Find the value of x when the triangle has 9 and 3

Find The Value Of X When The Triangle Has 9 And 3

Answers

Answer 1

Answer:

H²=h²+b²

H²=9²+3²

H²=81+9

H²=90

H=

[tex] \sqrt{90} [/tex]


Related Questions

find the equation of the line y=mx+b form with the slope 3 that passes through the point (5,19)

Answers

The equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4

Equation of a straight line

From the question, we are to determine the equation of the line that has a slope of 3 and that passes through the point (5,19)

Using the point-slope form of an equation of a line

y - y₁ = m(x - x₁)

Where m is the slope

and (x₁, y₁) is a point on the line

From the given information

m = 3

x₁ = 5

y₁ = 19

Putting the parameters into the equation, we get

y - 19 = 3(x - 5)

y - 19 = 3x - 15

y = 3x -15 + 19

y = 3x +4

Hence, the equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4

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What is the sum of the 12th square number and the 9th square number

Answers

Answer: 225

Step-by-step explanation:

What is a square number?

A square number is a product of a number times itself

So, the 12th square number would be 12 * 12, or 12²

The 9th square number would be 9 * 9, or 9²

The equation would be 12² + 9²

So:

12² + 9²

= 144 + 81

= 225

So, the answer is 225

Someone please help me

Answers

Step-by-step explanation:

Part A: [tex]u^6[/tex] can be written as the square of u³, or [tex](u^3)^2[/tex]. Similarly, [tex]v^6=(v^3)^2[/tex]. Hence, we can write this as a difference of two squares by writing it as

[tex](u^3)^2-(v^3)^2[/tex]

Part B:

Difference of Two Squares

We can first factor a difference of two squares a² - b² into (a+b)(a-b). Here, a would be u³ and b would be v³.

[tex](u^3+v^3)(u^3-v^3)[/tex]

Sum and Difference of Two Cubes

We can factor this further by the use of two special formulas to factor a sum of two cubes and a difference of two cubes. These formulas are as follows:

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)\\a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]

Since u³ + v³ is a sum of two cubes, let's rewrite it.

[tex]u^3+v^3=(u+v)(u^2-uv+v^2)[/tex]

Since u³ - v³ is a difference of two cubes, we can rewrite it as well.

[tex]u^3-v^3=(u-v)(u^2+uv+v^2)[/tex]

Now, let's multiply them together again to get the final factored form.

[tex]u^6-v^6=(u+v)(u^2-uv+v^2)(u-v)(u^2+uv+v^2)[/tex]

Part C:

If we want to factor [tex]x^6-1[/tex] completely, we can just see that x to the sixth power is just [tex]x^6[/tex] and 1 to the sixth power is just 1. Hence, x can substitute for u and 1 can substitute for v.

[tex]x^6-1=(x+1)(x^2-x(1)+1^2)(x-1)(x^2+x(1)+1^2)\\x^6-1=(x+1)(x^2-x+1)(x-1)(x^2+x+1)[/tex]

We can repeat this for [tex]x^6-64[/tex], as 64 is just 2 to the sixth power.

[tex]x^6-64=(x+2)(x^2-x(2)+2^2)(x-2)(x^2+x(2)+2^2)\\x^6-64=(x+2)(x^2-2x+4)(x-2)(x^2+2x+4)[/tex]

1) A school has an enrollment of 1500 students. The student population is expected to increase at a rate of 2.6% each year for the next 5 years.

a) A What is the growth factor as a decimal?




b) Estimate the number of students enrolled 10 years from now. Round to the nearest student.

Show your work!!

Answers

The growth factor as a decimal is 1.026 and the number of students enrolled 10 years from now is 1939

How to determine the growth factor?

