could anyone help me with this?
Answer:
Step-by-step explanation:
A=6x²
[tex]\frac{dA}{dt} =6\times 2x \times \frac{dx}{dt} \\\frac{dA}{dt}=12x \frac{dx}{dt}[/tex]
will give brainly .Which statements are true regarding undefinable terms in geometry? Check all that apply.
A point has no length or width.
A point indicates a location in a coordinate plane.
A plane has one dimension, length.
A line has a definite beginning and end.
A plane consists of an infinite set of lines.
A line consists of an infinite set of points.
The true statements about terms in geometry that are undefinable are;
A point has no length or widthA point indicates a location on the coordinate planeA line consists of an infinite set of points.A plane consists of an infinite set of points.How can the true statements be found?Three undefinable terms in geometry are;
1) Point
2) Line
3) Plane
The above terms do not have a formal definition but they can be described based on their properties.
The other geometric terms are defined based on the above undefinable terms.
A point can be described as a location in space that is dimensionless and can be specified on the coordinate plane as an ordered pairs (x, y).
True statements about a point are therefore;
A point has no length or widthA point indicates a location on the coordinate planeA line is infinitely long, that has no beginning or end. It has one dimension, with no thickness or height.
Given that a point is dimensionless, a line can be considered a set of points.
A true statement is therefore;
A line consists of an infinite set of points.A plane is a two dimensional geometric figure that have infinite length and width.
An infinite set of lines that forms a two dimensional figure can be used to describe a plane.
The true statement with regards to a plane is therefore;
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as part of a competition, diego must spin around in a circle 6 times and then run to a tree. the time he spends on each spin is represented by S AND THE TIME HE SPEND RUNNING is R. He gets to the tree 21 seconds after he starts spinning. If it takes diego 1.2 seconds to spin around each time, how many seconds did he spend running
The time he spent running is 13.80 seconds.
How much time did he spend running?
The equation that can be used to represent the time he gets to the tree is:
Time he gets to the tree = (time of each spin x total spins) + time he spent running
21 = (6 x 1.2) + r
21 = 7.20 + r
r = 21 - 7.20
r = 13.80 seconds
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What is the slope of the line containing (-2, 5) and (4,-4)?
A. 2
OB.
mle
O C. - /3/20
D. -2
Answer:
-1.5
Step-by-step explanation:
To work out the gradient of the line, we use this equation:
[tex] \frac{y2 - y1}{x2 - x1} [/tex]
Substituting in, we get:
[tex] \frac{5 - ( - 4)}{ - 2 - 4} [/tex]
Which simplifies to:
[tex] \frac{9}{ - 6} = \frac{3}{ - 2} = - \frac{3}{2} = - 1.5[/tex]
1
10 ft
Cone 1
2.5 ft
8 ftl
2 ft
Cone 2
3 5/6 + 2 4/9 in its simplest form
Answer:
>> [tex]6\frac{5}{18}[/tex]
Step-by-step explanation:
1) Add the whole numbers first.
[tex]5+\frac{5}{6} +\frac{4}{9}[/tex]
2) Find the Least Common Denominator (LCD) of [tex]\frac{5}{6} ,\frac{4}{9}[/tex] . In other words, find the Least Common Multiple (LCM) of [tex]6,9[/tex].
Method 1: By Listing Multiples
1. List the multiples of each number.
Multiples of 6 : 6, 12, 18, ...
Multiples of 9 : 9, 18, ...
2. Find the smallest number that is shared by all rows above. This is the LCM.
LCM = 18
3. Make the denominators the same as the LCD.
[tex]5+\frac{5\times 3}{6\times 3}+\frac{4\times 2}{9\times 2}[/tex]
4. Simplify. Denominators are now the same.
[tex]5+\frac{15}{18}+\frac{8}{18}[/tex]
5. Join the denominators.
[tex]5+\frac{15+8}{18}[/tex]
6. Simplify.
[tex]5+\frac{23}{18}[/tex]
7. Convert [tex]\frac{23}{18}[/tex] to mixed fraction.
[tex]5+1\frac{5}{18}[/tex]
8. Simplify.
[tex]6\frac{5}{18}[/tex]
Decimal Form: 6.277778
Cheers.
The addition of 3 5/6 + 2 4/9 is 113/18
What is fraction?The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.
