True
If two angles form a linear pair, the angles are supplementary. A linear pair types a straight angle which contains 180º, so you have 2 angles whose measures add to 180, which skill they are supplementary.
Cody Ray's credit card company uses the unpaid-balance method and charges a monthly periodic rate of
1.8%. His finance charge was $17.54, he made $376.90 in new charges and a $250 payment.
Based on Cody Ray's credit card details and the unpaid-balance method, Cody Ray's unpaid balance is $144.44 and his previous balance is $144.44. His new balance is $147.04
What are Cody Ray's balances?His unpaid balance is:
= Purchases + Finance charge - (Payments + Credit)
= 376.90 + 17.54 - 250
= $144.44
Previous balance is the $17.54 finance charges.
New balance:
= Unpaid balance + Finance charge + New Purchases
= 144.44 + (144.44 x 1.8%)
= $147.04
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4/5 = ? x 1/5 i need this for khanacademy pls
Answer:
? = 4
Step-by-step explanation:
4/5 = 4/1 x 1/5
4/5 = 4/5
A sample of bacteria is growing at an hourly rate of 15% according to the continuous exponential growth function. The sample began with 11 bacteria. How many bacteria will be in the sample after 21 hours
If the sample of bacteria is growing at an hourly rate of 15% continuously and the bacteria began with 11 bacteria then there will be 244.178 samples bacteria after 21 hours.
Given growth of bacteria 15% ,bacteria at beginning 11.
We have to find the number of sample of bacteria after 21 hours.
We have to first form exponential function which shows the growth of bacteria in variable t.
Exponential function which shows the sum is y=P[tex]e^{rt}[/tex]
where P is initial amount ,
r is rate and
y is the sum
So in our problem P=11 and r=0.15
y=11*[tex]e^{0.15t}[/tex]
To find the samples after 21 hours we have to put t=21.
y=11[tex]e^{0.15*21}[/tex]
y=11*[tex]e^{3.1}[/tex]
y=11*22.198 ([tex]e^{3.1}[/tex]=22.198 from e table)
y=244.178
Hence the samples after 21 hours will be 244 approximately.
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Which of the following is the graph of f(x) = x2 − 5x + 4? WILL MARK BRAINLIEST
A graph of a quadratic function with a minimum at 2, negative 9 and x intercepts at negative 1 and 5
B graph of a quadratic function with a minimum at 3, negative 4 and x intercepts at 1 and 5
C graph of a quadratic function with a minimum at 2.5, negative 2.4 and x intercepts at 1 and 4
D graph of a quadratic function with a minimum at negative 1.5, negative 6.2 and x intercepts at 1 and negative 4
C) graph of a quadratic function with a minimum at 2.5, negative 2.25 and x intercepts at 1 and 4
Step-by-step explanation:Standard Form of a Quadratic Function: ax² + bx + c = 0, where a ≠ 0
Given function: x² - 5x + 4
⇒ a = 1, b = -5, c = 4
The minimum of a function is the lowest point of its parabola. We can use the following formula to find the vertex or the minimum of the function: [tex]x=\dfrac{-b}{2a}[/tex] . This will give us the x-value of the vertex, and we will need to solve for the y-value.
The vertex or minimum.
Step 1: Find the x-value of the vertex.
[tex]\\\implies x=\dfrac{-(-5)}{2(1)}\\\\\implies x=\dfrac{5}{2}=2.5[/tex]
Step 2: Find the y-value of the vertex by substituting 2.5 as the value of x in the given function.
[tex]\\\implies x^2 - 5x + 4\\\\\implies 2.5^2-5(2.5)+4\\\\\implies 6.25-12.5+4\\\\\implies -2.25[/tex]
Vertex: (2.5, -2.25)
The x-intercepts (roots).
We can use the Quadratic Formula to find the roots of this function.
Quadratic Formula: [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] when [tex]ax^2+bx+c=0[/tex]
Equation: x² - 5x + 4 = 0
⇒ a = 1, b = -5, c = 4
Step 1: Substitute the values of a, b, and c into the formula.
[tex]\\\implies x=\dfrac{\bold{-(-5)}\pm\sqrt{\bold{(-5)^2}\bold{-4(1)(4)}}}{\bold{2(1)}}\\\\\implies x=\dfrac{5\pm\sqrt{\bold{25-16}}}{2}\\\\\implies x=\dfrac{5\pm\sqrt{\bold{9}}}{2}\\\\\implies x=\dfrac{5\pm3}{2}[/tex]
Step 2: Separate into two possible cases.
