In 1.4 moles of [tex](NH_4)_3PO_4[/tex], there are approximately 4.2 moles of nitrogen atoms and 16.8 moles of hydrogen atoms.
To determine the number of moles of nitrogen and hydrogen atoms in 1.4 moles of [tex](NH_4)_3PO_4[/tex], we need to analyze the chemical formula. In [tex](NH_4)_3PO_4[/tex], there are three ammonium ions [tex](NH_4^+)[/tex] and one phosphate ion [tex](PO4^3^-)[/tex].
Each ammonium ion consists of one nitrogen atom and four hydrogen atoms. Therefore, in [tex](NH_4)_3PO_4[/tex], there are three nitrogen atoms (from three ammonium ions) and twelve hydrogen atoms (from three ammonium ions).
To calculate the moles, we multiply the number of moles of [tex](NH_4)_3PO_4[/tex] by the respective stoichiometric coefficients. For nitrogen atoms, the coefficient is 3, and for hydrogen atoms, it is 12.
Thus, 1.4 moles of [tex](NH_4)_3PO_4[/tex] multiplied by 3 gives us 4.2 moles of nitrogen atoms. Similarly, multiplying 1.4 moles by 12 gives us 16.8 moles of hydrogen atoms. Therefore, in 1.4 moles of [tex](NH_4)_3PO_4[/tex], there are approximately 4.2 moles of nitrogen atoms and 16.8 moles of hydrogen atoms.
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Potassium sulfate is added to water. The equation that best represents this process
is:
K₂S(s) → K(s) + 2 S(s)
K₂S(s) K(s) + 2 S(s)
K₂SO4(s) → 2 K (aq) + SO4² (aq)
K₂S(s) 2 K (aq) + S² (aq)
K₂SO4(s) 2 K(s) + SO4(g)
K₂S(s)→2 K (aq) + S² (aq)
K₂SO4(s)→2 K(s) - SO4(g)
K₂SO4(s) 2 K (aq) + SO4²(aq)
The equation that best represents the addition of potassium sulfate to water is [tex]K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)[/tex]
Dissolution of potassium sulfate in waterWhen potassium sulfate is dissolved in water, it dissociates into its cation and anion according to the following equation:
[tex]K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)[/tex]
The positive ions are 2 moles of potassium ions while the negative ion is a mole of sulfate ion.
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What is the order in which electrons start filling the orbitals?
a. 1s 2s 2p 3s 3p 4s 3d 4p
b. 1s 2s 2p 3s 3p 3d 4s 4p
c. 1s 2s 2p 3s 4s 3p 3d 4p
d. 1s 2s 2p 3s 4s 4p 3p 3d
e. 1s 2s 2p 3s 4s 3p 4p 3d
a. 1s 2s 2p 3s 3p 4s 3d 4p is the correct option.
This gives the following order to fill the orbit: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, (8s, 5g, 6f, 7d, 8p, and 9s)
Aufbau's principle states that electrons fill low-energy atomic orbitals before they fill high-energy atomic orbitals. .. By following this rule, you can predict the electron configuration of an atom or ion.
There may be two electrons at the maximum of one orbit. Since the s subplane has only one orbit, it can hold up to two electrons. The p subplane has three orbitals, so it can hold up to six electrons. The d-subplane has five orbitals, so it can hold up to 10 electrons.
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What substitute for fossil fuel depletion has been heralded as the solution to the nation’s energy problems??
The renewable energies are the substitute for fossil fuel depletion has been heralded as the solution to the nation’s energy problems.
The benefits of renewable energies to the environment and economic are as follows.
The renewable energies produces less global warming.It also reliable and resilience.The renewable energies helps to improve public health.Through renewable energies ,jobs and other economic gets benefits.The prices of renewable energies is stable.The renewable energies is inexhaustible energy.learn about renewable energies
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Which of the following choices represents a balanced chemical equation?
Answer:
the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3
Explanation:
Noble gases have __ values of ionization energy due to their complete outermost shells
Answer:
high
Explanation:
The energy needed to ionize a neutral atom is known as ionization energy. An atom must have one or more electrons removed from its valence shell in order to get ionized and become a cation. Alternately, you must produce an anion by adding one or more electrons to the valence shell. The energy needed for ionization will be lower the fewer electrons are supplied or withdrawn. As a result, atoms having an incomplete valence shell have a tendency to ionize more quickly and with less energy. However, entire valence shell atoms will require a large amount of ionization energy. As a result, noble gases need significant energy to ionize since they contain a full valence shell, are extremely stable, and do not tend to ionize easily.
