Select the correct answer. Which chart best represents the following information about student results from a class assignment? Frequency 10 Score Frequency Chart 1 23 2 Frequency 10 24 8 25 4 Chart 2 26 3 27 5 28 4 29 5​

This is a simple harmonic motion exercise. The proof that the resultant force on the particle, at time t, is -225 Newtons is indicated below.

Note that we have been given the following:

Mass = 9kg,

Y = 45 N

ζ = 0.4 m

Then, Y/ζ  = 45N/0.4m

= 112.5 N/m

Hence, the spring constant =

K = 112. 5N/m

From this point we can resolve the Amplitude (A):
Amplitude is given as:

A = CB - PB

= 0.6 - 0.5

A = 0.1m

I) So because one spring is elongated by x and the other is compressed by x, Hence, the spring force is:

F[tex]_{net}[/tex] = - Kₓ - Kₓ

= - 2Kₓ
= -2 x 112.5 x* X

F[tex]_{net}[/tex] = -225x Newton ..........Lets call this expression 1

From equation 1 above, we know that

Ma = -225x

a = (-225/m) x

⇒ a ∝ - x,

Hence, the motion is is simple harmonic in nature.

The time period, T = 2 π√m/K[tex]_{eq}[/tex]

Where, K[tex]_{eq}[/tex] = 2K

= 2π√(9/225)

= 2π * 3/15

= 2(22/7) * (3/15)

= 1.25714285714; thus

T ≈ 1.26 secs...............lets call this expression 2

Note that Angular Frequency is = 2π/T

= 2π/1.26

= 4.9866550057

ω = 4.99 rad/s

Since the velocity at any point x from the mean position is given by

V = ω √ (A² - x²); hence

V = 4.99 √[(0.1)² - (0.05)²

V = 4.99 x 0.0866
V = 0.432134

V ≈ 0.432..........Lets call this expression 3

Along the x-axis, A simple harmonic motion can be depicted as:

x = A sin (ωt + Ф) ..........lets call this expression 4

where, Ф = Phase constant

At t = 0; x = A

A = A sinФ

⇒ SinФ = 1

⇒ Ф = π/2

Expression 4 becomes:

x = A sin (ωt + π/2)

Inserting the values of ω and A, we have

x = 0.1 sin (4.99t + π/2).........Lets call this expression 5a

or  x  = 0.1 cos (4.99t).......Lets call this expression 5b

Hence,

Sin(π/2  + Ф) = CosФ

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Answer:

the area would be 176.7

Step-by-step explanation:

You know the area of a circle is A = pi×r^2, so you need the radius.

You know C = 2pi×r, so r = C/(2pi)

r = 15pi / 2pi = 7.5

A = pi(7.5)^2 = 56.25pi ~ 176.715 square inches.

The area of the circle is about 176.7 square inches.

The radius of the circle is 7.5 inches. Therefore, the area of the circle will be 56.25π square inches.

Let r be the radius of the circle. Then the area of the circle will be given as,

A = πr² square units

The circumference of the circle will be given as,

C = 2πr units

The circumference of a circle is 15π inches. Then the radius of the circle is calculated as,

15π = 2πr

r = 7.5 inches

The area of the circle is calculated as,

A = π x 7.5²

A = 56.25π square inches

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[tex]\begin{array}{c|c|c|c} p & q & \neg q & p \land \neg q \\ T & T & F & F \\ T & F & T & T \\ F & T & F & F \\ F & F & T & F \end{array}[/tex]

[tex]\begin{array}{c|c|c|c} t & s & \neg t & \neg t \implies s \\ T & T & F & T \\ T & F & F & T \\ F & T & T & T \\ F & F & T & F \end{array}[/tex]

[tex]\begin{array}{c|c|c}p\land \neg q & \neg t \implies s & (p \land \neg q) \implies (\neg t \implies s) \\T & T & T \\ T & F & F \\ F & T & T \\ F & F & T \end{array}[/tex]

The given logical statement is false when [tex]p\land\neg q[/tex] and [tex]\neg t\implies s[/tex] are true and false, respectively.