The number of parts into which the whole has been divided is shown by the denominator. It is positioned in the fraction's lower portion, below the fractional bar.How many sections of the fraction are displayed or chosen is shown in the numerator. It is positioned above the fractional bar in the upper portion of the fraction.Given:
3 5/6 + 2 4/9
Now, writing it into normal fraction
3 5/6 + 2 4/9
= 23/ 6 + 22/9
= 23/6 x 3/3 + 22/9 x 2/2
= 69/ 18 + 44/18
= 113/18
Hence, the addition is 113/18
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Which expression is equivalent to
xay
8
700
8√√√x
y
8√√y
Mark this and return
128x56
√ 2x75
? Assume x > 0 and y> 0.
Save and Exit
The equivalent expression of [tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex] is [tex]\frac{8\sqrt y}{x}[/tex]
How to determine the equivalent expression?The expression is given as:
[tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex]
Divide 128 by 2
[tex]\sqrt{\frac{64x^5y^6}{x^7y^5}}[/tex]
Apply the law of indices to the variables
[tex]\sqrt{\frac{64y^{6-5}}{x^{7-5}}}[/tex]
Evaluate the differences
[tex]\sqrt{\frac{64y}{x^2}}[/tex]
Take the square root of 64
[tex]8\sqrt{\frac{y}{x^2}}[/tex]
Take the square root of x^2
[tex]\frac{8\sqrt y}{x}[/tex]
Hence, the equivalent expression of [tex]\sqrt{\frac{128x^5y^6}{2x^7y^5}}[/tex] is [tex]\frac{8\sqrt y}{x}[/tex]
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Suppose that the breaking strength of a rope (in pounds) is normally distributed, with a mean of 100 pounds and a standard deviation of 16. What is the probability that a certain rope will break before being subjected to 120 pounds? (You may need to use the standard normal distribution table. Round your answer to four decimal places.)
The probability that a certain rope will break before being subjected to 120 pounds is 89.4%.
What is the probability that a certain rope will break before being subjected to 120 pounds?The probability is calculated as follows:
Mean = 100
Standard deviation = 16
The probability is obtained from the z-score.
x = mean + z-score * standard deviation
120 = 100 + z-score * 16
z-score = 20/16
z-score = 1.25
From normal distribution table, the probability with a z-score of 1.25 is 89.4%
In conclusion, the probability is obtained from the z-score.
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Given the functions a(x) = 3x - 12 and b(x) = x-9, solve a[b(x)].
Oa[b(x)] = 3x²-21
O a[b(x)] = 3x² - 39
Oa[b(x)] = 3x - 21
Oa[b(x)] = 3x - 39
Answer:
Step-by-step explanation:
hello :
a(x) = 3x - 12 and b(x) = x-9, so
a[b(x)]=a(x-9) =3(x-9)-12
a[b(x)]=3x-9-12
a[b(x)]=3x+21
5. a. The area of an isosceles triangle is 60cm² and its base is 10cm. Find the length of its equal side.
Answer:
H = 12cm
b
I hope I was able to help
please help!!!!!!nnnn
Similar: yes
Similarity statement: [tex]ADCB \sim SVUT[/tex]
Scale factor: 1/3
find the product xy if
2^(x)+3^(y)=5,
2^(x+2)+3^(y+1)=18
The solution to the system of equation is (0, 1)
System of equationsGiven the following system of equation as shown below
2^(x)+3^(y)=5,
2^(x+2)+3^(y+1)=18
Rewrite
2^(x)+3^(y)=5,
2^x*2^2 + 3^y*3^1 = 18
___________
2^(x)+3^(y)=5,
4(2^x) + + 3(3^y) = 18
Let a = 2^x and b = 3^y
Substitute
a + b = 5
4a + 3b = 18
a = 5 - b
Substitute
4(5-b) + 3b = 18
20 - 4b + 3b = 18
-b = -2
b = 2
since a = 5 - b
a = 5 - 2
a = 3
Recall that a = 2^x and b = 3^y
2^x = 2
x = 0
Similarly
3^y = 3
y =1
Hence the solution to the system of equation is (0, 1)
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i don’t understand!!!
In other words, 12 goes in the top box and 13 goes in the bottom. The fraction slash sign is not part of either box.
===========================================================
Explanation:
Cosine is the ratio of adjacent over hypotenuse.
cos(angle) = adjacent/hypotenuse
For the reference angle X, the adjacent leg is 36 units long. It's the leg closest or touching angle X.
The hypotenuse is always the longest side. It is always opposite the 90 degree angle. The hypotenuse in this case is 39 units.