What was the purpose of varying the concentrations of sodium alginate and CaCl2?
To determine how stable the beads are as well ensue the securing of maximum enzymes as well as the retention of their activity.
What is concentration?The concentration of a substance simply means the amount of the substance in solution. Thus we are looking at the amounts of sodium alginate and CaCl2 in the system.
The concentrations of the sodium alginate and CaCl2 is varied in order to determine how stable the beads are as well ensue the securing of maximum enzymes as well as the retention of their activity.
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Which statement is true about real gases with the correct reason:
a.
Molecules have volume which causes deviations from ideal gases at high temperature .
b.
Molecules have volume which causes deviations from ideal gases at low temperature.
c.
Molecules have volume which causes deviations from ideal gases at low pressure .
d.
Molecules have volume which causes deviations from ideal gases at high pressure.
Volume of a real gas shows deviation from ideal gas on low temperature and high pressure
Only 2 options are correct then
Molecules have volume which causes deviations from ideal gases at low temperature.Molecules have volume which causes deviations from ideal gases at high pressure.There are 2 possible answers here : b and d.
The Ideal Gas Equation is : PV = nRT
Here, when pressure is increased and temperature is lowered, the volume of the molecules will substantially decrease, which means it has deviated from ideal behavior.
Pls Help!
A sample of seawater from a tidal estuary was found to contain a concentration of 727 mg of chloride ion per kg of seawater. If the density of the sample was 1.035 g/mL, what is the molarity of the chloride ion?
The molarity of the chloride ion is 2.0 * 10⁻⁵ M.
What is the molarity of the chloride ion?The molarity of the chloride ion is calculated using the formula below:
Molarity = (Percentage concentration * Density ) / (Molar mass * 100)The percentage concentration of chloride ion = 727/kg * 10⁻⁶ Kg * 100/1
The percentage concentration of chloride ion = 0.0727%
Molar mass of Chloride ion = 35.5 g/mol
Molarity = (0.0727 * 1.035)/(35.5 * 100)
Molarity of chloride ion = 2.0 * 10⁻⁵ M
In conclusion, the molarity of the chloride ion is obtained from the density and percent concentration of chloride ions in seawater.
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Phosphate buffer solution is purchased as a(n) 10x stock solution. The solution is more concentrated than the working stock. If tasked with making 941 mL of a 1x solution of PBS, how many mL of the stock solution would be needed
94.1 mL of 10x PBS should be needed
Given:
Phosphate buffer solution = 10x
Volume of 1x solution of PBS = 941 mL
To Find:
Volume of stock solution
Solution:
A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. Its pH changes very little when a small amount of strong acid or base is added to it.
using the formula
M1 x V1 = M2 x V2
(10x)* V1 = 1x* 941
V1 = 94.1 ml
So, 94.1 mL of 10x PBS should be needed
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When a water heater thermostat is set at 140 ° f or higher, a ______ should be installed to cool the water.
Tempering Valve should be installed to cool the water.
A tempering valve is also called an anti-scald valve.
The thermostat controls the temperature inside the tank between 120F to 140F.
A thermostat is just a switch that is actuated by temperature. The thermostat will activates one of the elements in response to a "request for heat" when it detects a water temperature below its predetermined point.
At 140 degrees F temperature water can cause a burn to the skin in five seconds.
The Tempering valve is the mixing chamber, where cold water is mixed with hot water.
It functions as a mixing device, mixing hot and cold water to generate the proper water temperature that is emitted from a certain outlet.
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How many molecules of zinc oxide are there in a 2 kg (2,000 g) sample?
Answer:
1.48 x 10²⁵ molecules ZnO
Explanation:
To find the amount of molecules, you need to (1) convert grams to moles (via molar mass) and then (2) convert moles to molecules (via Avogadro's Number). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units.
Molar Mass (ZnO): 65.380 g/mol + 15.998 g/mol
Molar Mass (ZnO): 81.378 g/mol
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
2,000 g ZnO 1 mole 6.022 x 10²³ molecules
--------------------- x ----------------- x --------------------------------------- =
81.378 g 1 mole
= 1.48 x 10²⁵ molecules ZnO
The name of Ra3N₂ is
Answer:
Radium Nitride
What is radium?
A radioactive element is radium. See what "radioactive" actually means.
Atoms make up the elements. Since most atoms are stable, they do not change over time. However, some of the heaviest atoms disintegrate and transform into different types. "Radioactivity" is the term for this breakdown or disintegration.
