Malik joins a gym. He gets $2 per month of the regular monthly rate for 3 months. Malik pays $49.50 for 3 months. What is the gym's regular monthly rate, Show your work​

Answer:

30 divided by 0.40 = 75

The original price was $75

Step-by-step explanation:

30 divided by 0.40 = 75

The original price was $75

Answer:

10

Step-by-step explanation:

5 x 8 / 4

40/4=10

Answer:

28.8

Step-by-step explanation:

0.08x60 sec

4.8x6

28.8

Answer:

Bottom left graph, ∠a + ∠b = 180°, ∠a + ∠b = 90°, ∠a + ∠b = 90°

Step-by-step explanation:

For the first problem, we can look at the slope. The slope of the equation is negative. The line has to be similar to the bottom slant of the letter "K".

There are two lines that are similar and have the same y-intercept, so it's just a matter of which slope matches.

The slope is -1, so that means to find a different point we go down 1 and right 1.

The only point that's the same on the two lines are (0, 3).

When go down 1 and right 1, the point should be: (1,2)

The only line that satisfy this is the bottom left graph.

For problem 2, ∠a and ∠b must add up to 180°.

So the equation for problem 2 is: ∠a + ∠b = 180°

For problem 3, ∠a and ∠b are equal because they're opposite angles.

So the equation for problem 3 is: ∠a = ∠b

For problem 4, ∠a and ∠b must add up to 90°.

So the equation for problem 4 is: ∠a + ∠b = 90°

For problem 5, ∠a and ∠b must add up to 90°, since the other angle is 90°, which is half to 180°.

So the equation for problem 5 is: ∠a + ∠b = 90°

Explanation:

We can rewrite y = -3 as y = 0x-3 or y = 0x+(-3)

Compare that to y = mx+b and we can see that m = 0 is the slope and b = -3 is the y intercept. The slope of 0 indicates a horizontal line.

We can think of it is as slope = rise/run = 0/1 = 0. A rise of 0 tells the reader "the graph does not go up or down at all". Every point on the line y = -3 has y coordinate of -3. Two such points are (0,-3) and (1,-3).

Answer:

11x

Step-by-step explanation:

To find it, you can simply expand the expression

(3x + 5)(4x - 3)

= 3x(4x - 3) + 5(4x - 3)

= 12x² - 9x + 20x - 15

= 12x² + 11x - 15

Answer:

b

Step-by-step explanation:

gud evng have a gud day

hope u enjoy ur day

(F*g)(x) means to multiply the two equations.

Multiply each term by each term:

2x-1 * 3x+5 =

2x * 3x + 2x*5 + (-1)*3x + (-1)*5 =

6x^2 + 10x -3x -5 =

6x^2+7x-5

Answer:2/36 or 1/18

Step-by-step explanation:

ANSWER:

2/36

EXPLANATION: Find what the gcf factor of all the denominators are the gcf of all the denominators is 36 but what you do to the top do to the bottom then add 3/36+4/36+6/36+9/36+12/36=34/36 so you need 2/36 to have a full circle

Answer:

5y + 8

and

8y +5 are the same solutions.

Answer:

Ignore los puntos.

Ignore the points.

Answer:  46

Step-by-step explanation:

Let the 3 consecutive even numbers be x, (x-2) and (x+2) respectively.

According to the question,

x + (x - 2) + (x + 2) = 132

or, x + x - 2 + x + 2 = 132

or, 3x = 132

or, x = 132 ÷ 3

or, x = 44

So, first even number = 44

Required third number = 44 + 2

= 46

Answer:

45; 9

Step-by-step explanation:

1) if the rate of the boat in still water is 'b' and the rate of the current is 'c', then it is possible to write the rate of the boat going upstream: b-c, downstream: b+c.

2) the basic formula is: D=r*t, where D - distance, r - rate/velocity, t - time;

3) according to the condition it takes 3 hours to travel 108 km upstream, it means according to  the formula above 3(b-c)=108;

4) according to the condition it takes 2 hours to travel 108 km downstream, it means according to the formula above 2(b+c)=108;

5) if to make up the system of two equations, then:

[tex]\left \{ {{3(b-c)=108} \atop {2(b+c)=108}} \right. \ => \ \left \{ {{b=45} \atop {c=9}} \right.[/tex]

6) rate of the boat in still water: 45 km/h;

rate of the current: 9 km/h.