Answer:

[tex]y=-2.5x+8[/tex]

Step-by-step explanation:

Parallel lines have the same slope but different y-intercepts. So, first, transform the given equation into the slope-intercept form, [tex]y=mx+b[/tex].

[tex]5x+2y=6[/tex]

[tex]2y=-5x+6[/tex]

[tex]y=-\frac{5}{2} x+3[/tex]

Then, determine the equation of a line that has a slope of [tex]-\frac{5}{2}[/tex] and passes through (1, 5.5). Substitute all the known values and solve for b.

[tex]y=mx+b[/tex]

[tex]5.5 = -\frac{5}{2} *1+b[/tex]

[tex]5.5=-2.5+b[/tex]

[tex]b=8[/tex]

Therefore, the answer is [tex]y=-2.5x+8[/tex].

Answer:

x = 14

Step-by-step explanation:

PMN forms a triangle and the sum of interior angles in a triangle is equal to 180 therefore we can use the following equation to find the value of x

32 + 64 + 6x = 180 add like terms

96 + 6x = 180 subtract 96 from both sides

6x = 84 divide both sides by 6

x = 14

4x - 10 = 7 - 2x (given)

6x - 10 = 7 (addition property of equality)

6x = 17 (addition property of equality)

x = 17/6 (division property of equality)

An equation is an expression that shows the relationship between two or more numbers and variables.

From the equation:

4x - 10 = 7 - 2x (given)

6x - 10 = 7 (addition property of equality)

6x = 17 (addition property of equality)

x = 17/6 (division property of equality)

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Answer:

iTS 6 2/3 OPTION 2.

Step-by-step explanation:

Because Area = L*B

SO L = A/b

L= 65/3 * 4/13(reciprocal and multiply)

L=20/3 = 6 2/3

Answer:

So answer is 6 2/3

because Look carefully

Area =length× width

length=Area÷ width

so

[tex]21 \frac{2}{3} \div 3 \frac{1}{4} = 6 \frac{2}{3} [/tex]

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

Area left for flowers = Area of flower garden - Area of bird bath.

Area of flower garden [ rectangle ] :

[tex]\qquad❖ \: \sf \:length \times width[/tex]

[tex]\qquad❖ \: \sf \:3 \times 2[/tex]

[tex]\qquad❖ \: \sf \: 6\: \: {m}^{2} [/tex]

Area of bird bath [ Circle ] :

[tex]\qquad❖ \: \sf \: \pi{r}^{2} [/tex]

[tex]\qquad❖ \: \sf \:3.14 \times ( \frac{1}{2} ) {}^{2} [/tex]

[tex]\qquad❖ \: \sf \:3.14 \times \frac{1}{4} [/tex]

[tex]\qquad❖ \: \sf \:0.785 \: \: m {}^{2} [/tex]

Area left for flowers :

[tex]\qquad❖ \: \sf \:6 - 0.785[/tex]

[tex]\qquad❖ \: \sf \:5.215 \: \: m {}^{2} [/tex]

[tex]\qquad❖ \: \sf \: \approx5.22 \: \: m {}^{2} [/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

Answer:

(2,-3)

Step-by-step explanation:

I am not sure if you meant the first equation to be y or -y.  I solved it as y.

y = x-5                       -x -3y =7

I am going to take the second equation and write it as x =

-x - 3y = 7  Give equation

-x = 3y +7   Add 3y to both sides

x = -3y-7  Multiplied each term in the equation by -1 so that x could be positive

I am going to substitute -3y-7 for x in the first equation up above

y = x - 5

y = -3y -7 - 5  Substitute -3y-7 for x

y = -3y -12  Combined -7-5

4y = -12  Added 3y to both sides

y = -3  Divided both sides by 4.

