Somebody help please I don’t understand

Similarly, if the consumer's income increases, they may choose to consume more of both function x1 and x2, or they may choose to consume more of one good and less of the other, depending on the relative prices and the marginal utility of each good.

The utility function represents the satisfaction or happiness a consumer derives from consuming two goods, x1 and x2. In this case, the utility function is u(x1, x2) = x1x2^2. This means that the consumer values x1 and x2 positively and that the value the consumer derives from x2 increases at a faster rate than x1 as they consume more of it.

The budget constraint, on the other hand, represents the limited resources or income of the consumer. It is given by p1x1 + p2x2 = w, where p1 and p2 are the prices of x1 and x2, respectively, and w is the consumer's income.

To find the optimal consumption bundle, we need to maximize the utility function subject to the budget constraint. This can be done using the method of Lagrange multipliers.

The Lagrangian function is given by:

L(x1, x2, λ) = x1x2^2 + λ(w - p1x1 - p2x2)

Taking partial derivatives with respect to x1, x2, and λ and setting them equal to zero, we get the following first-order conditions:

∂L/∂x1 = x2^2 - λp1 = 0

∂L/∂x2 = 2x1x2 - λp2 = 0

∂L/∂λ = w - p1x1 - p2x2 = 0

Solving these equations simultaneously, we can find the optimal values of x1 and x2 that maximize the utility function subject to the budget constraint. Once we have the optimal consumption bundle, we can use it to make predictions about how changes in prices or income will affect the consumer's consumption of x1 and x2. For example, if the price of x1 increases, the consumer will consume less of it and more of x2, assuming that the utility-maximizing bundle is still affordable.

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Answer:

Step-by-step explanation:

To simplify the fraction (−4c^−1)^3 / (12c^−8), we can apply the rules of exponents.

First, let's simplify the numerator: (-4c^(-1))^3. To raise a power to a power, we multiply the exponents, so we have:

(-4c^(-1))^3 = (-4)^3 * (c^(-1))^3

= -64 * c^(-3)

Now, let's simplify the denominator: 12c^(-8).

Putting the simplified numerator and denominator together, the fraction becomes:

(-64 * c^(-3)) / (12c^(-8))

To simplify further, we can divide the coefficients and subtract the exponents of the variable:

(-64 / 12) * (c^(-3 - (-8)))

= (-64 / 12) * (c^5)

= -16/3 * c^5

So, the fraction (−4c^−1)^3 / (12c^−8) simplifies to (-16/3) * c^5.

The speed of the particle at time t = 1.2 is 1.162. Therefore, the correct option is 1.162.

To find the speed of the particle at time t = 1.2, we need to find the magnitude of the velocity vector, which is the derivative of the position vector with respect to time.

The position vector of the particle in the y-plane is given by (x(t), y(t)) = (t-e, sin(4t)).

The velocity vector is therefore (x'(t), y'(t)) = (1, 4cos(4t)).

The speed of the particle at time t = 1.2 is the magnitude of the velocity vector at that time, which is

|v(1.2)| = √(1^2 + 4cos(4(1.2))^2)

≈ 1.162

Therefore, the answer is 1.162.

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The derivative of the function [tex]y = \int\limits {cosx sinx}  \,  (\frac{3}{5} )^{7}  dv[/tex] with respect to x is ( 3 / 5 )^7 sin x.\\(\frac{3}{5}) ^{7} sinx.

To use part 1 of the fundamental theorem of calculus to find the derivative of the function y = ∫ cos x sin x ( 3 / 5 )^7 dv, we first need to rewrite the integral in terms of x rather than v. To do this, we use the chain rule of integration:
[tex]\int\limits {cosx sinx} \, (\frac{3}{5} )^{7}  dv = (\frac{3}{5}) ^{7} cosxsinx dv = (\frac{3}{5} )^{7} [sinx v] + C[/tex]
where C is the constant of integration.

