Noah and his friends are going on to an amusement park.The total cost of admission for 8 students is $100, and all students share the cost equally.Noah brought $13 for his ticket.Did he bring enough money to get into the park

Answer:

315

Step-by-step explanation:

The approximate number of minutes that Avery spends on the extra curricular activities are 122 minutes.

Given that Avery spent 10 minutes outside, 64 minutes in riding her bike, 48 minutes on the trampoline.

We have to calculate the approximate time that Avery spends on extra curricular activities.

Time spent by Avery outside=10 minutes

Time spent by Avery in riding her bike=64 minutes

Time spent by Avery on trampoline=48 minutes

Total time spent by Avery on extra curricular activities is equal to 10+64+48

=122 minutes

Hence the total time spent by Avery on extra curricular activities is 122 minutes.

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Question is incomplete as the question should include that Avery spent 10 minutes outside,64 minutes in riding her bike, 48 minutes on trampoline and rest of the time in swimming.

Answer:

[tex]G(x) = 6-x^{4}[/tex]

Step-by-step explanation:

The red graph is the blue graph translated up 3 units, so the answer is [tex]G(x) = 6-x^{4}[/tex].

The function that describes the graph is an exponential function

From the graph, we have the following highlights:

The above is the description of an exponential function

Hence, the function that describes the graph is an exponential function

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Answer:

-5y-4=-(x+3)2-1/(2)

Step-by-step explanation:

ANSWER: It's D

Have a great day!!!

Labor productivity is normally measured by (c) dividing total real domestic output by the number of workers or by the number of labor hours.

What is labour productivity in India?

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The compound inequality represents the situation is r > 4 and r ≤ 4.1

r > 4

r ≤ 4.1

Therefore, r > 4 and r ≤ 4.1 is the compound inequality which represent the situation.

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Its A: r > 4 and r ≤ 4.1

Answer:

[tex]\textsf{2.} \quad y=\dfrac{35}{x}[/tex]

[tex]\textsf{3.} \quad y=-\dfrac{90}{x}[/tex]

[tex]\textsf{4.} \quad y=\dfrac{63}{x}[/tex]

[tex]\textsf{5.} \quad y=-\dfrac{112}{x}[/tex]

Step-by-step explanation:

If y is inversely proportional to x, then:

[tex]y \propto\dfrac{1}{x} \implies y=\dfrac{k}{x} \quad \textsf{(for some constant }k)[/tex]

Question 2

Substitute one of the given ordered pairs into the inverse variation equation and solve for k:

[tex]\implies 7=\dfrac{k}{5}[/tex]

[tex]\implies 7 \cdot 5=\dfrac{k}{5} \cdot 5[/tex]

[tex]\implies k=35[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:

[tex]\implies y=\dfrac{35}{x}[/tex]

Question 3

Substitute y = -15 and x = 6 into the formula and solve for k:

[tex]\implies -15=\dfrac{k}{6}[/tex]

[tex]\implies -15 \cdot 6=\dfrac{k}{6} \cdot 6[/tex]

[tex]\implies k=-90[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given values:

[tex]\implies y=-\dfrac{90}{x}[/tex]

Question 4

Substitute one of the given ordered pairs into the inverse variation equation and solve for k:

[tex]\implies 9=\dfrac{k}{7}[/tex]

[tex]\implies 9 \cdot 7=\dfrac{k}{7} \cdot 7[/tex]

[tex]\implies k=63[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:

[tex]\implies y=\dfrac{63}{x}[/tex]

Question 5

Substitute one of the given ordered pairs into the inverse variation equation and solve for k:

[tex]\implies -16=\dfrac{k}{7}[/tex]

[tex]\implies -16 \cdot 7=\dfrac{k}{7} \cdot 7[/tex]

[tex]\implies k=-112[/tex]

Substitute the found value of k into the formula to create the inverse variation equation for the given ordered pairs:

[tex]\implies y=-\dfrac{112}{x}[/tex]

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Pairs of triangles appear to be congruent are :

Triangles 2 and 3. Option B

Triangles 2 and 4. Option D

Triangles 3 and 4. Option E

Congruent triangles can be defined as the pairs of triangles with same measurement

Triangles 2 and 3 :

After observing triangles 2  and  3  it appears that triangle  is congruent to triangle  .

