pls help ! MAPPING SHAPES
A) only sequence a
b) only sequence b
c)both
d) neither

Answer:

7 1/3 inches

Step-by-step explanation:

2 (1 3/4 + 1 11/12)

9+11

3/4+11/12= -------------

12

20/12

=1 2/3+ 2

2(3 2/3)

= 7 1/3

Answer:

4 pepperoni pizzas

Step-by-step explanation:

3 cheese => 1 pepperoni

12cheese (3x4) => 4 (1x4) pepperoni

Answer:

$750

Step-by-step explanation:

2500 divided by 100 = 25 and 25 x 30 = 750

Sorry if im wrong

The price for 2500 pencils is $750.

The unitary technique involves first determining the value of a single unit,  followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

We have,

A box of 100 personalized pencils costs $30.

So, cost of 1 pencil = $30 / 100 = 3/10

Now, the price to buy the 2500 pencils

= 2500 x 3/10

= 250 x 3

= $750

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Answer:

Step-by-step explanation:

So this is a cylinder

R= 8.75in

h=43.12in

So it will be = 3.14x8.75²x43.12

=> 3.14x76.5625x43.12

3.14x 3301.375

i think it is correct

.

stay safe

.

have a nice TIME

Answer:

2. 12

3. 1 6/8

4. 8 5/8

5. 4 4/8

6. Eli is incorrect 1 3/8 x 3 is 4 1/8 which is greater than 3 1/8

The standerd form 4m – 2m^4 – 6m^2 +9.

We have given that the polynomial given below we have to find the standerd form  of the polynomial.

[tex]P(x)=a_nx^n+a_{n-1}x^{n-1}+......+a_1x+a_0[/tex]

n=4

Standard form of the polynomial

[tex]4m - 2m^4 - 6m^2 + 9[/tex]

Rearranginge term we get

[tex]=-2m^4 - 6m^2 + 4m + 9[/tex]

The third term of the given polynomial is 0.

Therefore,the standard form is,

[tex]-2m^4 - 6m^2 + 4m + 9[/tex]

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Answer:

[tex]A.\,\orange{ \bold{ \frac{x - 3}{3x + 1} }}[/tex]

Step-by-step explanation:

[tex] \frac{x + 2}{ {x}^{2} + 5x + 6 } \div \frac{3x + 1}{ {x}^{2} - 9} \\ \\ = \frac{x + 2}{ {x}^{2} + 3x + 2x+ 6 } \div \frac{3x + 1}{ {x}^{2} - {(3)}^{2} } \\ \\ = \frac{\cancel{x + 2}}{ \cancel{{({x}+ 3)}} \cancel{(x+ 2) }} \times \frac{\cancel{( {x} + 3)}( {x} - {3)}}{3x + 1} \\ \\ = \purple{ \bold{ \frac{x - 3}{3x + 1} }}[/tex]

Sale price of the crate of pears after 10% discount on cost price $50 is equals to $45.

" Sale price is defined as the amount on which something is sold out."

Formula used

Sale price = Cost price - Discount amount

According to the question,

Cost price of the crate of pears = $50

Discount  on sale price = 10%

Discount amount = 10% of $50

                             [tex]=\frac{10}{100}(50) \\\\= \$5[/tex]

Substitute the value in the formula of sale price we get,

Sale price = [tex]\$ ( 50 - 5)[/tex]

                 = $ 45

Hence, sale price of the crate of pears after 10% discount on cost price $50 is equals to $45.

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Answer:

sixt

Step-by-step explanation:

thats easy the sin should be six

[tex]cos(\theta )=\cfrac{\stackrel{adjacent}{3}}{\underset{hypotenuse}{5}}\qquad \impliedby \textit{let's now find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \sqrt{5^2-3^2}=b\implies \sqrt{25-9}=b\implies \sqrt{16}=b\implies 4=b \\\\[-0.35em] ~\dotfill[/tex]

[tex]sin(\theta )=\cfrac{\stackrel{opposite}{4}}{\underset{hypotenuse}{5}}\qquad \qquad tan(\theta )=\cfrac{\stackrel{opposite}{4}}{\underset{adjacent}{3}}\qquad \qquad cot=\cfrac{\stackrel{adjacent}{3}}{\underset{opposite}{4}} \\\\\\ sec(\theta )=\cfrac{\stackrel{hypotenuse}{5}}{\underset{adjacent}{3}}\qquad \qquad csc(\theta )=\cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{4}}[/tex]

The values of the five other trigonometric functions value for the same input θ for which cos(θ) = 3/5 are:

Trigonometric ratios for a right angled triangle are from the perspective of a particular non-right angle.

