Let |u| = 4 at an angle of 210° and |v| = 9 at an angle of 315°, and w = u – v. What is the magnitude and direction angle of w? |w| = 5. 5; θ = 156. 1° |w| = 5. 5; θ = 203. 9° |w| = 10. 8; θ = 156. 1° |w| = 10. 8; θ = 203. 9°.

Answers

Answer 1

The correct answer is |w| = 5.5; θ = 156.1°. The given magnitudes and direction angles of vectors u and v, and their subtraction to obtain vector w, the correct values are |w| = 5.5 and θ = 156.1°.

Given that |u| = 4 at an angle of 210°, and |v| = 9 at an angle of 315°, and w = u - v, we need to find the magnitude and direction angle of w.

|u| = 4 at an angle of 210°:

Let the terminal side of vector u make an angle of θ1 with the positive x-axis.

So, tanθ1 = (sinθ1)/(cosθ1) = (-4√3)/(-4) = √3

Therefore, θ1 = tan⁻¹(√3) + 180° = 210°

|v| = 9 at an angle of 315°:

Let the terminal side of vector v make an angle of θ2 with the positive x-axis.

So, tanθ2 = (sinθ2)/(cosθ2) = (-9)/(-9) = 1

Therefore, θ2 = tan⁻¹(1) + 315° = 225°

Now, w = u - v:

|w| = |u| * |v| * cos(θ1 - θ2)

|w| = 4.9 * cos(210° - 225°)

|w| = 5.5

Also, θ = 180° + (θ1 - θ2) + tan⁻¹(9√3/4)

θ = 156.1°

Hence, |w| = 5.5; θ = 156.1° is the correct option.

In conclusion, based on the proper values for the vector w's magnitude and direction angle are |w| = 5.5 and = 156.1°. These values are given for the vectors u and v.

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