Given the velocity v= ds dt and the initial position of a body moving along a coordinate line, find the body's position at time t

One of the most crucial devices for electronics and communication is the signal generator. For several reasons, including testing, debugging, and designing, it is utilized to produce various types of signals and frequencies.

Engineers create electronic signals using signal generators, which can be analogue or digital, to test circuit designs. Signal generators come in a wide variety of forms with various characteristics and uses. The most typical signal generator kinds and their distinctive qualities are listed below.

Therefore, radar level instruments operate on the principle of generating a signal and then measuring the time required for the signal to reflect off the process fluid back to the transmitter.

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The new period of the pendulum when it is taken to the new planet is  double of its period on Earth.

The period of a pendulum is given by the following formula;

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

where;

The acceleration due to gravity of the new planet is calculated as follows;

[tex]g_E = \frac{GM_E}{R_E^2} = 9.81 \ m/s^2 \\\\g(new \ planet) = \frac{G(4M_E)}{(4R_E)^2} = \frac{4GM_E}{16R_E^2} = \frac{GM_E}{4R_E^2} = \frac{9.81}{4} = 2.45 \ m/s^2[/tex]

[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\T =\frac{2\pi \sqrt{l} }{\sqrt{g} } \\\\T_1\sqrt{g_1} = T_2\sqrt{g_2} \\\\T_E\sqrt{g_E} = T\sqrt{g} \\\\T = \frac{T_E\sqrt{g_E}}{\sqrt{g} } \\\\T = \frac{T_E \times \sqrt{9.81} }{\sqrt{2.45} } \\\\T = 2T_E[/tex]

Thus, the new period of the pendulum when it is taken to the new planet is double of its period on Earth.

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Answer:

6m/s

Explanation:

a = (v-u)/t

acceleration, a

initial velocity, u

final velocity, v

time, t

substitute values and you'll get the answer

Answer:

6 m/s

Explanation:

Answer:

0.142 m/s

Explanation:

You solve it by conservation of momentum.

Before the impact the total momentum is, considering right the positive direction,

[tex]m_1v_1+m_2v_2 =6\cdot10^-^3\times 40.4\ kg\cdot m/s + 1.7\times 0 \ kg\cdot m/s =242.4\cdot 10^-^3\ kg\cdot m/s[/tex]

After the impact, we have a single body of mass [tex]m_1+m_2[/tex] and thus a single value of speed, V.

[tex](m_1+m_2)V =1.703 kg \cdot V[/tex]

Since no external forces are applied, the two quantities are equal after the impact. That allows us to solve for V

[tex]V= (242.4\cdot10^-^3 \ kg\cdot m/s )\div (1.703\ kg)=142.337\cdot10^-^3 m/s = 0.142 m/s[/tex]

Answer:

B. different temperatures

Explanation:

Thats how they transfer energy because if one object is hotter then the other, the heat can still be transfer to the other object and make their temperatures the same

Answer:

The units for specific heat can either be joules per gram per degree (J/goC) or calories per gram per degree

Explanation:

Answer:

ooops ignore this it wont let me leave this screen it does this weirdly s

Explanation:

The distance is the object from the mirror will be 5cm.

A mirror equation is an equation that relates object distance and image distance to focal length. It is often referred to as a mirror formula.

The object distance in a spherical mirror is the distance between the object and the pole of the mirror (u).

The given data in the problem is;

Image height = 18cm

Object height = 10cm

u is the object distance

v is the image distance = 9 cm

From the symmetry of the triangle;

[tex]\frac{image \ height }{object \ height} = \frac{v}{u} \\\\ \frac{18 }{10} = \frac{9}{u}\\\\ \rm u=\frac{90}{8} \\\\ u = 5\ cm[/tex],

Hence the distance is the object from the mirror will be 5cm.

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The main environmental effects of ozone depletion could include the following:

Ozone depletion is the gradual thinning of the ozone layer in the upper atmosphere as a result of the relelase of chemical compounds or gases.

Ozone layer helps prevent the Earth surface against incoming ultraviolet radiations that could cause damage to our environment.

Therefore, the main environmental effects of ozone depletion could include the following:

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The following are some of the primary environmental implications of ozone depletion and increased risk of skin cancer, sunburns, rapid aging, and the immune system being weakened.

The progressive weakening of the ozone layer in the upper atmosphere as a result of the release of chemical compounds or gases is known as ozone depletion.

The ozone layer protects the Earth's surface from harmful UV rays that may harm our environment. As a result, the primary environmental effects of ozone depletion could include:

1. An increased risk of skin cancer

2. Sunburns

3. Rapid aging

4. The immune system is weakened.

Hence increased risk of skin cancer is the main environmental effect of ozone depletion.

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Answer:

When a circuit breaker regularly trips or a fuse repeatedly blows, it is a sign that you are making excessive demands on the circuit and need to move some appliances and devices to other circuits. Or, it may indicate that your house has too few circuits and is in need of a service upgrade.