In a right angled triangle, two such angles are there which are not right angled(not of 90 degrees).

The slant side is called hypotenuse.

From the considered angle, the side opposite to it is called perpendicular, and the remaining side will be called base.

From that angle (suppose its measure is θ),

[tex]\sin(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of Hypotenuse}}\\\cos(\theta) = \dfrac{\text{Length of Base }}{\text{Length of Hypotenuse}}\\\\\tan(\theta) = \dfrac{\text{Length of perpendicular}}{\text{Length of base}}\\\\\cot(\theta) = \dfrac{\text{Length of base}}{\text{Length of perpendicular}}\\\\\sec(\theta) = \dfrac{\text{Length of Hypotenuse}}{\text{Length of base}}\\\\\csc(\theta) = \dfrac{\text{Length of Hypotenuse}}{\text{Length of perpendicular}}\\[/tex]

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

We're given that:

cosθ = 3/5 for some angle θ

Since we've got:

[tex]\cos(\theta) = \dfrac{\text{Length of Base }}{\text{Length of Hypotenuse}}[/tex]

Therefore, we have:

[tex]\dfrac{3}{5} = \dfrac{\text{Length of Base }}{\text{Length of Hypotenuse}}[/tex]

Let we consider a right angled triangle in which there is hypotenuse of length 5 units and base (from the perspective of one of its non-right angle) of 3 units (as shown in the image attached below).

(we couldve taken 3x and 5x instead of 3 and 5, for any positive real number value of 'x' as when we would take their ratio, that common factor 'x' would get cancelled out. We can think of 3 and 5 as the special case of 3x and 5x when x = 1)

Then, from that perspective, let the perpendicular be of the length 'p' units, then as per the pythagoras theorem, we get:

[tex]p^2 + 3^2 = 5^2\\p = \sqrt{25 - 9} = \sqrt{16} = 4 \: \rm units[/tex]

(took only the positive root to remove the square term because the value of p denotes length, which is a non-negative quantity).

Thus, we have:

From the perspective of the angle θ:

Thus, using these values, and the definition of the trigonometric ratios, we get:

Thus, the values of the five other trigonometric functions value for the same input θ for which cos(θ) = 3/5 are:

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All three are similar

In ∆SUT and ∆VWX

So by SSA they are similar

In ∆PRQ and rest two

All angles are.

So

They are similar by AAA congruence

Answer: w=8.5

Step-by-step explanation:

Just did it.

Answer:

0/5 = 0

0/200 = 0

0/ (-25) = 0

Step-by-step explanation: I am sure this is it because these are rational numbers

Answer:

2159.6 i think

Step-by-step explanation:

i used a rectangle calculator

Answer:

its c i just got done doing the same one

Step-by-step explanation:

got it right on my real numbers test and got 100% if you need more help comment under my answer

Step-by-step explanation:

so,

1cm : 4m

that means the factor is 1/400 (as 1 m = 100 cm).

also to remember : 1 m² = 100cm×100cm = 10,000 cm²

the area of a rectangle is

length × width

if both dimensions are shortened by a factor (1/400) in our case :

length×1/400 × width×1/400 =

= length × width × 1/400² = length × width × 1/160,000

that means the area of the actual tennis court is

160,000 times the area of the blueprint picture :

160,000 × 16.25 = 2,600,000 cm² = 260 m²

we now know that the actual length of the tennis court is 400 times the length of the blueprint length :

400 × 6.25 = 2,500 cm = 25 m

Answer: 33 plus 3x

Step-by-step explanation:  simplified it

Answer:

The answer is 5x3+8x2+5x

Step-by-step explanation:

Answer:

The area is about 96.06 or 96.1

Step-by-step explanation:

I tried my best to solve it, I'm sorry if it's wrong.