Each radioactive element releases rays that decay or disintegrate at a specific pace. There is no known way to speed up or slow this rate. Some changes happen quickly, some take longer, but no matter what, man cannot control the action.
In the case of radium, this decay would continue indefinitely until the radioactive material was ultimately converted to lead. For instance, in 1,590 years, half a gram of radium would transform into atoms with a lower atomic weight. Half of the remaining radium would transform after an additional 1,590 years, and so on until all of it turned into lead.
Attachment #1:
This is a revigator. It is a pot that was created specifically with radium, uranium, and other radioactive materials to contain water. When radioactivity was first discovered in 1912, people thought it was beneficial and "magical," similar to how homeopathic treatments are now. They would store water in it to allow it to absorb radiation, then they would drink the water. In the 1930s, several gadgets were subsequently recalled.
The enigmatic new radioactive elements captivated people's curiosity during the early 1900s. Although this starch didn't actually contain radium, it was given that name because of the rarity and beauty of radium. It was once thought of similarly to how titanium is now.
Madame Curie and her husband, Pierre Curie, made the discovery of radium. They were processing a ton of pitchblende, an ore that contains uranium. Although they were aware that the uranium was emitting invisible rays, they had the impression that there was another another, far more potent chemical present. They initially discovered polonium, another radioactive element, before successfully isolating a minute particle of radium.
The three types of rays that radium emits are alpha, beta, and gamma rays. Helium gas contains swiftly moving particles called alpha rays. In beta rays, the electrons move quickly. Gamma rays are similar to X-rays but typically more invasive. Every time one of these rays is emitted, its parent atom transforms into a different element. "Atomic transmutation" is the term for this transformation.
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What is the temperature change the H2O sample
Answer:
5.0 °C
Explanation:
To find the temperature change, you need to use the following equation:
Q = mcΔT
In this equation,
-----> Q = heat energy (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°C)
-----> ΔT = temperature change (°C)
You can find the temperature change by plugging the given values into the equation and simplifying.
Q = 209 J c = 4.18 J/g°C
m = 10.0 g ΔT = ? °C
Q = mcΔT <----- Equation
209 J = (10.0 g)(4.18 J/g°C)ΔT <----- Insert values
209 J = (41.8)ΔT <----- Multiply 10.0 and 4.18
5.0 = ΔT <----- Divide both sides by 41.8
Answer:
5° C temp change
Explanation:
Q = m c T
Given: Q =209 m = 10 c = 4.18 looking for T (change in temp)
209 = 10 * 4.18 T
T = 209 / (10*4.18) = 5° C
Describe the difference between radiopaque and radiolucent. Radiopaque refers to a _______________ or light appearance of a structure on a processed radiograph. Radiolucent refers to a _______________ appearance of a structure on a processed radiograph.
Radiopaque refers to a White or light appearance of a structure on a processed radiograph. Radiolucent refers to a Dark appearance of a structure on a processed radiograph.
What makes something radiodense as opposed to radiolucent?Materials that prevent electromagnetic radiation from passing through are referred to as radiodense or radiopaque, whereas materials that permit radiation to pass more readily are referred to as radiolucent. In contrast to radiolucent volumes, which appear significantly darker on radiographs, radiopaque volumes of material seem white.
What exactly does radiodensity mean?It is the relative inability of radio waves and X-rays to flow through a certain substance. Radiodensity (or radiopacity) is opacity to the radio wave and X-ray portion of the electromagnetic spectrum.
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Lorelai discovers a compound that is 64.8 g C, 13.62 g H, and 21.58 g O. What is the empirical formula of Lorelai's compound
The empirical formula of Lorelai's compound is C₄H₁₀O
Data obtained from the questionC = 64.8 gH = 13.62 gO = 21.58 gEmpirical formula =? How to determine the empirical formulaDivide by their molar mass
C = 64.8 / 12 = 5.4
H = 13.62 / 1 = 13.62
O = 21.58 / 16 = 1.35
Divide by the smallest
C = 5.4 / 1.35 = 4
H = 13.62 / 1.35 = 10
O = 1.35 / 1.35 = 1
Thus, the empirical formula of the compound is C₄H₁₀O
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A balloon filled with air has a volume of 4.24 liters at 23.00°c. if the balloon is cooled at constant pressure to 5.00°c, what is its new volume? the balloon’s volume at 5°c is liters.
The new volume if the balloon is cooled at constant pressure is 3.98 L.
Charles's law, states that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature if the pressure remains constant.
