The area of a circular swimming pool is approximately 18 m2

Answer:

40%

Step-by-step explanation:

Percent must be equal to 100, so if 60 are girls, then 40% must be boys.

line segment connecting the vertices of a hyperbola is called the transverse axis and the midpoint of the line segment is the center of the hyperbola.

What is transverse axis and center of hyperbola ?

The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints. The foci lie on the line that contains the transverse axis. The conjugate axis is perpendicular to the transverse axis and has the co-vertices as its endpoints.

And The center of a hyperbola is the midpoint of both the transverse and conjugate axes, where they intersect. Every hyperbola also has two asymptotes that pass through its center. As a hyperbola recedes from the center, its branches approach these asymptotes.

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Answer:

See below.

Step-by-step explanation:

a. If h is the number of hours of labour required to print the cards, construct an equation for the cost of the cards, C.

C = $250 + ($40/hr)*h

b. You have budgeted $1000 for the printing job. How many hours of labour can you afford? Give your answer to the nearest minute.

$1000 = $250 + ($40/hr)*h

($40/hr)*h = $750

h = 18.75 hours

(18.75 hours)(60 min/hr) = 1125 minutes

c. The company estimates that it can print 1000 cards per hour of labour. How many cards will you get printed with your current budget?

(18.75 hr)*(1000 cards/hr) = 18,750 cards

d. An alternative to printing is photocopying. The company charges 15 cents per side for the first 10 000 cards and then 10 cents per side for the remaining cards. Which is the cheaper option for 18 750 single-sided cards and by how much?

Photocopy Cost for the first 1000 single-sided cards is:

(1000 cards)*($0.15) = $150

Photocopy Cost for the final 17,750 single-sided cards is:

(17,750)*($0.10) = $1,775

Totoal photocopy cost for 18,750 single-sided cards is $1,925.  [1775+150]

The cheapest option for 18,750 cards is printing:  $1,000

Printing is (1,925 - 1000) $925 cheaper than photocopying.

Answer:

502.5

Step-by-step explanation:

C = 24(12) + 5.50(39)

C = 288 + 214.5

C = $502.5

The number to add to the set of data is 26

The set of data is given as:

11,14,23 and 16

Let the new number be x

So that

Mean = 18

Mean is calculated as:

Mean = Sum/Count

So, we have:

(11 + 14 + 23 + 16 + x)/5 = 18

Multiply by 5

11 + 14 + 23 + 16 + x = 90

Evaluate the like terms

x = 26

Hence, the number to add is 26

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Complete question

A set of data already has the values 11, 14, 23, and 16. What value would have to be added to the set for the mean of the five numbers to be 18?

The system of equations to represent the total cost, y, when x additional pieces are purchased with a basic cat tree at each store are;

y = 50x + 100    ------(eq 1)

y = 75x + 50    ------(eq 2)

A) Let the total cost of the cat tree be y

Let each additional piece added be x.

Since basic tree is $100 and each additional platform costs $50, then we can say that;

y = 50x + 100    ------(eq 1)

Now, their basic cat tree starts at $50 and each additional piece costs $75. Thus;

y = 75x + 50    ------(eq 2)

B) Subtract eq 1 from eq 2 to gte;

25x - 50 = 0

25x = 50

x = 50/25

x = 2

y = 75(2) - 50

y = $100

C) The Store that would be cheaper depending on the add - ons is Puuur Place because as x increases, it's y-value increases at a lesser rate than that of Meow.

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Answer:

[tex]6x^{2} -24x-10[/tex] with remainder -5

Answer:

[tex]6^2-24x-10-\frac{5}{x+4}[/tex]

In other words, [tex]6x^2-24x-10[/tex] is the answer and -5 is the remainder

Step-by-step explanation:

I used long division for this, and I uploaded an image for the steps. The final answer I got was [tex]6x^2-24x-10-\frac{5}{x+4}[/tex]

Putting the other player's king in check is always a good move. true

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Answer:

37

Step-by-step explanation:

6m+5n

plug in your given values

6(2) + 5(5)

12+25

=37

Answer:

37

Step-by-step explanation:

6m + 5n

6*2  +  5*5 = 12 + 25

= 37

The points which represents the vertices of the given equation are; (15, −2) and (−1, −2).

The complete question gives the equation of the ellipse as; (x-7)²/64+(y+2)²/9=1.

Since, It follows from convention that general equation of ellipse with centre as (h, k) takes the form;

(x-h)²/a² +(y-k)²/b² = 1.