Now, we can use part 1 of the fundamental theorem of calculus, which states that if F(x) = ∫ f(t) dt from a to x, then F'(x)=f(x). In other words, the derivative of the integral with respect to the upper limit of integration is the integrand evaluated at that upper limit. Applying this to our function, we have:
[tex]y' = \frac{d}{dx} [ (\frac{3}{5}) ^{7}  sinx v+ C] = (\frac{3}{5} )^{7} sinx (\frac{d}{dx} [v] )+0[/tex]

Since v is a constant with respect to x, its derivative is 0. Therefore, we can simplify the expression to:[tex]y' =  (\frac{3}{5}) ^{7} sin x\\[/tex]

So the derivative of the function [tex]y = \int\limits {cosx sinx}  \,  (\frac{3}{5} )^{7}  dv[/tex] with respect to x is [tex]( 3 / 5 )^7 sin x.\\(\frac{3}{5}) ^{7} sinx[/tex].

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The gradient of the linear function in this problem is given as follows:

1/4.

The slope-intercept equation for a linear function is presented as follows:

y = mx + b

The coefficients m and b represent the slope and the intercept, respectively, and are explained as follows:

The gradient is the slope of the linear function. From the graph, we have that when x increases by 4, y increases by 1, hence the slope is given as follows:

m = 1/4.

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S is transitive. Since S is reflexive, symmetric, and transitive, it is an equivalence relation.

To prove that S is an equivalence relation, we need to show that it satisfies three conditions: reflexivity, symmetry, and transitivity.

Reflexivity: For any ordered pair (a, b), we have a + b = b + a. So, (a, b) S (a, b), and S is reflexive.

Symmetry: If (a, b) S (c, d), then a + d = b + c. Rearranging this equation gives us d + a = c + b, which implies that (c, d) S (a, b). Therefore, S is symmetric.

Transitivity: If (a, b) S (c, d) and (c, d) S (e, f), then we have a + d = b + c and c + f = d + e. Adding these two equations gives us a + 2d + f = b + 2c + e. Rearranging this equation, we get (a, b) S (e, f). Hence, S is transitive.

Since S is reflexive, symmetric, and transitive, it is an equivalence relation.

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Cinnabon's realization that it doesn't just sell cinnamon rolls but instead sells "irresistible indulgence" is an example of a firm taking a customer-centric approach.

By shifting the focus from the product itself to the experience it provides, Cinnabon has identified and tapped into the emotional needs of its customers.

This realization has allowed the company to differentiate itself from its competitors and create a strong brand identity that resonates with its target market.

Additionally, by understanding its customers' desires and preferences, Cinnabon has been able to innovate and introduce new products and services that align with its brand promise of providing indulgent treats.

In summary, Cinnabon's focus on the customer and their experience has enabled the company to stay relevant and successful in a highly competitive industry.

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Answer:

$36.52

Step-by-step explanation:

To calculate how much each friend will pay, we need to consider the bill amount, sales tax, and tip. Let's break it down step by step:

Bill before tax: $84.62

Sales tax: 7% of the bill before tax

Sales tax = 7/100 * $84.62

= $5.92

Bill after tax: Bill before tax + Sales tax

Bill after tax = $84.62 + $5.92

= $90.54

Tip: 21% of the bill after tax

Tip = 21/100 * $90.54

= $19.01

Total amount per person: Bill after tax + Tip

Total amount per person = $90.54 + $19.01

= $109.55

Finally, to find out how much each friend will pay, we divide the total amount equally among the three friends:

Amount per friend = Total amount per person / Number of friends

= $109.55 / 3

= $36.52 (rounded to the nearest cent)

Each friend will pay approximately $36.52.
Hope this helps ^^

The highest common factor (H.C.F.) of 'a' and 'b' can be determined by finding the greatest common divisor of 14 and 1 since 'a' is a multiple of 'b' and 'b' is a factor of 'a'. Therefore, the H.C.F. of 'a' and 'b' is 1.

Given that 'a' and 'b' are two positive integers and a = 14b, we can see that 'a' is a multiple of 'b'. In other words, 'b' is a factor of 'a'. To find the H.C.F. of 'a' and 'b', we need to determine the greatest common divisor (G.C.D.) of 'a' and 'b'.

