Answer:
[tex]x=\frac{-5}{2}[/tex]
Step-by-step explanation:
[tex]f(x)=x^6+3x^5+2\\\\\implies f'(x)=6x^5+15x^4\\\\Equate\ f'(x)\ to\ 0\ for\ critical\ points\ (\ \because f'(x)=0\ at\ points\ of\ local\ extrema):\\\\3x^4(2x+5)=0\\\\x=0\ (or)\ x=\frac{-5}{2}\\\\\hrule\ \\\\\ (Second Derivative Test for x=(-5/2) )\\\\f''(x)=30x^4+60x^3\\\\f''(0)=0\ \ \implies Use\ first\ derivative\ test\ at\ x=0\\\\f''(\frac{-5}{2})=30(\frac{-5}{2})^3\cdot(\frac{-5}{2}+2)\\\\It\ is\ evident\ that\ f''(\frac{-5}{2}) > 0\\\\\implies x=\frac{-5}{2}\ is\ a\ point\ of\ local\ minima.[/tex]
[tex]\\\\\hrule\ \\\\\ (First Derivative Test for x=0 )\\\\f'(x)=3x^4(2x+5)\\\\f'(-0.1)=3(-0.1)^4\cdot(-0.2+5) > 0\\\\f'(0.1)=3(0.1)^4\cdot(0.2+5) > 0\\\\\implies x=0\ is\ a\ point\ of\ inflexion.\\\\[/tex]
The function has only one local minimum at x-coordinate equals to -2.5.
What are the x-coordinates of the local minima of the function f(x) = x⁶ + 3x⁵ + 2?To find the local minima of the function f(x) = x⁶ + 3x⁵ + 2, we need to find the critical points of the function where f'(x) = 0 or is undefined.
f(x) = x⁶ + 3x⁵ + 2f'(x) = 6x⁵ + 15x⁴Setting f'(x) = 0, we get:
6x⁵ + 15x⁴ = 03x⁴(2x + 5) = 0This gives us two critical points:
x = 0 (since 3x⁴ cannot be zero)x = -2.5To determine if these are local minima, we need to look at the sign of the derivative on either side of each critical point.
For x < -2.5, f'(x) < 0, indicating a decreasing function. For x > -2.5, f'(x) > 0, indicating an increasing function. Thus, -2.5 is a local minimum.
For x < 0, f'(x) < 0, indicating a decreasing function. For x > 0, f'(x) > 0, indicating an increasing function. Thus, 0 is not a local minimum.
Therefore, the x-coordinate of the only local minimum is -2.5.
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Solve the inequality. 14 + 10y ≥ 3(y + 14)
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{14+10y\geq 3(y+14) } \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{Simplify \ both \ sides \ of \ the \ inequality. }} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{10y+14\geq 3y+14 } \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{Subtract \ 3y \ from \ both \ sides. }} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{10y+14-3y\geq 3y+42-3y } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{7y+14\geq 41 } \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{ Subtract \ 14 \ from \ both \ sides. }} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{7y+14-14\geq 42-14 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{7y\geq 28 } \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sf{Divide \ both \ sides \ by \ 7. }} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{7y}{7}\geq \frac{28}{7} } \end{gathered}$}\\\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{y\geq 4} \end{gathered}$} }[/tex]describe how the graph is transformed from its parent function?
Answer:
It is stretched taller by a factor of 2.
suppose cos(a)=4/5. use the trig identity sin^2(a)+cos^2(a)=1 to find sin(a) in quadrant IV.