[tex]x_1=\dfrac{5-3}{2}\implies \dfrac{2}{2}\implies \boxed{1}\\\\x_2=\dfrac{5+3}{2}\implies \dfrac{8}{2}\implies \boxed{4}[/tex]
The x-intercepts of the given function are 1 and 4.
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Consider the graph of rational function f
f(x)
-4
I
T
1
-2
6-
4-
2+
-2-
-4-
-6.
0
4+12
O
N.
2
Which equation represents function ?
OA f(2)= =+
OB. f(2)=426
Oc f(2)==
OD. f(2)=342-6
TY
6
X
Answer: B
Step-by-step explanation:
There is a hole at x=2, so the numerator and denominator should both have a factor of x-2.
This eliminates everything except for B.
The graph of y = f(x) is graphed below. Wat is the end behavior of f(x)?
PLEASE ASAP
Answer:
B.) as x --> -∞, f(x) --> ∞ and x --> ∞, f(x) --> ∞
Step-by-step explanation:
F(x) is another way of representing "y". That being said, the question is asking you the behavior of the graph in terms of the y-axis. On both sides of the function, there is an arrow pointing upwards, towards infinite, positive y-values. Therefore, as "x" approaches -∞ and ∞, f(x) is approaching ∞ (positive infinity).
3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are
chosen at random. Use the binomial formula to calculate the following probabilities: (You must show
your work and round the solution to the nearest thousandths place.)
a. exactly two children will watch PBS
b. at most two children will watch PBS
C. at least 2 children will watch PBS
Using the binomial distribution, the probabilities are given as follows:
a) 0.4159 = 41.59%.
b) 0.5610 = 56.10%.
c) 0.8549 = 85.49%.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.For this problem, the values of the parameters are:
n = 3, p = 0.76.
Item a:
The probability is P(X = 2), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159[/tex]
Item b:
The probability is P(X < 3), hence:
P(X < 3) = 1 - P(X = 3)
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390[/tex]
Then:
P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.
Item c:
The probability is:
[tex]P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549[/tex]
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Leticia was driving 45 miles per hour. after traveling for four hours she found that she was to 250 miles east of albertville
Answer:
can you give the question?
Step-by-step explanation:
didnt ask a question
The number of bacteria in a certain population increases according to a continuous exponential growth model with a growth rate parameter of 4.9% per hour how many hours does it take for the size of the sample to double
Answer:
14.5 hours to the nearest tenth.
Step-by-step explanation:
4.9% = 0.049.
If the original number is 50 it will double to 100 so
100 = 50(1.049)^t
1.049^t = 2
t * log 1.049 = log 2
t = log 2 / log 1.049
= 14.49 hours,
7 cm
Intro
5 cm
A
5 cm
D
4 cm
B
E
3 cm
3 cm
C
7 cm
Which face has an area of 28 cm²?
Face
4 of 10
Done
Answer:
Step-by-step explanation:
Solution
The length of all the rectangles is 7
You need the width to be 4
Area rectangle = L*w
Area rectangle = 7*4
Area rectangle = 28
Answer: B
x = 8, y = 11
The variables x and y vary inversely. Use the given values to write an equation relating x and y . Then find y when x=2.
[tex]y = \frac{1}{mx} [/tex]
[tex]11 = \frac{1}{8m} [/tex]
[tex]m = \frac{1}{88} [/tex]
[tex]y = \frac{1}{ \frac{1}{88}x } = \frac{88}{x} [/tex]
[tex]when \: x = 2 \\ y = \frac{88}{2} = 44[/tex]
Find the cube of (x-1/3x)
Answer:
2/3x
Step-by-step explanation
Answer:
(x³-3x²-3x-1) / (27x³)
Step-by-step explanation:
((x-1) / (3x))³
= (x-1)³ / /3x)³
(x-1)³ = (x-1)(x-1)(x-1) = x³ - 3x² - 3x - 1
then:
(x-1)³ / (3x³) = (x³-3x²-3x-1) / (27x³)
Write Your recurrring decimal 0.255555...... as a fraction
Answer:
[tex]\frac{23}{90}[/tex]
Step-by-step explanation:
we require 2 equations with the recurring digit placed after the decimal point.
let x = 0.2555.. ( multiply both sides by 10 and 100 )
10x = 2.555... (1)
100x = 25.555.... (2)
subtract (1) from (2) thus eliminating the recurring digits
90x = 23 ( divide both sides by 90 )
x = [tex]\frac{23}{90}[/tex]
Answer:
[tex]\sf \dfrac{23}{90}[/tex]
Step-by-step explanation:
x = 0.25555..... --------------(I)
Number of non-recurring digits is 1. So, multiply equation (I) by 10.