I now know that y is -3, I will plug that into x = -3y-7 to solve for x

x = -3(-3) -7

x = 9-7   A negative times a negative is a positive

x = 2

Using the z-distribution, the critical value for a confidence level of 90% is of Z = 1.65.

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.65.

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The value of x has a z-score of three is 20

The given parameters are:

Mean = 2

Standard deviation = 6

z = 3

The z-score is calculated as:

[tex]z = \frac{x - \mu}{\sigma}[/tex]

So, we have:

[tex]3 = \frac{x -2}{6}[/tex]

Multiply through by 6

18 = x - 2

Add 2 to both sides

x = 20

Hence, the value of x has a z-score of three is 20

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Okay, it's very simple, to solve this triangle you need to understand what the other angles are. We know that angle A is 90º, as it is represented as a square.

We now need to solve for angle B. angle B can be solved for by

Sin (x) = Opposite / Hypotenuse = 3 / 3√5 = 2.24ish
sin(x) = 2.24

x = [tex]sin^{-1}[/tex](2.24)

Use sin.

Answer:

Step-by-step explanation:

what's the answer

The critical values are 0.622, 0.707, 0.789 and 0.834

The sample size is given as:

n = 8

Calculate the degrees of freedom using

df = n - 2

So, we have:

df = 8 - 2

df = 6

Using the table of values of critical values, we have:

Critical values = 0.622, 0.707, 0.789 and 0.834

By comparing the critical values and the linear correlation coefficient, we can conclude that there is no significant linear correlation.

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Answer:

Exact form: 7/143

Decimal form: /0.048951

Answer:

[tex]x=\frac{7}{143}[/tex]

Step-by-step explanation:

Simplify the right side of the equation. [tex]3x+21=432x[/tex]. Subtract 21 from both sides of the equation. [tex]3x=432x-21[/tex]. Subtract 432x from both sides of the equation, [tex]-429x=-21[/tex]. The negative signs cancel out to get [tex]429x=21[/tex]. Divide both sides but 429 to get [tex]x=\frac{21}{429}[/tex].  Reduce to get [tex]x=\frac{7}{143}[/tex].

Answer:

51

Step-by-step explanation:

Let c be the number of child tickets sold.

Let a be the number of adult tickets sold.

From the information given from the question, we can deduce:

6.10c + 9.70a = 1074.20 - Equation 1

c + a = 146 - Equation 2

From here, we can use the substitution method in solving simultaneous equations to find a and c. We will use Equation 2 as the base.

c = 146 - a - Equation 2A

We will then substitute equation 2A into Equation 1 to find a.

6.10(146-a) + 9.70a = 1074.20

890.6 - 6.10a + 9.70a = 1074.20

890.6 + 3.6a = 1074.20

3.6a = 1074.20 - 890.6

3.6a = 183.6

a = [tex]\frac{183.6}{3.6}[/tex]

a = 51

Therefore we know that 51  adult tickets were sold that day.

After that you can substitute a into equation 2 to find c.

Answer: -5

Step-by-step explanation:

[tex]h(4)=\frac{1}{2}(4)-5=-3\\\\f(4)=3h(4)+4=3(-3)+4=-5[/tex]

The volumes of the right prisms are listed below:

In this problem we have six cases of right prisms with rectangular bases, the volume of right prisms (V), in cubic length units, is equal to the product of the area of the base (A), in square length units, and the height (h), in length units. The equation of the volume of the right prism is shown below:

V = w · l · h     (1)

Where:

Now we proceed to calculate each volume:

Prism 1 (w = 2 / 3 ft, l = 1 / 3 ft, h = 1 / 2 ft)

V = (2 / 3 ft) · (1 / 3 ft) · (1 / 2 ft)

V = 1 / 9 ft³

Prism 2 (w = 1 / 8 in, l = 3 / 4 in, h = 13 / 16 in)

V = (1 / 8 in) · (3 / 4 in) · (13 / 16 in)

V = 39 / 512 in ³

Prism 3 (w = 7 / 8 cm, l = 1 / 4 cm, h = 1 / 12 cm)

