The scores earned in a flower-growing competition are represented in the stem-and-leaf plot.



0 5
1 0, 3, 7
2 4, 6, 8
3 2
4
5 8
Key: 5|8 means 58


What is the appropriate measure of variability for the data shown, and what is its value?
The range is the best measure of variability, and it equals 18.5.
The IQR is the best measure of variability, and it equals 45.
The range is the best measure of variability, and it equals 45.
The IQR is the best measure of variability, and it equals 18.5.

To find the equation of the tangent line to the graph of the function f(x) at x = a, we can use the extension of the power rule. The equation of the tangent line to the graph of the function f(x) = (9x/3) + 5 at x = 27 is           y = 9x - 232.

To find the equation of the tangent line to the graph of the function f(x) at x = a, we can use the extension of the power rule, which states that if   f(x) = x^n, then f'(x) = nx^(n-1).

First, we find the derivative of f(x) using the power rule:

f(x) = (9x/3) + 5

f'(x) = 9/3

Next, we evaluate f'(x) at x = 27:

f'(27) = 9/3 = 3

This gives us the slope of the tangent line at x = 27. To find the y-intercept of the tangent line, we need to find the y-coordinate of the point on the graph of f(x) that corresponds to x = 27. Plugging x = 27 into the original equation for f(x), we get:

f(27) = (9*27)/3 + 5 = 82

Therefore, the point on the graph of f(x) that corresponds to x = 27 is (27, 82). We can now use the point-slope form of the equation of a line to find the equation of the tangent line:

y - 82 = 3(x - 27)

Simplifying this equation gives:

y = 3x - 5*3 + 82

y = 3x - 232

Therefore, the equation of the tangent line to the graph of the function f(x) = (9x/3) + 5 at x = 27 is y = 3x - 232, which is in slope-intercept form.

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The required answer is  the function f: [0, +∞) → [0, +∞) given by {(x, y): y = x^2} becomes bijective.

To make the function f: R → R given by {(x, y): y = x^2} bijective, we need to restrict the domain and codomain so that the function is both injective (one-to-one) and surjective (onto).

Step 1: Restrict the domain to make the function injective.
The function is not injective in its current form because for some distinct x values, the y values are equal (for example, x = 1 and x = -1 both give y = 1). To make it injective, we can restrict the domain to either non-negative real numbers (x ≥ 0) or non-positive real numbers (x ≤ 0).

Step 2: Restrict the codomain to make the function surjective.
In its current form, the function is not surjective because there are y values in the co-domain with no corresponding x values (for example, y = -1 has no x value that satisfies y = x^2). To make it surjective, we can restrict the co-domain to non-negative real numbers (y ≥ 0).
So,

if we restrict the domain to non-negative real numbers (x ≥ 0) and the co-domain to non-negative real numbers (y ≥ 0),

the function f: [0, +∞) → [0, +∞) given by {(x, y): y = x^2} becomes bijective.

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You have a total of 96 different ways to choose to use your scholarship, considering all the available options for universities, summer camps, and study abroad trips.

To determine the number of ways you can choose to use your scholarship, we need to consider the different options available for each category: universities, summer camps, and study abroad trips.

For universities, you have 12 options to choose from.

For summer camps, you have 4 options to choose from.

For study abroad trips, you have 2 options to choose from.

To find the total number of ways you can choose to use your scholarship, we multiply the number of options for each category together:

Total number of ways = Number of university options × Number of summer camp options × Number of study abroad trip options

Total number of ways = 12 × 4 × 2 = 96.

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This is the solution to the given initial value problem using the Laplace transform method.

To solve the given IVP using the Laplace transform method, we first apply the Laplace transform to the differential equation y'' - y = t - 2 with the initial conditions y(2) = 3 and y'(2) = 0.

Taking the Laplace transform of the given equation, we get:

L{y''}(s) - L{y}(s) = L{t - 2}(s)

Now, we apply the Laplace transform properties for derivatives:

s^2Y(s) - sy(2) - y'(2) - Y(s) = (1/s^2) - (2/s)

Given the initial conditions y(2) = 3 and y'(2) = 0, we can plug them into the equation:

s^2Y(s) - 3s - Y(s) = (1/s^2) - (2/s)

Now, solve for Y(s):

Y(s) = (1/s^2) - (2/s) + 3s/(s^2 + 1) + 1/(s^2 + 1)

Next, perform the inverse Laplace transform to find y(t):

y(t) = L^{-1}{Y(s)}

y(t) = t - 2 + 3(sin(t) - 2cos(t)) + cos(t)

This is the solution to the given initial value problem using the Laplace transform method.

