PLEASE EXPLAIN AND SHOW ALL YOUR WORK

Answer: An equation of the plane can be written in the form Ax + By + Cz = D, where A, B, and C are the coefficients of the variables x, y, and z, respectively, and D is a constant. We can use the point-normal form of the equation of a plane to find the coefficients A, B, and C.

The point-normal form of the equation of a plane is:

A(x - x1) + B(y - y1) + C(z - z1) = 0

where (x1, y1, z1) is the point on the plane and (A, B, C) is the normal vector to the plane.

We can substitute the values of the point and normal vector into this equation:

8(x - 3) + (y - 9) - (z - 8) = 0

Simplifying and rearranging, we get:

8x + y - z = 47

Therefore, the equation of the plane through the point (3, 9, 8) with normal vector 8i + j - k is:

8x + y - z = 47

The equation of a plane in three-dimensional space can be written in the form ax + by + cz = d, where (a, b, c) is a normal vector to the plane, and d is a constant.

We are given that the plane passes through the point (3, 9, 8) and has a normal vector of 8i + j - k. Therefore, a = 8, b = 1, c = -1, and the equation of the plane is:

8x + y - z = d

To find the value of d, we substitute the coordinates of the given point into the equation:

8(3) + 1(9) - 1(8) = d

24 = d

Thus, the equation of the plane is:

8x + y - z = 24

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Answer:

The surface area of a cylinder can be calculated using the formula:

SA = 2πr^2 + 2πrh

where r is the radius of the base of the cylinder, h is the height of the cylinder,

Substituting r = 3 and h = 1 into the formula, we get:

SA = 2π(3)^2 + 2π(3)(1)

SA = 2π(9) + 2π(3)

SA = 18π + 6π

SA = 24π

Therefore, the surface area of the cylinder is 24π square units.

To compute 101^(4,800,000,023) mod 35 using the Chinese Remainder Theorem, we need to first decompose 35 into its prime factors: 35 = 5 × 7.

Next, we need to compute 101^(4,800,000,023) mod 5 and 101^(4,800,000,023) mod 7 separately.

To compute 101^(4,800,000,023) mod 5, we can use Fermat's Little Theorem, which states that if p is a prime number and a is a positive integer not divisible by p, then a^(p-1) ≡ 1 mod p. Since 5 is prime and 101 is not divisible by 5, we have 101^(4) ≡ 1 mod 5. Therefore, 101^(4,800,000,023) ≡ 101^(4 × 1,200,000,005 + 3) ≡ (101^4)^1,200,000,005 × 101^3 ≡ 1^1,200,000,005 × 101^3 ≡ 1 × 101^3 ≡ 1 mod 5.

To compute 101^(4,800,000,023) mod 7, we can use Euler's Totient Theorem, which states that if a and m are coprime positive integers, then a^φ(m) ≡ 1 mod m, where φ(m) is Euler's totient function. Since 7 is prime and φ(7) = 6, we have 101^6 ≡ 1 mod 7. Therefore, 101^(4,800,000,023) ≡ 101^(6 × 800,000,003 + 5) ≡ (101^6)^800,000,003 × 101^5 ≡ 1^800,000,003 × 101^5 ≡ 101^5 ≡ 4 mod 7.

Now we can use the Chinese Remainder Theorem to combine the results. Let x ≡ 1 mod 5 and x ≡ 4 mod 7. Then we can write x = 5k + 1 for some integer k. Substituting this into the second congruence, we get 5k + 1 ≡ 4 mod 7, or equivalently, k ≡ 6 mod 7. Therefore, x = 5k + 1 ≡ 5(6) + 1 ≡ 31 mod 35.

Hence, 101^(4,800,000,023) mod 35 = x = 31.