Option C

Triangles 2 and 4

After observing triangles 2  and 4   it appears that triangle 2 is congruent to triangle 4 .

Option D

E. Triangles 3 and 4

After observing triangles 3  and 4. They are congruent

Option E

Hence, Option B, D and E are correct of the triangles

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Answer:

Triangles 3 and 4
Triangles 1 and 4
Triangles 1 and 3

Step-by-step explanation:

if this is wrong tell me so i can edit the answer, but this is what i got

Answer: [tex]y+6=-2(x-4)[/tex]

Step-by-step explanation:

See attached image.

Answer:

maybe the answer ris 36×4 and then 30×4 and subtract the result?!?!

Answer:

11/20

Step-by-step explanation:

55% = 55/100

by simplifying this fraction (divide top and bottom by 5), you get 11/20

Answer:

See attached image

Step-by-step explanation:

I'm uncertain as to the "best statement."  None seem to accurately describe the situation. I picked the one that was least incorrect (if that makes any sense).

The correct answer is identity

x intercept:-

put y =0

(5,0)

y intercept

put x=0

(0,10)

option C

Question 1: Given a(x) = x + 5, what are the x-intercepts and y-intercepts of a?

a. x-intercept at (-5,0), y-intercept at (0,5)

b. x-intercept at (5,0), y-intercept at (0,-5)

c. x-intercept at (0,5), y-intercept at (5,0)

Answer: a

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = x + 5

x = -5

Since x is -5 and y is 0, the x-intercept is at (-5,0).

The y-intercept is the place where the graph touches the y-axis. Since the equation for the y-axis is just x=0, we can put in 0 for x to get it.

y = 0 + 5

y = 5

Since x is 0 and y is 5, the y-intercept is at (0,5).

Question 2: Given b(x) = 2x + 1, what are the x-intercepts and y-intercepts of b?

a. x-intercept at (0.5, 0), y-intercept at (0, 2)

b. x-intercept at (-0.5,0), y-intercept at (0, 1)

c. x-intercept at (0, -0.5), y-intercept at (1,0)

Answer: b

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = 2x + 1

x = -0.5

Since x is -0.5 and y is 0, the x-intercept is at (-0.5,0).

The y-intercept is the place where the graph touches the y-axis. Since the equation for the y-axis is just x=0, we can put in 0 for x to get it.

y = 2(0) + 1

y = 1

Since x is 0 and y is 1, the y-intercept is at (0,1).

Question 3: Given c(x) = 3x - 2, what are the x-intercepts and y-intercepts of c?

a. x-intercept at (-2,0), y-intercept at (0,2/3)

b. x-intercept at (0, 2), y-intercept at (3/2, 0)

c. x-intercept at (2/3, 0), y-intercept at (0, -2)

Answer: c

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = 3x - 2

x = [tex]\frac{2}{3}[/tex]

Since x is 2/3 and y is 0, the x-intercept is at (2/3,0).

If the equation is in the form y = mx + b, the y-intercept will be b. The y-intercept also crosses the graph x = 0, so the y-intercept is (0, -2).

Question 4: Given d(x) = -x + 1, find the x-intercepts and y-intercepts of d.

a. x-intercept at (0, 1), y-intercept at (1,0)

b. x-intercept at (1, 0), y-intercept at (0, -1)

c. x-intercept at (1,0), y-intercept at (0,1)

Answer: c

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = -x+1

x = -(-1) = 1

Since x is 1 and y is 0, the x-intercept is at (1,0).

If the equation is in the form y = mx + b, the y-intercept will be b. The y-intercept also crosses the graph x = 0, so the y-intercept is (0, 1).

Question 5: Given f(x) = -7x+5, find the x-intercepts and y-intercepts of f.

a. x-intercept at (-5/7, 0), y-intercept at (0, -7/5)

b. x-intercept at (5, 0), y-intercept at (0, 5/7)

c. x-intercept at (5/7, 0), y-intercept at (0, 5)

Answer: c

The x-intercept is the place where the graph touches the x-axis. Since the equation for the x-axis is just y=0, we can put in 0 for y to get it.

