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The possible sources of error that could be given for this experimental outcome is the change in the density of the air.

An experiment simply means the procedure that is carried out in order to refute a particular hypothesis. It should be noted that experiments are important to provide insights into the cause and effect of a particular situation.

In this situation, with every added book, the volume of that air column will reduce. It is just important that the temperature should remain constant when the gas compression is taking place.

Another source of error is the assumption of moles that was assumed was constant during the experiment. In this scenario, it's possible that some gas could have escaped while the compression was taking place.

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Answer:

A. Mass = 61kg, weight on moon = 97.8N

Explanation:

To calculate the weight (force) from Mass of a body, the following formula is used:

W = mg

Where;

W = weight (Newtons)

m = mass (kg)

g = acceleration due to gravity (9.8m/s²)

According to this question, a scale shows that I weigh 600N on Earth, the mass on Earth can be calculated thus:

Using W = mg

m = W/g

m = 600/9.8

m = 61.2

m = 61kg

However, this mass on Earth will weigh differently on the Moon because gravity in the moon is 1.6 N/kg. The weight of the 61kg on the Moon is:

W(moon) = mass × gravity

W = 61 × 1.6

W = 97.6 N

Therefore, Mass = 61kg, weight on moon = 97.8N

Answer:

Atomic number. The atomic number indicates the number of protons within the core of an atom. ...

Atomic mass. The name indicates the mass of an atom, expressed in atomic mass units (amu). ...

Electronegativity according to Pauling. let me know if you need more ;)

Answer:

53.3g/mol

Explanation

Moles=mass/molar mass

Molar mass= mass/moles

Molar mass= 192/3.6

= 53.3

Answer:

The answer is D.

Explanation:

I searched it up :)

Answer:

The pressure of  H₂(g) = 741 torr

Explanation:

Given that:

The atmospheric pressure measured in the lab  = 765 torr

The vapor pressure of water = 24 torr

By applying Dalton's Law of Partial Pressure :

Making The Pressure inside the tube due to the H₂(g) the subject of the formula :

we have:

= (765 -24) torr

= 741 torr

According to ideal gas law and Dalton's law of partial pressure, 0.0136 moles of hydrogen are produced in the reaction.

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.It is applicable to ideal gases which have hypothetical existence.Law was proposed by Benoit Paul Emile Clapeyron.

In the given problem, according to Dalton's law of partial pressure, pressure =765-24=741 torr

Substituting the given values in the ideal gas equation, n=PV/RT

n=741×45.6×10[tex]^-3[/tex]/8.314×298=0.0136 moles.

Thus 0.0136 moles of hydrogen are produced in the reaction.

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Answer:

rocky surface covered with landforms

Explanation:

Answer:

The amount of the first solution rick needs to mix together to create the love portion is 8.5 mL

Explanation:

So as to make the love potion, we have;

The percentage of carbonated water in the love portion = 40%

The percentage of green tea in the first solution = 65%

The percentage of carbonated water in the first solution = 15%

The percentage of whole milk in the first solution = 20%

The percentage of orange juice in the second solution = 17%

The percentage of lemonade in the second solution = 38%

The percentage of carbonated water in the second solution = 45%

Let 'x' represent the volume in mL of the first solution added to make the love portion, and let 'y' be the volume in mL of the second solution added to make the love portion, we have;

x + y = 51...(1)

0.15·x + 0.45·y = 0.40×51 = 20.4

0.15·x + 0.45·y = 20.4...(2)

Solving the system of simultaneous equation by making 'y' the subject of each of the equation gives;

For equation (1)

y = 51 - x

For equation (2)

y = 20.4/0.45 - (0.15/0.45)·x = 136 - 3·x

y = 136/3 - (1/3)·x

Equating the two equations of 'y', gives;

51 - x = 136/3 - (1/3)·x

51 - 136/3 = x - (1/3)·x

17/3 = (2/3)·x

(2/3)·x = 17/3

x = (3/2) × (17/3) = 17/2 = 8.5

x = 8.5

y = 51 - x = 42.5

y = 42.5

Therefore, the amount of the first solution rick needs to mix together to create the love portion, x = 8.5 mL

