If AABC = ADEC,
ZB = 2x + 31 and ZE = 7x - 24
A
D
B
E
x = [?]

Answer:

if you search the Question up the fist thing to pop up should say Gr7_Math_Revision_T2. on the 7th page your answer, I think. is there

Step-by-step explanation:

Step 1

Write and solve the inequality:

2,500 + 40a ≥ 4,000, or 40a ≥ 1,500

a ≥ 37.5

Step 2

If the shelter places 30 cats and 10 dogs,

or 40 animals, that will be enough to meet

its goal, because a = 40 is a solution to the

inequality a ≥ 37.5.

Answer:That’s um tuff

Step-by-step explanation:

Answer:

below if you cant read it, it takes 80 quarters

Step-by-step explanation:

Answer:3/4*5=3 3/5

Step-by-step explanation:

Answer:

Yes, because the beginning number has to be between 1 and 10. If there is a 10 in the ones place, move the decimal to the left and increase the power.

Answer: Yes ido

Step-by-step explanation:

Answer:

A) 0.58

B)  58/100

Step-by-step explanation:

Can i have brainliest if its right :)

Answer:

biologists have a 14ft john boat with trolling motor for sale or trade for hipnopotomus

Answer:

false

Step-by-step explanation:

Answer:

13 protons

14 neutrons

13 electrons

Step-by-step explanation:

protons and electrons are mostly always the same

Answer:

Number of Protons 13

Number of Neutrons 14

Number of Electrons 13

Answer:

45

Step-by-step explanation:

Answer:

The question is not complete, fortunately, I found a match:

Tran planned a rectangular pool and made a scale drawing using centimeters as the unit of measurement. he originally planned for the length of the pool to be 40 m but decided to change it to 32 m. if the length of the pool in his scale drawing is 8 cm, which statement about the change of scale is true?

one cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

one cm represented 40 m in the first scale, but now 1 cm represents 32 m in the second scale.

one cm represented 1 m in the first scale, but now 1 cm represents 5 ft in the second scale.

one cm represented 4 m in the first scale, but now 1 cm represents 5 m in the second scale.

answer:

one cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

Step-by-step explanation:

To calculate the scaling factor, we will divide the actual figure by the figure in the scale.

Before the change: 8cm in the drawing represents 40m

8cm ≡ 40m

∴ 1cm ≡ 40 ÷ 8 = 5m

∴ 1 cm represents 5m

After the change: 8cm in the drawing represents 32m

8cm ≡ 32m

∴ 1cm ≡ 32 ÷ 8 = 4

∴ 1cm represents 4m

Therefore, one cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

Answer:

It’s the first choice

Step-by-step explanation:

Answer:

The answer is C because 40% of 1450 is 580.

Answer:

1 solution

Step-by-step explanation:

A solution to a system of linear equations is where the two lines meet. In this case, the system only intercepts each other once, therefore it only has 1 solution.

Answer:

D

Step-by-step explanation:

If you match what the numbers say you will see the answer is D

[tex] = \frac{ - 1}{ \: \: 2} x + 2 = x + 7[/tex]

[tex] = \frac{ - 1}{ \: \: \: 2} x + 2 - x = 7[/tex]

[tex] = \frac{ - 3}{ \: \: \: 2}x + 2 = 7[/tex]

[tex] = \frac{ - 3}{ \: \ \: 2}x = 7 - 2 [/tex]

[tex] = \frac{ - 3}{ \: \: \: 2} x = 5[/tex]

[tex] x = 5 \: \div \frac{ - 3}{ \: \: \: 2} [/tex]

[tex]x = 5 \times \frac{ \: \: \: 2}{ - 3} [/tex]

[tex]x = \frac{ - 10}{ \: \: \: 3} [/tex]

[tex]∴ \frac{ - 1}{ \: \: \: 2} \times \frac{ - 10}{ \: \: \: 3} = \frac{ - 10}{ \: \: \: 3} + 7