10x = 2.5555.... --------------(II)
Number of recurring digits is 1. So, multiply equation (II) by 10.
100x = 25.5555...... (III)
Subtract equation (II) from (III)
100x = 25.5555........
10x = 2.5555.......
- -
90x = 23
x = 23/90
verify commutative property of multiplication and addition 5 4
- -
2 5
then what will the answer of this with prof and detaling
The commutative property of multiplication addition is illustrated below.
How to illustrate the information?The commutative property implies that the changing of orders of the numbers doesn't have a effect on the value.
In this case, 5 × 4 = 20. Also, changing them to 4 × 5 is still 20.
Likewise 2 + 5 as 5 + 2 gives 7.
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solve this two questions with explaining method also....
Answer:
6) Selling price = ₹ 1608
Labelled price = ₹ 2010
7) Profit percentage = 10.5%
Step-by-step explanation:
Finding the selling price:
6) Cost Price = ₹ 1200
[tex]\sf Profit = 33\dfrac{1}{3} \% * Cost\ price\\\\[/tex]
[tex]\sf = \dfrac{102}{300}*1200\\\\ = 102 * 4\\\\[/tex]
= ₹ 408
Selling price = Cost price + Profit
= 1200 + 408
= ₹ 1608
Let the labelled price = x
Discount % = 20%
(100-20)% of x = 1200 + 408
80% of x = 1608
[tex]\sf x = 1608*\dfrac{100}{80}\\\\[/tex]
x = ₹ 2010
Answer: Selling price = ₹ 1608
Labelled price = ₹ 2010
7) Let the Cost price = ₹ X
Marked price = (100 + 30)% of Cost price
[tex]\sf = \dfrac{130}{100}X\\\\ = 1.3 X[/tex]
Discount% = 15%
Selling price = (100 - 15)% of 1.3X
= 85% * 1.3X
= 0.85 * 1.3X
= 1.105X
[tex]\sf \boxed{\bf Profit \% =\dfrac{Selling \ price - Cost \ Price}{Cost \ price }*100}[/tex]
[tex]\sf = \dfrac{1.105X - X}{X}*100\\\\ = \dfrac{0.105X}{X}*100\\\\ = 0.105*100\\\\ = 10.5 \%[/tex]
Geometric Series
It has 6 terms, increases by a factor of 4, and has a sum of 1365. Find the value of the first term.
Since the geometric series has 6 terms, increases by a factor of 4, and has a sum of 1365, the value of the first term is 1.
What is the sum of a geometric series?The sum of a geometric series is given by
Sₙ = a(rⁿ - 1)/(r - 1) with r > 1 where
n = number of terms, a = first term and r = common ratioNow, since our Geometric Series has 6 terms, n = 6. Also, it increases by a factor of 4, so, r = 4 and has a sum of 1365, so Sₙ = 1356. So,we have that
n = 6, Sₙ = S₆ = 1365 andr = 4The value of the first termSince we require the first term, a , making a subject of the formula, we have
a = Sₙ(r - 1)/(rⁿ - 1)
Substituting the values of the variables into the equation, we have
a = Sₙ(r - 1)/(rⁿ - 1)
a = S₆(r - 1)/(r⁶ - 1)
a = 1365(4 - 1)/(4⁶ - 1)
a = 1365(3)/(4096 - 1)
a = 4095/4095
a = 1
So, the value of the first term is 1.
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pls look at pic!!!!!!!!!!!!
Answer:
I don't think the answer is in the options.
At a charity fundraiser, each female attendant donated $1,200 and each male attendant donated $800. If the average donation at the fundraiser was $900, what was the ratio of the number of female attendants to the number of male attendants.
Using the mean concept, the ratio of the number of female attendants to the number of male attendants was of 3.
What is the mean?The mean of a data-set is given by the sum of all observations in the data-set divided by the number of observations.
In this problem:
There were f + m donations.The sum was of 1200f + 800m.The average was of 900.Hence:
[tex]\frac{1200f + 800m}{f + m} = 900[/tex]
1200f + 800m = 900f + 900m
100m = 300f
[tex]\frac{f}{m} = 3[/tex]
Hence the ratio was of 3.