The given parameters are

Initial value of enrollment, a = 1500

Rate, r = 2.6%

The growth factor is then calculated as:

Growth factor = 1 + Rate

This gives

Growth factor = 1 + 2.6%

Evaluate the sum

Growth factor = 1.026

Hence, the growth factor as a decimal is 1.026

The number of students enrolled 10 years from now

As a general rule, the number of students enrolled t years from now is

Students = Initial value * Growth factor^Number of years

This is represented as

Students = 1500(1.026)^t

10 years from now means t = 10

So, we have

Students = 1500(1.026)^10

Evaluate

Students = 1939

Hence, the number of students enrolled 10 years from now is 1939

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In the 1980’s, a clinical trial was conducted to determine if taking an aspirin daily reduced the incidence of heart attacks. Of 22,071 medical doctors participating in the study, 11,037 were randomly assigned to take aspirin and 11,034 were randomly assigned to the placebo group. Doctors in this group were given a sugar pill disguised to look like aspirin. After six months, the proportion of heart attacks in the two groups was compared. Only 104 doctors who took aspirin had a heart attack, whereas 189 who received the placebo had a heart attack. Can we conclude from this study that taking aspirin reduced the chance of having a heart attack? the purpose of this study was to determine whether taking an aspirin daily reduces the proportion of heart attacks.

Answers

There is enough evidence to conclude that taking aspirin cannot  reduces the chance of cancer.

Given sample size of patients take aspirin 11037, sample size of patients who have assigned placebo group be 11034. 104 doctors who take aspirin had a heart attack, 189 doctors had placebo had heart attacks.

First we have to form hypothesis.

[tex]H_{0} :p{1} -p_{2} =0[/tex]

[tex]H_{1}:p_{1} -p_{2} < 0[/tex]

We have to find the respective probabilities.

[tex]p_{1}[/tex]=104/11037

=0.0094

[tex]p_{2}[/tex]=189/11034

=0.0171

Now their respective margin of errors.

[tex]s_{1}[/tex]=[tex]\sqrt{ {(0.0094*0.9906)/11037}[/tex]

=0.0009

[tex]s_{2}[/tex]=[tex]\sqrt{0.0171*0.9829}[/tex]

=0.0011

Hence the distribution of the differences,they are given by:

p=[tex]p_{1} -p_{2}[/tex]

=0.0094-0.0171

=-0.0077

S=[tex]\sqrt{s_{1} ^{2}+s_{2} ^{2} }[/tex]

=[tex]\sqrt{(0.0009)^{2} +(0.0011)^{2} }[/tex]

=0.00305

z=(p -f)/S (In which f=0 is the value tested at the null hypothesis)

=(-0.0077-0)/0.00305

=-2.52

p value will be 0.005.

p value of 0.05 significance level.

z=1.96.

1.96>0.005

So we will reject the null hypothesis which means it cannot reduce the whole chance of becomming a heart attack.

Hence there is enough evidence to conclude that taking aspirin cannot  reduces the chance of cancer.

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A rectangle measures 3.5 ft by 7 ft. It is enlarged by a scale factor of two. What is the area of the enlarged rectangle? T a m a​

Answers

Answer:

98

Step-by-step explanation:

Solution 1, (quick)

When enlarging by a scale factor, the shape's area is multiplied by the scale factor squared.

3.5*7*2^2=98

This works because for a rectangle width x and length y, width 2x and length is 2y, area is 4xy compared to area xy originally.

Solution 2, (technical)

Scale factor of 2 means multiplying by 2

3.5^2=7

7*2=14

7*14=98

When you roll two number cubes, what are the odds in simplest form against getting two numbers greater than 4?
A. 4:1
B. 1:4
C. 1:8
D. 8:1

Answers

The odds in simplest form against getting two numbers greater than 4 is 1 : 4.

What are the odds?

Probability determines the odds that a random event would happen. The odds  the event occurs is 1 and the probability that the event does not occur is 0.

The odds of getting two numbers greater than 4 = 2 x (numbers greater than 3 in a cube / total number of sides in a cube)

2(3/6)

2 x 1/2 = 1 : 4

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What is the slope of a line that is parallel to the line y = 3/4x+2?