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(i) The chain is not irreducible because there is no way to get from any positive state to any negative state or vice versa.

(ii) The stationary distribution has the form πk = c(1/4)r|k|, where r = 2 and c is a normalization constant.

(iii) The stationary distribution is not unique.

(i) The chain is not irreducible because there is no way to get from any positive state to any negative state or vice versa. For example, there is no way to get from state 1 to state -1 without first visiting the origin, and the probability of returning to the origin from state 1 is less than 1.

(ii) To find a stationary distribution, we need to solve the equations πP = π, where π is the stationary distribution and P is the transition probability matrix. We can write this as a system of linear equations and solve for the values of the constant r and normalization constant c.

We can see that the stationary distribution has the form πk = c(1/4)r|k|, where r = 2 and c is a normalization constant.

(iii) The stationary distribution is not unique because there is a free parameter c, which can be any positive constant. Any multiple of the stationary distribution is also a valid stationary distribution.

Therefore, the correct answer for part (i) is that the chain is not irreducible, and the correct answer for part (ii) is that a stationary distribution of the form πk = c(1/4)r|k| exists with r = 2 and c being a normalization constant. Finally, the correct answer for part (iii) is that the stationary distribution is not unique because there is a free parameter c.

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In this case, since the base is 16 feet and the height is 13 feet, we can calculate the area as (1/2) * 16 * 13 = 104 square feet. This means that Sharon will need to paint an area of 104 square feet on the wall.

To find the area of the wall to be painted, we can use the formula for the area of a triangle, which is given by the formula A = (1/2) * base * height.

In this case, the base of the triangle is 16 feet and the height is 13 feet. Plugging these values into the formula, we get:

A = (1/2) * 16 * 13

A = 8 * 13

A = 104 square feet

Therefore, the area of the wall to be painted is 104 square feet.

The area of a triangle is calculated by multiplying the length of the base by the height of the triangle and dividing it by 2.

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The lateral surface area of the roof is 46 ft².

Given dimensions of the roof of a dog house are:3.1 ft 3.14 ft 2.7 ft 11.00 ft 5 ft 3 ft
Now, to calculate the lateral surface area of the roof of the dog house, we need to find the dimensions of the sides of the roof.As per the given dimensions, we can see that there are two sides with dimensions:3.1 ft x 2.7 ft5 ft x 2.7 ft
Now, the lateral surface area of the roof of the dog house can be calculated by adding the area of these two sides. Lateral surface area of the roof = 2 × (3.1 ft × 2.7 ft) + 2 × (5 ft × 2.7 ft) = 46.62 ft²

Therefore, the lateral surface area of the roof is 46 ft².

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The volume of the cylindrical construction pipe given the height and radius to the nearest whole number is 550 cubic feet.

Volume of the cylindrical construction pipe = πr²h

Where,

π = 3.14

r = radius = 2.5 ft

h = height = 28 ft

Volume of the cylindrical construction pipe = πr²h

= 3.14 × 2.5² × 28

= 3.14 × 6.25 × 28

= 549.50 cubic ft

Approximately to the nearest whole number,

= 550 cubic ft

Hence, the cylindrical construction pipe has a volume of 550 cubic ft

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The tower is leaning at an angle of approximately 86.41 degrees.

To find the angle the tower is leaning, we can use trigonometry. Let's assume the tower is leaning towards the right.

We have a right triangle formed by the tower, the ground, and the rope. The side opposite the angle we're looking for is the height of the tower (54 feet), and the adjacent side is the distance from the base of the tower to the rope (3 feet).

The tangent function relates the opposite and adjacent sides of a right triangle:

tan(angle) = opposite/adjacent

In this case, we can plug in the values:

tan(angle) = 54/3

To find the angle, we need to take the inverse tangent (arctan) of both sides:

angle = arctan(54/3)

Using a calculator, we can find that the angle is approximately 86.41 degrees.

Therefore, the tower is leaning at an angle of approximately 86.41 degrees.