In this case, the number 14 is a multiple of 1 (14 = 1 * 14) and 1 is a factor of any positive integer, including 'b'. Therefore, the G.C.D. of 14 and 1 is 1.

Since 'b' is a factor of 'a' and 1 is the highest common divisor of 'b' and 14, it follows that 1 is the H.C.F. of 'a' and 'b'.

In conclusion, the H.C.F. of 'a' and 'b' is 1, indicating that 'a' and 'b' have no common factors other than 1.

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The area of the quadrilateral is 2 square units

From the question, we have the following parameters that can be used in our computation:

(-3, -3), (-2, -3), (-5, -1), and (-2, -1)

The area of the triangle in square units is calculated as

Area = 1/2 * |x₁y₂ - x₂y₁ + x₂y₃ - x₃y₂ + x₃y₄ - x₄y₃ + x₄y₁ - x₁y₄|

Substitute the known values in the above equation, so, we have the following representation

Area = 1/2 * |-3 * -3 - -3 * -2 + -2 * -1 - -3 * -5 + -5 * -1 - -1 * -2 + -2 * -3 - -3 * -1|

Evaluate the sum and the difference of products

Area = 1/2 * 4

So, we have

Area = 2

Hence, the area of the triangle is 2 square units

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The rate at which the area of the Rectangle is changing at the instant when the other side is 13 cm and increasing at 3 cm per minute is approximately -1.385 cm/min. Note that the negative sign indicates that the width is decreasing

To find how fast the area of the rectangle is changing, we can use the formula for the derivative of the area with respect to time. Let's denote the width of the rectangle as x (in cm) and the length as y (in cm). We are given that x = 6 cm and dy/dt = 3 cm/min. We want to find dx/dt, the rate at which the area is changing.

The area of a rectangle is given by A = x * y. Taking the derivative of both sides with respect to time t, we have:

dA/dt = (d/dt)(x * y)

To solve for dA/dt, we need to express y in terms of x. We know that the length y is increasing at a rate of dy/dt = 3 cm/min. Therefore, we can write:

dy/dt = 3 cm/min

dy = 3 dt

dy/dt = 3

Now, we can differentiate the area equation with respect to time:

dA/dt = x * (dy/dt) + y * (dx/dt)

Substituting the given values:

dA/dt = 6 * 3 + 13 * (dx/dt)

Since we are interested in finding dx/dt, we can rearrange the equation:

dx/dt = (dA/dt - 6 * 3) / 13

Now, let's plug in the given values and calculate the rate at which the area is changing:dx/dt = (dA/dt - 6 * 3) / 13

dx/dt = (0 - 6 * 3) / 13

dx/dt = -18 / 13

Therefore, the rate at which the area of the rectangle is changing at the instant when the other side is 13 cm and increasing at 3 cm per minute is approximately -1.385 cm/min. Note that the negative sign indicates that the width is decreasing

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The area of the rectangle is increasing at a rate of 18 cm^2 per minute when the other side is 13 cm and increasing at 3 cm per minute.

Let's use the formula for the area of a rectangle: A = lw, where A is the area, l is the length, and w is the width.

Since one side of the rectangle is fixed at 6 cm, we can express the area as a function of the other side w: A(w) = 6w.

The rate of change of the area with respect to time is given by the rectangle of A with respect to time t:

dA/dt = d/dt (6w) = 6 dw/dt

We also know that the width is increasing at a rate of 3 cm per minute, so dw/dt = 3 cm/min.

At the instant when the other side is 13 cm, the width of the rectangle is w = 13 cm. Therefore, the rate of change of the area at that instant is:

dA/dt = 6 dw/dt = 6(3) = 18 cm^2/min.

