Jason’s utility and telephone bills for the month totaled $180. The utility bill was 3 times as much as the telephone bill. How much was each bill?

Answers

Answer 1

Answer:

telephone was $45, utility was $135

Step-by-step explanation:

Let the telephone bill be x, then the utility bill is 3x

3x+x = 180

4x = 180

x = 45

3x = 135


Related Questions

During the winter, if the low temperature outside is a °C, the daily cost to heat a
building can be determined using the function f(x) = 5 (1.3) * . Find and
interpret the given function values and determine an appropriate domain for the function.
round all function values to the nearest hundredth.
f:7)= __, meaning when the low temp outside is __ celsius it would cost $__ to heat the building. this interpretation _______________ in the context of your problem.
f(9.5)=___, meaning when the low temp outside is ___ celsius it would cost & __ to heat the building. this interpretation _______________ in the context of the problem.
based on the observations above it is clear that an appropriate domain for the function is —————
PLEASE HELP

Answers

The values of the function are 5 and 1.5 and the domain is,

⇒ - ∞ < x < ∞

Here, The equation of the function is given as

f(x) = 5 (1.3)ˣ

The above function is an exponential function.

An exponential function is represented as

f(x) = abˣ

Where

a represents the initial value, b represents the rate of growth or decay

While x and f(x) are the input and output values

Hence, By comparison, we have

a = 5 and b = 1.3

This means that the function values are 5 and 1.3.

Since, the function is an exponential function.

The domain of an exponential function is the set of all real values

Hence, the domain of f(x) is the set of all real values.

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Find the Value of x. Round to the nearest tenth.

hyp = x
28°
11​

Answers

The calculated value of x in the right triangle is 12.5

How to calculate the value of x

From the question, we have the following parameters that can be used in our computation:

The right triangle

The value of x can be calculated using the following cosine rule

So, we have

cos(28) = 11/x

make x the subject of the formula

So, we have

x = 11/cos(28)

Evaluate the quotient

This gives

x = 12.5

Hence, the value of x is 12.5

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50 Points! Multiple choice geometry question. Photo attached. Thank you!

Answers

Answer:

5/4 = h/44, so h = 55

The height of the tree is 55 feet.

D is correct.

A researcher performed an experiment with two groups. She found the difference of the means for each group. Then
she combined the groups, chose two new groups, and found the difference between the means of those groups. She
repeated this process 200 times. The normal distribution of the difference in the means she found is given below. How
great would the difference in means between the first two groups have to be in order to be considered significant?
At least 8
O At least 10
At least 9
At least 7

Answers

Answer:

Step-by-step explanation:

To determine the significance level for the difference in means between the first two groups, we need to refer to the provided normal distribution. However, you haven't provided the details or parameters of the normal distribution, such as the mean and standard deviation. Without this information, it is not possible to determine the exact significance level required.

In hypothesis testing, the significance level, typically denoted as α (alpha), is chosen by the researcher before conducting the experiment. It represents the threshold at which the researcher considers the results to be statistically significant. Commonly used significance levels are 0.05 (5%) or 0.01 (1%).

Please provide the necessary parameters or more information about the normal distribution to determine the specific significance level for the difference in means between the first two groups.

Simplify > (x)3(−x3y)2

−x9y2

x5y2

−x6y2

x9y2

Answers

The simplified expression of the expression (x)³(−x³y)² is x⁹y²

Simplyfing the expression using the common factor

From the question, we have the following parameters that can be used in our computation:

(x)3(−x3y)2

Express properly

So, we have

(x)³(−x³y)²

Open the brackets

(x)³(−x³y)² = x³ * x⁶y²

Multiply (x)³ and x⁶ in the expression

So, we have the following representation

(x)³(−x³y)² = x⁹y²

Hence, the simplified expression is x⁹y²

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b) tan 2A cot A-1 = sec 2A

Answers

The trigonometric equation is tan 2A cot A-1 = sec 2A

We have to prove the trigonometric equation

tan 2A cot A-1 = sec 2A

Now let us take LHS

tan 2A cot A-1  

2tanA/1-tan²A - 1 . cotA - 1

2-1+tan²A/1-tan²A

1+tan²A/1-tan²A

sec2A

Hence, the trigonometric equation is tan 2A cot A-1 = sec 2A

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Tell whether the given value is a solution to the inequality.

y + 5 > 8l; y = 1

Answers

The solution of the inequality equation is determined as y > 3.