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To find the probability that both players create the same clothes outfit in a video game that allows a player to create a clothes outfit by choosing 1 of 3 hats, 1 of 2 shirts, and 1 of 4 pants, we need to use the multiplication rule of probability. Answer: 1/24

Probability of player 1 choosing a hat = 1/3Probability of player 1 choosing a shirt = 1/2Probability of player 1 choosing a pant = 1/4By the multiplication rule of probability,Probability of player 1 creating a clothes outfit = (1/3) × (1/2) × (1/4) = 1/24As there are only 24 possible outfits, the probability of both players creating the same outfit is the same as the probability of the second player choosing the same outfit as the first player. Hence,Probability of both players creating the same clothes outfit = 1/24 = 0.0417 or 4.17%Therefore, the correct option is 1/24.

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The odds that both players create the same clothes outfit are 1/24. Probability of both players creating the same outfit is 1/24.

There are a total of 3 × 2 × 4 = 24 outfits the players can create.

Both players will need to choose the exact same outfit, so there is only one possible outcome that will result in success.

To find the probability of this happening, divide the number of successful outcomes by the total number of possible outcomes.

Probability of both players creating the same outfit = number of successful outcomes / total number of possible outcomes

= 1/24

Hence, the odds that both players create the same clothes outfit are 1/24.

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We can estimate that roughly 50% of regulation soccer balls have a circumference greater than 69.9 cm (or exactly 70 cm).

According to the regulations set by FIFA, the circumference of a regulation soccer ball must be between 68cm and 70cm. Assuming that manufacturers adhere to these regulations, we can assume that the percentage of soccer balls with a circumference greater than 69.9 cm is equal to the percentage of soccer balls with a circumference of exactly 70 cm.

The midpoint between 68 cm and 70 cm is 69 cm, and since the circumference of a sphere is proportional to its radius, the circumference of a regulation soccer ball with a radius of 10.97 cm (which corresponds to a circumference of 69 cm) is approximately equal to the circumference of a soccer ball with a radius of 11.11 cm (which corresponds to a circumference of 70 cm).

Therefore, we can estimate that roughly 50% of regulation soccer balls have a circumference greater than 69.9 cm (or exactly 70 cm) and round to the nearest tenth of a percent.

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a) The volume generated by revolving the curve about the y-axis using the second Pappus-Guldinus theorem is V = 2π(0.64)

b) Using the first Pappus-Guldinus theorem, the y-coordinate of the centroid of the curve is y = 0.736.

c) The area of the surface generated by revolving the curve about the y-axis using the first Pappus-Guldinus theorem is A = 2π(0.736)(3.810)

a) The second Pappus-Guldinus theorem states that the volume generated by revolving a plane curve about an axis outside of the curve is equal to the product of the length of the curve and the distance traveled by the centroid of the curve. Applying this theorem to the given curve, we have V = 2π(0.64).

b) The first Pappus-Guldinus theorem states that the volume generated by revolving a plane curve about an axis is equal to the product of the area of the curve and the distance traveled by the centroid of the curve. In this case, we are given the length and area of the curve and are asked to find the y-coordinate of the centroid. Using the formula for the length of the curve and the given area,

we can find the radius of gyration of the curve about the x-axis. Then, using the formula for the centroid of a curve, we can find the y-coordinate of the centroid, which is y = 0.736.

c) Again, using the first Pappus-Guldinus theorem, we can find the area of the surface generated by revolving the curve about the y-axis. We have the length and the area of the curve, and we have already found the y-coordinate of the centroid in part

(b). Using these values, we can calculate the area of the surface generated by revolving the curve about the y-axis, which is A = 2π(0.736)(3.810).

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Answer:

Graph D is the correct graph.

The daily operating budget should be increasing at a rate of approximately $0.02 per day in order to meet the increased demand for 80 automobiles per year.

We are given a Cobb-Douglas production function: P = 20[tex]x^0.5[/tex] * [tex]y^0.5[/tex], where P represents the number of automobiles produced per year, x represents the number of employees, and y represents the daily operating budget in dollars.

To meet the increased demand for 80 automobiles per year, we need to determine the rate at which the daily operating budget should be increasing. Since we are maintaining a constant workforce of 130 workers, the number of employees (x) remains constant.

Using the production function, we can calculate the current production level as P = 1200 automobiles per year. To increase the production level by 80 automobiles per year, we set up the following equation: 1200 + 80 = 20[tex]x^0.5[/tex] * [tex]y^0.5[/tex].

Since the number of employees (x) remains constant at 130, we can solve the equation for the rate at which the daily operating budget (y) should be increasing.

By rearranging the equation and solving for y, we find that y should be increasing at a rate of approximately $0.02 per day.

Therefore, the daily operating budget should be increased at a rate of approximately $0.02 per day in order to meet the increased demand for 80 automobiles per year, while maintaining a constant workforce of 130 workers.