Answer:

74.08 atm

Explanation:

We'll begin by converting 91.7 kg to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

91.7 kg = 91.7 kg × 1000 g / 1 kg

91.7 kg = 91700 g

Next, we shall determine the number of mole present in 91700 g of methane, CH₄. This can be obtained as follow:

Mass of CH₄ = 91700 g

Molar mass of CH₄ = 12 + (4"1)

= 12 + 4

= 16 g/mol

Mole of CH₄ =?

Mole = mass /Molar mass

Mole of CH₄ = 91700 / 16

Mole of CH₄ = 5731.25 moles

Next, we shall convert 497.9 gallon to litres (L). This can be obtained as follow:

1 gallon = 3.785 L

Therefore,

497.9 gallon = 497.9 × 3.785

497.9 gallon = 1884.55 L

Next, we shall convert 23.7 ˚C to Kelvin temperature. This can be obtained as follow:

T(K) = T(˚C) + 273

T(˚C) = 23.7 ˚C

T(K) = 23.7 °C + 273

T(K) = 296.7 K

Finally, we shall determine the pressure in the tank as follow:

Number of mole (n) = 5731.25

Volume = 1884.55 L

Temperature (T) = 296.7 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 1884.55 = 5731.25 × 0.0821 × 296.7

P × 1884.55 = 139607.92

Divide both side by 1884.55

P = 139607.92 / 1884.55

P = 74.08 atm

Therefore the pressure in the tank is 74.08 atm

Answer and Explanation:

The molar mass of a substance is all of the weights from the elements combined.

So, we have the elements

CU, S, and [tex]O_{4}[/tex]

CU has a mass is 65

S mass is 32

O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.

Now we add.

65 + 32 + 64 is 161.

So, the answer is 160, or answer choice A.

#teamtrees #PAW (Plant And Water)

The pressure is directly proportional to temperature (when the pressure decrease the temperature decrease too). Because the air parcel expands so the molecules will not interact with each other as much.

The energy of the particles does not change but the fact that the particles are more spaced out means the parcel is cooler.

so now, the warmer a parcel of air the more water vapor it can hold. so, if a parcel of air cools it's ability to hold water vapor drops and if it drops to a low enough point that is when the water vapor will condense and turn back into liquid water. This is how clouds and precipitation form on the the windward side of the mountain.

Clouds and precipitation form on the windward side of the mountain due to change in temperature and pressure.

Temperature of any substance is directly proportional to the pressure of that substance.

If the temperature of the wind increases so that winds get warmer and at the same time pressure of gas also increases, due to which particles will go far from each other. After this warm air rises up and cools down will condenses to form clouds, after this precipitate will falls on the windward side of the mountain.

Hence due to temperature and pressure precipitate will form on the windward side of the mountain.​

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Answer:

16 electrons in a sulfur atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and six in shell three.

Explanation:

Answer:

21 Kg of CO.

Explanation:

The balanced equation for the reaction is given below:

Fe₂O₃ + 3CO —> 2Fe + 3CO₂

Next, we shall determine the masses of Fe₂O₃ and CO that reacted from the balanced equation. This can be obtained as illustrated below:

Molar mass of Fe₂O₃ = (56×2) + (16×3)

= 112 + 48

= 160 g/mol

Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO from the balanced equation = 3 × 28 = 84 g

SUMMARY:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Finally, we shall determine the mass of of CO required for the reduction of 40 kg of Fe₂O₃. This can be obtained as follow:

From the balanced equation above,

160 g Fe₂O₃ required 84 g of CO.

Therefore, 40 Kg of Fe₂O₃ will require = (40 kg × 84 g) / 160 g = 21 Kg of CO.

Thus, 21 Kg of CO is required for the reaction.