What is the solution of the inequality equation?

A solution for an inequality in y is a number such that when we substitute that number for y we have a true statement.

For the given inequality equation, which is;

y + 5 > 8

The solution of the inequality equation is calculated as follows;

y + 5 > 8

Subtract 5 from both sides of the equation as shown below;

y + 5 - 5 > 8 - 5

y > 3

The solution of the inequality equation is determined as 3, so we can conclude that any value less than  3 is not true and the proposed solution of 1 is not true or correct for the inequality equation.

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The product of a number and five added to 17

Answers

Answer:

The phrase "The product of a number and five added to 17" can be represented mathematically as:

5x + 17

In this expression, 'x' represents the unknown number. The product of the number and five is calculated by multiplying the number by 5, and then 17 is added to the result.

Write the equation of a line perpendicular to the one above that passes through (-2, 9). You may use either slope intercept or point slope form.

Answers

Answer:

-3x + 3

Step-by-step explanation:

To find the equation of a line perpendicular to the line passing through (-2, 1) and (4, 3), we need to determine the slope of the original line first. Then, we can use the negative reciprocal of that slope to find the slope of the perpendicular line. Finally, we can use the point-slope form to write the equation of the perpendicular line.

Step 1: Find the slope of the original line.

Slope (m) = (change in y) / (change in x)

m = (3 - 1) / (4 - (-2))

m = 2 / 6

m = 1/3

Step 2: Determine the slope of the perpendicular line.

The slope of the perpendicular line is the negative reciprocal of the original line's slope.

Perpendicular slope = -1 / (1/3)

Perpendicular slope = -3

Step 3: Use the point-slope form to write the equation.

The point-slope form is given by:

y - y1 = m(x - x1)

Using the point (-2, 9) and the perpendicular slope (-3), we can write the equation as:

y - 9 = -3(x - (-2))

y - 9 = -3(x + 2)

y - 9 = -3x - 6

y = -3x + 3

Therefore, the equation of the line perpendicular to the line passing through (-2, 1) and (4, 3) and passing through (-2, 9) is y = -3x + 3.

Cameron surveyed her friends about the number of apps they use. The responses were 15, 16, 18, 9, 18, 4, 19, 20, 17, and 36 apps. Use the range and interquartile range to describe how the data vary.

Answers

The middle half of the data values vary by:

Interquartile = [tex]Q_3-Q_1[/tex] =>  19.25 - 13.5 = 5.25

The given data is :

15, 16, 18, 9, 18, 4, 19, 20, 17, and 36 apps.

We have to find:

Use the range and interquartile range to describe how the data vary.

We have to arrange the data from smallest to largest.

4, 9, 15, 16, 17, 18, 18, 19, 20, 36

Range of the data is : Highest no. - lowest no.

Range of the data is: 36 - 4 = 32

The location of the [tex]Q_1[/tex] = (n + 1) × 0.25 (where n is the total no. in the data)

The location of the [tex]Q_1[/tex] = (10 + 1)  × 0.25 = 11  × 0.25 = 2.75

∴[tex]Q_1[/tex] = 15 × 0.75 + 9 × 0.25  = 13.5

The location of the [tex]Q_3[/tex] = (n + 1) × 0.75

The location of the [tex]Q_3[/tex] = 11 × 0.75 = 8.75

∴[tex]Q_3[/tex] = 19 × 0.75 + 20 × 0.25 = 19.25

Hence, The middle half of the data values vary by:

Interquartile = [tex]Q_3-Q_1[/tex] =>  19.25 - 13.5 = 5.25

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100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!

Answers

From the relationship of AC bar ≅ BD bar, we can tell that ABCD is a rectangle.

How is this a rectangle ?

A quadrilateral with two sets of parallel sides is known as a parallelogram.

If ABCD is a parallelogram where AC and BD have equal lengths, then the opposite sides of ABCD are also equal. ABCD has two sets of sides that are parallel and have the same length.

