FGH and PQR are vertical angles. If FGH is 29 what is the measure of PQR?

Answers

Answer 1
Answer:

< PGR = 61°

Step-by-step explanation:

[tex]< FG4\ and\ < PQR\ are\ vortical\ angles.[/tex]

    [tex]< FG4=29[/tex]°

    [tex]< PQR=90\ - < FG4[/tex]

                 [tex]=90\ -29[/tex]°

                 [tex]=61[/tex]°

I hope this helps you

:)


Related Questions

Which of the following is equivalent to : 3x + 6 + 2x + 2 + x
A. 5x + 8
B. 6x + 8
C. 14x

Answers

option b is correct, (b)6x+8

help ! 50 points Savanah is shopping for planters for her new plants. Which measurement should she use to determine how much soil each planter will hold?
A. Area
B. Depth
C. Perimeter
D. Volume

Answers

B is the answer you need to know how depth it is

Geometry question pic Below




Arc JK = ______°
M<1 = ______°

Answers

Answer:

Step-by-step explanation:

evaluate the expression when c=9 and d=4. 5c+d

Answers

Answer:

5(9)+4= 45+4.....= 49

Step-by-step explanation:

Evaluate each expression.
a. 1/2(5+13)-4.5
b.(5+11)-(24-15)•(3)
c.6²+3•7-9÷3​

Answers

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♫[/tex]

Let's solve ~

Expression 1

[tex]\qquad \sf  \dashrightarrow \: \frac{1}{2} (5 + 13) - 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \: \frac{1}{2} (18) - 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \: 9 - 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \:4.5[/tex]

Expression 2

[tex]\qquad \sf  \dashrightarrow \:(5 + 11) - (24 - 15) \times 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:16 - (9 \times 3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:16 - 27[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 11[/tex]

Expression 3

[tex]\qquad \sf  \dashrightarrow \: {6}^{2} + (3 \times 7) - (9 \div 3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:36 + 21 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:57 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:54[/tex]

HELP NO LINKS OR TROLLING

Answers

Answer:

20.28 cm²

Step-by-step explanation:

The rectangle on the bottom is 7 cm by 2 cm.

The semicircle has a diameter of 7 cm - 1 cm - 2 cm = 4 cm

diameter = 4 cm

radius = diameter/2 = 2 cm

total area = area of semicircle + area of rectangle

total area = (1/2)πr² + LW

total area = (1/2)(3.14)(2 cm)(2 cm) + 7 cm × 2 cm

total area = 20.28 cm²

Area of rectangle

2(7)14cm²

Area of semicircle

π(7-3/2)²/2(4/2)²π/24π/212.56cm²/26.28cm²

Total area

6.28+1420.28cm²

What is the value of x?

Answers

Answer:

30 degrees

Step-by-step explanation:

because if its 60 at the bottom and 30 on the left it only makes sense that it would be 30 on the right.

Also can you mark brainlyest you dont have to thoe

Find the value of x
.

12.5,−10,−7.5,x
; The mean is 11.5
.

Answers

Step-by-step explanation:

please mark me as brainlest

Answer:

x = 51

Step-by-step explanation:

If the mean = 11.5, then that means all numbers added together divided by four = 11.5. Let's write this algebraically:

[tex]\frac{12.5+(-10)+(-7.5)+x}{4}=11.5[/tex]

Now, let's solve for x:

[tex]12.5-10-7.5+x=11.5(4)[/tex]

[tex]-5+x=46[/tex]

[tex]x=51[/tex]

I hope this helps!

There are only blue sweets, green sweets and red sweets in a box.the ratio of the number of blue sweets to the number of green sweets is 2: 7the ratio of the number of green sweets to the number of red sweets is 3 : 1there are less than 140 sweets in the box.what is the greatest possible number of red sweets in the box? your final answer must include the words, 'red sweets'.

Answers

Answer:

According to question if we observe, number of red sweets are the least

It 's only 1%

Step-by-step explanation:

I’m not entirely sure with this question, anyone can please help?

Answers

Step-by-step explanation:

3x + 4 = 72 - x

3x - x = 72 - 4

2x = 68

x = 39

Researchers randomly surveyed people at two amusement parks, Funland and Thrillville, to find out how many times they visit the park per year. Following are the data from the two surveys.

Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2

Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8

How many more times per year, on average, do people visit Thrillville than Funland?

Answers

On average, people visit Thrillville 2 more times per year than Funland.

Averages

To determine how many more times per year, on average, do people visit Thrillville than Funland, the following calculation must be performed:

Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2 = 4545 / 15 = 3Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8 = 100100 / 20 = 55 - 3 = 2

Therefore, on average, people visit Thrillville 2 more times per year than Funland.

Learn more about averages in https://brainly.com/question/2426692

If PQRS is a square and TR = 17, find each missing value. Round to the nearest tenth.

Answers

[tex]\huge\mathfrak\pink{Answer}[/tex]The area of rhombus PQRS is 120 m.

Step-by-step explanation:

correct me if I'm wrong.