Therefore,
cos(X) = 36/39 = (12*3)/(13*3) = 12/13
A tower is composed of a prism with a square base and a pyramid. The base length is 20 meters, and the height of the prism is 40 meters, while the slant height of the pyramid is 10√2 meters. What is the total surface area, including the bottom base? 400√2 + 3,600 m2 200√2 + 3,600 m2 400√2 + 400 m2 4000√2 m2
The total surface area of the tower composed of a prism with a square base and a pyramid is 3600 + 400√2 m²
How to find the surface are of a composite figure?Total surface area of the tower = area of the base + 4(area of the rectangular surface) + 4(area of the triangular surface)
Therefore,
area of the base = 20² = 400 m²
4(area of the rectangular surface) = 4(40 × 20) = 3200 m²
4(area of the triangular surface) = 4(1 / 2 × 10√2 × 20) = 4(100√2) = 400√2 m²
Therefore,
total surface area = 400 + 3200 + 400√2
total surface area = 3600 + 400√2 m²
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Answer:
a)400V2 plus 3,600 m2
Step-by-step explanation:
Please tell me fast I am on a time crunch
A candy shop sells a box of chocolates for $30. It has $29 worth of chocolates plus $1 for the box. The box includes two kinds of candy: caramels and truffles. Lita knows how much the different types of candies cost per pound and how many pounds are in a box. She said,
If x is the number of pounds of caramels included in the box and y is the number of pounds of truffles in the box, then I can write the following equations based on what I know about one of these boxes:
x + y = 3
8x + 12y + 1 = 30
Assuming Lita used the information given and her other knowledge of the candies, use her equations to answer the following:
How many pounds of candy are in the box?
What is the price per pound of the caramels
What does the term 12y in the second equation represent?
What does 8x + 12y + 1 in the second equation represent?
Answer:
There are 3 lbs of candy in the box.
The caramels are $8 per pound.
12y represents the total cost of truffles in the box.
8x + 12y + 1 represents the cost of caramels in the box + the cost of truffles in the box + the cost of the box.
Step-by-step explanation:
x = the number of pounds of caramels
y = the number of pounds of truffles
x + y = total lbs. and we know x + y = 3
We know x is the number of pounds of caramels.
8x = (cost per pound of caramels) × (number of pounds of caramels)
So 8 = cost of caramels
We know y = number of pounds of truffles. So 12 is the cost of truffles by pound, and 12y is the total cost of truffles in the box.
Based on all the above,
The cost of caramels in the box + the cost of truffles in the box + the cost of the box is = total cost of the box. 8x + 12y + 1 = 30
What is the volume of the cylinder?
The volume of a cylinder with a diameter of 16 feet and height of 10 feet is 2010.62 ft³
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The volume of a cylinder with radius (r) and height (h) is:
Volume = πr²h
Given that h = 10 ft, r = 16/2 = 8 ft
The volume = π * 8² * 10 = 2010.62 ft³
The volume of a cylinder with a diameter of 16 feet and height of 10 feet is 2010.62 ft³
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Which of the following graphs includes the possible values for the number of people who still need to sign up for the team?
Number line with closed circle on 5 and shading to the left
Number line with closed circle on 5 and shading to the right.
Number line with open circle on 5 and shading to the left.
Number line with open circle on 5 and shading to the right.
The graph that includes the possible values for the number of people who still need to sign up for the team is:
Number line with closed circle on 5 and shading to the right.
What is the situation and which inequality models it?Researching this problem on the internet, a team currently has 4 players, and needs at least 9.
When x players are signed, the number of players will be of 4 + x. Since the team needs at least 9 players, the inequality is:
[tex]4 + x \geq 9[/tex]
The solution is:
[tex]x \geq 9 - 4[/tex]
[tex]x \geq 5[/tex]
Which is represented as follows:
Number line with closed circle on 5 and shading to the right.
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Help me please!!!!!!!!
Answer:
The ratios are not equal, so this is not a dilation.
Step-by-step explanation:
4/3 is the first ratio
3/4 is the second ratio
Since these ratios are not equal there is not a dilation.
The lengths of the sides of the right triangle above are a, 3, and c. What is a in terms of c?
