if f'(x) = x^2/1 x^5 and f(1)=3 then f(4)

Answers

Answer 1

Therefore, the value of function f(4) is: f(4) = ln (1025^(1/5) * e^15 / 2) - ln 2^(1/5) ≈ 20.212.

We can solve this problem by integrating the given derivative to obtain the function f(x), and then evaluating f(4).

From the given derivative, we can see that f'(x) can be written as:

f'(x) = x^2 / (1 + x^5)

To find f(x), we integrate both sides of the equation with respect to x:

∫ f'(x) dx = ∫ x^2 / (1 + x^5) dx

Using substitution, let u = 1 + x^5, so that du/dx = 5x^4 and dx = du / (5x^4).

Substituting these into the integral, we get:

f(x) = ∫ f'(x) dx = ∫ x^2 / (1 + x^5) dx

= (1/5) ∫ 1/u du

= (1/5) ln|1 + x^5| + C

where C is the constant of integration.

To determine the value of C, we use the initial condition f(1) = 3. Substituting x = 1 and f(x) = 3 into the above expression for f(x), we get:

3 = (1/5) ln|1 + 1^5| + C

C = 3 - (1/5) ln 2

So the function f(x) is:

f(x) = (1/5) ln|1 + x^5| + 3 - (1/5) ln 2

To find f(4), we substitute x = 4 into the expression for f(x):

f(4) = (1/5) ln|1 + 4^5| + 3 - (1/5) ln 2

= (1/5) ln 1025 + 3 - (1/5) ln 2

= ln (1025^(1/5) * e^15 / 2) - ln 2^(1/5)

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

simply substitute the constants with 5 and 3.

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

Given the quadratic equation X^2+10x+22=13

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x^2+10x = -9

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coefficient of x = 10

half of coefficient of x = 10/2 = 5

square of half of coefficient of x= 5² = 25

Add 25 to both sides

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(x+5)² = 16

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Answer:

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Answers

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Answers

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Answer:

Answer

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x

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Rewrite the formula to find the width of the base of the prism if the volume, length of the base, and height of the prism are already known.

volume of a rectangular prism,V = lwh

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h = height of the prism

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Answers

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Step-by-step explanation:

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