Since the kinetic energy is equal to the potential energy then the speed of the object is √2gh.

The term work refers to the product of force and distance moved by force while energy is the ability to do work. The question is incomplete as the figure is not shown.

We know that the kinetic energy is equal to the potential energy hence;

mgh = 1/2mv^2

gh= 1/2v^2

v = √2gh

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Answer:

Potential energy.

Explanation:

Batteries are a form of chemical energy which  is stored in the bonds of molecules contained within the battery acid, batteries are a form of potential energy making chemical potential energy too.

Answer:

Mirror angle:

0°

25°

50°

Angle of incidence (θi):

0°

25°

50°

Angle of reflection (θr)

0°

25°

50°

Explanation:

The mirror angle is the same as the angles of incidence and reflection.

Brainlist Pls!

According to Hooke 's law

[tex]\\ \rm\rightarrowtail \nu=k\sqrt{\dfrac{\ell}{m}}[/tex]

[tex]\\ \rm\rightarrowtail \nu\propto \dfrac{1}{\sqrt{m}}[/tex]

Hence lower the mass higher the frequency

Explanation:

The gravitational potential energy of an object is given by GPE=mgh

where m is the mass of the object, g is the gravitational field strength (9.81 m/s² on earth) and h the height it is lifted at above the GPE reference ground.

Mass 1 has a GPE=m¹gh=(2)(9.81)(10)=196.2 Joule

Mass 2 has a GPE=m²gh=(4)(9.81)(10)=392.4 Joule

Object 2 has more potential energy and it makes sense since it's heavier

Hope this helps :))

The time taken for the charge to pass through the cross-section of the wire is 6.0s.

Given the data in the question;

Current; [tex]I = 5.0A[/tex]

Charge; [tex]Q = 30C[/tex]

Time; [tex]t = \ ?[/tex]

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

[tex]I = \frac{Q}{t}[/tex]

Where Q is the charge and t is time elapsed.

We substitute our given values into the expression above to determine the time it took the charge to pass through this wire.

[tex]I = \frac{Q}{t}\\ \\5.0A = \frac{30C}{t} \\\\t = \frac{30C}{5.0A} \\\\t = 6.0s[/tex]

Therefore, the time taken for the charge to pass through the cross-section of the wire is 6.0s.

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The time taken by 30 coulombs of charge to pass through this wire is 6 seconds.

The pace at which electrons flow past a point in an electrical circuit is referred to as current.

Current is the ratio of charge and time. Given that the current is equal to 5.0 Amp, while the charge is equal to 30C. Therefore, the time will be equal to,

[tex]I=\dfrac{Q}{t}\\\\5 =\dfrac{30}{t}\\\\t = 6\rm\ sec[/tex]

Hence, the time taken by 30 coulombs of charge to pass through this wire is 6 seconds.

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This is defined as a propagation of disturbances from place to place in a regular and organized way.

The answers provided above are therefore the most appropriate choices in this scenario.

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Answer: Light waves do not require a medium to propagate and As a wave's frequency increases, more energy is carried by the wave in a given time period.

Explanation:

Average acceleration is the change in velocity with time.
Acceleration takes place when velocity changes with time. Velocity being a vector quantity may change in magnitude or direction any of the change results to acceleration

The pace at which a body's velocity varies is represented by average acceleration, which is a vector quantity.

The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The formula for acceleration is;

[tex]\rm a = \frac{v-u}{t}[/tex]

u is the initial speed

v is the final speed

t is the time interval

a is the acceleration of ball

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Answer:

There are 602 calories in 10 ounces of Ground Beef (85% Lean / 15% Fat).  serving sizes of Ground Beef

Explanation:

hope this helps if not please let me now

Answer:

Explanation:

You need to consider the index of refraction.

index of refraction of air: 1.00

index of refraction of water: 1.33

Index of refraction of steel: 2.75681

If the sound wave passed from air into water, it passes from a lower index to a higher index of refraction.

As the wave travels into the more dense medium (higher n), it slows down. Therefore from air to water (lower to higher) it slows down, and from water to steel (n of steel is higher that n of water) therefore it slows down even more.

Answer:

I think is o or mavey it could be D

Answer:

if you doctor suspect that you have COPD , they will calculate your fev1/fvc ratio . this represent the percentage of your lung capacity that you can explain in one second. the higher your percentage , the larger your lung capacity and the healthier your lungs

The ratio  [tex]\frac{FEV1}{FVC}[/tex]  indicates the diameter of an airway. The greater the value, the more quickly air can pass through the airway.

The volume of air in the lungs at different stages of the respiratory cycle is referred to as lung volumes and lung capacities. An adult human male's entire lung capacity is around 6 liters of air.

The ratio  [tex]\frac{FEV1}{FVC}[/tex]  indicates the diameter of an airway. The greater the value, the more quickly air can pass through the airway. As a result, the lower the resistance, the broader the airway becomes.