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The expected value of X is 65.805. This means that if we were to repeat this experiment many times, on average, the value of X would be close to 65.805.

To find the expected value of a discrete random variable X, we use the formula:

E[X] = Σ(xi * pi)

where xi is the value of X and pi is the probability of X taking that value.

In this case, we are given the probability distribution function (PDF) of X, which lists the possible values of X and their corresponding probabilities. So we can simply plug in these values into the formula to find the expected value:

E[X] = 65.7(0.06) + 98.5(0.18) + 72.6(0.13) + 72.3(0.09) + 52.2(0.54)

= 3.942 + 17.73 + 9.438 + 6.507 + 28.188

= 65.805

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The coefficient of determination of 0.49 means that approximately 49% of the variability in the dependent variable can be explained by the independent variable(s) in the regression model. In other words, the model is able to explain 49% of the total variation in the response variable.

The coefficient of correlation of 0.70 indicates a strong positive linear relationship between the two variables. It means that there is a high degree of association between the independent and dependent variables, and that the change in one variable is closely related to the change in the other variable. A correlation coefficient of 0.70 is considered a moderate to strong correlation, with values closer to 1 indicating a stronger relationship.

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To determine how many years it will take for Tom's investment to double, we can use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:

A is the final amount (double the initial investment)

P is the principal amount (initial investment)

r is the annual interest rate (9.24% or 0.0924)

n is the number of times the interest is compounded per year (monthly, so n = 12)

t is the time in years

In this case, Tom wants his investment to double, so the final amount (A) will be $8,000 * 2 = $16,000. We can plug in these values and solve for t:

$16,000 = $8,000(1 + 0.0924/12)^(12t)

Dividing both sides by $8,000:

2 = (1 + 0.0924/12)^(12t)

Taking the natural logarithm (ln) of both sides:

ln(2) = ln[(1 + 0.0924/12)^(12t)]

Using the logarithmic property ln(a^b) = b * ln(a):

ln(2) = 12t * ln(1 + 0.0924/12)

Dividing both sides by 12 * ln(1 + 0.0924/12):

t = ln(2) / (12 * ln(1 + 0.0924/12))

Using a calculator, we find:

t ≈ 9.81

Therefore, it will take approximately 9.81 years (rounding to hundredths) for Tom's investment to double.

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Given that f(8) = 14, it means that the input 8 results in an output of 14. The question asks for the inverse of this function, f^-1(14), which means we need to find the input that results in an output of 14.

To do this, we need to use the fact that f^-1(f(x)) = x for any x in the domain of f(x). In other words, if we apply the inverse function to the output of f(x), we should get back the original input.

So, we can start by finding the inverse function of f(x). If y = f(x), then we have:

y = 2x - 6

x = (y + 6)/2

Therefore, the inverse function of f(x) is f^-1(x) = (x + 6)/2.

Now, we can use this inverse function to find f^-1(14):

f^-1(14) = (14 + 6)/2 = 10

Therefore, the input that results in an output of 14 for the original function f(x) is 10.

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Sample size is less than 5% of the population size.

The finite correction factor adjusts for the effect of a finite population size on the calculation of the standard error of the sample mean.

It is typically used when the sample size is a significant fraction of the population size, and helps to correct for the potential bias in the standard error estimate that can arise when the sample size is large relative to the population size.

However, as a general rule, if the sample size is less than 5% of the population size, then the effect of the finite population correction factor is typically negligible. In such cases, it is common to use the standard formula for the standard error of the sample mean without the finite correction factor.

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The standard deviation of the value of the variable at the end of 3 years is 3√3.

a) To find the expected value of the variable x after 3 years, we can use the properties of the Wiener process. The expected value of the variable at any given time t is given by:

E[x(t)] = x(0) + a * t

Given that x(0) = 10 and a = 2, we can substitute these values into the equation:

E[x(3)] = 10 + 2 * 3 = 10 + 6 = 16

Therefore, the expected value of the variable x after 3 years is 16.

b) The standard deviation of the value of the variable at the end of 3 years can be calculated using the formula:

σ = √(b^2 * t)

Given that b = 3 and t = 3, we can substitute these values into the formula:

σ = √(3^2 * 3) = √(9 * 3) = √27 = 3√3

Therefore, the standard deviation of the value of the variable at the end of 3 years is 3√3.