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The options that can be used to find m∠abc are:

m∠abc = 180° - m∠bca

m∠abc = m∠bac + m∠bca

To find m∠abc, the measure of angle ABC, you can use the following expressions:

m∠abc = 180° - m∠bca (Angle Sum Property of a Triangle): This expression states that the sum of the measures of the angles in a triangle is always 180 degrees. By subtracting the measures of the other two angles from 180 degrees, you can find the measure of angle ABC.

m∠abc = m∠bac + m∠bca (Angle Addition Property): This expression states that the measure of an angle formed by two intersecting lines is equal to the sum of the measures of the adjacent angles. By adding the measures of angles BAC and BCA, you can find the measure of angle ABC.

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which expressions can be used to find m∠abc? select two options.

The chi-square test for homogeneity is used if he wants to determine if the distributions are the same.

What is the chi-square test?

Chi-square is a statistical test that looks at how categorical variables from a random sample differ from one another to see if the expected and actual findings match together well.  It is a contrast of two sets of statistical data. Karl Pearson developed this test in 1900 for the analysis and distribution of categorical data.

Here,

We have to determine for which situations should the chi-square test for homogeneity be used.

We concluded from the given option that:

A researcher is trying to determine if salaries for men and women in the tech industry have the same distribution.

He surveys a random sample of men and women in the industry and records the distribution of salaries for each gender.

He wants to determine if the distributions are the same.

Hence, the chi-square test for homogeneity is used if he wants to determine if the distributions are the same.

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a. The expression (3x^4)^2 is incorrectly simplified because the exponent 2 must be distributed to both the 3 and the x^4. This means that the expression should be simplified as follows: (3x^4)^2 = 3^2 * (x^4)^2 = 9x^8

b. The expression 4x^0 = 0 is incorrectly simplified because any number raised to the power of 0 equals 1.

This means that the expression should be simplified as follows:
4x^0 = 4 * 1 = 4

c. The expression 5x^2 = 1/5x^2 is incorrectly simplified because the right side of the equation is the reciprocal of 5x^2.

This means that the expression should be simplified as follows:
5x^2 ≠ 1/5x^2

d. The expression 8x/4x^-1 = 2 is incorrectly simplified because the denominator 4x^-1 can be simplified as 4/x, which means that the expression should be simplified as follows:
8x/(4x^-1) = 8x * (4/x) = 32

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This is the Taylor series representation of the function f centered at x=6.

To find the Taylor series for f centered at 6, we need to use the formula:
f(x) = Σn=0 to infinity (f^(n)(a) / n!) (x - a)^n
where f^(n)(a) denotes the nth derivative of f evaluated at x = a.
In this case, we know that f^(n)(6) = (-1)^n * n! * 5^n * (n^3). So, we can substitute this into the formula above:
f(x) = Σn=0 to infinity ((-1)^n * n! * 5^n * (n^3) / n!) (x - 6)^n
Simplifying, we get:
f(x) = Σn=0 to infinity (-1)^n * 5^n * n^2 * (x - 6)^n
This is the Taylor series for f centered at 6.
This is the Taylor series representation of the function f centered at x=6.

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The chances the car is actually green are 41%, which means there is still a significant chance that the car was actually blue.

No, the answer is not 41%. To find the chances the car is actually green, we need to use Bayes' Theorem:

P(G|W) = P(W|G) * P(G) / P(W)

where P(G|W) is the probability of the car being green given that a witness saw a green car, P(W|G) is the probability of a witness correctly identifying a green car (0.8 in this case), P(G) is the prior probability of the car being green (0.15), and P(W) is the overall probability of a witness seeing any car and correctly identifying its color.

To find P(W), we need to consider both the probability of a witness seeing a green car and correctly identifying its color (0.8 * 0.15 = 0.12) and the probability of a witness seeing a blue car and incorrectly identifying it as green (0.2 * 0.85 = 0.17).

So, P(W) = 0.12 + 0.17 = 0.29.

Now we can plug in the values and solve for P(G|W):

P(G|W) = 0.8 * 0.15 / 0.29 = 0.41

Therefore, the chances the car is actually green are 41%, which means there is still a significant chance that the car was actually blue.

