PLS PLS PLS THIS IS VOCAB FOR MATH ONLY HAVE UNTILL 7:30 TO DO SEVERAL ASSIGHNMENTS1. a number belonging to the set made up of the counting numbers: 1, 2, 3, and so on

2. a number that is greater than zero

3. a line that graphically represents all numbers

4. a pair of numbers whose sum is zero

5. any number belonging to the set of counting number, or zero

6. a number that is less than zero

7. a number belonging to the set made up of the whole numbers and their opposites

8. two numbers that are the same distance from zero on the number line but in opposite directions

Answer:

false

Step-by-step explanation:

Answer:

Is it Khan Academy? You do 5.8 - 2.7 = 3.1

Step-by-step explanation:

Hope that helps!

Answer:

$452.56

Step-by-step explanation:

400 * 1.025^(5)

Step-by-step explanation:

b 8 is the answer

simplify to2^4^(3/4) then 2^3 then that simplies to 8

Answer:

120 deg

Step-by-step explanation:

There is an angle symbol in the equilateral triangle and another symbol in half of the vertex angle. Those two angles are congruent.

The measure of the vertex angle is 2 * 60 deg = 120 deg

Answer: 120 deg

Answer:

-5+5

= 0

Step-by-step explanation:

Answer:

-5+5

= 0

Step-by-step explanation:

Answer:

x = 0.3333333333

Step-by-step explanation:

Simplifying

42x = 14

Solving

42x = 14

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '42'.

x = 0.3333333333

Simplifying

x = 0.3333333333

Answer: 95 divided by 9 is 10.5 BUT WITH THE 5 REPEATING

Step-by-step explanation:

Answer:

68.5

Step-by-step explanation:

each pack 7.5 kg

price for each pack $3

he bought 3

7.5 x 3=22.5

22.5 x3=66.5

Answer:

The number to use are 10, 7, 20 and 3.

Step-by-step explanation:

Given

[tex]17 * 23[/tex]

Required

Which numbers would be used using the area model or partial products

The number to use are 10, 7, 20 and 3.

This is shown below:

[tex]\begin{array}{ccc}{ } & {10} & {7} & {20} & { } & { } \ \\ {3} & { } & { } \ \end{array}[/tex]

When the numbers are multiplied, we get:

[tex]\begin{array}{cccc}{ } & {10} & {7} & {} & {20} & {200} &{140} &{=340}\ \\ {3} & {30 } & {21 } &{=51} \ \end{array}[/tex]

[tex]Total = 340 + 51[/tex]

[tex]Total = 391[/tex]

Answer:

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}[/tex]

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}[/tex]

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}[/tex]

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}[/tex]

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1[/tex]

[tex]\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}[/tex]

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x[/tex]

Step-by-step explanation:

Required

Simplify

Solving (1):

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}[/tex]

Factorize the numerator and the denominator

[tex]\frac{x^2(x + 2) -9(x+2)}{x(x^2-x-6)}[/tex]

Factor out x+2 at the numerator

[tex]\frac{(x^2 -9)(x+2)}{x(x^2-x-6)}[/tex]

Express x^2 - 9 as difference of two squares

[tex]\frac{(x^2 -3^2)(x+2)}{x(x^2-x-6)}[/tex]

[tex]\frac{(x -3)(x+3)(x+2)}{x(x^2-x-6)}[/tex]

Expand the denominator

[tex]\frac{(x -3)(x+3)(x+2)}{x(x^2-3x+2x-6)}[/tex]

Factorize

[tex]\frac{(x -3)(x+3)(x+2)}{x(x(x-3)+2(x-3))}[/tex]

[tex]\frac{(x -3)(x+3)(x+2)}{x(x+2)(x-3)}[/tex]

Cancel out same factors

[tex]\frac{(x+3)}{x}[/tex]

Hence:

[tex]\frac{x^3 + 2x^2 -9x-18}{x^3-x^2-6x}= \frac{(x+3)}{x}[/tex]

Solving (2):

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2}[/tex]

Expand the numerator and factorize the denominator

[tex]\frac{3x^2 - 6x + x - 2}{x^2(x- 2)}[/tex]

Factorize the numerator

[tex]\frac{3x(x - 2) + 1(x - 2)}{x^2(x- 2)}[/tex]

