These figures are congruent. What is the measurement? pic below

If rectangle has an area of 114cm squared and a perimeter of 50 cm, the dimensions of the rectangle are approximately 5 cm by 22.8 cm.

Let's assume the length of the rectangle is "l" and the width is "w". We can start by using the formula for the area of a rectangle, which is A = lw. From the given information, we know that the area is 114cm².

So, we have:

lw = 114

Next, we can use the formula for the perimeter of a rectangle, which is P = 2l + 2w. From the given information, we know that the perimeter is 50cm.

So, we have:

2l + 2w = 50

We now have two equations with two variables, which we can solve using substitution or elimination. Let's use substitution by solving the first equation for l:

l = 114/w

We can then substitute this expression for l in the second equation:

2(114/w) + 2w = 50

Multiplying both sides by w to eliminate the fraction, we get:

228 + 2w² = 50w

Rearranging and simplifying, we get a quadratic equation:

2w² - 50w + 228 = 0

We can solve for w using the quadratic formula:

w = [50 ± √(50² - 4(2)(228))]/(2(2)) ≈ 11.4 or 5

Since the length and width must be positive, we can discard the solution w = 11.4. Therefore, the width of the rectangle is approximately 5 cm. We can then use the equation lw = 114 to solve for the length:

l(5) = 114

l ≈ 22.8

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Answer:

The half-life of a radioactive substance is the time it takes for half of the initial amount of the substance to decay. We can use the fact that 8% of the original amount remains after 100 days to determine the half-life of the isotope.

Let's assume that the initial amount of the substance is 1 unit (it could be any amount, but we're assuming 1 unit for simplicity). After one half-life, half of the original amount remains, or 0.5 units. After two half-lives, half of the remaining amount remains, or 0.25 units. After three half-lives, half of the remaining amount remains, or 0.125 units. We can see that the amount of substance remaining after each half-life is half of the previous amount.

We can use this information to set up the following equation:

0.08 = (1/2)^n

where n is the number of half-lives that have elapsed. We want to solve for n.

Taking the logarithm of both sides, we get:

log(0.08) = n*log(1/2)

Solving for n, we get:

n = log(0.08) / log(1/2) = 3.42

So the number of half-lives that have elapsed is approximately 3.42. Since we know that 100 days is the time for three half-lives (from the previous calculation), we can find the half-life by dividing 100 days by 3.42:

Half-life = 100 days / 3.42 = 29.2 days (rounded to one decimal place)

Therefore, the half-life of the radioactive isotope that leaked into the stream is approximately 29.2 days.

If the initial velocity is 75 feet per second, it will take approximately 5.125 seconds for the ball to hit the ground.

The given formula h= -16t²+vt+s represents the height (h) of an object thrown vertically in the air at time (t), with initial velocity (v) and initial height (s). In this case, we are given that the initial height of the softball is 4 feet and the initial velocity is 75 feet per second.

We want to find out how long it will take for the ball to hit the ground, which means we want to find the time (t) when the height (h) is 0.

Substituting the given values into the formula, we get:

0 = -16t² + 75t + 4

This is a quadratic equation in standard form, which we can solve using the quadratic formula:

t = (-b ± √(b² - 4ac)) / 2a

Where a=-16, b=75, and c=4. Substituting these values into the formula, we get:

t = (-75 ± √(75² - 4(-16)(4))) / 2(-16)

t = (-75 ± √(5625 + 256)) / (-32)

t = (-75 ± √(5881)) / (-32)

We can simplify the expression under the square root as follows:

√(5881) = √(49121) = 711 = 77

So we have:

t = (-75 ± 77) / (-32)

Simplifying further, we get two possible solutions:

t = 0.5 seconds or t = 5.125 seconds

Since the softball player hits the ball when it is 4 feet above the ground, we can disregard the solution t=0.5 seconds (which corresponds to when the ball is at its maximum height) and conclude that it will take approximately 5.125 seconds for the ball to hit the ground.

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Answer:

mean, 25.8 median 23

Step-by-step explanation:

Arrange the data in an ascending order and the median is the middle value. If the number of values is an even number, the median will be the average of the two middle numbers.

The mean of a set of numbers is the sum divided by the number of terms.

Answer:

Step-by-step explanation:

The converse of the conditional statement "If a polygon has three sides, then it is a triangle" is:

D. If a polygon is a triangle, then it has three sides.

In the original conditional statement, the "if" part is "a polygon has three sides," and the "then" part is "it is a triangle." The converse switches the positions of the "if" and "then" parts, resulting in the statement "If a polygon is a triangle, then it has three sides."

A) One way to write mixed fractions [tex]6\frac{2}{4} \\[/tex]  is 3 + 3 + [tex]\frac{1}{4}[/tex] +[tex]\frac{1}{4}\\[/tex]

B) Saturday: 3 to 4 hours work = trim bushes and weed garden

Sunday: 4 to 5 hour work = paint sheet and mow lawn

A) [tex]6\frac{2}{4} \\[/tex]  can be written as a simple fraction 6 + [tex]\frac{2}{4}[/tex]

This can be further broken into and written as

3 + 3 +  [tex]\frac{1}{4}[/tex] +[tex]\frac{1}{4}\\[/tex]

B) Saturday : 3 to 4 hours of work

Trim bushes + Weed garden

[tex]1\frac{1}{6} +2\frac{2}{6}[/tex]

1 + [tex]\frac{1}{6}[/tex] + 2+ [tex]\frac{2}{6}\\[/tex]

3 + [tex]\frac{3}{6}[/tex]

3 + [tex]\frac{1}{2}[/tex]

[tex]3\frac{1}{2}[/tex]

Sunday: 4 to 5 hours of work

Paint sheet + mow lawn

[tex]1\frac{3}{6} +3 \frac{4}{6}[/tex]

1 + 3 + [tex]\frac{3}{6} +\frac{4}{6}[/tex]

4 + [tex]\frac{8}{6}[/tex]

[tex]4\frac{8}{6}[/tex]

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The Given question is incomplete the complete question is :

Mr. mason likes to work around the yard during the weekends

The solutions to the quadratic equation 6x² = -3x + 1 to the nearest hundredth are -0.73 and 0.23.