[/tex]

Answer:

-5

Step-by-step explanation:

h(-2)=3(-2)+1

= -6+1

= -5

hope this help you!! :))))))

Answer:

17.7 meters

Step-by-step explanation:

x = 30

15 + 0.09*30

0.09*30 = 2.7

2.7 + 15 = 17.7 meters

Answer:

7

Step-by-step explanation:

Answer:10 watermelons

Step-by-step explanation:

Answer:

the person above me was correct

Step-by-step explanation:

btw it was c

Answer: C

Step-by-step explanation: I took the quiz yesterday

Answer:

f(5) = 82

Step-by-step explanation:

To evaluate f(5) substitute x = 5 into f(x) , that is

f(5) = 3(5)² + 7 = 3(25) + 7 = 75 + 7 = 82

Answer:

If it does not cross the x axis.

Step-by-step explanation:

If the quadratic equation does not cross the x axis (or more specifically, if the quadratic is an upward opening parabola and the vertex is above the x axis, or if the quadratic is a downward opening parabola and the vertex is below the x axis), it will have no real solution

The fundamental theorem of algebra says that quadratics must have 2 solutions, so the solutions must be imaginary.

Answer:

x > 83 / 3

Step-by-step explanation:

Let's solve your inequality step-by-step.

3x+5>88

Step 1: Subtract 5 from both sides.

3x+5−5>88−5

3x>83

Step 2: Divide both sides by 3.

3x/3 > 83/3

x > 83/3

Answer:

The largest area she can enclose for her garden with this fencing is [tex]56 ft^2[/tex]

Step-by-step explanation:

Suppose the rectangular space Mrs. Greene wants to plant has dimensions x feet and y feet.

Since each section of fencing is 1-foot long, both x and y must be integer numbers.

The perimeter of the rectangular space is calculated as:

P = 2x + 2y

And we know she uses all 30 sections of fencing, thus:

2x + 2y = 30, where x, y are integers and positive.

Simplifying by 2:

x + y = 15

Solve for x:

x = 15 - y

This equation doesn't have infinitely many solutions, since both numbers must be integers and positive. Suppose we start by setting y=1, then x=14. That is a possible arrangement for the garden.

Another valid option is for y=2, x=13

Continuing with these patterns, we find the maximum value for y is 7, x=8, because if we set y=8, x=7, this is the same condition as y=7, x=8.

Thus, from y=1 to y=7, there are 8 possible combinations for the arrangement of the garden.

The area of a rectangle is

[tex]A=x\cdot y[/tex]

Testing some possible arrangements:

y=1, x=14

[tex]A=1\cdot 14= 14 ft^2[/tex]

y=2, x=13

[tex]A=2\cdot 13= 26 ft^2[/tex]

y=3, x=12

[tex]A=3\cdot 12= 36 ft^2[/tex]

We can notice the combination y=7, x=8 has an area of:

[tex]A=7\cdot 8= 56 ft^2[/tex]

This is the largest possible area of all combinations, thus:

The largest area she can enclose for her garden with this fencing is [tex]56 ft^2[/tex]

Answer:

a ≥ [tex]-\frac{64}{3}[/tex]

Step-by-step explanation:

You would solve this exactly as if the ≥ sign was an equal sign:

[tex](\frac{3}{4} )a[/tex] ≥ [tex]-16[/tex]   [Given]

3a ≥ -64   [Multiply 4 on both sides of the sign]

a ≥ [tex]-\frac{64}{3}[/tex]   [Simplify]

Hope this helps! I apologize if I'm incorrect

Answer:

Yes, he did

Step-by-step explanation:

We have that:.

Total time = 45

At time t, he moves at 8mph.

This gives: 8t

The time left is: 45 - t and he moves at 5mph, this gives 5(45 - t).

Hence, the total is

8t + 5(45 - t)

By comparison, we can conclude that Larry modeled the situation correctly.