Factor out x - 2

[tex]\frac{(3x + 1)(x - 2)}{x^2(x- 2)}[/tex]

Cancel out x - 2

[tex]\frac{3x + 1}{x^2}[/tex]

Hence:

[tex]\frac{3x^2 - 5x - 2}{x^3 - 2x^2} = \frac{3x + 1}{x^2}[/tex]

Solving (3):

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}[/tex]

Express x^2 - 9 as difference of two squares

[tex]\frac{6 - 2x}{x^2 - 3^2} * \frac{15 + 5x}{4x}[/tex]

Factorize all:

[tex]\frac{2(3 - x)}{(x- 3)(x+3)} * \frac{5(3 + x)}{2(2x)}[/tex]

Cancel out x + 3 and 3 + x

[tex]\frac{2(3 - x)}{(x- 3)} * \frac{5}{2(2x)}[/tex]

[tex]\frac{3 - x}{x- 3} * \frac{5}{2x}[/tex]

Express [tex]3 - x[/tex] as [tex]-(x - 3)[/tex]

[tex]\frac{-(x-3)}{x- 3} * \frac{5}{2x}\\[/tex]

[tex]-1 * \frac{5}{2x}[/tex]

[tex]-\frac{5}{2x}[/tex]

Hence:

[tex]\frac{6 - 2x}{x^2 - 9} * \frac{15 + 5x}{4x}=-\frac{5}{2x}[/tex]

Solving (4):

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x}[/tex]

Expand x^2 - 6x + 9 and factorize 5x - 15

[tex]\frac{x^2 -3x -3x+ 9}{5(x - 3)} / \frac{5}{3-x}[/tex]

Factorize

[tex]\frac{x(x -3) -3(x-3)}{5(x - 3)} / \frac{5}{3-x}[/tex]

[tex]\frac{(x -3)(x-3)}{5(x - 3)} / \frac{5}{3-x}[/tex]

Cancel out x - 3

[tex]\frac{(x -3)}{5} / \frac{5}{3-x}[/tex]

Change / to *

[tex]\frac{(x -3)}{5} * \frac{3-x}{5}[/tex]

Express [tex]3 - x[/tex] as [tex]-(x - 3)[/tex]

[tex]\frac{(x -3)}{5} * \frac{-(x-3)}{5}[/tex]

[tex]\frac{-(x-3)(x -3)}{5*5}[/tex]

[tex]\frac{-(x-3)^2}{25}[/tex]

Hence:

[tex]\frac{x^2 -6x + 9}{5x - 15} / \frac{5}{3-x} = \frac{-(x-3)^2}{25}[/tex]

Solving (5):

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}[/tex]

Factorize the numerator and expand the denominator

[tex]\frac{x^2(x - 1) -1(x - 1)}{x^2 - x-x+1}[/tex]

Factor out x - 1 at the numerator and factorize the denominator

[tex]\frac{(x^2 - 1)(x - 1)}{x(x -1)- 1(x-1)}[/tex]

Express x^2 - 1 as difference of two squares and factor out x - 1 at the denominator

[tex]\frac{(x +1)(x-1)(x - 1)}{(x -1)(x-1)}[/tex]

[tex]x +1[/tex]

Hence:

[tex]\frac{x^3 - x^2 -x + 1}{x^2 - 2x+1}= x +1[/tex]

Solving (6):

[tex]\frac{9x^2 + 3x}{6x^2}[/tex]

Factorize:

[tex]\frac{3x(3x + 1)}{3x(2x)}[/tex]

Divide by 3x

[tex]\frac{3x + 1}{2x}[/tex]

Hence:

[tex]\frac{9x^2 + 3x}{6x^2} = \frac{3x + 1}{2x}[/tex]

Solving (7):

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x}[/tex]

Change / to *

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}[/tex]

Expand

[tex]\frac{x^2-2x-x+2}{4x} * \frac{12x^2}{x^2 - 2x} * \frac{x}{x-1}[/tex]

Factorize

[tex]\frac{x(x-2)-1(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}[/tex]

[tex]\frac{(x-1)(x-2)}{4x} * \frac{12x^2}{x(x - 2)} * \frac{x}{x-1}[/tex]