V = (7 / 8 cm) · (1 / 4 cm) · (1 / 12 cm)

V = 7 / 384 cm³

Prism 4 (w = 1 / 7 cm, l = 7 / 8 cm, h = 2 / 3 cm)

V = (1 / 7 cm) · (7 / 8 cm) · (2 / 3 cm)

V = 1 / 12 cm³

Prism 5 (w = 9 / 10 m, l = 2 / 3 m, h = 1 / 5 m)

V = (9 / 10 m) · (2 / 3 m) · (1 / 5 m)

V = 3 / 25 m³

Prism 6 (w = 7 / 8 yd, l = 6 / 7 yd, h = 1 / 2 yd)

V = (7 / 8 yd) · (6 / 7 yd) · (1 / 2 yd)

V = 3 / 8 yd³

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The value of the sum of the angles x + y of the given triangle is; 220°

We know that the sum of angles in a straight line is equal to 180°. Thus;

∠CFE + ∠OFE = 180

140 + ∠OFE = 180

∠OFE = 180 - 140

∠OFE = 40°

Similarly, we can use the same principle to get;

∠OEF + ∠BEF = 180°

∠OEF + y = 180°

∠OEF = 180 - y

Similarly,

∠AOF + ∠EOF = 180°

x + ∠EOF = 180°

∠EOF = 180 - x

Sum of angles in a triangle is equal to 180°. Thus;

40 + 180 - y + 180 - x = 180

Rearranging gives;

x + y = 180 + 180 + 40 - 180

x + y = 220°

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The total interest on the mortgage loan  is $219,249.60

What is a mortgage loan?

It is a loan taken in order to purchase a property that requires periodic repayments such as monthly repayment since most mortgages are repaid monthly.

Our first task is to determine the monthly repayment using the present value formula of an ordinary annuity because the monthly payment becomes due at the end of each month.

PV=monthly repayment*(1-(1+r)^-N/r

PV=loan amount=$210,000

monthly repayment=unknown(assume it is X)

r=monthly interest rate=5.5%/12=0.00458333333333333

N=number of monthly payments in 30 years=30*12=360

$210,000=X*(1-(1+0.00458333333333333)^-360/0.00458333333333333

$210,000=X*(1-(1.00458333333333333)^-360/0.00458333333333333

$210,000=X*(1-0.19277525234572900)/0.00458333333333333

$210,000=X*0.80722474765427100/0.00458333333333333

$210,000=X*176.12176312456800000

X=$210,000/176.12176312456800000

X=monthly payment=$1,192.36

total repayments(360 months)=$1,192.36*360

total repayments(360 months)=$429,249.60

Total interest=total repayments(360 months)-loan amount

Total interest=$429,249.60-$210,000

Total interest=$219,249.60

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Linking each equation with its equivalent equation below:

Equivalent equation can be defined as an equation that has the same value with another equation.

Equivalent equation are not directly the same but can be transformed to look like each other.

In conclusion, The equivalent equations have been matched in the list above.

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The point has a real part of 0 and an imaginary part of 18, and thus corresponds to the point (0,18) in the complex plane.

The insurance cost for the second year from the information given will be $476.

The insurance cost for the second year will be:

= $14000 × 0.034

= $476

Therefore, the insurance cost for the second year will be $476

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The insurance cost for the second year from the information given will be $476.

How to calculate the insurance cost?

The insurance cost for the second year will be:

= $14000 × 0.034

= $476

Therefore, the insurance cost for the second year will be $476

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Answer:

y = 40

Step-by-step explanation:

y/8 = 5

———————————————————

Multiply both sides by 8:

8y/8 = 5 * 8

———————————————————

Simplify:

y = 40

Hope that helps! :)

Answer:

Y = 40

Step-by-step explanation:

Step 1:

y/8 = 5

Bring 8 to the right side changing its arithmetic sign to multiply.

Step 2:

y = 5 x 8

Now multiply 5 by 8 to get the answer.