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Answer:

Step-by-step explanation:

Use the parent function, then shift as necessary

Parent function:

y= log₅ x     >put in exponential form

[tex]5^{y} =x[/tex]  

Since our variables are a bit backwards work backwards

For y = 0    x=1

For y=1   x= 5

For y= 2  x=10  and so on and so forth

Put into T table

x   |    y

1    |    0

5   |   1

10  | 2

This is your parent:   There is a stretch of 2 and a shift of 1 to right for your function

so mulitply y by 2 and move over to right by 1

x   |    y

1  +1   |    0 *2

5 +1   |     1*2

10+ 1   |      2*2

x   |    y

2   |    0

6   |   2

11  |  4

Your asymptote is x=1 because you shifted right 1

The test statistic is x02 = (n - 1)s2/σ2 = 19s2/5. The approximate p-value for this test is 0.025.

a. For x02 = 25.2 and n = 20, the test statistic is:

x02 = (n - 1)s2/σ2 = 19s2/5

where s2 is the sample variance. Under the null hypothesis, x02 follows a chi-squared distribution with n - 1 = 19 degrees of freedom. The p-value is the probability of observing a test statistic as extreme or more extreme than the observed one, assuming the null hypothesis is true. Using a chi-squared distribution table or calculator, we find that the probability of observing a chi-squared value of 19s2/5 or less with 19 degrees of freedom is approximately 0.05. Therefore, the approximate p-value for this test is 0.05.

b. For x02 = 15.2 and n = 12, the test statistic is:

x02 = (n - 1)s2/σ2 = 11s2/5

where s2 is the sample variance. Under the null hypothesis, x02 follows a chi-squared distribution with n - 1 = 11 degrees of freedom. Using a chi-squared distribution table or calculator, we find that the probability of observing a chi-squared value of 11s2/5 or less with 11 degrees of freedom is approximately 0.10. Therefore, the approximate p-value for this test is 0.10.

c. For x02 = 4.2 and n = 15, the test statistic is:

x02 = (n - 1)s2/σ2 = 14s2/5

where s2 is the sample variance. Under the null hypothesis, x02 follows a chi-squared distribution with n - 1 = 14 degrees of freedom. Using a chi-squared distribution table or calculator, we find that the probability of observing a chi-squared value of 14s2/5 or less with 14 degrees of freedom is approximately 0.025. Therefore, the approximate p-value for this test is 0.025.

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The likelihood that the value resulting from the spin is no greater than two is 0.4, which is equivalent to 40%.

According to the distribution table, there are a total of ten slots on the wheel, and their corresponding values are as follows: 0, 1, 2, 5, and 10. In order to compute the likelihood of obtaining a value that is at most 2, we must first establish the number of possibilities that are desirable and then divide that figure by the entire number of outcomes that are feasible.

In this particular scenario, the outcomes that are desirable are the numbers 0 and 1, which indicates that there are three distinct possibilities that fulfil the requirement. Due to the fact that there are 10 spots on the wheel, the total number of events that could occur is 10.

Therefore, the probability of achieving a result that is no greater than two is three out of ten, which can be streamlined down to 0.3 or thirty percent. When a participant spins the wheel, there is a chance that they will win a value of 0, 1, or 2 at a rate of thirty percent of the time.

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To determine the change in angular momentum (ΔL) of a cylinder from t = 0 to t = t0, a student can use the equation:

ΔL = I * Δω

where ΔL is the change in angular momentum, I is the moment of inertia of the cylinder, and Δω is the change in angular velocity.

To calculate Δω, the student needs to know the initial and final angular velocities, ω0 and ωt0, respectively. The change in angular velocity can be calculated as:

Δω = ωt0 - ω0

Once Δω is determined, the student can use the moment of inertia (I) of the cylinder to calculate ΔL using the equation mentioned earlier.

The moment of inertia (I) depends on the mass distribution and shape of the cylinder. For a solid cylinder rotating about its central axis, the moment of inertia is given by:

I = (1/2) * m * r^2

where m is the mass of the cylinder and r is the radius of the cylinder.

By substituting the known values for Δω and I into the equation ΔL = I * Δω, the student can calculate the change in angular momentum (ΔL) of the cylinder from t = 0 to t = t0.

It's important to note that this method assumes that no external torques act on the cylinder during the time interval. If there are external torques involved, the equation for ΔL would need to include those torques as well.

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The limit of this expression as x approaches 0 is 1. To prove this, we can use L'Hospital's Rule.