Answer:
sin a = -3/5
Step-by-step explanation:
sin^2(a)+cos^2(a)=1
sin^2(a)+ (4/5)^2 = 1
sin^2(a) = 1 - 16/25 = 9/25
sin a = 3/5 ( in Quadrant 1)
In quadrat IV the sine is negative
so sin a = -3/5
PLs answer fast i need this questions answer
Answer:
[tex]x=6[/tex]
Step-by-step explanation:
Given equation:
[tex]x-\left(2x-\dfrac{3x-4}{7}\right)=\dfrac{4x-27}{3}-3[/tex]
Expand the left side:
[tex]\implies x-2x+\dfrac{3x-4}{7}=\dfrac{4x-27}{3}-3[/tex]
Let all terms on the left side have the same denominator of 7:
[tex]\implies \dfrac{7x}{7}-\dfrac{14x}{7}+\dfrac{3x-4}{7}=\dfrac{4x-27}{3}-3[/tex]
Join the terms on the left side:
[tex]\implies \dfrac{7x-14x+3x-4}{7}=\dfrac{4x-27}{3}-3[/tex]
[tex]\implies \dfrac{-4x-4}{7}=\dfrac{4x-27}{3}-3[/tex]
Let all the terms on the right side have the same denominator of 3:
[tex]\implies \dfrac{-4x-4}{7}=\dfrac{4x-27}{3}-\dfrac{9}{3}[/tex]
Join the terms on the right side:
[tex]\implies \dfrac{-4x-4}{7}=\dfrac{4x-27-9}{3}[/tex]
[tex]\implies \dfrac{-4x-4}{7}=\dfrac{4x-36}{3}[/tex]
Cross multiply:
[tex]\implies 3(-4x-4)=7(4x-36)[/tex]
Expand:
[tex]\implies -12x-12=28x-252[/tex]
Add 12x to both sides:
[tex]\implies -12=40x-252[/tex]
Add 252 to both sides:
[tex]\implies 240=40x[/tex]
Divide both sides by 40:
[tex]\implies 6=x[/tex]
[tex]\implies x=6[/tex]
The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If the orbital period of planet Y is twice the orbital period of planet X, by what factor is the mean distance increased?
Answer:
2√2
Step-by-step explanation:
We can find the relationship of interest by solving the given equation for A, the mean distance.
Solve for A[tex]T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}[/tex]
Substitute valuesThe mean distance of planet X is found in terms of its period to be ...
[tex]D_x=T_x\sqrt{T_x}[/tex]
The mean distance of planet Y can be found using the given relation ...
[tex]T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x[/tex]
The mean distance of planet Y is increased from that of planet X by the factor ...
2√2
a solution of the equation 3x + y = 15?
Step-by-step explanation:
Since there is 2 unknown variable ,
so we need 2 equation to find their values.
The two-way frequency table below shows data on playing a sport and playing a musical instrument for students in a class.
Complete the following two-way table of row relative frequencies.
(If necessary, round your answers to the nearest hundredth.)
Here is the completed table:
Plays a sport Doesn't play a sport
Plays a musical instrument 0.46 0.54
Doesn't play a musical instrument 0.73 0.27
What are the row frequencies?
Relative frequency measures how often a value appears relative to the sum of the total values.
Plays a sport Doesn't play a sport
Plays a musical instrument (6/13) = 0.46 (7/13) = 0.54
Doesn't play a musical instrument (8/11) 0.73 (3/11) =0.27
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The sum of three numbers $a, b$ and $c$ is 60. If we decrease $a$ by 7, we get the value $N$. If we increase $b$ by 7, we get the value $N$. If we multiply $c$ by 7, we also get the value $N$. What is the value of $N$
The value of N is 28.
What is the solution of the equation?A mathematical statement that has a "equal to" symbol between two expressions with equal values is called an equation.
Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side. It demonstrates the equality of the relationship between the expressions printed on the left and right sides. We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved.
According to the question,
a+b+c=60
a-7=N
b+7=N
7c=N
From the above three equations,
a=N+7
b=N-7
c=N/7
So, N+7+N-7+N/7=60
2N+N/7=60
14N+N=420
15N=420
N=28
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Find the missing side. Round your answer to the nearest tenth.
Answer:
26.1 to the nearest tenth.
Step-by-step explanation:
tan 43 = x / 28
x = 28 tan 43
= 26.1102
please help !!!!!!!!!
Answer:
D. completing the square
Step-by-step explanation:
The process shown rearranges the standard-form quadratic equation to vertex form. It involves factoring out the leading coefficient and distributing the constant so that the variable terms can be written as a perfect square.