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make k the subject!
Using the order of operations, what should be done first to evaluate 12 divided by (negative 6) (3) + (negative 2)?
According to the order of operations, brackets are solved first which contains the division operation. Hence, 12 is divided by -6 first.
Order of Operations
Given expression is,
(12 ÷ (-6))(3) + (-2)
According to the BODMAS rule of operations, the precedence order of operations is as follows,
Brackets > Of > Division > Multiplication > Addition > Subtraction
Hence, we will start by solving the brackets first, then solve the division and then the addition.
Evaluation
Solving the given expression as per the order of operations,
Brackets are solved first, then division followed by multiplication and then addition. Division is always of the highest precedence among all operations after brackets and of.
12 ÷ (-6)(3) + (-2)
= 12 ÷ (-6)(3) - 2 [∵ +(-n) = -n]
= (-2)(3) -2
= -6 - 2
= -8
Thus, solving the +(-2) and then division of 12 by (-6) are the first operations to be performed in order to evaluate the given expression.
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What are the two numbers on the upper left and the three on the bottom?
The computation of the equation shows.that x is -4 and y is 0.6.
How to calculate the value?4x + 5y = -1
-5x - 8y = 10
The value of x and y will be calculated thus:
-5 × (4x + 5y = -1)
4 × -(5x - 8y = 10)
-20x - 25y = 5
-20x -32y = 40
Add the equation
57y = 45
y = 45/75 = 0.6
Since 4x + 5y = -1
4x + 5(0.6) = -1
4x + 3 = -1
x = -1 - 3
x = -4
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WILL VOTE BRAINLIEST FOR THE FIRST RIGHT ANSWER
Answer:
B
Step-by-step explanation:
Let t and d be their ages now.
2 years ago, their ages were t - 2 and d 2.
Now, Tyler is 3 years older than David: t = d + 3
2 years ago, Tyler was 4 times as old as David: t - 2 = 4(d - 2)
The system of equations is:
t = d + 3
t - 2 = 4(d - 2)
Answer: B
Answer:
D
Step-by-step explanation:
Can someone do this please?
Answer:
<1 =73
Step-by-step explanation:
The sum of the angles of a triangle add to 180 degrees
72+ 35 + <1 = 180
Add like terms
107 + <1 = 180
Subtract 107 from each side
<1 = 180-107
<1 =73
what is the
area of
Rectangle with the length 3 XY
and width
14X2y
Answer: [tex]42x^3 y^2[/tex]
Step-by-step explanation:
[tex]A=(3xy)(14x^2 y)=42x^3 y^2[/tex]
Rule 1: Multiply by 2 then add 1 starting from 1.
Rule 2: Divide by 2 then add 4 starting from 40.
I need to make a sequence and I need help :)
PLease dont delete my question :(
Rule 1:
1, 3, 7, 15, 31, 63, 127, 255, 511, 1023 etc
Rule 2:
40, 24, 16, 12, 10, 9, 8.5, 8.25, 8.125, 8.0625 etc
Hope this helps!
(‼️‼️I WILL MARK BRAINLIEST PLEASE HELP‼️‼️)Dilate the figure by the scale factor. Then enter
the new coordinates.
K = 5
(-3,-1)
A
(-1,-4) C
B(2,-2)
A' ([?], [ ])
B' ([ ], [ ])
C' ([ ], [ ])
Triangle ABC is dilated by a scale factor of 5 to get A'(-15, -5), B'(10, -10) and C'(-5, -20)
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformations are reflection, translation, rotation and dilation.
Rigid transformation preserves the shape and size of the figure. Reflection, translation, rotation are rigid transformations.
Triangle ABC has vertices at A(-3, -1), B(2, -2) and C(-1, -4). It is then dilated by a scale factor of 5 to get A'(-15, -5), B'(10, -10) and C'(-5, -20)
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If p= the motorcycle's original price in dollars, which algebraic expression
represents the reduced price?
A. 275-p
B. 275p
C. 275+ p
D. p - 275
Answer: D
Step-by-step explanation:
If the original price was p, a price reduction would be p- the amount. Per the given answers, $275 is used for the reduction amount.
Construct the indicated confidence interval for the population mean mu.
Using the z-distribution, the confidence interval is given by: (11.95, 12.65).