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a. All collections on the preceding page and its content are well-defined.

b. The difficulty in deciding whether a given collection is a set or not usually arises when the criteria for membership in the collection are ambiguous or subjective.

c. A collection of happy people can be considered a set, depending on how it is defined and the context in which it is used.

d. Collections of people with pretty faces are not well-defined because the notion of beauty or prettiness is subjective and can vary from person to person.

The preceding page and its content.

The collection is based on personal preferences or opinions, it becomes challenging to determine whether an item belongs to the collection. Another challenge is when the collection includes elements that are themselves collections or have complex properties.

If the criteria for membership in the collection are well-defined and objective, such as people who exhibit certain behaviors or express happiness in a measurable way, then it can be considered a set.

If the criteria are subjective or vague, such as being perceived as happy by others, it becomes difficult to determine membership and the collection may not be well-defined.

One person finds attractive, another may not.

Beauty is influenced by cultural, societal and personal preferences, making it difficult to establish clear and objective criteria for determining membership in such a collection.

collections of people with pretty faces are not well-defined sets.

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Allie will have 2 oranges left over after dividing them evenly among the 11 baskets.

If Allie has 123 oranges and she wants to evenly divide them among 11 baskets, we can find the number of oranges left over by dividing the total number of oranges by the number of baskets and calculating the remainder.

To evenly distribute the oranges among the 11 baskets, we perform the division:

123 ÷ 11 = 11 with a remainder of 2

The quotient 11 represents the number of oranges that can be evenly distributed among the 11 baskets. The remainder 2 represents the number of oranges left over after the even distribution.

Therefore, Allie will have 2 oranges left over after dividing them evenly among the 11 baskets.

It's important to note that when dividing a certain number of objects among a specific number of groups, remainders may occur if the division is not exact. In this case, with 123 oranges and 11 baskets, 11 oranges can be evenly distributed, leaving 2 oranges as leftovers.

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Thus, the coordinates of points D and B for the given parallelogram are D=(-3,0) and B=(-1,6).

In the parallelogram ABCD, we are given coordinates A=(-4,3), B=(-1,b), C=(0,3), and D=(a,0). To find the values of a and b, we can use the properties of a parallelogram.

In a parallelogram, opposite sides are parallel and equal in length. We can use the midpoint formula to find the coordinates of the midpoint for both diagonal AC and diagonal BD. Since the diagonals of a parallelogram bisect each other, these midpoints should be equal.

Midpoint formula: M = ((x1+x2)/2, (y1+y2)/2)

For diagonal AC:
M_AC = ((-4+0)/2, (3+3)/2) = (-2,3)

For diagonal BD:
M_BD = ((-1+a)/2, (b+0)/2)

Since the midpoints M_AC and M_BD are equal:
M_AC = M_BD
(-2,3) = ((-1+a)/2, b/2)

Now we can create two equations from the x and y coordinates:
1) -2 = (-1+a)/2
2) 3 = b/2

Solve the equations:

1) Multiply both sides by 2: -4 = -1+a
  Add 1 to both sides: -3 = a

2) Multiply both sides by 2: 6 = b

So, the values of a and b are a = -3 and b = 6. Therefore, the coordinates of points D and B are D=(-3,0) and B=(-1,6).

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The Maclaurin series expansion for sin(x) is: sin(x) = x - /3! + [tex]x^5[/tex]/5! - [tex]x^7[/tex]/7!

To approximate sin(1/2) with a maximum error of 0.01, we need to find the smallest value of n for which the absolute value of the remainder term Rn(1/2) is less than 0.01.

The remainder term is given by:

Rn(x) = sin(x) - Pn(x)

where Pn(x) is the nth-degree Maclaurin polynomial for sin(x), given by:

Pn(x) = x - [tex]x^3[/tex]/3! + [tex]x^5[/tex]/5! - ... + (-1)(n+1) * x(2n-1)/(2n-1)!

Since we want the maximum error to be less than 0.01, we have:

|Rn(1/2)| ≤ 0.01

We can use the Lagrange form of the remainder term to get an upper bound for Rn(1/2):

|Rn(1/2)| ≤ |f(n+1)(c)| * |(1/2)(n+1)/(n+1)!|

where f(n+1)(c) is the (n+1)th derivative of sin(x) evaluated at some value c between 0 and 1/2.

For sin(x), the (n+1)th derivative is given by:

f^(n+1)(x) = sin(x + (n+1)π/2)

Since the derivative of sin(x) has a maximum absolute value of 1, we can bound |f(n+1)(c)| by 1:

|Rn(1/2)| ≤ (1) * |(1/2)(n+1)/(n+1)!|

We want to find the smallest value of n for which this upper bound is less than 0.01:

|(1/2)(n+1)/(n+1)!| < 0.01

We can use a table of values or a graphing calculator to find that the smallest value of n that satisfies this inequality is n = 3.