What is a perfect square trinomial?A perfect square trinomial is the square of a binomial. It has the form ...
(x +b)² = x² +2bx +b²
Given two variable terms, x² and 2bx, the perfect square trinomial can be formed by adding b², which is the square of half the x-term coefficient.
When b² is added to the sum (x² +2bx), the square is complete. The sum (x² +2bx +b²) can be written as the square (x +b)².
Completing the squareThis process of adding b² to the sum (x² +2bx) will change the polynomial unless a similar quantity is subtracted. That is why the 3rd line of the problem statement show 4 being added and subtracted inside parentheses:
y = 5(x² +4x +4 -4) -17
When we're applying this transformation, we do not want to change the equation. We simply want to rearrange it.
In the next step, the subtracted term is brought outside the parentheses. This lets us write the quantity in parentheses as a perfect square.
y = 5(x² +4x +4) +5(-4) -17
y = 5(x² +4x +4) -20 -17
This process of adding and subtracting a suitable quantity and rearranging the equation so the variable terms make a perfect square is called ...
"completing the square."
__
Additional comment
The equation in this form is said to be in "vertex form."
y = a(x -h)² +k
In this form, the constant 'a' is a vertical scale factor; the ordered pair (h, k) identifies the vertex of the quadratic on a graph.
HELPPPPPPPP!! loook at pic>>>>>>>>
The vertex form of the function is f(x) = -2(x-4)^2 + 2
Vertex form of a functionThe standard vertex form of a function is expressed according to the expression;
f(x) = a(x-h)^2+k
where
a is a constant = -2
(h, k) is the vertex = (4, 2)
Substitute
f(x) = -2(x-4))^2+2
f(x) = -2(x-4)^2 + 2
Hence the vertex form of the function is f(x) = -2(x-4)^2 + 2
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Three consecutive positive prime numbers have a sum that is a multiple of . What is the least possible sum
Answer:
3, 7, 14
Step-by-step explanation:
small brain
The difference between two number is 3.take the numbers as x and y form a equation?
The difference between two numbers are [tex]3[/tex] and numbers are [tex]x[/tex] and [tex]y[/tex] so the equation is [tex]x-y=3[/tex]
How to find the equation and what is the equation ?
equation, statement of equality between two expressions consisting of variables and/or numbers. In essence, equations are questions, and the development of mathematics has been driven by attempts to find answers to those questions in a systematic way.
if the difference of two numbers are [tex]3[/tex]
And one number is [tex]x[/tex] and another is [tex]y[/tex]
So we write the equation with operation of subtraction
[tex]x-y=3[/tex]
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8 more than 3 times a number is the same as -5 times the number.
a. x = -1
b. x = 1
c. x = -2
Answer:
3x +8 = -5x
3x + 5x = -8
8x = -8x
x = -8 /8
x = -1
Hope it helps...
Please contact me for further explanation....
A Ferris wheel is boarding platform is 2 meters above the ground, has a diameter of 68 meters, and rotates once every 9 minutes. How many minutes of the ride are spent higher than 37 meters above the ground
4.440 minutes of the ride is spent higher than 37 meters above the ground.
How to find the time spent on the ride?We have to find the amount of time spent by the ride 37 meters above the ground.
We know that 37 meters above the ground is actually one meter above the center.
We can find the angle above the center as shown below:
arcsin(1/34) = 0.0294 radians
Now we have to find the angle of rotation:
The angle of rotation of the Ferris wheel above 37 meters = π - (2*0.0294)
= 3.1 radians
The angular velocity of the Ferris wheel = Angle covered/Time
= 2π/9 rad/min.
Therefore time spent above 37 meters = 3.1*9/2π
= 3.1*9/6.28319
= 4.440 minutes
Therefore, we have found that 4.440 minutes of the ride is spent higher than 37 meters above the ground.