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The function f takes a binary string of length 2, and returns the first bit of that string, which is either 0 or 1.

Therefore, the range of f is {0, 1}.

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The maximum velocity of the car is 0 m/s and the time t' when it stops is t' = -10/a when subjected to acceleration.

Given that the jet car is originally traveling at a velocity of 10 m/s and is subjected to acceleration, we need to determine the car's maximum velocity and the time t' when it stops.

We can use the equation of motion:
v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

Let's assume that the car comes to a stop at time t' and the final velocity is 0 m/s.
0 = 10 + at'
t' = -10/a

Now, to determine the maximum velocity, we can use another equation of motion:
[tex]v^2 = u^2 + 2as[/tex]

Where:
s = distance

As the car stops, the distance traveled before coming to a stop will be:
[tex]s = ut' + (1/2)at'^2[/tex]

Substituting the value of t' in the above equation, we get:
[tex]s = 10(-10/a) + (1/2)a(-10/a)^2[/tex]
s = -50/a

Now, substituting the values of s, u, and a in the equation of motion, we get:
[tex]v^2 = 10^2 + 2a(-50/a)[/tex]
[tex]v^2 = 100 - 100\\v^2 = 0[/tex]

v = 0 m/s

Hence, the maximum velocity of the car is 0 m/s and the time t' when it stops is t' = -10/a.

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If in the circle centered at "A", we have NA ≅ PA, MO⊥NA, and RO⊥PA, then the measure of the the segment PO is (d) 3.5 ft.

From the figure, we observe the triangles OAN and OAP are "right-triangles" where one "common-side" is OA and the two "congruent-sides" NA ≅ PA (given), it follows that they are congruent.

⇒ OP ≅ ON;

We know that, the perpendicular drawn from circle's center on chord divides it in two "congruent-segments",

So, We have;

PO ≅ RP, and NO ≅ MN;

​Which means that, PO = RO/2 and ON = MO/2 = 7/2;

Since, OP ≅ ON, we get:

⇒ PO = 7/2 = 3.5,

Therefore, the correct option is (d).

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Answer:

Step-by-step explanation:

The moment of inertia about the z-axis of a thin spherical shell with equation x² + y² + z² = 2a and constant density 8 is 8.

The moment of inertia of a solid object measures its resistance to rotational motion around a specific axis. For a thin spherical shell, the moment of inertia about the z-axis can be calculated using the formula:

I = ∫(r²) dm

where r is the perpendicular distance from the axis of rotation (z-axis) to an infinitesimally small mass element dm.

In this case, the spherical shell has constant density, so the mass per unit volume is constant. Therefore, dm = ρ dV, where ρ is the density and dV is the volume element.

Since the equation of the spherical shell is x² + y² + z² = 2a, we can rewrite it as r² + z² = 2a, where r is the distance from the z-axis to a point on the shell. The moment of inertia can be calculated by integrating over the volume of the shell:

I = ∫∫∫ (r²) ρ dV

Since the density is constant, ρ can be taken out of the integral:

I = ρ ∫∫∫ (r²) dV

The integral represents the volume of the spherical shell, which is 4πa². Therefore, we have:

I = ρ (4πa²)

Substituting the given density ρ = 8, we get:

I = 8 (4πa²) = 32πa²

So, the moment of inertia about the z-axis of the thin spherical shell is 32πa².

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The probability that a puppy is picked from the pet store is 0.375 or 37.5%.

To determine the probability of picking a puppy from the pet store, we need to take into account the relative frequency of puppies compared to the other pets.

According to the problem statement, puppies are chosen twice as often as the other pets. Therefore, we can assign a weight of 2 to each puppy and a weight of 1 to each of the other pets.

This means that the total weight of all the puppies is 6 x 2 = 12, while the total weight of all the other pets is (9+4+7) x 1 = 20.

To calculate the probability of picking a puppy, we need to divide the weight of all the puppies by the total weight of all the pets:

Probability of picking a puppy = Weight of all the puppies / Total weight of all the pets

= 12 / (12+20)

= 12 / 32

= 3 / 8

= 0.375

Therefore, the probability of picking a puppy from the pet store is 0.375 or 37.5%.