The new volume is calculated using the Charles law formula
V₁ / T₁ = V₂ / T₂
where,
V₁ = The initial volume of air = 4.24 l
T₁ = 23.00 °C into kelvin = 23 +273 =296 K
T₂ = 5.00 °C into kelvin = 5.00 + 273 = 278 K
V₂ = ?
By making V₂ subject the subject of the formula by multiplying both sides by T₂
V₂ = ( V₁ × T₂ ) / T₁
V₂ = (4.24 L × 278 K) / 296 k
= 3.98 L
Therefore, the new volume, if the balloon is cooled at constant pressure, is 3.98 L.
An air-filled balloon will contract when chilled and expand when heated. This occurs because the gas that makes up the air within the balloon expands when it is warm and contracts when it is cool.
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Answer: at 5 its ... 3.98
Explanation:
If a 4L solution is 80% concentrated lime juice and 20% water, how much 30% concentrated lime juice must be added so that the concentration of the resulting solution is 50% concentrated lime juice
The volume of 30% concentrated lime juice that must be added to a 4L solution of 80% concentrated lime juice and 20% water is 6 L.
What are mixtures?Mixtures are substances which are formed when two or more substances are physically combined together.
Mixtures are heterogenous in nature and the constituents can be easily separated.
The volume of 30% concentrated lime juice that must be added to a 4L solution of 80% concentrated lime juice and 20% water, so that the concentration of the resulting solution is 50% concentrated lime juice is determined as follows:
Let the volume of 30% lime juice required be x;
total volume of lime juice = 0.3x
For 80% lime juice, volume of lime juice = 0.8 * 4 = 3.2 L
New volume of lime juice = 4 + x
New amount of lime juice added = 3.2 + 0.3x
Also, new amount of lime juice = 0.5 * ( 4 + x)
3.2 + 0.3x = 0.5 * ( 4 + x)
0.2x = 1.2
x = 6 L
In conclusion, the volume to be added is obtained from the percent concentration.
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Increasing the catalytic stability by optimizing the formation of zeolite-supported Mo carbide species ex situ for methane dehydroaromatization
Answer:
The synthesis of zeolite-supported Mo carbide species was studied by testing different reduction/carburization conditions applied to a zeolite-supported Mo oxide catalyst, with the aim to find the optimized treatment conditions necessary to form stable supported Mo carbide catalysts ex situ for application in methane dehydroaromatization reaction. Four types of treatment were performed and studied using temperature-programmed reduction and carburization profiles: (1) heating the catalyst in a reducing gas, H2, up to reaction temperature and switching to CH4; (2) heating the catalyst in a reducing gas, H2, mixed with dilute CH4; (3) heating the catalyst in CH4 up to reaction temperature; and (4) heating the catalyst in an inert gas (commonly He) up to reaction temperature and then switching to CH4 or to H2 followed by CH4 or to H2/CH4 mixture. Each of these processes were stopped at intermediate points to analyze the phases that were present in order to identify the structural evolution of the supported Mo carbides that originate from the supported Mo oxides. Once the supported carbides were formed, they were quenched under the same gas mixture, and then they were each tested in methane dehydroaromatization via previous heating to reaction temperature in He flow. Despite all of them showing only presence of Mo2C species on HZSM-5, the catalytic properties were dramatically different. Catalysts treated in H2 or CH4/H2 showed remarkably higher stability. These catalysts exhibited a higher Mo dispersion and thus exposure on the active surface.
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In an aqueous solution containing Mn(II) and Mn (IV) salts, which cation would you expect to be the more strongly hydrated
In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.
A chemical event called hydration occurs when two substances interact with water. Since Mn (IV) has a stronger cation with a +4 charge than Mn (II), it will draw more oxygen ions from the Mn(II) in aqueous solution. Mn(IV) will consequently be more intensely hydrated.
Another reason for this is that Mn(IV) ions are often smaller than ions. Now, if we take a look at the element that significantly influences hydration, it is ion size. Therefore, the ion will be more hydrated if it is smaller.
So, In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.
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What is the frequency of an
orange light with a wavelength of 483 nm?
[?] × 10²] Hz
Please explain how to solve as well I’m very confused.
Answer:
6.21 x 10¹⁴ Hz
Explanation:
The frequency can be found using the following equation:
λ = c / f
In this equation,
-----> λ = wavelength (m)
-----> c = speed of light (3.0 x 10⁸ m/s)
-----> f = frequency (Hz)
After converting the wavelength from nm to m, you can plug the given values into the equation and simplify to find the frequency.