Answers

Answer: 3/4

Step-by-step explanation:

Parallel lines have the same slope.

From the top of a 16 m tall building, the angle of depression to a car on the road is 35°. To the nearest metre, how far is the car from the base of the building?

Answers

The distance of the car to the base of the building is 23 metres.

How to find the distance of the car from the building using angle of depression?

The situation will form a right angle triangle.

Therefore, the distance of the car to the base of the building is the adjacent side of the right angle triangle formed.

Therefore,

tan 35 = opposite / adjacent

tan 35 = 16 / x

x tan 35 = 16

x = 16 / tan 35

Therefore,

x = 16 / 0.70020753821

x = 22.8506141103

x = 23 meters

Therefore, the distance of the car to the base of the building is 23 metres.

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Help please you don’t know how much this means to me

Answers

Problem 6:a)

[tex]a(0) = 1 \: \: \: \: \: \: b(0) = 2 \: \: \: \: \: c(0) = 3 \\ a(1) = b(0) + c(0) = 2 + 3 = 5 \\ b(1) = a(0) + c(0) = 1 + 3 = 4 \\ c(1) = a(0) + b(0) = 1 + 2 = 3 \\ \\ a(2) = b(1) + c(1) = 4 + 3 = 7 \\ b(2) = a(1) + c(1) = 5 + 3 = 8 \\ c(2) = a(1) + b(1) = 5 + 4 = 9[/tex]

[tex]a(3) = b(2) + c(2) = 8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16 \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\ \\ a(4) = b(3) + c(3) = 16 + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33[/tex]

[tex]a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 = 63 \\ \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\ [/tex]

[tex]a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\ \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513[/tex]

[tex]a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\ \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025 + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049[/tex]

b)

[tex]a(n) + b(n) + c(n) = \\ 2(a(n - 1) + b(n - 1) + c(n - 1)) \\ 6 \times 2 {}^{n } [/tex]

c)

[tex]6 \times 2 {}^{n} > 100 \: 000 \\ 2 {}^{n} > \frac{100 \: 000}{6} \\ n > log {}^{2} ( \frac{100 \: 000}{6} ) \\ n > 14.02468 \\ n = 15[/tex]

PLEASE HELP QUICKLY️️️​

Answers

Answer:

first option x = 7

Step-by-step explanation:

"x" is the cathetus opposite the angle of 30°

14 is the hypotenuse

use the sine function

[tex]sin30^{0} =\frac{x}{14}[/tex]

[tex]x=14sen30^{0} =14(0.5)=7[/tex]

Hope this helps

Write the equation of the sinusoidal function shown.
A) y = cos x - 1
B)y=sin x - 1
C) y=2 sin x - 1
D) y = 2 cos x - 1

Answers

Answer:

A. y= cos x - 1

Step-by-step explanation:

short answer: this is basically the parent graph cos(x), just vertically shifted down 1 unit.


longer answer:

standard form is y = a cos(bx-c) +d

a = amplitude

b = 2pi/period

c = horizontal shift

d = vertical shift (also equal to midline)


for this graph

a=1

period is 2pi, so b=1

there is no horizontal shift so c=0

d= -1 because it is shifted down one unit from axis (midline is at -1)

How many solutions does this nonlinear system of equations have? NEED HELP ASAP!

Answers

Answer:

Step-by-step explanation:

two

Can someone please help me with this? I'll give brainliest :)


Based on the information given find the slope from [2,5] Is interval notation and means from x=2 to x=5.
16. y = 3x - 4
17. y = 2x^2-4x - 2


Answers

The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

How to determine the slope?