It's important to note that this probability assumes that all the pets are equally likely to be chosen, except for the fact that puppies are chosen twice as often.

If there are any other factors that could influence the likelihood of picking a certain pet, such as their position in the store or their visibility, this probability may not accurately reflect the true likelihood of picking a puppy.

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The critical value for the linear correlation coefficient r depends on the sample size n and the significance level alpha, and it is usually found using a table or a calculator. When n=20 and alpha=0.01, the critical value is approximately 0.575.

The critical value for the linear correlation coefficient r depends on the sample size n and the significance level alpha.

When n=20 and alpha=0.01, we can use a table or a calculator to find the critical value.

The table or calculator will give us a value that corresponds to the upper tail of the t-distribution with n-2 degrees of freedom and an area of 0.005 (half of the significance level).

This value is sometimes denoted as t_alpha/2,n-2 or t0.005,18.

Using a calculator, we can find that t0.005,18 is approximately 2.878.

This means that if the absolute value of the computed correlation coefficient r is greater than 0.575, we can reject the null hypothesis of no correlation at the 0.01 level of significance.

Therefore, the correct answer is A, 0.575.

In summary, the critical value for the linear correlation coefficient r depends on the sample size n and the significance level alpha, and it is usually found using a table or a calculator.

When n=20 and alpha=0.01, the critical value is approximately 0.575.

This means that any computed correlation coefficient r with an absolute value greater than 0.575 would be significant at the 0.01 level of significance.

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The tuition at the local college in 2000, assuming it followed the same growth rate as after 2017, can be estimated to be approximately $4,018. The tuition in 2010, using the same growth rate, would be around $9,049.

To find the tuition in 2000, we need to calculate the value of f(x) when x represents the number of years since 2000. Since the given function models the cost of tuition x years since 2017, we need to determine how many years have passed between 2000 and 2017, which is 17 years. Plugging this value into the function, we get:

f(17) = 15(1.07)^17 ≈ $4,018

Therefore, the estimated tuition in 2000, assuming it followed the same growth rate as after 2017, would be approximately $4,018.

To determine the tuition in 2010, we need to calculate the value of f(x) when x represents the number of years since 2010. Since 2010 is 7 years before 2017, we have:

f(7) = 15(1.07)^7 ≈ $9,049

Hence, the estimated tuition in 2010, using the same growth rate, would be around $9,049. It is important to note that these calculations are based on the assumption that the tuition growth rate before 2017 was consistent with the growth rate after 2017 as provided by the function f(x).

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The area of a regular 20-gon with a radius of 5 mm is approximately 218.8 square millimeters.

To find the area of a regular polygon, we can divide it into congruent triangles. A regular 20-gon can be divided into 20 congruent triangles, each formed by connecting the center of the polygon with two adjacent vertices. Since the polygon is regular, all of its angles and side lengths are equal.

To calculate the area of one of these triangles, we need to find its base and height. The base of each triangle is one side of the polygon, and the height can be determined by drawing a perpendicular line from the center of the polygon to the base. The height is equal to the radius of the polygon.

In this case, the radius is given as 5 mm. Thus, the height of each triangle is also 5 mm. To find the base, we can use basic trigonometry. The base can be divided into two equal segments, with each segment forming one side of a right triangle. The angle of each triangle is 360 degrees divided by the number of sides, which in this case is 20. Therefore, each triangle has an angle of 18 degrees.

Using trigonometry, we can find that the base of each triangle is 2 * 5 mm * tan(18 degrees). The area of each triangle is then (base * height) / 2. Multiplying the area of one triangle by the total number of triangles (20) gives us the total area of the regular 20-gon. After performing these calculations, the area is approximately 218.8 square millimeters.

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A measurement that is closest to the the distance between point B and point D is 6√5 or 13.42 units.