483 nm 1 m
--------------- x --------------------- = 4.83 x 10⁻⁷ m
1 x 10⁹ nm
λ = c / f <----- Given equation
4.83 x 10⁻⁷ m = 3.0 x 10⁸ m/s / f <----- Insert values
(4.83 x 10⁻⁷ m) x f = 3.0 x 10⁸ m/s <----- Multiply both sides by f
f = 6.21 x 10¹⁴ Hz <----- Divide both sides by 4.83 x 10⁻⁷
According to the Arrhenius definitions of acids and bases, choose the bases from the list of acids and bases. Check all that apply.
Answer:
a
d
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Answer:
A C D. All the other answers got it wrong for Edg3
Explanation:
How many moles of H2O are in 64.0 g of H2O
Answer:
Explanation:
stoichiometry of C₂H₂ to H₂O is 2:2.
Number of moles of C₂H₂ = molar mass of C₂H₂
Since the molar mass of C₂H₂ is 26 g/mol.
Number of C₂H₂ moles reacted = 64.0 g / 26 g/mol = 2.46 mol.
according to a molar ratio of 2:2.
the number of H₂O moles formed = a number of C₂H₂ moles reacted.
Therefore the number of H₂O moles produced = 2.46 mol
Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. The volume of gas collected is 0.128 L, at a temperature of 297K and a pressure of 762 mm Hg. The vapour pressure of H2O at 297K is 22.4 torr. What is the mass of oxygen collected?
The mass of oxygen collected from the thermal decomposition of potassium chlorate at a temperature of 297 K and 762 mmHg is 0.16 g
How to determine the mole of oxygen producedWe'll begin by obtaining the number of mole of oxygen gas produced from the reaction. This can be obtained by using the ideal gas equation as illustrated below:
Volume (V) = 0.128 L Temperature (T) = 297 KPressure (P) = 762 – 22.4 = 739.6 mmHgGas constant (R) = 62.363 mmHg.L/Kmol Number of mole (n) =?PV = nRT
739.6 × 0.128 = n × 62.363 × 297
Divide both sides by 62.363 × 297
n = (739.6 × 0.128) / (62.363 × 297)
n = 0.0051 mole
Thus, the number of mole of oxygen gas produced is 0.0051 mole
How to determine the mass of oxygen collectedHaven obtain the number of mole of oxygen gas produced, we can determine the mass of the oxygen produced as follow:'
Mole = 0.0051 moleMolar mass of oxygen gas = 32 g/moleMass of oxygen =?Mole = mass / molar mass
0.0051 = mass of oxygen / 32
Cross multiply
Mass of oxygen = 0.0051 × 32
Mass of oxygen = 0.16 g
Thus, we can conclude that the mass of oxygen gas collected is 0.16 g
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Which of the following is the best definition of a chemical change?
A. All of these
B. The ability of something to undergo a change or reaction.
C. A change that alters the identity, or chemical composition, of a substance at the atomic level.
D. Something that can be observed or measured without changing the identity of the substance.
Chemical changes are changes that alter the identity or the chemical composition of substances at the atomic level.
What are chemical changes?When a substance changes chemically, the identity of the substance changes.
In other words, chemical changes are changes that occur to substances such that the entire chemical properties of the substances change.
These changes happen at the atomic levels of substances. Sometimes, the changes can also be physical as well.
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1. A gas occupies 0.60 m3 at a 5.0 atm. If the temperature of the gas remains the same and the pressure decreases to 2.5 atm, what would be the new volume occupied by the gas
The new volume occupied by the gas is 1.2 m³.
Here Boyle's law is applied.
What is Boyle's law?At a constant temperature, the volume of a gas is inversely proportional to the pressure exerted on it.
PV = constant
where,
P = Pressure applied
V = Volume of the gas
Calculation:Given,
P₁ = 5.0 atm
V₁ = 0.60 m³
P₂ = 2.5 atm
To find
V₂ =?
As PV = constant
Therefore,
P₁ V₁ = P₂ V₂
5 × 0.6 = 2.5 × V₂
3 = 2.5 × V₂
V₂ = 3/2.5
V₂ = 1.2 m³
Hence, the new volume occupied by the gas is 1.2 m³.
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HELP PLS PLS PLS ILL MARK U BRAINLIEST
Answer:
2 FeCl3 → 2 Fe + 3 Cl2
Explanation:
2 Fe and 6 Cl on the reactants side, and 2 Fe and 6 Cl on the products side.
Calculate the concentration of a solution if 15 g of salt is added to 170 g of water.
