Solution for
Y= x+3
Y= 3x+1

Answer:

3X=15

X=5

2X5= 10

G=10

Step-by-step explanation:

#First find the gradient first, remember that the formula of equation of the line is y = mx + c and gradient's symbol is m

y = ½x - 3

#so the gradient is ½, now u can find the equation of the lime.

y - y1 = m(x - x1)

y - 4 = ½(x - 6)

y - 4 = ½x - 3

y = ½x - 3 + 4

y = ½x + 1

Answer:

n+524

Step-by-step explanation:

you add both years worth of biking together!

Answer:

3.25

Step-by-step explanation:

Answer:

Step-by-step explanation:

The amount of money that Ms. Gonzalez spends on small folders than large folders will be $12.75.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

Ms. Gonzalez buys folders for her office. She buys 4 small folders for every 1 large folder. She buys 15 folders in all. Small folders cost $0.75, and large folders cost $1.25.

Let 'x' be the number of small folders and 'y' be the large folders. Then the equations are given as,

x + y = 15          ...1

y = 4x              ...2

From equations 1 and 2, then we have

x + 4x = 15

5x = 15

x = 3

Then the value of 'y' is given as,

3 + y = 15

y = 12

The cost of the small folder is given as,

⇒ $0.75 × 3

⇒ $2.25

The cost of the large folder is given as,

⇒ $1.25 × 12

⇒ $15

The difference is given as,

⇒ $15 - $2.25

⇒ $12.75

The amount of money that Ms. Gonzalez spends on small folders than large folders will be $12.75.

More about the solution of the equation link is given below.

https://brainly.com/question/545403

#SPJ5

Answer:

D & E

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

Answer:

7 cubic meters away

Step-by-step explanation:

Answer:

Slope: 5/1

y-intercept: 2

Step-by-step explanation:

Answer:

[tex]\frac{1}{5}[/tex] = [tex]\frac{2}{10}[/tex] = [tex]\frac{20}{100}[/tex]

Step-by-step explanation:

It's all about equivalent fractions.

[tex]\frac{1}{5}[/tex]

[tex]\frac{2}{10}[/tex]

[tex]\frac{20}{100}[/tex]

[tex]\frac{1}{5}[/tex] 1 × 2 = 2. 5 × 2 = 10. That is what makes [tex]\frac{2}{10}[/tex].

[tex]\frac{2}{10}[/tex] 2 × 10 = 20. 10 × 10 = 100. That is what makes [tex]\frac{20}{100}[/tex].

Answer:

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Step-by-step explanation:

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Answer:

The control group is the group that takes the sugar pill

Step-by-step explanation:

In drug testing, to determine the efficacy of a drug, different groups of experimental subjects are recruited, one group is given the drug to be tested (treatment group) while another group is given a placebo.

A placebo is a fake version of the drug to be tested that does not have any therapeutic effect on the test subjects that receive it. In this case, the control group receives the placebo which is the sugar pill. They serve as the baseline of measurement when the outcome of the effect of the drug testing is done. The groups that received the actual drugs are compared against the groups that received the hoax treatment, and any change occuring  in the test subjects become the changes occuring as a result of the test drug used, when the observations on the control group has been ruled out.

Answer:

y=-2x+5

Step-by-step explanation:

To figure out the equation of a line, use the formula y=mx+c, where y and x represent the co-ordinate values, m is the slope and c is the y-intercept (where the graph cuts the y-axis).

The slope can be found by taking two points (x1,y1) and (x2,y2), and using the formula m=(y2-y1)/(x2-x1):

(0,5) and (1,3)

m=(3-5)/(1-0)

m=-2

We can see from the graph that the line cuts the y-axis at y=5, so c=5.

Now that we know m and c, we plug these values into our formula to get y=-2x+5

Answer:

[tex]\bar x =2.53[/tex] -- Mean

[tex]Median= 2[/tex]

[tex]Mode = 2[/tex]

[tex]Range = 8[/tex]

[tex]Q_1 = 1[/tex]

[tex]Q_3 = 3[/tex]

[tex]IQR = 2[/tex]

Step-by-step explanation:

Given

n = 30

Data: 2 3 1 2 6 4 2 1 5 3 2 3 1 2 2 1 3 1 2 2 4 2 1 2 9 3 2 1 1 3

Solving (a): The mean

This is calculated as:

[tex]\bar x =\frac{\sum x}{n}[/tex]

[tex]\bar x =\frac{2 +3 +1 +2 +6 +4 +2 +1 +5 +3 +2 +3+ 1+ 2 +2 +1 +3 +1 +2 +2 +4 +2 +1 +2 +9 +3 +2 +1 +1 +3}{30}[/tex]

[tex]\bar x =\frac{76}{30}[/tex]

[tex]\bar x =2.53[/tex]

Solving (b): The median

First arrange the given data

Arranged: 1 1 1 1 1 1 1 1 2 2 2 2 2 2 2 2 2 2 2 3 3 3 3 3 3 4 4 5 6 9

[tex]Median =\frac{1}{2}(n+1)[/tex]

[tex]Median =\frac{1}{2}(30+1)[/tex]

[tex]Median =\frac{1}{2}(31)[/tex]

[tex]Median = 15.5th[/tex]

This implies that the median is the average of the 15th and 16th item

[tex]Median = \frac{2+2}{2}[/tex]

[tex]Median = \frac{4}{2}[/tex]

[tex]Median= 2[/tex]

Solving (c): The mode

From the given data; 2 has the highest frequency of 11.