Answer: x<-1

Step-by-step explanation:

The answer is A!

Answer:

See below.

Step-by-step explanation:

Solving the inequality :-

Graph A shows the solution to the inequality correctly

Answer:

x = 17.9

Step-by-step explanation:

[tex]tan40^{0} =\frac{15}{x}[/tex]

[tex]x=\frac{15}{tan40^{0} } =17.88[/tex]

rounded: 17.9

Hope this helps

Answer:

36 ,36 30,2

Step-by-step explanation:

hope it's okay to you

The possible values of z is an illustration of the sum operator

The sum of all possible values of z is 17

The conditions in the question are:

x <= y <= z

xyz = 2(x + y + z)

Using the trial by error method, the possible values of x, y and z are:

The sum of the z values are:

z = 8 + 5 + 4

Evaluate the sum

z = 17

Hence, the sum of all possible values of z is 17

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The amount of money that Han saves by using a coupon is $1.5%

The percentage off Clare's purchase with the coupon is 25%

A coupon reduces the price at which an item is sold

Amount saved = coupon discouunt x normal price

10% x $15

0.1 x $15 = $1.5

Percent off = (6/24 x 100  = 25%

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Answer:

Slope of the line is undefined

Step-by-step explanation:

(x₁, y₁) = (-1 , 3)  and (x₂, y₂) = (-1 , 8)

The line is parallel to y-axis. The slope of the line parallel to y-axis is undefined.

Answer:

money left= -50•games played + 47.50

Answer:

Given equation:

[tex]\left(\dfrac{1}{27}\right)^x=3^{(-4x+6)}[/tex]

27 can be written as [tex]3^3[/tex]

Also [tex]\dfrac{1}{a^b}[/tex] can be written as [tex]a^{-b}[/tex]

[tex]\implies \dfrac{1}{27}=\dfrac{1}{3^3}=3^{-3}[/tex]

Therefore, we can rewrite the given equation with base 3:

[tex]\implies (3^{-3})^x=3^{(-4x+6)}[/tex]

To solve, apply the exponent rule [tex](a^b)^c=a^{bc}[/tex]

[tex]\implies 3^{-3 \cdot x}=3^{(-4x+6)}[/tex]

[tex]\implies 3^{(-3x)}=3^{(-4x+6)}[/tex]

[tex]\textsf{If }a^{f(x)}=a^{g(x)}, \textsf{ then } f(x)=g(x)[/tex]

[tex]\implies -3x=-4x+6[/tex]

Add [tex]4x[/tex] to both sides:

[tex]\implies x=6[/tex]

Question 1

Focus on the triangle on the left.

sine is the ratio of opposite over hypotenuse

sin(angle) = opposite/hypotenuse

sin(44) = w/30

w = 30*sin(44)

w = 20.839751 approximately

Now move onto the triangle on the right. We'll use cosine this time.

cos(angle) = adjacent/hypotenuse

cos(x) = w/45

cos(x) = 20.839751/45

cos(x) = 0.463106

x = arccos(0.463106) ... arccosine is the same as [tex]\cos^{-1}[/tex]

x = 62.412286

==========================================================

Question 2

Focus on the triangle on the left.

sin(angle) = opposite/hypotenuse

sin(32) = w/5

w = 5*sin(32)

w = 2.649596

Now move to the triangle on the right.

sin(angle) = opposite/hypotenuse

sin(x) = w/5

sin(x) = 2.649596/5

sin(x) = 0.5299192

x = arcsin(0.5299192) .... arcsine is the same as [tex]\sin^{-1}[/tex]

x = 31.999996

==========================================================

Question 3

This time we use the tangent ratio.

Focus on the triangle that has legs of w and 16.

tan(angle) = opposite/adjacent

tan(70) = 16/w

w*tan(70) = 16

w = 16/tan(70)

w = 5.823524

Now let y = x+w and focus on the largest triangle this time.

tan(angle) = opposite/adjacent

tan(41) = 16/y

y = 16/tan(41)

y = 18.405895

This leads to:

y = x+w

x = y-w

x = 18.405895 - 5.823524

x = 12.582371