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

[tex]m = \frac{y_2 -y_1}{x_2-x_1}[/tex]

16. y = 3x - 4

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

[tex]m = \frac{11 - 2}{5 - 2}[/tex]

[tex]m = \frac{9}{3}[/tex]

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

17. y = 2x^2-4x - 2

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

[tex]m = \frac{28 + 2}{5 - 2}[/tex]

[tex]m = \frac{30}{3}[/tex]

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

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If the parabola of equation y=k−x2 is tangent to the line of the equation y=x then what is the value of k ?

Answers

The value of k is 1/4.

According to the statement

we have given

The equation of parabola is y=k−x2

And tangent to the line of equation is y = x

and we have to find the value of K.

So, let y=k−x2  -(1)

and let  y = x  -(2)

(2) is the tangent to the (1) then

therefore they cut at

y=k−x2  -(1)

y = x  -(2)

so, put (2) in the (1) then

x = k- (x)^2

(x)^2 + x = k

The above written equation has one real number then for this D =0

so, (x)^2 + x - k = 0

-1 -1*4*k = 0

-1 - 4k = 0

-4k = 1

The value of k is -1/4.

So, The value of k is 1/4.

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Which search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line

Answers

The wide-area search method employs the use of markers such as knots at regular intervals along the search line.

Given the method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line.

In order to locate, relieve distress, and preserve the life of a person who has been reported missing or is believed to be lost, stranded, or is considered a high-risk missing person, wide area search and rescue refers to activities occurring within large geographic areas. It also refers to the removal of any survivors to a safe location.

Hence, the wide-area search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line

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Consider the function f(x) = x² + 10x + 25 for x ≥ -5.
What is the value of f-¹(x) when x = 4?

Answers

Answer:

-3

Step-by-step explanation:

Find the midpoint of a and b when a has coordinates (2,3) and b has coordinates (8,9)

Answers

The midpoint of co-ordinate is (5, 6)

Add both "x" coordinates, and divide by 2.

Add both "y" coordinates, and divide by 2.

Given that;

Coordinates of A = (2,3)

Coordinates of B = (8,9)

Find:

Midpoint of co-ordinate

Computation:

Midpoint of co-ordinate = [(x1 + x2) / 2], [(y1 + y2) / 2]

Midpoint of co-ordinate = [(2 + 8) / 2], [(3 + 9) / 2]

Midpoint of co-ordinate = [10 / 2], [12 / 2]

Midpoint of co-ordinate = (5, 6)

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Decrease 100kg by 30%

Answers

Answer:

70

Step-by-step explanation:

the 30/100 of 100 is 30

So 100-30=70

Answer:

70kg

Step-by-step explanation:

30% of 100kg is

--> 100 x 30/100 which is 30kg.

If you want to decrease 100kg by 30%, you can take away 30kg from 100kg.

--> 100 - 30 = 70

So 70kg is the remainder.


In the diagram AB/BC = AD/DE
Substitute the known values into the proportion and solve for DE

Answers

Answer:

[tex]\huge\boxed{\sf DE = 9}[/tex]

Step-by-step explanation:

From the figure,

AB = 2

BC = 3

AD = 6

Substitute in the given formula

[tex]\displaystyle \frac{AB}{BC} =\frac{AD}{DE} \\\\\frac{2}{3} = \frac{6}{DE} \\\\Cross \ Multiply \\\\2 \times DE = 6 \times 3\\\\2DE = 18\\\\Divide \ 2 \ to \ both \ sides\\\\DE = 18/2\\\\DE = 9\\\\\rule[225]{225}{2}[/tex]

BRAINLIEST TO CORRECT ANSWER
There is a pair of parallel sides in the following shape.
what is the area

Answers

The area of the given figure is 38 square units

Area of a trapezoid

The area of the given trapezoid is expressed as:

A = 0.5(a+b)h

where

a and b are the sides

h is the height

Substitute

A = 0.5(9+10) * 4

A = 19 * 2

A = 38 square units

Hence the area of the given figure is 38 square units

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Janice bought 30 items each priced at 30 cents, 2 dollars, or 3 dollars. If her total purchase price was $\$$30.00, how many 30-cent items did she purchase

Answers

she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

According to the statement

Janice bought total items = 30

Price of items are 30 cents, 2 dollars, or 3 dollars.