Take the natural log of both sides and use the chain rule to simplify:

lim x→0 cot(3x)sin(9x) = lim x→0 ln(cot(3x)sin(9x))

Apply L'Hospital's Rule:

lim x→0 ln(cot(3x)sin(9x)) = lim x→0 [3cos(3x)cot(3x) - 9sin(9x)sin(9x)]/[3sin(3x)cot(3x) + 9cos(9x)sin(9x)]

Apply L'Hospital's Rule again:

lim x→0 [3cos(3x)cot(3x) - 9sin(9x)sin(9x)]/[3sin(3x)cot(3x) + 9cos(9x)sin(9x)] = lim x→0 [3(−sin(3x))cot(3x) - 9(cos(9x))sin(9x)]/[3(−cos(3x))cot(3x) + 9(−sin(9x))sin(9x)]

Simplify each side of the equation:

lim x→0 [3(−sin(3x))cot(3x) - 9(cos(9x))sin(9x)]/[3(−cos(3x))cot(3x) + 9(−sin(9x))sin(9x)] = lim x→0 −3/9

= -1/3

Since the limit of both sides of the equation is the same, the original limit must also be -1/3.

However, since cot(0) and sin(0) both equal 0, the limit of the original expression is 1.

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The limit of the expression lim(x→0) cot(3x) sin(9x) is 1.

We can use the properties of trigonometric functions to simplify the expression without needing to apply L'Hôpital's rule.

Recall that cot(x) = cos(x) / sin(x). Applying this to the expression:

lim(x→0) (cos(3x) / sin(3x)) sin(9x)

The sin(3x) term in the numerator and denominator cancels out:

lim(x→0) cos(3x) sin(9x) / sin(3x)

Next, we can simplify the expression further by applying the identity sin(A + B) = sin(A)cos(B) + cos(A)sin(B) to sin(9x):

lim(x→0) cos(3x) (sin(3x)cos(6x) + cos(3x)sin(6x)) / sin(3x)

Now, we can cancel out the sin(3x) term in the numerator and denominator:

lim(x→0) cos(3x) (cos(6x) + cos(3x)sin(6x)) / 1

As x approaches 0, all trigonometric functions in the expression approach their respective limits. Therefore, we can evaluate the limit directly:

lim(x→0) cos(3x) (cos(6x) + cos(3x)sin(6x)) / 1 = cos(0) (cos(0) + cos(0)sin(0)) / 1 = 1(1 + 1(0)) = 1(1 + 0) = 1

Hence, the limit of the expression lim(x→0) cot(3x) sin(9x) is 1.

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In this circuit, we have a MOSFET amplifier with given parameters: VDD = VSS = 5V, I0 = 500µA, RL = 7kΩ, RSig = 1kΩ. The MOSFET parameters are: [tex]VT = 2V, (W/L)*kn' = 4mA/V^2[/tex], and [tex]λ = 0V^{-1[/tex].

The circuit represents a common-source amplifier configuration with an n-channel MOSFET. It operates with a supply voltage of 5V, and the input signal is connected to a 1kΩ resistor. The load resistor is 7kΩ, and the MOSFET has a threshold voltage of 2V, a transconductance parameter of 4mA/V^2, and negligible channel-length modulation.

The common-source amplifier configuration uses the MOSFET in the triode region for signal amplification. With a bias current (I0) of 500µA flowing through the MOSFET, a voltage drop develops across RSig, generating an input signal voltage. The MOSFET operates in the saturation region, given VT = 2V. The transconductance parameter ((W/L)*kn') determines the amplification capability of the MOSFET, with a higher value resulting in higher gain. The load resistor RL sets the output impedance of the amplifier. In this case, RL = 7kΩ. The MOSFET's λ parameter, representing channel-length modulation, is negligible (λ = 0V^-1), indicating minimal dependence of the drain current on the drain-to-source voltage. Overall, this circuit configuration allows for amplification of the input signal and provides an amplified output signal at the drain of the MOSFET.

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Based on the information provided, we have a pair of parallel lines intersected by a transversal. The angles formed by the transversal and the parallel lines are related to each other in specific ways.

In this case, we are given that angle ZA is equal to 75°. Since the figure has parallel lines, we can determine that angle ZA is corresponding to angle OA (denoted as angle ΟΑ), meaning they have the same measure. Therefore, angle OA is also 75°.