Answer:

2Fe + 3Cl2 → 2FeCl3

Explanation:

Answer:

Explanation:what’s the answer

Answer: A. With Earth between the Moon and the Sun.

Explanation:

Answer: 248.66g

Explanation:

4.3e24 / 6.23e23 = 6.9 mols O2

6.9(18.02*2)=248.66

Answer:

I think it is C

Explanation:

Answer:

John Dalton

Explanation:

Both John Dalton and Democritus thought that the atom was an indivisible sphere until J.J. Thompson came out with the plum pudding model. Hope I helped!

Answer:

[tex]\% N=82.2\% \\\\\% H=17.8\%[/tex]

Explanation:

Hello there!

In this case, since ammonia is NH₃, we can see nitrogen weights 14.01 g/mol and hydrogen 3.03 g/mol as there is one only nitrogen atom and three hydrogen atoms; thus, the total mass is 17.04 g/mol. In such a way, the percent composition of each element turns out to be:

[tex]\% N=\frac{14.01}{17.04}*100\%=82.2\% \\\\\% H=\frac{3.03}{17.04}*100\%=17.8\%[/tex]

Best regards!

Answer:

The answer is C. six months

Explanation:

I hope this helps you bestie:))

Answer:

correct formula: C2F4

Explanation:

tetra means 4. There are 2 C and 4 F in dicarbon tetrafluoride.

Answer:

3, 9, 3

Explanation:

The coefficient of 3 tells us that there are three molecules (the chemical unit of NH3). Each molecule of ammonia (NH3) is made up of 1 atom of nitrogen bonded to 3 atoms of hydrogen.

Since there are three molecules, we have three times the amount of atoms there are in one molecule.

3 x 1 = 3 nitrogen

3 x 3 = 9 hydrogen

Answer:

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Explanation:

Aluminum sulfate Al₂(SO₄)₃ has a molar mass of 342.15 g/mol.

Molar mass is the amount of mass that a substance contains in one mole of a substance, which can be an element or a compound.

So in this case you can apply the following rule of three: if 342.15 grams are present in 1 mole of aluminum sulfate, how much mass is present in 0.063*10⁻⁴ moles of the compound?

[tex]mass of aluminum sulphate=\frac{0.063*10^{-4}moles*342.15 grams }{1 mole}[/tex]

mass of aluminum sulphate= 2.15*10⁻³ grams

The mass of 0.063*10⁻⁴ moles of aluminum sulphate  is 2.15*10⁻³ grams.

Answer:

stars and lightning. this is the answer ok

Answer:

[tex]0.8\overline 3[/tex] moles of A and 2.5 moles of B in the one-phase system

[tex]1.1 \overline 6[/tex] moles of A and [tex]0.1458 \overline 3[/tex] moles of B in the two-phase system

[tex]0.3541 \overline 6[/tex] moles of B remains in the system

Explanation:

The given parameters are;

The extent of miscibility of liquid B and C = Partially miscible

The number of moles of liquid B added to 1 mole of liquid A that forms a two-phase system = 0.125 mol of liquid B

The number of moles of liquid B added to 1 mole of liquid A that forms a one -phase system = 3 moles of liquid B

Whereby the system consist of 2.5 mol of B and 2 mol of C at 25°C, we have;

The 1 mole of A mixes with 3 moles of B to form a single phase solution

Therefore;

2.5 moles of B will mix with (1/3)×2.5 moles of A = 5/6 moles of A

The remaining number of moles of A in the system = 2 - 5/6 =  7/6 moles of A

Similarly, we have;

At least, 0.125 mole of B combines with 1 mole of A to form a two-phase system

7/6 moles of A will combine with 7/6 × 0.125 = 7/48 moles of B to form a two-phase system

The number of moles of B left = 0.5 - 7/48 = 17/48 = 0.3541[tex]\overline 6[/tex] moles of A

Therefore, we have;

5/6 moles of A and 2.5 moles of B in the one-phase system

7/6 moles of A and 7/48 moles of B in the two-phase system

17/48 moles of B remaining in the system