Total purchase price of Janice = 30$

If we let she bought 10 items at price of 3$, Then it is not possible

So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.

we know that 1 CENT = 0.01 $

We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.

Now, Let she bought 20 items at price of 0.01$

Then 20*0.3 = 6$

It means 30$-6$ = 24$

24$ are left to purchase the things which are at price of 2$ and 3$.

If we let she purchase 4 items at cost $3 then

Then 4*$3 = 12$

It means 24$-12$ = 12$

Now, with remaining money she bought 6 items at cost $2.

So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

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she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

According to the statement

Janice bought total items = 30

Price of items are 30 cents, 2 dollars, or 3 dollars.

Total purchase price of Janice = 30$

If we let she bought 10 items at price of 3$, Then it is not possible

So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.

we know that 1 CENT = 0.01 $

We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.

Now, Let she bought 20 items at price of 0.01$

Then 20*0.3 = 6$

It means 30$-6$ = 24$

24$ are left to purchase the things which are at price of 2$ and 3$.

If we let she purchase 4 items at cost $3 then

Then 4*$3 = 12$

It means 24$-12$ = 12$

Now, with remaining money she bought 6 items at cost $2.

So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

Half of a set of the parts are manufactured by machine A and half by machine B. Eight percent of all the parts are defective. Two percent of the parts manufactured on machine A are defective. Find the probability that a part was manufactured on machine A, given that the part is defective. (Round your answer to 4 decimal places.)

Answers

The probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.

What is probability?Probability is the branch of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely it is that a claim is true. The probability of an event is a number between 0 and 1, with 0 indicating impossibility and 1 indicating certainty.

To find the probability that a part was manufactured on machine A, given that the part is defective:

The probability that a part was manufactured on machine A given that part is defective:

P ( A | D )

P ( A | D ) = [P (A) * P ( D | A )]/ P ( D )

Where: P (A) is the probability that the part is manufactured in machine A which is 0.2 (half of the parts are manufactured in machine A)

P (D/A) is the probability of a defective part given that the part was manufactured in machine A which is 2% or 0.02

And finally, the probability of defective part in the production is 8% or 0.08 hence :

P ( A | D ) = [ ( 0.2 ) * 0.02 ] / 0.08

P ( A | D ) = 0.024

Therefore, the probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.

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The temperature was -20.5°F at 5 A.M. and rose 5 degrees per hour for the next 5 hours. Melissa says the temperature at 10 A.M. was -5.5°F. Which statement identifies Melissa’s error and the correct answer?A.Melissa multiplied incorrectly. The correct answer is -0.5°F.B.Melissa multiplied incorrectly. The correct answer is 9.5°F.C.Melissa added incorrectly. The correct answer is 4.5°F.D.Melissa added incorrectly. The correct answer is 5.5°F.

Answers

The statement which identifies Melissa’s error and the correct answer is; Melissa added incorrectly. The correct answer is 4.5°F

Temperature

Initial temperature = -20.5°FChange in temperature per hour = 5°FNumber of hours = 5

New temperature = Initial temperature + (Change in temperature per × Number of hours)

= -20.5°F + (5°F × 5)

= -20.5°F + (25°F)

= 4.5°F

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Answer:

C

Step-by-step explanation:

On the way to visit her grandmother, Sally drove at an average speed of 85 mph. On the way home (taking the same route) she only averaged 65 mph. If the total round trip took 18 hours, how many hours did it take Sally to drive to her grandmother's? Write your answer as a decimal.​

Answers

Answer:

7.8 hours

Step-by-step explanation:

We will use the formula:

distance =rate×time

We don't know the distance but it is the same distance going and returning. Two rate×time calculations will both equal that distance from Sally's to Grandma's. See image.