The expression for a in terms of c is [tex]a^{2}= \sqrt{c^{2} -9}[/tex]. The correct option is the third option [tex]a^{2}= \sqrt{c^{2} -9}[/tex]
Pythagorean theoremFrom the question, we are to determine the expression for a in terms of c
In the given right triangle, we can write that
[tex]c^{2} = a^{2} +3^{2}[/tex] (Pythagorean theorem)
Thus,
[tex]c^{2} = a^{2} +9[/tex]
[tex]a^{2}= c^{2} -9[/tex]
[tex]a^{2}= \sqrt{c^{2} -9}[/tex]
Hence, the expression for a in terms of c is [tex]a^{2}= \sqrt{c^{2} -9}[/tex]. The correct option is the third option [tex]a^{2}= \sqrt{c^{2} -9}[/tex]
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A particle travels so that its distance D (in metres) from its origin O is modelled by the equation D = 24 + 15t - [tex]\frac{t^{2} }{2}[/tex], where t is the time in minutes after the particle has started to move.
a. calculate the particle's distance from O when it first started to move.
b. determine the time when the particle first reaches O. Give your answer to 2 decimal places.
c. determine the particle's speed when it has been moving for 3 minutes. Give your answer in m [tex]S^{-1}[/tex]
(a) The particle's distance from O when it first started to move is 24 m.
(b) The time when the particle first reaches O is 15 mins.
(c) The particle's speed when it has been moving for 3 minutes is 0.2 m/s.
Particle's distance from O when it first started to move
D = 24 + 15 - t²/2
when the time, t = 0
D = 24 m
When the object first reaches OWhen the object reaches O, its final velocity, v = 0
v = dD/dt
v = 15 - t
0 = 15 - t
t = 15 mins
Speed of the particle after 3 minutesv = 15 - t
v = 15 - 3
v = 12 m/min
v = 12 m/min x 1min/60s = 0.2 m/s
Thus, the particle's distance from O when it first started to move is 24 m.
The time when the particle first reaches O is 15 mins.
The particle's speed when it has been moving for 3 minutes is 0.2 m/s.
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Suppose f(x)=2^x. What is the graph of g(x)=1/3f(x)?
Please see the blue curve of the image attached below to know the graph of the function g(x) = (1/3) · 2ˣ.
How to graph a transformed function
Herein we have an original function f(x). The transformed function g(x) is the result of compressing f(x) by 1/3. Then, we find that g(x) = (1/3) · 2ˣ. Lastly, we graph both function on a Cartesian plane with the help of a graphing tool.
The result is attached below. Please notice that the original function f(x) is represented by the red curve, while the transformed function g(x) is represented by the blue curve.
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Simplify the following
Answer is 6
Firstly changing mixed fraction.
[tex] \frac{3}{2} - \frac{5}{4} + \frac{23}{4} [/tex]
By taking the LCM
[tex] \frac{6 - 5 + 23}{4} [/tex]
-5 + 23 (-) (+) = (-)
[tex] \frac{6 + 18}{4} [/tex]
[tex] \frac{24}{4} [/tex]
[tex]6[/tex]
Hope it helps you, any confusions you may ask!
Answer:
6 (work below)
Step-by-step explanation:
1 1/2 = 3/2
1 1/4 = 5/4
5 3/4 = 23/4
The least common multiple of the denominators is 4, so 3/2 will become 6/4.
6/4 - 5/4 = 1/4 + 23/4 = 24/4 = 6
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f(x)=2^x. What is g(x)?
The function g(x) is g(x)= (3x)^2
How to solve for g(x)?The complete question is in the image
From the graph in the image, we have:
f(x) = x^2
The function f(x) is stretched by a factor of 3 to form g(x).
This means that:
g(x) = f(3x)
So, we have:
g(x)= (3x)^2
Hence, the function g(x) is g(x)= (3x)^2
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x is directly proportional to y. When x = 4, y = 7. Work out the value
of y when x = 12
Answer:
y = 21
Step-by-step explanation:
When x is directly proportional to y:
When x increases, y also increases.
In this case, it is so you write,
1. Write down the formula: y=kx
k being the constant.
Let's use "When x = 4, y = 7" to work out the constant.
2. Substitute the 'when' values: 7=k×4
3. Rearrange to find the constant: 7÷4=k
4. Find k: k=1.75
Now let's see the new problem, 'what is y when x = 12'.
5. Substitute the values now but keep the constant: y = 1.75 × 12
6. Rearrange if needed.
7. Find the missing value: y = 21
Hope this helped and if you require further assistance from me please comment below! :)
Ps: If it was inversely proportional then the formula would be y = k / x
with k still being the constant.