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Use the base example of two people walking to describe a system of two linear equation has i.) 0 solution 2) 1 solution 3) an infinite solution
The system has:
No solutions for two parallel lines.1 solution for two nonparallel lines.Infinite solutions for two equations that describe the same line.How to identify the number of solutions for the systems?A system of two linear equations is given by:
y = a*x + b
y = c*x + d
1) The system has no solutions when both lines are parallel lines, this happens when both lines have the same slope and different y-intercept.
y = a*x + b
y = a*x + d
2) The system has one solution when the lines have different slopes:
y = a*x + b
y = c*x + d
3) The system has infinite solutions when both equations describe the same line:
y = a*x + b
y = a*x + b
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Himari gave birth to twins and named them Adrian and Chang. When they were first born, Adrian massed 2.872.872, point, 87 kilograms and was 54.554.554, point, 5 centimeters tall, and Chang massed 4.544.544, point, 54 kilograms and was 515151 centimeters tall.
How much did the babies mass in total?
The total mass of Adrian and Chang at birth is 7.41 kilograms
MassAdrian weight = 2.87 kilograms and Adrian height = 54.5 centimetersChang weight = 4.54 kilogramsChang height = 51.5 centimetersTotal mass of the babies = Adrian weight + Chang weight
= 2.87 kilograms + 4.54 kilograms
= 7.41 kilograms
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Tests show that the hydrogen ion concentration of a sample of apple juice is 0.0003 and that of ammonia is . find the approximate ph of each liquid using the formula , where is the hydrogen ion concentration.
The pH value of the apple juice is 3.5, is the correct answer.
The pH value of the ammonia is 8.9, is the correct answer.
The question seems to be incomplete and complete question is shown below
Tests show that the hydrogen ion concentration of a sample of apple juice is 0.0003 and that of ammonia is 1.3 x 10-9. Find the approximate pH of each liquid using the formula pH = -log (H+), where (H+) is the hydrogen ion concentration The pH value of the apple juice is___ The pH value of ammonia is____
1.pH of apple juice
A. 8.11
B. 1.75
C. 3.5
D. 2.1
2. pH of ammonia
A. 1.1
B. 7.0
C. 5.4
D. 8.9
The pH of a solution is defined as the logarithm of the reciprocal of the hydrogen ion concentration [H+] of the given solution.
From the formula;
pH = -log[ H⁺ ]
Given the data in the question.
For the Apple juice
hydrogen ion concentration H⁺ = 0.0003
pH of the apple juice pH = ?
pH = -log[ H⁺ ]
pH = -log[ 0.0003 ]
pH = 3.5
The pH value of the apple juice is 3.5
For the ammonia
hydrogen ion concentration H⁺ = 1.3 × 10⁻⁹
pH of the ammonia pH = ?
pH = -log[ H⁺ ]
pH = -log[ 1.3 × 10⁻⁹]
pH = 8.9
The pH value of the ammonia is 8.9
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Mr.david gave ross a number and asked him to divide it by 15. The quotient and remainder obtained by ross are 341 and 12 respectively. Find the number that teacher gave ross.
The number the teacher gave Ross is 5127
Word problems on linear equationsFrom the question, we are to determine the number that the teacher gave Ross
From the given information,
Mr. David gave Ross a number and asked him to divide it by 15.
Let the number be x
That is,
x/15
The quotient and remainder obtained by ross are 341 and 12 respectively
That is,
x/15 = 341 + 12/15
Now, we will solve the equation for x
x/15 = 341 + 12/15
Multiply through by 15
x = 15×341 + 12
x = 5115 + 12
x = 5127
Hence, the number the teacher gave Ross is 5127
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PLSS HELP ASAP
A bag of marbles contains 7 red, 8 orange, 9 purple, 7 white, and 5 yellow. Mark reaches into the bag and randomly picks out 3 marbles all at once.
How many different 3-marble groups are possible?
What is the probability that he will select 2 red and 1 yellow marbles?
based on the number of marbles in the bag, the number of marble groups possible is 7,140 groups.
the probability of selecting 2 red and 1 yellow is 1/68.
what number of 3-marble groups can be made?first, find the number of marbles:
= 7 + 8 + 9 + 7 + 5
= 36
the number of marble groups are:
= 36 ! / (3 ! x 33 !)