0 = -7x+5

x = -5/-7= 5/7

Since x is 5/7 and y is 0, the x-intercept is at (5/7,0).

If the equation is in the form y = mx + b, the y-intercept will be b. The y-intercept also crosses the graph x = 0, so the y-intercept is (0, 5).

1) If the discriminant is greater than 0, the quadratic equation has 2 real solutions. Here D is grater than 0 . the quadratic equation has two real, distinct (different) roots.

2) If the discriminant of a quadratic equation is 4, then there are two real roots.

3) A discriminant of zero indicates that the quadratic has a repeated real number solution. A negative discriminant indicates that neither of the solutions are real numbers.

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Answer:

49 different ways

Step-by-step explanation:

If there are seven roads that lead to the top, you have seven possible choices to go to the top of the hill.

Then, to come back to the start, you also have seven possible choices (seven roads), and you can pick any road.

So, if you have seven ways to go up and seven ways to go down, the number of different ways of going to the top and coming back is the product of these numbers of possible choices.

N(total) = N(up) * N(down)

N(total) = 7 * 7

N(total) = 49 different ways

Brainliest pls and tysm!

The volume of the shipping crate is 36 m per cube.

According to the statement

we have given that the

A rectangular-prism-shaped toy chest is 2 m by 1 m by 1 m. A shipping crate is packed with 18 of these toy chests.

And we have to find the volume of the crate.

So,

volume of toy = 2*1*1

Volume of toy = 2 meter per cube.

And Now,

The volume of shipping crate = Volume of one toy* total number of toys in crate

so, Substitute the values in the formula then

The volume of shipping crate = Volume of one toy* total number of toys in crate

The volume of shipping crate = 2*18

The volume of shipping crate = 36 m per cube.

So, The volume of the shipping crate is 36 m per cube.

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The square of the given number will have 199 digits.

A number with hundred digits is given.

The first two digits of the given number are 2 and 9.

We can use the following formula to find the total number of digits in the square of a number.

2n - 1

Where n is the total number of digits in the given number.

Let us take a number with 2 digits:

29*29 = 841     { 2*2 - 1 = 3}

We can see that the square of the 2-digit number has 3 digits in it.

Let us take a number with 3 digits:

299*299 = 89401     { 2*3 - 1 = 5}

We can see that the square of the 3-digit number has 5 digits in it.

Similarly, we can find the number of digits in the square of a 100-digit as shown below:

2n - 1 = 2*100 - 1

= 200 - 1

= 199

Therefore, we have found that the square of the given number will have 199 digits.

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Answer:

The slope of the line segment CD is ( - [tex]\frac{8}{9}[/tex] )

Step-by-step explanation:

( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )

( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )

Coordinates of the midpoint are

( [tex]\frac{x_{1} +x_{2} }{2}[/tex] , [tex]\frac{y_{1} +y_{2} }{2}[/tex] )

The slope of a line segment with coordinates of the ends

( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] )

( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )

is m = [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

~~~~~~~~~~~~~

Point D is the midpoint of a segment AB

A ( 4 , 12 )

B ( - 6 , - 8 )

( [tex]\frac{-6+4}{2}[/tex] , [tex]\frac{-8+12}{2}[/tex] ) = ( - 1 , 2 )

D ( - 1 , 2 )

C ( 8 , - 6 )

[tex]m_{CD}[/tex] = [tex]\frac{-6-2}{8-(-1)}[/tex] = - [tex]\frac{8}{9}[/tex]

=======================================================

Explanation:

Triangle ABC is similar to triangle DEF. The order of the lettering is important because it tells us how the letters pair up.

Based on that, we can determine how the segments pair up

We want to find how long EF is, which means we'll involve BC = 17 since it is paired with it.

The diagram shows that AC = 14 and DF = 3, which is another pair we'll use

--------------------------

The key takeaway is that

Those two facts lead to the steps below

[tex]\frac{AC}{DF} = \frac{BC}{EF}\\\\\frac{14}{3} = \frac{17}{EF}\\\\14*EF = 3*17\\\\14*EF = 51\\\\EF = \frac{51}{14}\\\\EF \approx 3.642857\\\\EF \approx 3.6\\\\[/tex]

The proportion in step 1 is valid due to the similar triangles, and because of the corresponding side pairs mentioned. In step 3, I cross multiplied.

Answer:

3.6 cm

Step-by-step explanation:

Similar Triangle Theorem

If two triangles are similar, the ratio of their corresponding sides is equal.

Given triangles:

Therefore the corresponding sides are:

To find the measure of side EF, use the Similar Triangle Theorem:

[tex]\implies \sf AC:DF=BC:EF[/tex]

[tex]\implies \sf \dfrac{AC}{DF}=\dfrac{BC}{EF}[/tex]

[tex]\implies \sf \dfrac{14}{3}=\dfrac{17}{EF}[/tex]

[tex]\implies \sf EF=17 \cdot \dfrac{3}{14}[/tex]

[tex]\implies \sf EF=\dfrac{51}{14}[/tex]

[tex]\implies \sf EF=3.642857...[/tex]

[tex]\implies \sf EF=3.6\:cm\:\:(nearest\:tenth)[/tex]

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The final temperature at the time Tariq goes to bed was +12 degrees, represented as integers.

The initial temperature of the day was 0 degrees.

The temperature rose 23 degrees in the afternoon.

This implies that we move +23 on the scale, represented as an integer.

The temperature decreased 11 degrees in the evening.

This implies that we move -11 on the scale, represented as an integer.

This moves the temperature to +23 -11 = +12 degrees, represented as an integer.

Thus, the final temperature at the time Tariq goes to bed was +12 degrees, represented as integers.

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The domain and the range of the function are given as follows:

b. Yes; domain: all re.al numbers; range: y greater-than-or-equal-to 0.

Since each input is related to only one output values, the graph is a function. It is defined for all values of x, assuming only non-negative values, hence the correct option is:

b. Yes; domain: all re.al numbers; range: y greater-than-or-equal-to 0.

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By critically observing the graph shown in the image attached below, we can logically deduce that the slope of the graph of this function is equal to 0 for x, between x = -3 and x = -2.

Similarly, the slope of the graph of this function is also equal to 0 for x, between x = 3 and x = 4.

Based on the graph (see attachment), the greatest value of y is 4 while the smallest value of y is -3.

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Answer:

f(x) = 50x + 100

Explanation:

The term "Rs. 100" is constant. The term "Rs. 50" keeps changing per km.

Linear equation: y = mx + b, where 'm' is rate of change, 'b' is constant

Equation built:

f(x) = 50x + 100

This will determine the cost for journey of x meters.

Answer:

(3x+y) (2x-7y)

Step-by-step explanation:

first write -19xy as a difference and you get 6x^2+2xy-21xy-7y^2

and then take the factor 2x from the expression that is 2x(3x+y) and do the same with the -7 that is = -7(3x+y). So this is you answer= (3x+y)(2x-7)

The probability of drawing a red four and then a blue four is:

P = 1/100

We know that there are 10 cards in total, then the probability of drawing a red four (there is only one of these cards) is:

p = 1/10

Now we put the red four again, the probability of getting a red blue is computed in the same way:

q = 1/10

The probability for both events happening consecutively is:

P = p*q = (1/10)*(1/10) = 1/100

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Answer:

Step-by-step explanation:

The y-intercept of f(x) is (0,1), so the y-intercept of g(x) is (0,3).

f(x) has a horizontal asymptote at y=0. and so does g(x).

f(x) does not have an x-intercept, and neither does g(x).

Answer:

y-intercept at (0, 3)

horizontal asymptote of y = 0

no x-intercept

Step-by-step explanation:

Definitions

y-intercept: the point(s) at which the curve crosses the y-axis (when x=0).

x-intercept: the point(s) at which the curve crosses the x-axis (when y=0).

Asymptote: a line that the curve gets infinitely close to, but never touches.

Given function:

[tex]f(x)=2^x[/tex]

Properties of function f(x):

[tex]\textsf{If }g(x)=3f(x):[/tex]

[tex]\implies g(x)=3(2)^x[/tex]

Properties of function g(x):

Therefore the true statements are:

Answer:

using pythagoras theorem