The fact that ABCD possesses two sets of sides that are parallel and of equal length logically leads to the conclusion that it also has four angles that are right. One reason for this is that the angles opposite each other in a parallelogram are of equal measure, while the sum of the angles at each corner of a parallelogram is always 180 degrees.Therefore, ABCD is a rectangle.

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5. [0.5/1 Points] DETAILS PREVIOUS ANSWERS SALGTRIG4 7.3.112.
A rectangle is to be inscribed in a semicircle of radius 4 cm as shown in the following figure.
10
4 cm-
(a) Find the function that models the area of the rectangle.
A(0) = 16 sin (20)
Need Help? Read It
MY NOTES
4
ASK YOUR TEACHER
(b) Find the largest possible area for such an inscribed rectangle. [Hint: Use the fact that sin(u) achieves its maximum value at u=/2.]
16
cm²
(c) Find the dimensions of the inscribed rectangle with the largest possible area. (Round your answers to two decimal places.)
smaller dimension 2
x cm
larger dimension 25
x cm
PR.

Answers

The Area function [tex]A(x) = 2x * \sqrt(16 - x^2).[/tex]

How to solve

(a) For a rectangle inscribed in a semicircle of radius 4 cm, let half-length be x and height be y.

Therefore, the Area function [tex]A(x) = 2x * \sqrt(16 - x^2).[/tex]

(b) Maximum area occurs when x = [tex]4 * sin(\pi/4), so A(4 * sin(\pi/4)) = 16 cm^2.[/tex]

(c) Dimensions for the largest inscribed rectangle are smaller dimension (height) ≈ of 2.83 cm, a larger dimension (base) ≈ of 5.66 cm.

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The length and breadth of a rectangular flower bed are 16m and 9 m, respectively. How many plants can be planted in it, if each plant requires a space of 1.2m x 1m?​

Answers

The calculated number of plants the flower bed can contain is 120

Calculating hw many plants can be planted in it

From the question, we have the following parameters that can be used in our computation:

Dimensions = 16 m by 9 m

So, the area of the flower bed is

Area = 16 * 9

Evaluate

Area =  144

Also, we have

Each plant requires a space of 1.2m x 1m?

This means that

Plant area = 1.2 * 1

Plant area = 1.2

So, we have

Plants = 144/1.2

Evaluate

Plants = 120

Hence, the number of plants is 120

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Answer:

Step-by-step explanation:

To calculate the number of plants that can be planted in the rectangular flower bed, we need to calculate the area of the flower bed and divide it by the space required for each plant.

The area of the flower bed is calculated by multiplying its length and breadth.

So, the area of the flower bed is 16m x 9m = 144 sq.m.

Each plant requires a space of 1.2m x 1m = 1.2 sq.m.

Therefore, the number of plants that can be planted in the flower bed is:

144 sq.m. ÷ 1.2 sq.m./plant = 120 plants.

So, you can plant 120 plants in the rectangular flower bed.

solve for v, PV/T=pv/t

Answers

No matter the values of P, V, T, p, and t, as long as the equation PV/T = pv/t holds true, the solution for v is always equal to V.

To solve for v in the equation PV/T = pv/t, we can manipulate the equation to isolate v on one side.

Starting with the given equation:

PV/T = pv/t

To isolate v, we can cross-multiply:

PVt = pVt

Next, we divide both sides of the equation by pt:

V = v

Therefore, the solution is v = V.

In other words, v is equal to V, which means they represent the same values.

This implies that v and V are interchangeable and can be used interchangeably in the equation.

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e
B
0
14. The table shows the number of inches of
rain over five months. What would be an
appropriate display of the data? Explain.
(Lesson 2)
Month
Number
of Inches
of Rain
Jan. Feb. Mar.
1.5
2.2
3.6
Apr.
5.3
May
4.8

Answers

The graph of the given function is attached.

Given is a function for the rainfall in 5 months in inches.

We need to display the data,

So, as we can see that the data is not showing any proportion or pattern,

So, it can be displayed as a line chart.

Hence the chart is attached for the function.

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-49 = 7i, what number is the i.

Answers

Answer:

-7

Step-by-step explanation:

divide by 7 on both sides and you get i = -7

Please help due 5 min!!!!