Considering the definition of percentage by mass, the concentration of a solution if 15 g of salt is added to 170 g of water is 8.108 %.
Percentage by massThe percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.
In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
[tex]percentage by mass=\frac{mass of solute}{mass of solution}x100[/tex]
Concentration of the solutionIn this case, you know:
mass of solute= 15 gmass of water= 170 gmass of solution= mass of solute + mass of water= 15 + 170 g= 185 gReplacing in the definition of percentage by mass:
[tex]percentage by mass=\frac{15 grams}{185 grams}x100[/tex]
Solving:
percent by mass= 8.108 %
Finally, the concentration of a solution if 15 g of salt is added to 170 g of water is 8.108 %.
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HELPPP!!! how do i solve this
8. What mass of sodium hypochlorite (NaClO) is required to prepare 1.5 L of chlorine bleach, if the bleach is a 0.70 mol/L solution of sodium hypochlorite? Show your work and explain each step. The molar mass of sodium hypochlorite is 74.44 g/mol.
9. What is the final concentration when 420 mL of a 12.0 mol/L sodium hydroxide solution is diluted to 2.0 L? Show your work and explain each step.
Taking into account the definition of molarity, molar mass and dilution:
the mass of sodium hypochlorite (NaClO) required is 78.162 grams.the final concentration of a sodium hydroxide solution is 2.52 mol/L.Definition of molarityMolar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
[tex]molarity=\frac{number of moles}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{L}[/tex].
Definition of molar massThe molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
Mass of sodium hypochlorite (NaClO)If the bleach is a 0.70 mol/L solution of sodium hypochlorite and is required to prepare 1.5 L of chlorine bleach, replacing in the definition of molarity you get:
0.70 [tex]\frac{moles}{L}[/tex]=[tex]\frac{number of moles}{1.5 L}[/tex]
Solving:
0.70 [tex]\frac{moles}{L}[/tex]× 1.5 L= number of moles
1.05 moles= number of moles
The molar mass of sodium hypochlorite is 74.44 g/mol. So you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 74.44 grams, 1.05 moles of the compound contains how much mass?
[tex]mass=\frac{1..05 molesx74.44 grams}{1 mole}[/tex]
mass= 78.162 grams
Finally, the mass of sodium hypochlorite (NaClO) required is 78.162 grams.
DilutionDilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal concentration of sodium hydroxide solutionIn this case, you know:
Ci= 12 mol/LVi= 420 mLCf= ?Vf= 2 L= 2000 mL (being 1 L= 1000 mL)Replacing in the definition of dilution:
12 mol/L× 420mL= Cf× 2000 mL
Solving:
(12 mol/L× 420mL)÷ 2000 mL= Cf
2.52 mol/L= Cf
In summary, the final concentration of a sodium hydroxide solution is 2.52 mol/L.
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dilution:
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In the reclassify transactions screen, which 3 elements of a transaction can be reclassified?
The 3 elements of a transaction that can be reclassified are:
Account, Location ClassOn an account transaction screen, one can see there are different elements that exist and some of them are:
invoices, sales receipts, checks, or bills, etcWhat is a Transaction?This refers to the proof that exists that a person has bought a good or service and can also stand as an agreement.
Hence, we can see that On an account transaction screen, one can see there are different elements that exist and some of them are:
invoices, sales receipts, checks, or bills, etcHowever, there are only 3 elements that can be reclassified on the reclassify transactions screen and they are:
Account, Location ClassRead more about transactions here:
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Tin and oxygen can combine to form two compounds of different combining proportions. Resulting formulas of these compounds include
a. Sn2O and SnO2 d. SnO and SnO3
b. SnO and SnO2 e. SnO2 and SnO4
c. SnO4 and SnO
???
Answer:
B.) SnO and SnO₂
Explanation:
Tin can either exist as Sn²⁺ or Sn⁴⁺ when ionized. Oxygen always exists as O²⁻ when ionized.
When ions combine, sometimes there needs to be different amounts of each ion in order to create an overall charge of 0. In one combination of the ions (Sn²⁺ and O²⁻), there only needs to be one atom of each ion. In another combination (Sn⁴⁺ and O²⁻), you need to have more anions to balance the high positive charge of the cation.
SnO
-----> Sn²⁺ and O²⁻
-----> +2 + (-2) = 0
SnO₂
-----> Sn⁴⁺ and O²⁻
-----> +4 + (-2) + (-2) = 0