Cancel out x - 2 and x - 1

[tex]\frac{1}{4x} * \frac{12x^2}{x} * \frac{x}{1}[/tex]

Cancel out x

[tex]\frac{1}{4x} * \frac{12x^2}{1} * \frac{1}{1}[/tex]

[tex]\frac{12x^2}{4x}[/tex]

[tex]3x[/tex]

Hence:

[tex]\frac{x^2-3x+2}{4x} * \frac{12x^2}{x^2 - 2x} / \frac{x - 1}{x} = 3x[/tex]

Answer:

34+12x=100 12x=66 x=66/12=11/2 answer:11/2

Step-by-step explanation:

Answer:

[tex]12n+34>100[/tex]

Step-by-step explanation:

Let d be the number of days.

We have been that each day Katie finds 12 more seashells on beach, so after collecting shells for d days Katie will have 12d shells.  

We are also told that Katie already has 34 seashells in her collection, so total number of shells in Katie collection after d days will be: [tex]12n+34[/tex]

As Katie wants to collect over 100 seashells, so the total number of shells collected in d days will be greater than 100.

Answer:

it's 80% of 125

the value of x = 125

Step-by-step explanation:

Answer: The ratio of eggs, eggs, to two cups of flour. Let me write two cups of flour. Cups of flour. In either case is, is four eggs for every three cups of flour 5/2

Step-by-step explanation: Im not sure through

Answer:

7 miles per day

Step-by-step explanation:

Solve:

84 divided by 12

Check:

12 multiplied by 7

Hope this helps!

Answer:

All sides will be 11 and all angles will be 90 degrees.

Step-by-step explanation:

As all sides of square are equal. And all angles are right angled.

Hope it helped!!

Answer:

1)whole numbers

2)integers

3)rational numbers

Los lados es = sqrt(1681)

=41cm

Answer:

y = 6

Step-by-step explanation:

I'm going to assume you want to solve for y.

Step 1: Move all constants to 1 side, isolating y and its coefficient:

14 = 3y - 4

14 + 4 = 3y - 4 + 4

18 = 3y

Step 2: Divide both sides by 3 to solve for y:

3y = 18

3y / 3 = 18 / 3

y = 6

Final answer: y = 6

Answer:

she scored 42

Step-by-step explanation:

Answer:

vyvv6

Step-by-step explanation:

6g6t5g6g66ftce6tswftzadtxevyze

Answer:

x=9

y=3

Step-by-step explanation:

since all three sides of an equlateral triangle are equal:

3x+y=30   then y=30-3x

4x-2y=30

4x-2(30-3x)=30

4x-60+6x=30

10x=90

x=9

3x+y=4x-2y

x=3y

y=3

Answer:

its C. 8 :) please give me brainlist

Answer:

14.06

Step-by-step explanation:

The absolute value is the distance between a number and zero. The distance between 0 and 14.06 is 14.06.

Answer:

14.06

Step-by-step explanation:

|14.06| means the absolute value of 14.06, which is 14.06!

Hope that helps!

Answer:

6.5 hours

Step-by-step explanation:

123-45=78

78/12=6.5

Theo had the limousine reserved for 6.5 hours.

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Theo's equation for the cost of renting a limousine is:

c = 45 + 12h

where c is the total cost,

and h is the number of hours reserved.

If the final bill amounts to $123,

we can set c equal to 123 and solve for h:

123 = 45 + 12h

Subtracting 45 from both sides:

78 = 12h

Dividing both sides by 12:

h = 6.5

Therefore, Theo had the limousine reserved for 6.5 hours.

Learn more about algebraic Expression here:

https://brainly.com/question/953809

#SPJ3

Answer:

V = pi x radius x 2 x height OR pi x diameter x height

Hope that helps!

Answer:

the formula for the volume of a cylinder is V=πr²h

Answer:

Step-by-step explanation:

Answer:

First option is the correct answer.

[tex] (m + n - 1) \sqrt{p} [/tex]

Step-by-step explanation:

[tex]m\sqrt{p} + n\sqrt{p} - \sqrt{p} \\ \\ = (m + n - 1) \sqrt{p} [/tex]

Answer:

y=3x-7

Step-by-step explanation:

i plotted the point, and used the slope to get the equation