Answers

The midsegments of a trapezoid is parallel to each base, and its length is one-half the sum of the lengths of the bases

................................................

Answers

Answer:

4,12,36,108,324.....

Step-by-step explanation:

The sequence represented by the equation [tex]a=4(3)^{n-1}[/tex]is a geometric sequence with first term 5 and common ratio 3. The first 4 terms of the sequence are:

[tex]a_1 = 4(3)^{1-1} =4(3)^0 = 4[/tex]

[tex]a_2 =4(3)^{2-1} = 4(3)^1 = 12[/tex]

[tex]a_3 =4(3)^{3-1} = 4(3)^2 = 36[/tex]

[tex]a_4 = 4(3)^{4-1} =4(3)^3 = 108[/tex]

[tex]a_5=4(3)^{5-1} =4(3)^4=324[/tex]

The sequence can be written as:

[tex]a_n = 4(3)^{n-1}[/tex]

where n is the term number.

Therefore, the sequence is 4,12,36,108,324.....

Answer:

The answer is 4,12,36,108,324

Step-by-step Explanation:

a1=4(3)¹‐¹=4(3)⁰=4

a2=4(3)²‐¹=4×3=12

a3=4(3)³‐¹=4(3)²=4×9=36

a4=4(3)⁴‐¹=4(3)³=4×27=108

a5=4(3)⁵‐¹=4(3)⁴=4×81=324

Identify the sequence graphed below and the average rate of change from n = 1 to n = 3.

coordinate plane showing the points 2, 10, point 3, 5, point 4, 2.5, and point 5, 1.25

a
an = 20(one half)n − 1; average rate of change is fifteen halves

b
an = 10(one half)n − 1; average rate of change is fifteen halves

c
an = 20(one half)n − 1; average rate of change is negative fifteen halves

d
an = 10(one half)n − 1; average rate of change is negative fifteen halves

Answers

The sequence based on the information would be: B. an = [tex]10 1/2^{-1}[/tex]average rate of change is negative fifteen halves.

How to explain the function

This question is about exponent function/series. You are given 3 points from the function, point A (1,10), point B( 2, 5), and point  C(4,1.25).  

If you insert point A to the function, an will give a result of 10 for n=1.

For n=0, the result would be:

an= 10([tex]1/2^{-1}[/tex])

= 10 * 2

= 20

Then the average rate of change from n=0 to n=2 would be:

Rate of change= (y₂ -y₁)/ (x₂ -x₁)

Rate of change= (5-20)/ (2-0)

= -15/2

= negative fifteen halves

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17 in. 16 in. 14 in.​

Answers

The surface area of the rectangular prism is 1468 square inches

What is the surface area of the rectangular prism?

From the question, we have the following parameters that can be used in our computation:

17 in by 16 in by 14 in

The surface area of the rectangular prism is calculated as

Area = 2 * (17 * 16 + 17 * 14 + 16 * 14)

Evaluate

Area = 1468

Hence, the area is 1468 square inches

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Question

What is the surface area of this rectangular prism?

17 in. by 16 in. by 14 in.​

3.3.4√20+5-43 calculate ​

Answers

Here are the steps to calculate the expression √20 + 5 - 43 :

Step 1: Simplify the square root of 20:

[tex]\sqrt{20}[/tex]

Step 2: Calculate the value of the square root:

[tex]\sqrt{20} = 2\sqrt{5}[/tex]

Step 3: Substitute the value of the square root into the expression:

[tex]2\sqrt{5} + 5 - 43[/tex]

Step 4: Perform addition:

[tex]2\sqrt{5} + 5 = 2\sqrt{5} + \frac{5}{1} = \frac{2\sqrt{5} + 5}{1}[/tex]

Step 5: Perform subtraction:

[tex]\frac{2\sqrt{5} + 5}{1} - 43 = \frac{2\sqrt{5} + 5 - 43}{1}[/tex]

Step 6: Simplify the numerator:

[tex]\frac{2\sqrt{5} - 38}{1}[/tex]

Step 7: Simplify the expression:

[tex]2\sqrt{5} - 38[/tex]

Therefore, the calculation √20 + 5 - 43 simplifies to 2√5 - 38.