Solution
We can start with the pythagorean theorem:
(leg 1)² + (leg 2)² = (hypotenuse)²
Substitute the values we know.
15² + x² = 32²
Solve for x.
X =

Answers

Answer:

28.26658805 (I included every digit in case your teacher needs you to round)

Step-by-step explanation:

In order to find x, we need to isolate x by subtracting 15^2 and taking the square root of both sides.

Thus, we have:

[tex]15^2+x^2=32^2\\x^2=32^2-15^2\\\sqrt{x^2} =\sqrt{(32^2-15^2)} \\\sqrt{x^2}=\sqrt{799} \\x=28.26658805[/tex]

Which point is the solution to the inequality shown in this graph?? Help pls
a.(0,5)
b.(-3,-1)
c.(0,0)
d.(3,3).​

Answers

Answer:

only (0,5)

Step-by-step explanation:

(0,5) is in the shaded region on the graph, so it is a solution.

One other point is in the unshaded region so it is NOT a solution. The other two points are on the dashed line, so they are NOT solutions. If the line was solid (not dashed) they would work, but since the line is dashed they are NOT solutions.

Answer:

A. (0,5)

Step-by-step explanation:

A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 16% of the employees needed corrective shoes, 23% needed major dental work, and 3% needed both corrective shoes and major dental work. What is the probability that an employee selected at random will need either corrective shoes or major dental work

Answers

Probability of people needing corrective shoes or dental work is 0.36.

What is probability?

The proportion of favorable cases to all possible cases used to determine how likely an event is to occur.

What are mutually exclusive events?

A statistical term used to describe events that cannot occur concurrently is "mutually exclusive".

Here, the two events getting corrective shoes and getting dental work are not mutually exclusive events.

P(corrective shoes or dental work) = P(corrective shoes) + P(dental work) - P(corrective shoes and dental work)

P(corrective shoes or dental work)  = 0.16 + 0.23 - 0.03

P(corrective shoes or dental work)  = 0.36

Hence, the probability of people needing corrective shoes or dental work is 0.36.

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3) angle of an isosceles triangle is 70°, find the value of If one remaining angles. a) 40°, 40° b) 45°, 45° c) 40°70° d)50⁰, 50⁰​

Answers

The remaining two angles of the given isosceles triangle is Option(C) 40°,70° .

What are the remaining two angles in the isosceles triangle ?

For an isosceles triangle, the two sides of the triangle are congruent and equal in length . Also the angles subtending the adjacent equal sides of the isosceles triangle are of same measure.  

We also know that the sum of the three interior angles of any triangle is always equal to 180° .

In the options given, in Option(C) the angles measure 40° and 70° .

Thus as one angle of the isosceles triangle is given to be 70°, the other angle of its adjacent side is also 70° .

The sum of the interior angles of the triangle is equal to -

70° + 40° + 70° = 180° which satisfies the property.

Therefore, the remaining two angles of the given isosceles triangle is Option(C) 40°,70° .

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Using the quadratic formula, solve the
equation below to find the two possible
values of t.
6x^2-35=-11x
Give each value as a fraction in its
simplest form.

Answers

The two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

What are the two possible solution to the equation?

Given the equation; 6x² - 35 = -11x

The quadratic formula is expressed as;

x = [ -b±√( b² - 4(ac)  ]/2a

First, we re-arrange our equation in the form of ax² + bx + c = 0

6x² + 11x - 35 = 0

a = 6b = 11c = -35

We substitute into the formula.

x = [ -b±√( b² - 4(ac)  ]/2a

x = [ -11±√( 11² - 4( 6 × -35 )  ]/2×6

x = [ -11±√( 121 + 840 ]/12

x = [ -11±√961 ]/12

x = [ -11 ± 31 ]/12

x = (-11 + 31)/12,  (-11 + 31 )/12

x = 20/12,  -42/12

x = 5/3, -7/2

Therefore, the two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

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