= 7,140 groups
the probability of picking 2 red and 1 yellow is:
= (( (7! / (2! x 5!)) x ( ( 5! / (1! x 4!))) / 7,140
= 1 / 68
= 1.47%
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If a pet store has 15 puppies 12 kittens and 6 rabbits
A researcher conducts an experiment to determine whether the type of car (sports vs. utility vehicle) and color of the car (red vs. blue) impact how fast people drive. The researcher decides that the best way to conduct the study is to assign each participant to all four conditions of the experiment. The researcher is using a:
The researcher is using a within-subjects factorial design.
According to statement
A researcher conducts an experiment to determine whether the type of car and color of the car impact how fast people drive.
This can be done by within-subjects factorial design.
In a within-subjects factorial design, all of the independent variables are manipulated within subjects. This would mean that each participant was tested in all conditions.
Another common example of a within-subjects design is medical testing.
So, The researcher is using a within-subjects factorial design.
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A school cafeteria uses 10
8 bowls of chocolate pudding.
How many cups of milk are in each bowl of chocolate pudding?
cups
Using proportions, it is found that there are 5 cups of milk in each bowl of chocolate pudding.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The cafeteria used 10 quarts for 8 bowls, hence the number of quarts per bowl is:
10/8 = 1.25
Each quart has 4 cups, hence the number of cups is:
4 x 1.25 = 5 cups.
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Help me with this question please
Answer:
[tex]\dfrac{991}{40\sqrt{2}}[/tex]
Step-by-step explanation:
Given expression:
[tex]\sqrt{72}-\dfrac{48}{\sqrt{50}}-\dfrac{45}{\sqrt{128}}+2\sqrt{98}[/tex]
Rewrite 72 as 36·2, 50 as 25·2, 128 as 64·2 and 98 as 49·2:
[tex]\implies \sqrt{36 \cdot 2}-\dfrac{48}{\sqrt{25 \cdot 2}}-\dfrac{45}{\sqrt{64 \cdot 2}}+2\sqrt{49 \cdot 2}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:[/tex]
[tex]\implies \sqrt{36}\sqrt{2}-\dfrac{48}{\sqrt{25}\sqrt{2}}-\dfrac{45}{\sqrt{64}\sqrt{ 2}}+2\sqrt{49}\sqrt{2}[/tex]
Rewrite 36 as 6², 25 as 5², 64 as 8² and 49 as 7²:
[tex]\implies \sqrt{6^2}\sqrt{2}-\dfrac{48}{\sqrt{5^2}\sqrt{2}}-\dfrac{45}{\sqrt{8^2}\sqrt{ 2}}+2\sqrt{7^2}\sqrt{2}[/tex]
[tex]\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0[/tex]
[tex]\implies 6\sqrt{2}-\dfrac{48}{5\sqrt{2}}-\dfrac{45}{8\sqrt{ 2}}+2\cdot 7\sqrt{2}[/tex]
Simplify:
[tex]\implies 6\sqrt{2}-\dfrac{48}{5\sqrt{2}}-\dfrac{45}{8\sqrt{ 2}}+14\sqrt{2}[/tex]
Combine like terms:
[tex]\implies 20\sqrt{2}-\dfrac{48}{5\sqrt{2}}-\dfrac{45}{8\sqrt{ 2}}[/tex]
Make the denominators of the two fractions the same:
[tex]\implies 20\sqrt{2}-\dfrac{384}{40\sqrt{2}}-\dfrac{225}{40\sqrt{ 2}}[/tex]
Rewrite 20√2 as a fraction with denominator 40√2:
[tex]\implies 20\sqrt{2}\cdot\dfrac{40\sqrt{2}}{40\sqrt{2}}-\dfrac{384}{40\sqrt{2}}-\dfrac{225}{40\sqrt{ 2}}[/tex]
[tex]\implies \dfrac{1600}{40\sqrt{2}}-\dfrac{384}{40\sqrt{2}}-\dfrac{225}{40\sqrt{ 2}}[/tex]
Combine fractions:
[tex]\implies \dfrac{991}{40\sqrt{2}}[/tex]
A couple quick algebra 1 questions for 50 points!
