mg (s) + 2 HCl (aq) ---> MgCl₂ (s) + H₂ (g)

Reactants: 1 magnesium, 2 hydrogen, 2 chlorine

Products: 1 magnesium, 2 hydrogen, 2 chlorine

Now, you need to use the mole-to-mole ratios from the balanced equation to convert between moles. Since we were not given a limiting reactant, the easiest way to find the actual moles of MgCl₂ is to start from both reactants.

4.59 moles Mg            1 mole MgCl₂
-------------------------  x  ------------------------  =  4.59 moles MgCl₂
                                       1 mole Mg

4.59 moles HCl           1 mole MgCl₂
-------------------------  x  ------------------------  =  2.30 moles MgCl₂
                                     2 moles HCl

Since HCl produces the smaller amount of product, it must be the limiting reactant. In other words, HCl runs out before all of the Mg is completely used up. Therefore, the actual amount of MgCl₂ produced in 2.30 moles.

Answer:

4.62 atm

Explanation:

To find the missing pressure, you need to use the Combined Gas Law equation:

P₁V₁ / T₁ = P₂V₂ / T₂

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.

P₁ = 8.01 atm                      P₁ = ? atm

V₁ = 715 mL                        V₁ = 963 mL

T₁ = 67 °C                           T₁ = 52 °C

P₁V₁ / T₁ = P₂V₂ / T₂

(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C

85.47985 = P₂(963 mL) / 52 °C

4444.952 = P₂(936 mL)

4.62 atm = P₂

For each pair of molecules given in the table below, the correct relationships are identified as follows.

A molecule is a bonded collection of atoms that represents the smallest fundamental unit of a chemical compound that may participate in a chemical process.

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The sun sending out electromagnetic waves is best describes the source of radiation heat.

Radiation heat is the form of electromagnetic waves.

Radiation heat, commonly referred to as thermal radiation, is the electromagnetic radiation that defines how photons exchange heat. The technique of heat transfer known as radiant heat does not require a medium to be propagated in.

Two molecules colliding with each other produce kinetic energy, moving objects have kinetic energy. Radiation heat is thermal energy. Sun directly sends thermal radiation through electromagnetic waves.

Hence , The sun sends out electromagnetic waves directly is best describes the source of radiation heat.

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Answer:

28.0 grams CsF

Explanation:

To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol

Molar Mass (CsF): 151.908 g/mol

Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)

Molar Mass (CsXeF₇): 397.186 g/mol

1 CsF + XeF₆ -----> 1 CsXeF₇

73.1 g CsXeF₇             1 mole                 1 mole CsF              151.908 g
----------------------  x  --------------------  x  ------------------------  x  ------------------  =
                                  397.186 g           1 mole CsXeF₇             1 mole

=  27.958 g CsF

=  28.0 g CsF

The chemical equation for the reaction is [tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]

Chromium metal is higher in the reactivity series than cobalt. Thus, chromium will displace cobalt from solutions.

Therefore, the equation for the reaction between chromium metal and cobalt (II) chloride will be written as:

[tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]

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Chromium metal is immersed in an aqueous solution of cobalt(II) chloride. Express your answer as a chemical equation. Identify all of the phases in your answer. Enter no reaction if no reaction occurs.

A mathematical function known as an orbital is used to describe the wave-like behavior of an electron, an electron pair, or (less frequently) nucleons.

Atomic orbitals outline the potential locations of electrons within an atom. In molecules, molecular orbitals play the same function.

Each atomic orbital has three quantum numbers, n, l, and ml, attached to it. The wave function was used to calculate these numbers.

The square of the wave function 2 can be used to calculate the size and form of an orbital.

All atomic orbitals are centered on the atomic nucleus and have unique forms.

The s, p, and d orbitals—orbitals that correspond to the s, p, and d subshells—are the orbitals that are most frequently encountered in introductory quantum chemistry.

F orbitals can be found in the ground states of heavier atoms as well.

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Answer:

In chemistry, an orbital is related to also a wave function. An Orbital is a practical region or part that is around the nucleus in a molecule and maybe an atom. It can contain up to two electrons, electrons form themselves around the nucleus.

Explanation:

No Explanation

Answer:

2 the mass is greater than 10.0gram

Explanation:

2 the mass is greater than 10.0gram

Answer:

Bromine

Explanation:

To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol *K)

-----> T = temperature (K)

After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.

P = 1.98 atm                                            R = 0.08206 atm*L/mol *K

V = 752 mL / 1,000 = 0.752 L                T = 62 °C + 273.15 = 335.15 K

n = ? moles

PV = nRT

(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)

1.48896 = n(27.5024)

0.0541 = n

You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.

Molar Mass = mass / moles

Molar Mass = 4.32 g / 0.0541 moles

Molar Mass = 79.8 g/mol

This molar mass is closest to the molar mass of bromine (79.904 g/mol).

The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

Mass of solute = Mass percent of solute x  Mass of the solution

Here,

Mass percent of solute = 18.7 %

Mass of the solution = 27.2 kg

Now put the value in above formula we get

Mass of solute = Mass percent of solute x  Mass of the solution

                         = [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]

                         = [tex]\frac{508.64}{100}[/tex]

                         = 5.086

Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

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From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M

The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.

Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.

If that be the case, we are in order to write the expression;

[H3O+]  [OH-] = 1 * 10^-14

[H3O+] = 1 * 10^-14/ [OH-]

[H3O+] = 1 * 10^-14/ 1 x 10^ -8

[H3O+] = 1 * 10^-6 M

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Answer:

See below

Explanation:

Q = m c T      c = specific heat   T = temp change  Q = heat joules

32 = 4 c 40     c = .2 J/g-C

314 to 344 k is a change of 30 K  

Q = m c T

  = 4 * .2 * 30 = 24 Joules

Answer:

(a) 0.2 J/g°K

(b) 24 J

Explanation:

(a)

To find the specific heat capacity, you need to use the following equation:

Q = mcΔT

In this formula,

-----> Q = heat energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°K)

-----> ΔT = change in temperature (K)

You can plug the given values into the equations and simplify to find the missing value.

Q = 32 J                          c = ? J/g°K

m = 4.0 g                        ΔT = 40 K

Q = mcΔT                                              <----- Equation

32 J = (4.0 g) x c x (40 K)                     <----- Insert variables

32 J = (160) x c                                      <----- Multiply 4.0 and 40

0.2 = c                                                   <----- Divide both sides by 160

(b)

To find the energy of the same sample, you can use the same equation. This time, you know the specific heat capacity, have a different change in temperature, and are solving for energy (Q).

Q = ? J                           c = 0.2 J/g°K

m = 4.0 g                       ΔT = 344 K - 314 K = 30 K

Q = mcΔT                                         <----- Given equation

Q = (4.0 g)(0.2 J/g°K)(30 K)             <----- Insert values

Q = 24                                              <----- Multiply

The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

Mass of solute = Mass percent of solute x  Mass of the solution

Here,

Mass percent of solute = 18.7 %

Mass of the solution = 27.2 kg

Now put the value in above formula we get

Mass of solute = Mass percent of solute x  Mass of the solution

                         = [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]

                         = [tex]\frac{508.64}{100}[/tex]

                         = 5.086

Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.

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