Hence the lower the resistance, the broader the airway becomes.

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In order to create a magnifier in convex lens, you should choose a short focal length that is lesser than 1 meter.

A convex lens is also referred to as converging lens and it can be defined as a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image.

In Science, a magnifier refer to an optical instrument that allow us to look at a very near object because its image is generally formed farther away. Thus, the image of the object appears to be much larger.

In this context, you should choose a short focal length that is lesser than 1 meter when you want to create a magnifier in convex lens because the nearer the object is to the lens, the larger would be the image formed.

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The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

Given data :

Distance of star from earth = 4.3 light years

Observers time = 3.7 years

Observers time = 3.7 * 365 * 24 * 60 * 60

Distance of star from earth = 4.3 * 9.46 * 10¹⁵

The velocity the spacecraft must travel will be calculated using the equation

V = distance / time

   = ( 4.3 * 9.46 * 10¹⁵ ) / ( 3.7 * 365 * 24 * 60 * 60 )

   = 3.49 * 10⁸ m/s

Hence we can conclude that The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

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Attached below is the missing detail related to the question

The constant velocity must the spacecraft travels from the earth will be 3.49×10⁸ m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Distance of earth from stars = 4.3 light year

The given time = 3.7 year

One year converted into the second as;

[tex]\rm 1 \ year = 3.7 \times 365 \ days \ \times 24 \ hour \times 60 \ minute \times 60 \ sec \\\\ 1 year = 116 \times 10^6 \ sec[/tex]

1 light-year into a kilometer as;

[tex]\rm 4.3 \ light year = 4.3 \times 9.46 \times 10^{15 metre} \\\\[/tex]

At what constant velocity must a spacecraft travel from the earth if it is to reach the star in 3. 7 years,

The velocity of the spacecraft's travel from the earth will be;

[tex]\rm V = \frac{d}{t} \\\\ V= \frac{4.3 \times 9.46 \times 10^{15}}{3.7 \times 365 \times 24 \times 60 \times 60 } \\\\\ V= 3.49 \times 10^8 \ m/sec[/tex]

Hence the constant velocity must the spacecraft travels from the earth will be  3.49×10⁸ m/sec.

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The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

ω = 2π x (5.25 / 3)

ω =  11 rad/s

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

v = 11r m/s

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[tex]\small\color{blue}{⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰}[/tex]

Which best describes an action related to interdependence?

A. limiting the amount of fish harvested to ensure future availability

B. finding methods for extracting oil with minimal damage to the environment

C. using calculations to ensure that lumber is used efficiently

D. predicting the profits from selling metal that is extracted from ore

[tex]\small\color{blue}{⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰}[/tex]

The living things in an ecosystem are interdependent. This means that living things depend on their interactions with each other and also nonliving things for survival. For example, a tree depends on sunlight for energy and food.

[tex]\small\color{blue}{⊱─━━━━━━━━━⊱༻●༺⊰━━━━━━━━━─⊰}[/tex]

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Answer:

open

Explanation:

in open system mechanical energy is lost to its surroundings

The answers to your questions are as listed below

A) The total momentum of the system is :  < - 167, 133, 87 >   kg m/s

B) Velocity of the center of mass of this system : < - 10.44 , 8.31, 5.44 > m/s

C) Total kinetic energy of the system : 5159.5 J  

D) Translational kinetic energy of the system :  1660.84 J

E) kinetic energy relative to the center of mass : 3498.66 J

Given data :

m₁ = 4 kg ,   V₁ = < 10, -5, 15 > m/s

m₂ = 9 kg,   V₂ = < -15, 5, -3 > m/s

m₃ = 3 kg    V₃ = < -24, 36, 18 > m/s.

Total momentum = Σ mv

= < 4*10 + 9*(-15) + 3*(-24), 4*(-5) + 9*5 + 3*36, 4*15 + 9 (-3) + 3*18 >

= < - 167, 133, 87 >   kg m/s

Velocity = < - 167 / 16 , 133/ 16, 87/ 16 >

              =  < - 10.44 , 8.31, 5.44 > m/s

Total Kinetic energy = 1/2 m₁v₁² + 1/2 m₂v₂²  + 1/2 m₃v₃²  --- ( 1 )

where : v² = v₁² + v₂² + v₃²

therefore

Total kinetic energy = 700 + 1165.5 + 3294

                                  = 5159.5 J  

Translational kinetic energy ( Kcm ) = 1/2 ( m₁ + m₂ + m₃ ) * Velocity²

                                                           = 1/2 ( 16 ) * (  - 10.44² + 8.31² + 5.44² )

Hence translational kinetic energy = 1660.84 J

E) The Kinetic energy of the system relative to the center of mass

Krel = Ktotal - Kcm

       = 5159.5 - 1660.84

       = 3498.66 J

Hence we can conclude that the answers to your questions are as listed above.

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