A popular brand has introduced a new design of jeans. All major stores have stocked the jeans because the brand usually sells very well. But the cost of these jeans is much higher than those of other brands, so people don't buy them.

Answers

The price of the jeans will decrease because supply is greater than demand hence the stores will sell them at discounted prices.

How do we calculate?

The store owners would be forced to cut pricing if the jeans weren't purchased at all or as frequently as the other brands. Either they choose that choice, return the goods if possible  or just toss the jeans away. It generally takes some trial and error to determine the proper price.

For instance, the owner may lower the price to $75 and test whether the 25% discount works or not if the jeans initially sell for $100 and nobody buys them for a week.

The price might remain there if people continue to buy and if not, the cost might decrease even further.

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Will give you brainly! :) Thank you for taking time out of your day to answer this!​

Answers

The probability values are P(30 ≤ Amount ≤ 59) = 0.43, P(Amount ≥ 60 or Amount < 30) = 0.57 and P(Amount ≥ 40) = 0.45

Calculating the probability values

At least $30 but not more than $59

This means that we use the money spent from 30 to 59

So, we have

30 to 59 = 76 + 58 + 67

30 to 59 = 201

Total = 85 + 98 + 201 + 84

Total = 468

Next, we have

P(30 ≤ Amount ≤ 59) = 201/468

P(30 ≤ Amount ≤ 59) = 0.43

At least $60 or less than $30

This means that we use the money spent less than 30 and greater than or equal to 60

So, we have

At least $60 or less than $30 = 84 + 85 + 98

At least $60 or less than $30 = 267

Next, we have

P(Amount ≥ 60 or Amount < 30) = 267/468

P(Amount ≥ 60 or Amount < 30) = 0.57

At least $40

This means that we use the money spent greater than or equal to 40

So, we have

At least $40 = 58 + 67 + 84

At least $40 = 209

Next, we have

P(Amount ≥ 40) = 209/468

P(Amount ≥ 40) = 0.45

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The algebraic expression below is a polynomial. x-1^k, where k is a real number

Answers

Answer: True

Step-by-step explanation:

A telephone pole is 54 feet tall. A guy wire runs 83 feet, from point A at the top of the telephone pole, to the ground at point B. The base of the telephone pole is at point C. Triangle ABC is a right triangle.

How far from the base of the telephone pole, to the nearest tenth of a foot, is the guy wire secured to the ground at point B?

Answers

Okay, let's break this down step-by-step:

* The telephone pole is 54 feet tall

* The guy wire runs 83 feet from point A (top of pole) to point B (ground)

* So the hypotenuse (AB) of the right triangle is 83 feet

* The opposite side (AC) is 54 feet (height of pole)

To find the adjacent side (BC), we use the Pythagorean theorem:

a^2 + b^2 = c^2

54^2 + BC^2 = 83^2

Solving for BC gives:

BC = sqrt(83^2 - 54^2) = sqrt(1296 - 2916) = sqrt(1620) = 40 feet

So the guy wire is secured 40 feet from the base of the telephone pole.

Rounded to the nearest tenth is 40.0 feet.

Therefore, the final answer is:

40.0

Let me know if you have any other questions!

The weight (in kilograms) of 14 patients were measured as 59, 63, 61, 62, 58, 60, 58, 57, 57, 56, 50, 69, 58 and 50. What is the range weight (in kilograms) of these patients?

Answers

Answer:

57 kilograms. .........................................................................kg

Find area of the shape

Answers

Answer:

130.4

Step-by-step explanation:

6 x 14 = 84

8 x 4 = 32

(4 x 7.2)/2 = 14.4

What are the solutions of the equation 2 log x = log (5x-6)? Select all that apply.
A x=1
B. x=2
C. x= 3
D. x = 5
E. x=6

Answers

Answer:

B, C

Step-by-step explanation:

x^2 = 5x - 6

x = 2 or x = 3

A kid's size small T-shirt is designed to fit children
who weigh between 43 and 55 pounds.
a. Write an inequality to describe w, the weight
of a child who has outgrown the small T-shirt.
9 √
b. Write an inequality to describe y, the weight
of a child who is not ready for the small T-shirt
yet.