Only answer if you know the answer, quick shout-out to Dinofish32, tysm for the help!
The variation given in the first question is not a direct variation and there is no constant of variation.
Direct variationy = k × x
when
y = -40 and x = -0.5
y = k × x
-40 = k × -0.5
-40 = -0.5k
k = -40/-0.5
k = 80
When y = 8 and x = 2.5
y = k × x
8 = k × 2.5
8 = 2.5k
k = 8 / 2.5
k = 3.2
When y = 4 and x = -3
y = k × x
4 = k × -3
4 = -3k
k = -4/3
when y = 8 and x = -6
y = k × x
8 = k × -6
8 = -6k
k = 8/-6
k = -4/3
This is a direct variation and the constant of proportionality is -4/3
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I have no clue how to do this
The length and the width of the rectangle are 10 inches and 6 inches respectively.
In the question, we are given that the length of a rectangle exceeds its width by 4 inches, and the area is 60 square inches.
We are asked for the length and the width of the rectangle.
We assume the width (w) of the rectangle to be x inches.
Its length (l), exceeds its width (w) by 4 inches.
Thus, its length (l) = x + 4 inches.
Now, the area can be calculated using the formula, A = l*w, where A is its area, l is its length, and w is its width.
Thus, the area = (x + 4)x = x² + 4x.
But, we are given that the area is 60 square inches.
Putting the value, we get a quadratic equation:
x² + 4x = 60.
or, x² + 4x - 60 = 0,
or, x² + 10x - 6x - 60 = 0,
or, x(x + 10) - 6(x + 10) = 0,
or, (x - 6)(x + 10) = 0.
By the zero-product rule, we get:
Either, x - 6 = 0, or, x = 6,
or, x + 10 = 0, or, x = -10, but this is not possible as the width of a rectangle cannot be negative.
Thus, the width = x = 6 inches.
The length = x + 4 = 10 inches.
Thus, the length and the width of the rectangle are 10 inches and 6 inches respectively.
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re arranging equations
please help choose answer
Answer:
D. d = √(V/5)
E. A = √(b/c).
Step-by-step explanation:
V = 5d^2
Divide both sides by 5:
V/5 = d^2
Now take the square root of both sides:
d = √(V/5)
Note - it's the square root of the whole term (V/5).
b = cA^2
A^2 = b/c
A = √(b/c).
I have trouble understanding how stuff is worded so please help me I need to know by 4 o’clock today.
Answer:
Hector makes a tent shaped like a rectangular pyramid the volume is 56 cubic feet and the area is 24 square feet how tall is the tent
Step-by-step explanation:
WILL GIVE BRAINLIEST!!!!!!!!!
Considering the given proportions, the correct statements are:
A person in the group who is more likely to read is a boy.A person in the group who is more likely to listen to music is a girl.What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
The table gives these following proportions:
Boys and girls regarding books, boys are likelier to prefer books.Boys and girls regarding music, girls are likelier to prefer music.Hence the correct statements are:
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Alan will be traveling out of town for business. during his travel, he is scheduled to have 4 dinners, 5 lunches, and 3 breakfasts. his employer will pay him for these meals at the following rate: $20.20 for dinner, $10.70 for lunch, and $6.93 for dinner. what is the total amount alan will be paid for these meals?
money paid by employer to Alan is $ 155.09
word problemA word problem is a type of mathematics exercise where the majority of the issue's context is supplied in spoken language as opposed to mathematical notation.
money paid for dinner by employer=$20.20
money paid for lunch by employer =$10.70
money paid for breakfast by employer =$6.93
according to question,
in this problem we will simply multiply quantity of dinners with amount
to get our answer.
so as given in problem Alan scheduled 4 dinners , 5 lunches and 3 breakfast
(4×$20.20)+(5×$10.70)+(3×$6.93)
80.8+53.5+20.79
=$ 155.09
hence money paid by employer to Alan is $ 155.09
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