To summarize:

ZA = 75°

OA = 75°

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The fact that the median value of retirement accounts per household is $0 indicates that a significant percentage of households have no retirement accounts.

This means that there is a wide wealth gap in the country and many households are not saving for their retirement, or they are using other forms of savings such as real estate or investments.

While the mean value of retirement accounts is $94,500, this does not give a complete picture of the distribution of retirement account balances. The mean is highly influenced by extreme values or outliers, such as households with very high balances. Therefore, it is important to consider both the mean and median when analyzing the distribution of retirement account balances.

The median value of $0 suggests that there is a large number of households with no retirement accounts, which could be due to several reasons. For instance, some households may not have access to employer-sponsored retirement plans, or they may not have enough disposable income to contribute to individual retirement accounts. Additionally, some households may not prioritize saving for retirement or may choose to rely on other sources of income in retirement, such as Social Security.

The fact that a significant percentage of households do not have retirement accounts can have serious implications for their financial well-being in retirement. Without adequate savings, households may be forced to rely on Social Security or other forms of government assistance, which may not be sufficient to cover all their expenses. This underscores the importance of encouraging households to save for retirement, as well as providing access to retirement savings plans and education on financial planning.

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Answer:

167925

Step-by-step explanation:

Liabilities are things that he owes.

Home value is an asset (not a liability).

Mortgage is a liability (he owes!).

Credit card balance is a liability (he has to pay that much).

Owned equip is owned (asset).

Car value is an asset.

Investments are assets.

The kitchen loan is a liability (he has to pay that back).

So add up those liabilities: Mortgage + credit card + kitchen loan

149367+6283+12275 = 167925

The statement "Chi-square is nonnegative in value; it is zero or positively valued" is true.

No, the chi-square value is always nonnegative, meaning it can only be zero or a positive value.

Chi-square is a statistical measure used in hypothesis testing and is calculated by summing the squared differences between observed and expected frequencies.

The chi-square value is a nonnegative statistical measure that is commonly used in hypothesis testing to assess the relationship between observed and expected frequencies in categorical data.

It is calculated by summing the squared differences between the observed frequencies and the expected frequencies.

The resulting value follows a chi-square distribution, which is always nonnegative.

A value of zero indicates that the observed and expected frequencies match perfectly, while positive values indicate increasing deviations from the expected frequencies.

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g∘f(x) or g(f(x)) is equal to 27x + 43.

To find g∘f(x) or g(f(x)), we need to substitute the function f(x) into the function g(x).

Given:

f(x) = 3x + 4

g(x) = 9x + 7

To find g∘f(x), we substitute f(x) into g(x) as follows:

g(f(x)) = g(3x + 4)

Now, we substitute 3x + 4 for x in the function g(x):

g(f(x)) = 9(3x + 4) + 7

Expanding and simplifying:

g(f(x)) = 27x + 36 + 7

g(f(x)) = 27x + 43

Therefore, g∘f(x) or g(f(x)) is equal to 27x + 43.

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To solve the equation sin x(sin x 1) = 0, we need to find the values of x that satisfy the equation. The product of sin x and (sin x 1) equals zero when either sin x equals zero or sin x 1 equals zero. So we have two possibilities: sin x = 0 or sin x = 1.

If sin x = 0, then x can be any integer multiple of π, because sin x = 0 when x = nπ.

If sin x = 1, then x must be π/2 radians or (π/2) + 2πn radians for some integer n.

Therefore, the solutions to the equation sin x(sin x 1) = 0 are x = nπ or x = (π/2) + 2πn, where n is an integer.

To solve the equation sin x(sin x 1) = 0, we use the zero-product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. So we set sin x = 0 and sin x 1 = 0 and solve for x.

If sin x = 0, then x = nπ for some integer n. This is because sin x = 0 when x = nπ, where n is an integer.

If sin x 1 = 0, then sin x = 1, which means x is either π/2 radians or (π/2) + 2πn radians for some integer n.

Therefore, the solutions to the equation sin x(sin x 1) = 0 are x = nπ or x = (π/2) + 2πn, where n is an integer.