So,

[tex]Mode = 2[/tex]

Solving (d): The Range

[tex]Range = Highest\ Data - Lowest\ Data[/tex]

The highest is 9 and the lowest is 1,

So:

[tex]Range = 9 - 1[/tex]

[tex]Range = 8[/tex]

Solving (e): Lower (Q1) and Upper (Q3) quartile.

Q1 is calculated as:

[tex]Q_1 = \frac{1}{4}(n+1)th[/tex]

[tex]Q_1 = \frac{1}{4}(30+1)th[/tex]

[tex]Q_1 = \frac{1}{4}(31)th[/tex]

[tex]Q_1 = 7.75th[/tex]

[tex]Q_1 = 8th\ item[/tex]

[tex]Q_1 = 1[/tex] -- from the arranged data

Q3 is calculated as:

[tex]Q_3 = \frac{3}{4}(n+1)th[/tex]

[tex]Q_3 = \frac{3}{4}(30+1)th[/tex]

[tex]Q_3 = \frac{3}{4}(31)th[/tex]

[tex]Q_3 = 23.25th[/tex]

[tex]Q_3 = 23rd\ item[/tex]

[tex]Q_3 = 3[/tex] -- from the arranged data

Solving (f): The interquartile range (IQR)

[tex]IQR = Q_3 - Q_1[/tex]

[tex]IQR = 3-1[/tex]

[tex]IQR = 2[/tex]

Answer:

x=12.727822

Step-by-step explanation:

Since we know two of the angles, we can find the third.  180-90-45=45.  This means the two sides of the triangle are also equal, and we know the hypotenuse is 18.  So we can use the Pythagorean theorem.

x²+x²=18²

2x²=324

x²=162

x=√162

x=12.727822

Step-by-step explanation:

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Answer:

X=6 To y=-6

y=-4 TO X = 4

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Answer:

guganitckihkgucifufu

Answer:

d. 31

Step-by-step explanation:

BRAINLIEST PLEASE

Answer:

(6, -4)? is this on khan academy or smth

Step-by-step explanation:

Answer:5/2a + 10/3b

Step-by-step explanation:

(1/6)(15a+20b)

=(1/6)(15a)+(1/6)(20b)

Answer:

uff si está bien fácil por favor tu te sabes la respuesta y yo tambien

Step-by-step explanation:

3cos2x +sinx=1

3(1-2sin²x)+sinx=1

3-6sin²x+sinx=1

sinx(-6sinx+1)=1

either

sinx=1

sinx=sin(90)

:.x=90

or

-6sinx+1=1

-6sinx=1-1

sinx=0/-6

sinx=sin0,sin180

:.x=0,180and90

Answer:

y = (1/4) 2^x

Step-by-step explanation:

Remark

y = a * x^n is the general equation. Let's see what that means.

Solution

Solve for x

t_12 = a x^12

1024 = a x^12

t_8 = a x^8

64 = a x^8

Now divide the two equations.

1024/64 = a x^12/a x^8       Cancel out the as

1024 / 64 = x^12 / x^8

16 = x^(12 - 8)

16 = x^4                               Take the 4th root of both sides.

[tex]\sqrt[4]{x^4}[/tex]  =  [tex]\sqrt[4]{16}[/tex]

x = 2

Go back and solve for a

y_12 = a x^12

1024 = a 2^12

1024 = a 4096                   Divide by 4096

1024 / 4096 = a

a = 1/4

Problem 7

a) First of negative numbers are probably not a good idea. It means that the population is going to decrease. That's not what will happen if you take care of the fruit flies.

So for the domain, 0 is a good starting point.

That will give you 100 flies on day 0. That's how many you bought.

I'm not a biologist so I have no idea in the world how long a fruit fly will live even with the best of care. I'm going to try 60 days and see what happens.

y = 100 * 1.05 ^60

y = 100 * 18.68

y = 1868

Is this number reasonable? Even with the biggest olive jar you can find, and the best care, I don't think that number is realistic. It's too large. Eventually all will die of disease because they are living in their own waste. So Let's try 20 days

y = 100 * 1.05^20

y = 100 * 2.65

y = 265

That's a lot more reasonable. So for convenience sake let us say that 265 flies could live for 20 days

So to answer the question

The domain would be 0 to 20

The range would be 100 to 265

b)

2 weeks = 2*7 days

2 weeks = 14 days

y = 100 * 1.05^14

y = 100 * 1.98

y = 198 fruit flies.

Answer:

2528839

Step-by-step explanation:

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