Write these decimals in order from smallest to largest: 0.507, 0.75, 0.5, 0.078
Alan is building a garden shaped like a rectangle with a semicircle attached to one short side. If he has 70 feet of fencing to go around it, what dimensions will give him the maximum area in the garden? Round the answers to the nearest tenth.
The dimension that would give the maximum area is 20.8569
How to solve for the maximum area
Let the shorter side be = x
Perimeter of the semi-circle is πx
Twice the Length of the longer side
[tex][70-(\pi )x -x][/tex]
Length = [tex][70-(1+\pi )x]/2[/tex]
Total area =
area of rectangle + area of the semi-circle.
Total area =
[tex]x[[70-(1+\pi )x]/2] + [(\pi )(x/2)^2]/2[/tex]
When we square it we would have
[tex]70x +[(\pi /4)-(1+\pi)]x^2[/tex]
This gives
[tex]70x - [3.3562]x^2[/tex]
From here we divide by 2
[tex]35x - 1.6781x^2[/tex]
The maximum side would be at
[tex]x = 35/2*1.6781[/tex]
This gives us 20.8569
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Evaluate the sum (for math nerds)
[tex]i {}^{0!} + i {}^{1!} + i {}^{2!} + i {}^{3!} + ... + i {}^{100!} [/tex]
Note that :
[tex]i = \sqrt[]{ - 1} [/tex]
Answer: i+96
Step-by-step explanation:
Note that [tex]i^{4k}[/tex], where k is an integer, is equal to 1.
This means that [tex]i^{4!}=i^{5!}=i^{6}=\cdots=i^{99!}+i^{100!}=1[/tex]
So, we can rewrite the sum as [tex]i^{1}+i^{1}+i^{2}+i^3+97(1)=i+i-1-i+97=i+96[/tex]
[tex]n![/tex] is divisible by 4 for all [tex]n\ge4[/tex]. This means, for instance,
[tex]i^{4!} = \left(i^4\right)^{3!} = 1^{3!} = 1[/tex]
[tex]i^{5!} = \left(i^4\right)^{5\times3!} = 1^{5\times3!} = 1[/tex]
etc, so that [tex]i^{n!} = 1[/tex] for all [tex]n\ge4[/tex].
Meanwhile,
[tex]i^{0!} = i^1 = i[/tex]
[tex]i^{1!} = i^1 = i[/tex]
[tex]i^{2!} = i^2 = -1[/tex]
[tex]i^{3!} = i^6 = (-1)^3 = -1[/tex]
Then the sum we want is
[tex]i^{0!} + i^{1!} + i^{2!} + i^{3!} + 97\times1 = i + i - 1 - 1 + 97 = \boxed{95+2i}[/tex]
(2x + 1) (x - 1) solve for X
Put brackets equal 0
(2x + 1) (x - 1) = 0
(2x + 1) = 0
-1, then ÷2
x = - 1/2 or - 0.5
(x - 1) = 0
+1
x = 1
So, x = - 0.5 & x = 1
Hope this helps!
Answer:
x = -0.5
x = 1
Step-by-step explanation:
Hello!
We can set each factor to 0 and solve for x in both.
(2x + 1) = 0There are 2 solutions for x, -0.5 and 1.
Which function below has the following domain and range?
Domain: {-9, - 5, 2, 6, 10}
Range: { -2, 0, 8}
O {(-9, 10), (-2,8)}
O ((-9, -2), ( – 5, 0), (2, 8), (6, 5), (10, 9))}
O ((-2,-5), (8, 10), (0, 6), (-2, -9), (0, 2)}
O {(2,0), (-5, -2), (10, 8), (6, 0), (-9, -2)}
{(2,0),(-5,-2),(10,8),(6,0),(-9,-2)} is the correct answer (D)
Answer:
(d) {(2, 0), (-5, -2), (10, 8), (6, 0), (-9, -2)}
Step-by-step explanation:
The domain is the list of x-values. The range is the list of y-values. You are looking for the set that matches the given lists.
ChoicesA.The list of x-values is {-9, -2}. The list is too short.
B.The list of x-values is {-9, -5, 2, 6, 10}. This matches the required domain.
The list of y-values is {-2, 0, 8, 5, 9}. The list is too long.
C.The list of x-values is {-2, 8, 0, -2, 0}. The list does not match the given domain list.
D.The list of x-values is {2, -5, 10, 6, -9}. This matches the given domain.
The list of y-values is {0, -2, 8, 0, -2}. This matches the given range.
The function of interest is ...
{(2, 0), (-5, -2), (10, 8), (6, 0), (-9, -2)}