In conclusion, the solutions to the equation sin x(sin x 1) = 0 are x = nπ or x = (π/2) + 2πn, where n is an integer. This is because the product of sin x and (sin x 1) equals zero when either sin x equals zero or sin x 1 equals zero. We use the zero-product property to find the values of x that satisfy the equation.

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The 2x2 change-of-basis matrix PS2+S1 is [1/3 -1/3; 1/6 1/3].

The component vector of f(x) with respect to S2 is (35/6, 31/6).

The vector space V consists of all linear combinations of 1 + x². The ordered basis S = {1 + 2x, x} and S2 = {1 + 2x + x², 2 + x + 2x²} are given for V. To find the change-of-basis matrix PS2+S1, we need to express the basis vectors of S in terms of S2, and then form a matrix using the coefficients of the resulting linear combinations.

After performing the necessary calculations, we get PS2+S1 = [1/3 -1/3; 1/6 1/3].

The component vector of f(x) with respect to Sj is obtained by expressing f(x) as a linear combination of the basis vectors in Sj, and then finding the coefficients of the resulting linear combination.

For S2,

we have f(x) = 5 + 3x + 5x² = (35/6)(1 + 2x + x²) + (31/6)(2 + x + 2x²), which gives us the component vector of f(x) with respect to S2 as (35/6, 31/6).

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A loan of $17,500 with a fixed annual percentage rate (APR) of 9% for a term of 5 years will result in a monthly payment of approximately $355.62.

To calculate the monthly payment, we can use the formula for the monthly payment of a fixed-rate loan, which takes into account the loan amount, the interest rate, and the loan term. The formula is:

M = [tex]P * (r * (1 + r)^n) / ((1 + r)^n - 1)[/tex]

Where:

M = Monthly payment

P = Loan amount

r = Monthly interest rate (APR divided by 12)

n = Total number of payments (loan term in months)

In this case, the loan amount (P) is $17,500, the annual percentage rate (APR) is 9%, and the loan term is 5 years (or 60 months). To calculate the monthly interest rate (r), we divide the APR by 12 (months). Therefore, r = 0.09 / 12 = 0.0075.

Plugging in the values into the formula, we get:

M = 17500 * (0.0075 * [tex](1 + 0.0075)^{60})[/tex] / ([tex](1 + 0.0075)^{60}[/tex] - 1)

M ≈ $355.62

Therefore, the monthly payment for the loan of $17,500 at a fixed APR of 9% for 5 years is approximately $355.62.

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1/12 is a fraction that is smaller than 1/6, and the product of 1/6 and 1/2 relates to 1/6 by being a fraction that is smaller than it.

The product of 1/6 and 1/2 is 1/12, which is not directly related to 1/6200.

The divide 1 by 1/6200, the result would be 6200, which is 12 multiplied by 516.67.

This shows that 1/6200 is equivalent to 1/12 of 516.67, which is a way to indirectly relate it to the product of 1/6 and 1/2.
The product of 1/6 and 1/2 relates to 1/6 because when you multiply these two fractions, you get a smaller fraction as a result. In this case, (1/6) x (1/2) = 1/12.

Which is smaller than both original fractions.

This demonstrates that when multiplying two fractions, the product is typically smaller than the original fractions.

The product of 1/6 and 1/2 which is (1/6) x (1/2) = 1/12 is smaller than 1/6.

This is because multiplying 1/6 by a fraction less than 1 (such as 1/2) results in a product that is smaller than the original fraction.

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A value of theta in the first quadrant that satisfies the equation is approximately 0.4548 radians or 26.1 degrees.

Starting with the equation:

6sin(2θ) = 5

Divide both sides by 6:

sin(2θ) = 5/6

We know that sine is positive in the first and second quadrants. Since we are looking for a value of theta in the first quadrant, we can use the inverse sine function to solve for 2θ:

2θ = sin⁻¹(5/6)

Using a calculator, we get:

2θ ≈ 0.9095 radians

Dividing by 2, we get:

θ ≈ 0.4548 radians

To convert to degrees, we can use the conversion formula:

1 radian = 180/π degrees

So:

θ ≈ 0.4548 radians = (180/π) * 0.4548 degrees ≈ 26.1 degrees

Therefore, a value of theta in the first quadrant that satisfies the equation is approximately 0.4548 radians or 26.1 degrees.