Therefore, the third-degree Maclaurin polynomial for sin(x) is:

P3(x) = x - [tex]x^3[/tex]/3! + [tex]x^5[/tex]/5!

and the approximation for sin(1/2) with a maximum error of 0.01 is:

sin(1/2) ≈ P3(1/2) = 1/2 - (1/2)/3! + (1/2)/5!

This approximation has an error given by:

|R3(1/2)| ≤ |f^(4)(c)| * |(1/2)/4!| ≤ (1) * |(1/2)/4!| ≈ 0.0024

which is less than 0.01, as required.

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The area of the region that lies inside the first curve and outside the second curve is 13π/4.

To find the area of the region that lies inside the first curve and outside the second curve, we need to find the points of intersection of these two curves.

Setting the two equations equal to each other, we have:

3 cos(θ) = 4 − cos(θ)

Simplifying, we get:

4 cos(θ) = 4

cos(θ) = 1

θ = 0

So the two curves intersect at θ = 0.

To find the area of the region between the curves, we integrate the difference of the two equations with respect to θ over the interval [0, π]:

A = ∫[0,π] (4 - cos(θ))^2/2 - (3cos(θ))^2/2 dθ

Simplifying, we get:

A = ∫[0,π] 8 - 7cos(θ) + cos^2(θ) dθ

Using trigonometric identities, we can simplify this to:

A = ∫[0,π] 13/2 - 7/2 cos(2θ) dθ

Evaluating the integral, we get:

A = [13/2θ - 7/4 sin(2θ)] [0,π]

A = 13π/4 - 0

A = 13π/4

Therefore, the area of the region that lies inside the first curve and outside the second curve is 13π/4.

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If one hundred 98% confidence intervals are constructed for a population parameter, we would expect approximately 98 of the intervals to capture the unknown parameter.

In a 98% confidence interval, there is a 98% probability that the true population parameter lies within the interval. This means that if we were to construct 100 such intervals, we would expect about 98 of them to contain the true population parameter, and the remaining 2 intervals would not capture the unknown parameter. However, it's important to note that the actual number of intervals that capture the parameter may vary due to random sampling variability.

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The probability is 1/24.

There are 4 meals and 4 people, so there are 4! = 24 ways to serve the meals to the people.

However, only one of these ways is correct, so the probability that the waiter will serve the correct meal to the correct person is:

P(correct) = 1/24

This is because there is only one way to serve the meals that matches the correct combination of alphabets used in Sonia.

Therefore, the probability that the waiter will serve the correct meal to the correct person is 1/24.

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Answer:

x = 2

Step-by-step explanation:

2x + 15 = 27 - 4x

add 4x to both sides:

2x + 15 + 4x = 27 -4x + 4x

that is 6x + 15 = 27

subtract 15 from both sides:

6x + 15 - 15 = 27 - 15

that is 6x = 12

divide both sides by 6:

x = 2

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathtt{2x + 15 = 27 - 4x }[/tex]

[tex]\mathtt{2x + 15 = -4x + 27}[/tex]

[tex]\large\text{ADD 4x to BOTH SIDES}[/tex]

[tex]\mathtt{2x + 15 - 4x = -4x + 27 + 4x}[/tex]

[tex]\large\text{SIMPLIFY it}[/tex]

[tex]\mathtt{2x + 4x + 15 = 27}[/tex]

[tex]\mathtt{6x + 15 = 27}[/tex]

[tex]\large\text{SUBTRACT 15 to BOTH SIDES}[/tex]

[tex]\mathtt{6x + 15 - 15 = 27 - 15}[/tex]

[tex]\large\text{SIMPLIFY it}[/tex]

[tex]\mathtt{6x = 27 - 15}[/tex]

[tex]\mathtt{6x = 12}[/tex]

[tex]\large\text{DIVIDE 6 to BOTH SIDES}[/tex]

[tex]\mathtt{\dfrac{6x}{6} = \dfrac{12}{6}}[/tex]

[tex]\mathtt{x= \dfrac{12}{6}}[/tex]

[tex]\mathtt{x= 2}[/tex]

[tex]\huge\text{Therefore your answer should be:}\\\\\huge\boxed{\mathtt{x = 2}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]