Consequently, it follows from observation that the value of a and b in the given equation in the task content is; √64 = 8 and √9 = 3 respectively.

Since, 8 > 3, The vertices of the ellipse are given by; (h±a, k).

The vertices in this scenario are therefore;

(7+8, -2) and (7-8, -2).

= (15, -2) and (-1, -2).

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Answer:

A.  63.8 in^2

Step-by-step explanation:

The surface area of a cylinder is given by:

A=2πrh+2πr^2

2πr^2 gives the area of the 2 ends, each with area πr^2.

2πrh gives the suface area of the outside of the cylinder.

r = 0.4 inches

h = 25 inches

Area = 63.8 in^2

The equation which represent the interpretation of the scenario is 5 + 2x

Total laws mowed = Number of lawns Homer mowed + (Additional laws mowed each month × Number of months)

= 5 + (2 × x)

= 5 + 2x

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The taxi fare for a journey of n miles in dollars is 1 + 2n

Linear equations are equations that have constant average rates of change, slope or gradient

The given parameters about the taxi fares are given as

First two miles = $5

Additional mile = Increment of $2

Let the number of miles be n

So, we have:

2 miles = $5

Additional miles = (n - 2) * 2

Add the above expressions

5 + (n - 2)* 2

Represent the value with f(n)

So, we have:

f(n) = 5 + (n - 2)* 2

Expand the bracket

f(n) = 5 + 2n - 4

Collect the like terms

f(n) = 5 - 4+ 2n

Evaluate the like terns

f(n) = 1 + 2n

Hence, the taxi fare for a journey of n miles in dollars is 1 + 2n

So, the complete parameters are:

First two miles = $5

Additional mile = Increment of $2

n miles  1 + 2n

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Area covered with grass seed = 10.4[tex]m^{2}[/tex].

What is trapezoid geometry?

A quadrilateral with one set of parallel opposite sides is referred to as a trapezoid. It can have congruent sides (isosceles) and right angles (a right trapezoid), but neither is necessary.

Area of the trapezoid ={ (a+b)/2} +h

where a and b is base and h is height of the trapezoid geometry.

In the question,

a=6m , b=7m and h=4m.

According to the formula { (a+b)/2} +h.

Area covered with grass seed = {(6+7)/2} + 4

                                                    = 10.4[tex]m^{2}[/tex].

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Answer:

26

Step-by-step explanation:

GOT IT RIGHT`

You have to find the slope of the line. It will give you the conversion rate from inches to centimetres or the other way around.

Looking closely at the graph, or using a ruler as reference, you can estimate that 30 cm ≈ 12 in. In terms of the graph, the line very nearly passes through the point (12, 30). It also passes through the origin, (0, 0), since 0 cm = 0 in exactly.

The slope of the line is then

[tex]\dfrac{30\,\mathrm{cm}-0\,\mathrm{cm}}{12\,\mathrm{in}-0\,\mathrm{in}} = \dfrac{30\,\rm cm}{12\,\rm in} = \dfrac{5\,\rm cm}{2\,\rm in} = 2.5\dfrac{\rm cm}{\rm in}[/tex]

which means that 1 in ≈ 2.5 cm.

So, if Sarah's height is 64 in, we convert this to cm and find her height is (approximately)

[tex]64\,\mathrm{in} \times 2.5\dfrac{\rm cm}{\rm in} = \boxed{160\,\rm cm}[/tex]

Answer:

it is False

Step-by-step explanation:

Answer:

c) 700

Step-by-step explanation:

Add 800 and 600, and then divide by the number of number, or in this case, two. This should give you 700.

A quadratic equation in standard form that can be used to determine the value of x is [tex]x^{2}[/tex] - 8x - 65 = 0.

The Factor of the equation from Part B is (x - 13)(x + 5)  and the possible solutions to the equation is x = 13 or -5.

The value for the second number is 5

The general formula for quadratic equation in a in standard form is

a[tex]x^{2}[/tex] + bx + c = 0

Given that the  difference between two integers is 8

Let the two integers = x and y,

and their product is 65. If the larger of the two numbers is x. Then,

x - y = 8 and xy = 65

Since we are looking for the value of x, make y the subject of formula in the first equation.

y = x - 8

Substitute y in the second equation.

x(x - 8) = 65

[tex]x^{2}[/tex] - 8x - 65 = 0

[tex]x^{2}[/tex] - 13x + 5x - 65 = 0

(x - 13)(x + 5) = 0

x = 13 or -5

We will ignore -5 since x is the larger number.