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Two samples are paired if the sample values are paired.

Paired samples are a type of dependent samples where each observation in one sample is uniquely paired or matched with an observation in the other sample. The pairing is usually based on a natural association, such as measuring the same variable on the same subject before and after a treatment, or measuring two variables on the same subject at the same time. Paired samples are often analyzed using methods such as paired t-test or Wilcoxon signed-rank test, which take into account the dependency between the samples. Pairing can also help to reduce variability and increase statistical power in the analysis.

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Answer: 80, 80

Step-by-step explanation:

The perimeter of a rectangle/square formula:

2L+2w=P                     >P=320

2L+2w=320                 >solve for one of variables let's pick L

2L = 320 - 2w              

L =  (320 - 2w)/2          >Simplify the dividing by 2            

L = 160-w

You also need Area formula:

A =  L(w)                            >Substitute from what we found from Perimeter

                                            formula

A = (160-w)(w)                   >Distribute w

A =  160w - w²                   >Maximum are happens at the vertex of this

                                             quadratic

A = w² - 160w

Vertex x formula in (x, y) for vertex:

a=1  b= -160     from A = w² - 160w   from standard form:  ax²+bx+c

[tex]w =- \frac{b}{2a}\\\\w= - \frac{-160}{2(1)}[/tex]

w=80

Substitute back into Perimeter to find L

L = 160-w

L = 160 - 80

L = 80

To prove that triangle PQR is a right triangle, we need to show that it satisfies the Pythagorean theorem, which states that the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, we need to check if 12.5^2 + 30^2 = 32.5^2 holds true.

In triangle PQR, let's label the sides as follows: PQ = 12.5 cm, QR = 30 cm, and RP = 32.5 cm.

To determine if triangle PQR is a right triangle, we need to apply the Pythagorean theorem. According to the theorem, the sum of the squares of the two shorter sides should be equal to the square of the longest side, which is the hypotenuse.

Calculating the squares of the side lengths:

PQ^2 = (12.5 cm)^2 = 156.25 cm^2

QR^2 = (30 cm)^2 = 900 cm^2

RP^2 = (32.5 cm)^2 = 1056.25 cm^2

Now, we check if PQ^2 + QR^2 = RP^2:

156.25 cm^2 + 900 cm^2 = 1056.25 cm^2

Since the equation is true, i.e., both sides are equal, we can conclude that triangle PQR satisfies the Pythagorean theorem and is, therefore, a right triangle.

Therefore, triangle PQR is a right triangle based on the given side lengths.

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The β-coordinate vector of x is [c1, c2] = [(3x1 - x2 - 5x3)/20, (x2 - 2x1)/10 + (3x1 - x2 - 5x3)/40]. This is the vector representation of x in the basis β.

To find the β-coordinate vector of x, we need to express x as a linear combination of b1 and b2. Let the β-coordinate vector of x be [c1, c2]. Then we have:

x = c1*b1 + c2*b2

Substituting the given values for b1 and b2, we get:

[x1, x2, x3] = c1*[2, -2, 4] + c2*[6, 1, -3]

This gives us a system of equations:

2c1 + 6c2 = x1
-2c1 + c2 = x2
4c1 - 3c2 = x3

We can solve this system using Gaussian elimination or other methods to get the values of c1 and c2. The solution is:

c1 = (3x1 - x2 - 5x3)/20
c2 = (x2 - 2x1)/10 + c1/2

Therefore, the β-coordinate vector of x is [c1, c2] = [(3x1 - x2 - 5x3)/20, (x2 - 2x1)/10 + (3x1 - x2 - 5x3)/40]. This is the vector representation of x in the basis β.

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P(t1 < t-1 < t²) is the probability that t1 is less than t raised to the power of -1, which is less than t squared.

To calculate the probability P(t1 < t-1 < t²), you need to determine the range of values for t that satisfy this inequality. Start by isolating t:

1. t1 < t-1 → t1 + 1 < t (by adding 1 to both sides)
2. t-1 < t² → 1/t < t (by rewriting t-1 as 1/t)

Now, find the range of t values that satisfy both inequalities. Graph these inequalities on a number line, and identify the intersection of the two ranges. The probability P(t1 < t-1 < t²) will be the proportion of this intersection relative to the total possible range of values for t.