[tex]\huge\mathfrak\red{Hope it's help}[/tex]

Mark and Henry win some money and share it in the ratio 1:3. Mark gets £9. How much did Henry get?

Answers

Answer:

£27

Step-by-step explanation:

1:3 = M:H

Mark gets £9

1 = £9

3: £9 x 3 = £27

Answer: the answer is £27

Step-by-step explanation: it is related to ratio if mark gets 9 so 9 times 3 . Equals to 27 . You can make criss cross way . 1 won't make the answer different. Hope it helps

HELPPPPPPPPPPPPPPPPPPP

Answers

Answer:

i dont know use the internet

Step-by-step explanation:

this is the right way

The least common denominator of 7/12, 1/3, and 3/4 is

Answers

Answer:

12.

Step-by-step explanation:

3, 4, and 12 all divide into 12 .

-3.28+4.4-9.7

fdsafdsa

Answers

Answer: -8.58

Explanation

we add -3.28+-9.7

-(12.98 - 4.4) = -8.58

Please answer this question throughly and with the work you used to answer it and I’ll give brainliest!

Answers

With the given budget, the inequality that must be used is:

$5.5*s ≤ $350

Which inequality is the correct one?

We know that the budget is $500.

Then, we know that there is a fixed cost of $150, then the budget left is:

$500 - $150 = $350

With these $350 they pay the food for the students, which costs $5.50 per student.

So the number of students that can go must be such that:

s*$5.50 ≤ $350

There says that the cost in food for the s students must be smaller than or equal to the remaining $350.

So the correct option is the second one.

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PLEASE HELP ASAP
(answer as many as you can please)

a. write the first four terms of the series

b. does the series diverge or converge?

c. if the series has a sum, find the sum

Answers

Answer:

A) -4,-4/3,-4/9,-4/27

B) converge

C) no idea

Figure #3 (Round to the nearest tenth)
Volume =_____cm^3​

Answers

The volume of a cylinder is pi•r^2•h. In this case we are finding the volume of a half cylinder, so the answer will be divided by two.
The diameter is 4 so the radius is 2.
Pi • 2^2 • 15 = 188.496 / 2 = 94.248

Company X tried selling widgets at various prices to see how much profit they would make. The following table shows the widget selling price, x, and the total profit earned at that price, y. Write a quadratic regression equation for this set of data, rounding all coefficients to the nearest hundredth. Using this equation, find the profit, to the nearest dollar, for a selling price of 28.25 dollars

Answers

Answer:

y = -7.235451 x^2 + 402.5542 x - 2382.736

if p(x)=x2+2x-5 and g(x)=x-3, what is p(x) – gx)?

Answers

Answer:

x2+x-2

Step-by-step explanation:

i had this question before

An integer number is chosen randomly between 1 and 1000. What is the probability that the number picked is divisible by 3 or 5 (i. E. , either 3 or 5 or both)?

Answers

Answer:

Umm..... sorry but.....my answer came.......

The probability that the number picked is divisible by 3 or 5 is 0.555.

What is probability?

Probability sampling is defined as a sampling technique in which the researcher chooses samples from a larger population using a method based on the theory of probability.

An integer number is chosen randomly between 1 and 1000.

The number of numbers divisible by 3, which is;

[tex]\rm \dfrac{1000}{3}=3333.3 = 333[/tex]

The number of numbers divisible by 5, which is;

[tex]\rm \dfrac{1000}{5}=200[/tex]

The probability that the number picked is divisible by 3 or 5 is;

[tex]\rm Probability=\dfrac{Number \ divisble \ by \ 3+ Number \ divisble \ by \ 5}{1000}\\\\ Probability =\dfrac{333+200}{1000}\\\\Probability=\dfrac{533}{1000}\\\\Probability=0.533[/tex]

Hence, the probability that the number picked is divisible by 3 or 5 is 0.555.

Learn more about probability here;

https://brainly.com/question/14461856

#SPJ4

Determine the solution to each linear system by using the substitution method
3x+2y=4
2x-y=5

Answers

Answer:

The solution is x = 2

Step-by-step explanation:

i) 3x+2y=4

ii) 2x-y=5

Let's isolate y for the second equation

2x-y=5

2x-5 = y

y = 2x-5

Now use this y and substitute it in the first equation.

3x+2y=4

3x + 2(2x-5) = 4

3x + 4x - 10 = 4

7x / 7 = 14 / 7

x = 2

Evaluate the expression when x = 3.

x² + 6x - 3

Answers

Answer:

X=3

[tex] {3}^{2} + 6(3) - 3 \\ 9 + 18 - 3 \\ 27 - 3 \\ = 24[/tex]

vertically stretched by a factor of 2, then translated
4 units left and 1 unit down

Answers

A vertical stretch of scale factor 2, followed by a translation of 4 units left and 1 unit down is written as:

g(x) = 2*f(x + 4) - 1

How to write the given transformation?

For a general function f(x), a vertical stretch of scale factor K is written as:

g(x) = K*f(x).

Horizontal translation:

For a general function f(x), a horizontal translation of N units is written as:

g(x) = f(x + N).

