If I have 5.0 moles of bromine gas that is kept at 46.7 oC in a 1.4 L container, what is the pressure of the container? (R = 0.0821 (L*atm)/(mol*K))

Round your answer to 1 decimal place.

Answers

Answer 1

The pressure of the container is approximately 94.0 atm when there are 5.0 moles of bromine gas at a temperature of 46.7°C in a 1.4 L container.

To determine the pressure of the container, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15:

T = 46.7 + 273.15 = 319.25 K

Next, we can substitute the given values into the ideal gas law equation:

PV = nRT

P * 1.4 L = 5.0 mol * (0.0821 (Latm)/(molK)) * 319.25 K

Simplifying the equation:

P * 1.4 L = 131.4935 (L*atm)

Dividing both sides of the equation by 1.4 L:

P = 131.4935 (L*atm) / 1.4 L

P ≈ 94.0 atm

Therefore, the pressure of the container is approximately 94.0 atm when there are 5.0 moles of bromine gas at a temperature of 46.7°C in a 1.4 L container.

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