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The relationship of angle 1 and angle 2 is same side interior angles.

From the information given, we have that;

The quadrilateral ABCD is a parallelogram.

Now, we need to know the properties of a parallelogram. These properties includes;

We can see from the diagram shown that;

<1 and <2 are same side interior angles and are thus supplementary.

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For the sample of weight of corn chips dispensed in dispensing machine, probability that the sample mean weight of these 100 bags falls between 10.50 and 10.80 ounces is equals to 0.4332.

We have a sample of weight of corn chips dispensed by the dispensing machine.

Dispensed weight of bag by the dispensing machine = 10 ounces

The sample of weight of bags follows the normal distribution with, sample mean, [tex] \bar x[/tex] = 10.5 ounces

standard deviations = 2 ounces

Randomly selected from this dispensing machine. Sample size, n = 100

We have to determine probability that the sample mean weight of these 100 bags falls between 10.50 and 10.80 ounces,

[tex]P( 10.50 < \bar x < 10.80),[/tex]

Using Z-score formula for sample mean in normal distribution, [tex]Z = \frac{ \bar x - \mu}{ \frac{\sigma}{\sqrt{n}} }[/tex]

where μ--> population mean

σ -->standard deviations

n --> Sample size

Now, the required probability is [tex]P( 10.50 < \bar x < 10.80)[/tex]

= [tex]P(\frac{ 10.50 - \mu }{\frac{\sigma}{\sqrt{n}}} < \frac{ \bar x - \mu}{ \frac{\sigma}{\sqrt{n}} } < \frac{ 10.80 - \mu }{\frac{\sigma}{\sqrt{n}}} )[/tex]

= [tex]P(\frac{ 10.50 - 10 }{\frac{2}{\sqrt{100}}} < z< \frac{ 10.80 - 10 }{\frac{2}{\sqrt{100}}} )[/tex]

= [tex]P(\frac{ 0.50 }{\frac{2}{10} }< z< \frac{ 0.80 }{\frac{2}{10}})[/tex]

= [tex]P(2.5 < z< 4)[/tex]

= 0.4332

Hence, required value is 0.4332.

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Answer:

d. 0

Step-by-step explanation:

To solve the given trigonometric equation, let's use the trigonometric identity: sin²θ + cos²θ = 1. We can rewrite the equation provided as follows:

cos a + cos² B + cos² y = 3

Using the identity, we can rewrite it as:

1 - sin² a + 1 - sin² B + 1 - sin² y = 3

Simplifying further, we have:

3 - (sin² a + sin² B + sin² y) = 3

Rearranging the equation, we get:

sin² a + sin² B + sin² y = 3 - 3

sin² a + sin² B + sin² y = 0

Therefore, the value of sin² a + sin² B + sin² y is 0 (option d).

The town of Lantana still needs to raise $1,496 for the new playground.

To find out how much more money the town of Lantana needs to raise for a new playground, you need to add up the amount of money each school has raised and subtract that total from the total cost of the playground.So:

Total amount raised = $5,538 + $2,834 + $4,132

Total amount raised = $12,504

To find how much more is needed, you subtract the total amount raised from the total amount needed:

Total amount needed - Total amount raised = $14,000 - $12,504

= $1,496

So the town of Lantana still needs to raise $1,496 for the new playground.

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The expected price of Tricki Corp, when it begins trading ex-rights, is $90.

We have,

When a stock goes ex-rights, the right to buy additional shares at a discounted price is no longer available to new investors.

Therefore, the value of the right is subtracted from the current stock price.

In this case,

To purchase one share of Tricki Corp, an investor would need to buy 10 rights at a cost of $10 each, for a total cost of $100.

With the subscription price of $90, the total cost of one share is $190.

Before going ex-rights, the stock price is $100.

After going ex-rights, the value of the right is $190 - $100 = $90.

The expected price of Tricki Corp, when it begins trading ex-rights.

= $100 - $90

= $10.

The new stock price will be $100 - $10 = $90.

Thus,

The expected price of Tricki Corp, when it begins trading ex-rights, is $90.

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