In Mathematics and Geometry, the distance between two (2) end points that are on a coordinate plane can be calculated by using the following mathematical equation:

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

Where:

x and y represent the data points (coordinates) on a cartesian coordinate.

By substituting the given end points into the distance formula, we have the following;

Distance = √[(-1 - 5)² + (3 + 9)²]

Distance = √[(-6)² + (12)²]

Distance = √[36 + 144]

Distance = √180

Distance = 6√5 or 13.42 units.

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It is expected that 300 participants out of the 900 who participate in the survey would receive a coupon for sleigh rides.

To determine the number of participants expected to receive a coupon for sleigh rides, we need to divide the total number of participants (900) by the number of coupon options (3) since each option has an equal chance of being received.

The expected number of participants receiving a coupon for sleigh rides can be calculated as follows:

Total participants / Number of coupon options = Expected number of participants receiving a sleigh ride coupon

900 participants / 3 coupon options = 300 participants.

Therefore, it is expected that 300 participants out of the 900 who participate in the survey would receive a coupon for sleigh rides.

It's important to note that this calculation assumes an equal chance of receiving each type of coupon and does not consider any specific preferences or biases that participants may have.

The calculation is based on the assumption of a random distribution of coupons among the participants.

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Responsible financial plan will take into consideration both short term and long term goals.

Given,

A financial plan is to be made.

A financial plan protects you from life's surprises. A Personal financial plan reduces doubt or uncertainty about your decisions and make adjustments to help overcome obstacles that could alter your lifestyle.

Now,

To make a better financial plan one should consider his/her short term as well long term goals.

Short term goals:

Short term goals include the goals that are needed to be achieved in the time frame 2-4 years.

For example,

One has to buy a car in the coming 3 years than this type of goals are considered short term and financial plan is to be made according to the price of car that is to be paid after 3 years while buying a car.

Long term goals:

Long term goals include the goals that are needed to be achieved in the time frame 10-12 years.

For example,

Retirement can be considered as long term plan for which one has to save a big amount of corpus so that after retirement his/her expenses will be well taken care off.

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The derivative of the function y = -3x + 5t/(1 + t[tex]^3[/tex]) is (-3x + 5)/(1 + x[tex]^3[/tex]).

To find the derivative of the given function using the first part of the Fundamental Theorem of Calculus, we need to evaluate the integral of the function.

The integral of the function f(t) with respect to t, from a constant 'a' to 'x', is denoted as:

∫[a to x] f(t) dt

In this case, the function is y = (-t[tex]^3[/tex] + 5)/(1 + t[tex]^3[/tex]), and we need to find its derivative.

Using the Fundamental Theorem of Calculus, the derivative of y with respect to x is:

d/dx ∫[a to x] (-t[tex]^3[/tex] + 5)/(1 + t[tex]^3[/tex]) dt

Applying the first part of the Fundamental Theorem of Calculus, we can differentiate the integral with respect to x:

d/dx ∫[a to x] (-t[tex]^3[/tex] + 5)/(1 + t[tex]^3[/tex]) dt = (-x[tex]^3[/tex] + 5)/(1 + x[tex]^3[/tex])

The derivative of the given function y = (-t[tex]^3[/tex] + 5)/(1 + t^3) with respect to x is (-x[tex]^3[/tex] + 5)/(1 + x[tex]^3[/tex]).

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The answer of the given question based on the degrees is , Philip covered 270 degrees in 45 minutes and 0.75 turn in the game.

To answer this question, we must know that a full circle contains 360 degrees.

Therefore, we can use the proportion as follows:

60 minutes = 360 degrees

1 minute = 6 degrees

1 turn = 360 degrees

Here, Philip watched the volleyball game for 45 minutes.

Thus, the total degrees covered in 45 minutes are:

6 degrees/minute × 45 minutes = 270 degrees

And the number of turns covered in 45 minutes is:

360 degrees/turn × 45 minutes / 60 minutes/turn = 0.75 turn

Therefore, Philip covered 270 degrees in 45 minutes and 0.75 turn in the game.

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