To get y Substitute x in the second equation.

xy = 65

13y = 65

y = 65/13

y = 5

Therefore, a quadratic equation in standard form that can be used to determine the value of x is [tex]x^{2}[/tex] - 8x - 65 = 0. The Factor of the equation from Part B is (x - 13)(x + 5)  and the possible solutions to the equation is x = 13 or -5. The value for the second number is 5

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Answer:

A and B

Step-by-step explanation:

x < 100 means x is less than 100. Therefore, pick any x-values that are less than 100 which are x = 54 and x = 89.

Hence, A and B are the answer.

The equivalent expression of the expression is 128x^5y^6/2x^7y^5

The expression is given as:

128x^5y^6/2x^7y^5

Divide 128 by 2

64x^5y^6/x^7y^5

Apply the law of indices

64y^(6-5)/x^(7-5)

Evaluate the differences

64y/x^2

Hence, the equivalent expression of the expression is 128x^5y^6/2x^7y^5

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Complete question

Select the correct answer. which expression is equivalent to 128x^5y^6/2x^7y^5 , if x > 0 and y > 0

Answer: -4, 0, 2

Step-by-step explanation:

The graph intersects the x-axis at [tex]x=-4, x=0, x=2[/tex].

Using proportions, it is found that the fraction of each candy bar that each friend will get is:

[tex]\frac{2}{3}[/tex].

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Considering the three friends that were there initially and the three that arrived later, 4 candy bars will be split between 6 friends, hence the fraction that each will get is:

[tex]\frac{4}{6} = \frac{2}{3}[/tex]

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The height of the frame is 15 feet.

From the information given, the following can be depicted:

b - 10/a = 2/5

2a = 5b - 50

2a - 5b = -50

Also, slope of AC:

= (b - 10(/(a - 5) = 2/5

2a - 50 = -5b + 50

2a + 5b = 100

Both equations will be solved

The height of the frame will be:

= 5 + 10

= 15 feet

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Answer:

3 2/5

Step-by-step explanation:

Each slash/mark on the number line is 1/5, meaning that 6 marks away is 3 2/5.

To further explain how I know each mark is 1/5, each question had a denominator of 5, and if you count each mark from 2 1/5 (2 2/5, 2 3/5, 2 4/5, 3, etc) you will eventually land on 4 evenly.

The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)

From the given figure, the coordinate of the vertex A is represented as:

A = (-5, 2)

The coordinates of the vertex that A maps to after Daniel's reflections

The rule of reflection across the line x = -1 is

(x, y) ⇒ (-x - 2, y)

So, we have:

A' = (5 - 2, 2)

Evaluate the difference

A' = (3, 2)

The rule of reflection across the line y = 2 is

(x, y) ⇒ (x, -y + 4)

So, we have:

A'' = (3, -2 + 4)

Evaluate the difference

A'' = (3, 4)

Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)

The coordinates of the vertex that A maps to after Zachary's reflections

The rule of reflection across the line y = 2 is

(x, y) ⇒ (x, -y + 4)

So, we have:

A' = (-5, -2 + 4)

Evaluate the difference

A' = (-5, 2)

The rule of reflection across the line x = -1 is

(x, y) ⇒ (-x - 2, y)

So, we have:

A'' = (5 - 2, 2)

Evaluate the difference

A'' = (3, 2)

Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)

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Answer:

y = 9.84 mm

Step-by-step explanation:

Law of sine:

   [tex]\sf \boxed{\bf \dfrac{a}{Sin \ A}=\dfrac{b}{Sin \ B}= \dfrac{c}{Sin \ C}}[/tex]

    a = y

    A = 31°

   b  = 17 mm

    B = 117°

[tex]\sf \dfrac{y}{Sin \ 31^\circ}=\dfrac{17}{Sin \ 117^\circ}\\\\[/tex]

          [tex]\sf y = \dfrac{17}{Sin \ 117^\circ}*Sin \ 31^\circ\\\\ y = \dfrac{17}{0.89}*0.515\\\\y = 9.84 \ mm[/tex]

Answer:

5

Step-by-step explanation:

5×(-4)=20

5×3=15

5×0.5=2.5

5×5=25

5×0=0

5×(-2)=-10

Answer: [tex]\triangle RQP \sim \triangle VPW[/tex]

Step-by-step explanation:

By the corresponding angles theorem, [tex]\angle RPQ \cong \angle VWP[/tex] and [tex]\angle RQP \cong \angle VPW[/tex].

Therefore, [tex]\triangle RQP \sim \triangle VPW[/tex] by AA.