If N is positive, the shift is to the left.If N is negative, the shift is to the right.

Vertical translation:

For a general function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N.

If N is positive, the shift is upwards.If N is negative, the shift is downwards.

So, if we start with a function f(x) and we stretch it vertically with a scale factor of 2, we get:

g(x) = 2*f(x)

Then we translate it 4 units left:

g(x) = 2*f(x + 4)

Then we translate 1 unit down:

g(x) = 2*f(x + 4) - 1

This is the equation for the transformation.

If you want to learn more about transformations, you can read:

https://brainly.com/question/4289712

The diagonals of quadrilateral EFGH intersect at D(1,3). EFGH has vertices at E(2,6) and F(-4,5). What must be the coordinates of G and H to ensure that EFGH is
a parallelogram?

Answers

Answer:

G(0, 0), H(6, 1)

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

Point D is the midpoint of both diagonals.

Endpoint of EG is point G with coordinates (x, y):

(2 + x)/2 = 1 ⇒ 2 + x = 2 ⇒ x = 0(6 + y)/2 = 3 ⇒ 6 + y = 6 ⇒ y = 0G = (0, 0)

Endpont of FH is point H with coordinates (x, y):

(-4 + x)/2 = 1 ⇒ - 4 + x = 2 ⇒ x = 4 + 2 ⇒ x = 6(5 + y)/2 = 3 ⇒ 5 + y = 6 ⇒ y = 6 - 5 ⇒ y = 1H = (6, 1)

BRAINLIEST FOR CORRECT ANSWER: What is the area of this figure?

Answers

there is no figure to find the area of

4x−4<8 AND 9x+5>23

Doing Khan Academy
HelP!!

Answers

Answer:

x<3 and x>2

Step-by-step explanation:

write the symbols this < and > to get the correct answer

I need help. SO confused

Answers

Answer:

The answer would be 1/4% or 25%.

Step-by-step explanation:

The reason why is that there were 20 students in the class. 5 people wanted to work in groups. That is 25% of the students. That is why 25% or 1/4% is your answer.

I have already done Number one but I need help with 2. Please help when you find time to!

Answers

Answer:

Step-by-step explanation:

Formulae

Area of a triangle = 1/2 x base x height

Area of a rectangle = width x length

Question 1

Surface area of square based pyramid = area of base + 4 × area of triangle

⇒ SA = (6 × 6) + 4(1/2 × 6 × 14)

         = 36 + 168

         = 204 yd²

Question 2

Surface area of a cuboid = 2 × base area + 2 × end area + 2 × side area

⇒ SA = 2(10 × 6) + 2(6 × 3) + 2(10 × 3)

         = 120 + 36 + 60

         = 216 mm²

Extra credit question

Surface area of a triangular based prism = base area + 2 × triangle area + 2 × side areas

base area = 3 × 10 = 30 mm²

triangle area = 1/2 × 3 × 2 = 3 mm²

side area = 10 × 2.5 = 25 mm²

⇒ total SA = 30 + (2 × 3) + (2 × 25)

                 = 30 + 6 + 50

                 = 86 mm²

Concept :-

We can solve these questions by using the formulas of area of triangle and rectangle, which will make our work easier. So, we know that,

[tex] \blue{ \underline{ \boxed{ \begin{array}{cc} \sf1. ~Area_{Triangle} = \dfrac{1} {2} \times b \times h \qquad \: \: \: \: \: \: \: \\ \\ \\ \sf2. \: Area_{Rectangle} = Length \times Breadth \end{array}}}} \\ \\ [/tex]

Using these formulas and figuring out the number of triangles and rectangles in each shape, we will solve this question.

Solution :-

1. In this square pyramid, if we closely observe, we will get to know that there are 1 rectangle and 4 triangular faces. Thus,

[tex]\sf \hookrightarrow Area=6 \times 6 + 4( \dfrac{1}{2} \times 6 \times 14) \\ \\ \\ \sf \hookrightarrow Area=36 + 168 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Area= {204 \: yd}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ [/tex]

2. Now, here, we can use the formula of total surface area for cuboid, i.e.

TSA = 2( lb + bh + hl )

[tex]\sf \hookrightarrow Area=2(10 \times 6 + 6 \times 3 + 10 \times 3) \\ \\ \\ \sf \hookrightarrow Area=2(60 + 18 + 30) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Area=2 \times 108 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Area= {216 \: mm}^{2} \: \: \qquad \qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]

Extra Credit Question.

Here, we can find out the total surface area by finding,

Base area i.e. length x breadth ( B.A. )

Side area i.e. length x breadth ( S.A. )

triangular area = 1/2 x b x h ( T.A. )

Now,

TSA = BA + 2 x S.A. + 2 x T.A.

[tex]\sf \hookrightarrow Area=(10 \times 3) + 2(10 \times 2.5) + 2(\dfrac{1}{2} \times 3 \times 2) \\ \\ \\ \sf \hookrightarrow Area= 30 + 2 \times 25 + 2 \times 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Area=30 + 50 + 6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \hookrightarrow Area= {86 \: mm}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ [/tex]

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