Answers

A) The inequality that the weight of a child who has outgrown the small T-shirt is w > 55. B) The inequality that the weight of a child who is not ready for the small T-shirt yet. Is y < 43

How to determine the inequalities

a. To describe the weight (w) of a child who has outgrown the small T-shirt, we can use the inequality:

w > 55

This inequality states that the weight of a child (w) must be greater than 55 pounds for them to have outgrown the small T-shirt.

b. To describe the weight (y) of a child who is not ready for the small T-shirt yet, we can use the inequality:

y < 43

This inequality states that the weight of a child (y) must be less than 43 pounds for them to not be ready for the small T-shirt yet.

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Pls Need this ASAP
When purchasing a home, you need a loan for $80,000. The interest rate of the
loan is 8% and you are required to make monthly payment of $587.

Answers

Answer:

1) 5m

2) 0.25tan

Step-by-step explanation:

Other Questions
A cylindrical bar of metal having a diameter of 15.7 mm and a length of 178 mm is deformed elastically in tension with a force of 49100 N. Given that the elastic modulus and Poisson's ratio of the metal are 67.1 GPa and 0.34 respectively, Determine the following:(a) The amount by which this specimen will elongate (in mm) in the direction of the applied stress. The entry field with incorrect answer now contains modified data.(b) The change in diameter of the specimen (in mm). Indicate an increase in diameter with a positive number and a decrease with a negative number. Two identical spoons are electroplated with Ag or Cd through the use of the electrolytic cells. A current of 5.00A was supplied to each cell for 600. seconds, and the masses of the spoons before and after the electroplating were recorded. Write down the mathematical equations can best be used to account for the much larger increase in mass of the spoon electroplated with Ag compared with the spoon electroplated with Cd. What insurance related issues are currently being prioritized in Tennessee Find The Area of the parallelogram... 10. Johnny pushed a wheel borrow that was 50kg, if the net force on thewheel borrow is 15N east, what is the wheel borrows acceleration? what is the rate of markup applied for a cellphone sold for 15,000 with an original price 13,000? need help po MATH Which of the following is true?a. Blood glucose decreases to normal. b. Blood glucose increases to normal.c. Liver breaks down glycogen and releases glucose to the blood.d. Liver takes up glucose and stores it as glycogen.e. Pancreas releases glucagon.f. Body cells take up more glucose. UHHHHHHHHHHHH THIS IS EASY MATH WORK BUT I ONLY HAVE 2 BRAINCELLS THAT ARE SLOW SO JSJSJJSJJSJ HELP. B. En la siguiente tabla se muestran algunos valores de la base y la altura de distintos rectngulos cuya rea es la misma.Anoten los datos que faltan.34Base (b)2Altura (h)24a) Cul es el rea de los rectngulos?84La relacin entre los valores de la tabla es de proporcionalidad directa, inversa, o ninguna de las dos?En caso de que haya proporcionalidad, cul es la constante de proporcionalidad? In 1790, Republicans agreed to most of Hamilton's plan to solve the economic crisis, yet the cost was the location of the new nations' capital. Identify where they decided to place the new capital. A. Near Poughkeepsie B. New York C. On the Potomac River in the South D. Philadelphia 1. Given A = {1,2,3,4}, B ={1,2,4,5), C={3,4,6}, D= {7,8}. U={1,2,3,4,5,6,7,8,9}What is A UB? Bn C? CD? A'? (A U B) HELP ASAP HELPPP MARKING BRAINLIEST Whatis are computer? help me plz plz i need my grades up geometry: help needed, its urgent!angle 1 measures 75 degrees, is this table right? tysm for whoever helps !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11 Estimate the constant rate of withdrawal (in m3 /s) from a 1375 ha reservoir in a month of 30 days during which the reservoir level dropped by 0.75 m in spite of an average inflow into the reservoir of 0.5 Mm3 /day. During the month, the average seepage loss from the reservoir was 2.5 cm, total precipitation on the reservoir was 18.5 cm and the total evaporation was 9.5 cm In this stage of team building, individuals are settling into their roles and communication is very important.stormingperformingformingnormingand the right answer please Qu es un adjetivo? 2 Qu clases existen? Expliquen cada una randy needs to save 2550$ for a vacation. he has 6 months to save the money. how much money must he save each month?