What is a z-distribution confidence interval?The confidence interval is:
[tex]\overline{x} \pm z\frac{\sigma}{\sqrt{n}}[/tex]
In which:
[tex]\overline{x}[/tex] is the sample mean.z is the critical value.n is the sample size.[tex]\sigma[/tex] is the standard deviation for the population.In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.
The other parameters are given as follows:
[tex]\overline{x} = 12.3, \sigma = 1.5, n = 50[/tex]
Hence the bounds of the interval are:
[tex]\overline{x} - z\frac{\sigma}{\sqrt{n}} = 12.3 - 1.645\frac{1.5}{\sqrt{50}} = 11.95[/tex]
[tex]\overline{x} - z\frac{\sigma}{\sqrt{n}} = 12.3 + 1.645\frac{1.5}{\sqrt{50}} = 12.65[/tex]
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Subject
mathematics, 06.11.2020 05:30 tonya3498
2. (15 points) sheila needs to hire a babysitter for the evening. the babysitter charges $10 for each
hour and also charges for the time she spends driving to and from the house. she thinks it will take
1.5 hours of total driving time. sheila is willing to spend $80 for the night for babysitting.
a. write an equation to determine for how many hours sheila can afford to hire the babysitter.
b. use the guess-and-check method to determine how many hours of babysitting sheila can
afford.
c. sheila finds another babysitter that lives much closer to her and would only need 1 hour of
driving time. however, she charges $15 per hour. write an equation to determine how many hours
of babysitting sheila could buy from her.
d. can sheila afford the same amount of babysitting from the second sitter as she could from the
first sitter?
a. The equation we get is 10(1.5 + x) = 80, where x is the number of hours Sheila can afford to hire the babysitter.
b. Sheila can afford the babysitter for 6 hours and 30 minutes.
c. The equation we get is 15(1 + x) = 80, where x is the number of hours Sheila can afford to hire the new babysitter.
d. Sheila can afford to hire the new babysitter for 4 hours and 20 minutes, while the first babysitter was hired for 6 hours and 30 minutes.
Thus, Sheila can't afford the same amount of babysitting from the second sitter as she could from the first sitter.
a. We assume the hours affordable to Sheila be x hours.
Per hour charge of the babysitter = $10.
Time taken by the babysitter traveling = 1.5 hours.
Therefore, total chargeable time = 1.5 + x.
Therefore, the total charge by the babysitter = $10(1.5 + x).
This needs to be equal to the amount Sheila is willing to spend, that is, $80.
Thus, the equation we get is: 10(1.5 + x) = 80.
b. We are asked to determine the hours Sheila can afford to hire the babysitter.
We have got the equation 10(1.5 + x) = 80, where x is the hours Sheila can afford to hire the babysitter.
Thus, by solving this equation, we can determine the hours Sheila can afford to hire the babysitter.
10(1.5 + x) = 80,
or, 1.5 + x = 8,
or, x = 8 - 1.5 = 6.5 = 6 hours and 30 minutes.
Thus, Sheila can afford the babysitter for 6 hours and 30 minutes.
c. Per hour charge of the new babysitter = $15.
Time taken by the new babysitter traveling = 1 hour.
Therefore, total chargeable time = 1 + x.
Therefore, the total charge by the new babysitter = $15(1 + x).
This needs to be equal to the amount Sheila is willing to spend, that is, $80.
Thus, the equation we get is: 15(1 + x) = 80.
d. We are asked whether Sheila affords the same amount of babysitting from the second sitter as she could from the first sitter.
To determine this, we need to find the hours she affords from the second babysitter, for which, we solve the equation 15(1 + x) = 80 as follows:
15(1 + x) = 80,
or, 1 + x = 80/15,
or, x = 80/15 - 1 = 65/15 = 13/3 = 4 hours and 20 minutes.
Sheila can afford to hire the new babysitter for 4 hours and 20 minutes, while the first babysitter was hired for 6 hours and 30 minutes.
Thus, Sheila can't afford the same amount of babysitting from the second sitter as she could from the first sitter.
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Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.
The square root of the quantity 3 x plus 12 end quantity equals 9.
The value of x from the given expression is 23
Radical equationsGiven the following equation
√3x+12 = 9
Square both sides
√3x+12)² = 9²
3x + 12. = 81
Subtract 12 from both sides
3x + 12 - 12 = 81- 12
3x = 69
x = 23
Hence the value of x from the given expression is 23
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