Isabelle takes the bus to work. The bus ride to work costs her $2.50 each time. She could buy a bus pass for a one-time fee of $15.00 and would then only pay $1.00 each time to ride the bus. How many times would she have to take the bus for the cost to be the same?

y = total cost

x = amount of times she takes the bus

Let's create two equations to model the data in the problem above.

y = $2.50x

y = $1x + $15

Now, let's set them equal to each other and solve for x.

$2.50x = $1x + $15

Subtract $1x from both sides.

$1.50x = $15

Divide both sides by $1.50

x = 10

She would have to ride the bus 10 times for the cost to be equal.

Answer:

10 Trips

Step-by-step explanation:

Create 2 algebraic Equations, X is the number of trips and y is the total cost. y=2.5x, and y=x+15. Set them equal to eachother and solve for X.  2.5X=X+15. Subtract X from both sides to get 1.5X=15. Divide by 1.5 to get 10.  X=10, 10 Trips!

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