² = QR² - QT²

= 13² - 5²

= 169 - 25

= 144

TR = √144

TR = 12 cm

Menentukan panjang PR

PR = 2 × TR

= 2 × 12 cm

PR = 24 cm

division is 1.92307692308

multiply is 325

Answer:

Proved

Step-by-step explanation:

Given

[tex](2 * 10^2) * (3 * 10^5) = 3.5 * 10^7 + 2.5 * 10^7[/tex]

Required

Prove

On the right hand side, we have:

[tex]2 * 10^2 * 3 * 10^5 = 3.5 * 10^7 + 2.5 * 10^7[/tex]

Rewrite:

[tex]2 * 3* 10^2 * 10^5 = 3.5 * 10^7 + 2.5 * 10^7[/tex]

[tex]6* 10^2 * 10^5 = 3.5 * 10^7 + 2.5 * 10^7[/tex]

Apply law of indices

[tex]6* 10^{2+5} = 3.5 * 10^7 + 2.5 * 10^7[/tex]

[tex]6* 10^7 = 3.5 * 10^7 + 2.5 * 10^7[/tex]

Express 6 as 3.5 + 2.5

[tex](3.5 + 2.5)* 10^7 = 3.5 * 10^7 + 2.5 * 10^7[/tex]

Open bracket

[tex]3.5 *10^7+ 2.5*10^7 = 3.5 * 10^7 + 2.5 * 10^7[/tex]

Proved

Answer:

C. 48.

Step-by-step explanation:

If the mean is 12, then 12 must be 2x, 3x, 4x, and 3x divided by 4.

      --> [tex]\frac{2x+3x+4x+3x}{4}=12[/tex]

      --> [tex]\frac{12x}{4}=12[/tex]

      --> [tex]\\3x=12[/tex]

      --> x=4

Add: 2x+3x+4x+3x=8+12+16+12=48

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

[tex]A(t) = A(0)(1-r)^t[/tex]

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

[tex]A(5.3) = 0.5A(0)[/tex]

We use this to find r. So

[tex]A(t) = A(0)(1-r)^t[/tex]

[tex]0.5A(0) = A(0)(1-r)^{5.3}[/tex]

[tex](1-r)^{5.3} = 0.5[/tex]

[tex]\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}[/tex]

[tex]1 - r = 0.5^{\frac{1}{5.3}}[/tex]

[tex]1 - r = 0.8774[/tex]

So

[tex]A(t) = A(0)(0.8774)^{t}[/tex]

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that [tex]A(26.5) = 14.5[/tex], and use this to find A(0). So

[tex]A(t) = A(0)(0.8774)^{t}[/tex]

[tex]14.5 = A(0)(0.8774)^{26.5}[/tex]

[tex]A(0) = \frac{14.5}{(0.8774)^{26.5}}[/tex]

[tex]A(0) = 464[tex]

464 grams.

Pythagorean theorem.

a^2+b^2=c^2

This means that the square of the length of the 2 legs of a right triangle added together = the square of the length of the hypotenuses or diagonal.

If you know 2 of the values in the 3 variables a,b,c what would you do to find the missing variable value?

I will not write the exact answers to this problem. I think you can figure how to write it out yourselves.

Answer:

00

Step-by-step explanation:

Answer:

i need to know what the answer is to solve for m

Step-by-step explanation:

Answer:

C. [tex] \frac{8\sqrt{89}}{89} [/tex]

Step-by-step explanation:

Cos A = Adj/Hyp

Reference angle = <A

Adjacent side = 8 ft

Hypotenuse = √(8² + 5²) = √89 (pythagorean theorem)

Thus:

[tex] Cos (A) = \frac{8}{\sqrt{89}} [/tex]

Rationalize

[tex] Cos (A) = \frac{8 * \sqrt{89}}{\sqrt{89} * \sqrt{89}} [/tex]

[tex] Cos (A) = \frac{8\sqrt{89}}{89} [/tex]

Answer:

v= 1/6

Step-by-step explanation:

1. Simiplify 10/3v = 10/3v -5/9= -10v/3

2. Multiply both sides by 3

3. Use this rule : a/b × c = ac/b

4. 5× 3= 15 -15/9= -10v

5. Simiplify 15/9 = 5/3 -5/3 = -10v

6. Divide both side by -10 -5/3/-10=v

7. Two negative make a postive 5/3/10 = v

8. Simplify 5/3/10= 5/3×10

9. Simplify 3×10=30 5/30=v

10. Simplify 5/30 = 1/6v

11. Swith sides v= 1/6

Answer:

5(3x+5)

Step-by-step explanation:

Answer:

5(3x + 5)

Step-by-step explanation:

Factor out 5 of 15x + 25 then you'll get your answer.

Hope this helps:)

Answer:

Step 1:  Determine why circle 1 is similar to circle 2

The reason why circle 1 is similar to circle 2 is that they both expand at the same rate.  While x grows larger, both circle 1 and circle 2 grow at a proportional rate.  Circle 2 grows is 5 times bigger than circle 1 given any value 5.

When x = 3:  circle 1 = 6 and circle 2 = 30

When x = 10:  circle 1 = 20 and circle 2 = 100

Answer:

Circle 2 is a dilation of circle 1 with a scale factor of 5.

Step-by-step explanation:

Took the quiz and got a perfect score :)