Step 3:

y = 40

Therefore, y is equal to 40.

Answer:

dependent

Step-by-step explanation:

because when x decreases y has to also decrease, so they are dependent on eachother

The derivative of the function [tex]f(x)=5^{2x}[/tex] is [tex]\frac{df}{dx} =2ln5(5^{2x})[/tex]

The derivative of a function f(x) is the ratio of the change in f(x) to the change in x

The given function is:

[tex]f(x)=5^{2x}[/tex]

Let u = 2x

Find the derivative of u. That is, du/dx

du/dx = 2

f(x) = 5^u

[tex]\frac{df}{du} =5^ulnu[/tex]

Using the chain rule of derivative

[tex]\frac{df}{dx}=\frac{df}{du} \times\frac{du}{dx}[/tex]

[tex]\frac{df}{dx} =5^uln5 \times 2\\\\\frac{df}{dx} =2ln5(5^{2x})[/tex]

The derivative of the function [tex]f(x)=5^{2x}[/tex] is [tex]\frac{df}{dx} =2ln5(5^{2x})[/tex]

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There does not appear to be a linear relationship between the high school girls' height and their IQ scores.

The complete question is added as an attachment

To plot the scatter plot, we make use of the following representations:

Next, we enter the values in a graphing calculator.

From the summary on the graphing calculator, we can conclude that the scatter plot is (c)

To determine the sample correlation coefficient, we make use of the following representations:

Next, we enter the values in a graphing calculator.

From the graphing calculator, we have the following summary:

X Values

Y Values

X and Y Combined

R Calculation

r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

r = -19.25 / √((107.875)(813.5))

r = -0.065

Hence, the sample correlation coefficient is -0.065

In (b), we have:

r = -0.065

This means that there is a negative correlation

i.e. There does not appear to be a linear relationship between the high school girls' height and their IQ scores.

To do this, we have:

Number of pairs, n = 8

Significance level =0.01

Using a graphing calculator;

At 0.01 significance level, the critical correlation coefficient is 0.7887

0.7887 is greater than 0.01

This means that we accept the null hypothesis.

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The value of the text statistic. F  is given as : 0.742 See explanation below.

A test statistic is a numerical value determined by a statistical test.

It quantifies the distance between your observed data and the null hypothesis of no link between variables or no difference between sample groups.

Test Statistic F is given by:

= σ²₁/σ²₂

= 0.93²/1.08²

= (0.93/1.08)²

= 0.8611²

= 0.742

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Answer:

D. g(x) is a reflection of f(x) over the x-axis.

Step-by-step explanation:

So when you have the equation: [tex]-2x^2[/tex] it's just negating the value of f(x), which is [tex]2x^2[/tex] and since f(x) represents the y-value, you're negating the y-value and the x-value is unchanged. So each point on f(x) was originally: (x, f(x)) and now it's (x, -f(x)). Since the y-value is changing, it's going to be reflecting across the x-axis. So g(x) is a reflection of f(x) over the x-axis.

The coordinates of A exist (11, 0).

Let, the point A (-5, -2) exists reflected over the line y = -1, and then stand reflected over the line x = 3.

The distance between the y value exists -1 - (-2)= 1

We move 1 unit beyond the line y = -1

After reflection over the line y = -1 the coordinates of A becomes (-5, 1-1) is (-5, 0)

It exists reflected over the line x = 3

The distance between -5 and 3 exists 3 - (-5) = 8

We move 8 units out from the line x = 3

The Point (-5, 0) becomes (3 + 8, 0) exists (11, 0).

Therefore, the coordinates of A exist (11, 0).

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The complete question:

The point A (-5, -2) is reflected over the line y = -1, and then is reflected over the line x = 3. What are the coordinates of A.

Answer:

(12 + n/3) = 2n + 1

Step-by-step explanation:

(12 + n/3) = 2n + 1

36 + n = 6n + 3

33 = 5n

n = 33/5