Given the quadratic equation in the question:

6x² = -3x + 1

To solve the quadratic equation 6x² = -3x + 1, we can rearrange it into standard form, where one side is set to zero:

6x² + 3x - 1 = 0

Now we can solve the equation using the quadratic formula, which states that for an equation in the form ax² + bx + c = 0, the solutions for x are given by:

[tex]x = \frac{-b \±\sqrt{b^2-4ac} }{2a}[/tex]

Here; a = 6, b = 3, and c = -1.

Let's substitute these values into the quadratic formula:

[tex]x = \frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\ x= \frac{-3 \±\sqrt{3^2-4\ *\ 6\ *\ -1} }{2*6}\\\\x = \frac{-3 \±\sqrt{9+24} }{12}\\\\x = \frac{-3 \±\sqrt{33} }{12}\\\\x = -0.73, \ x=0.23[/tex]

Therefore, the values of x are -0.73 and 0.23.

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The height of the plane is 5 miles.

To solve this problem, we can visualize it as a right triangle. The horizontal distance traveled by the plane forms the base of the triangle, which is 12 miles. The total distance traveled by the plane forms the hypotenuse of the triangle, which is 13 miles. We need to find the height, which corresponds to the vertical side of the triangle.

Using the Pythagorean theorem, we can calculate the height as follows:

height^2 + 12^2 = 13^2

height^2 + 144 = 169

height^2 = 169 - 144

height^2 = 25

Taking the square root of both sides, we get:

height = √25

height = 5

Therefore, the height of the plane is 5 miles.

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The detergent with the coupon is the better buy since it has a lower price per ounce.

To determine which option is the better buy, we need to compare the prices per ounce for each detergent brand.

First, let's calculate the price per ounce for the 32-ounce bottle of detergent after applying the coupon:

Price per ounce = (Price - Coupon) / Ounces

Price per ounce = ($1.39 - $0.35) / 32

Price per ounce = $1.04 / 32

Price per ounce ≈ $0.0325

Next, let's calculate the price per ounce for the 20-ounce bottle of the other brand:

Price per ounce = Price / Ounces

Price per ounce = $0.79 / 20

Price per ounce = $0.0395

Comparing the two price per ounce values, we can see that the price per ounce for the detergent with the coupon is approximately $0.0325, while the price per ounce for the other brand is $0.0395.

Therefore, the detergent with the coupon is the better buy since it has a lower price per ounce.

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The number of pages that each book contained is given as follows:

465 pages.

The number of pages that each book contained is obtained applying the proportions in the context of the problem.

A head teacher shared 27 notebooks among 9 students, hence the number of the notebooks per student is given as follows:

27/9 = 3 notebooks per student.

One of them students found that each of his books combined 155 pages, hence the number of pages on the book is given as follows:

155 x 3 = 465 pages.

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The 9th term of the geometric sequence 4, -16, 64, ... is 262144.

To find the 9th term of the geometric sequence 4, -16, 64, ... , we need to determine the common ratio (r) of the sequence.

To do this, we can divide any term by its preceding term:

-16 / 4 = -4

64 / -16 = -4

We see that the common ratio (r) is -4.

To find the 9th term, we can use the formula for the nth term of a geometric sequence:

Tn = a * r^(n-1)

Where Tn is the nth term, a is the first term, r is the common ratio, and n is the term number.

In this case, the first term a is 4, the common ratio r is -4, and we want to find the 9th term.

T9 = 4 * (-4)^(9-1)

T9 = 4 * (-4)^8

T9 = 4 * 65536

T9 = 262144

Therefore, the 9th term of the geometric sequence 4, -16, 64, ... is 262144.

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Answer:

Step-by-step explanation:

The approximate price of the new car in 2014 is:

B. $32,200

The general form of a linear equation is given by:

y = mx + c

where y is the future price of the car, x is the number of years, m is the rate of change of price and c is the initial price of the car

c = $27,700

m = ($29,200 - $27,700)/(2010 - 2008)

m = 1500/2

m = $750 per year

In 2014, x = 2014 - 2008 = 6 years

Substituting into y = mx + c:

y = 750(6) + 27,700

y = 4500 + 27700

y = $32,200

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The value of the parameter p that satisfies the given conditions is 36.

Let the roots of the quadratic equation [tex]3x^2 - 24x + p = 0[/tex] be denoted by α and β, where α is the root that is triple the value of β.

Then we have:

α = 3β

The sum and product of the roots of the quadratic equation are given by:

α + β = 8 (from the coefficient of x in the linear term)

αβ = p/3 (from the constant term)

Substituting α = 3β in the first equation gives:

3β + β = 8

4β = 8

β = 2

Therefore, α = 6.

So the roots of the quadratic equation are α = 6 and β = 2.

The product of the roots is:

αβ = 6 × 2 = 12

From the equation αβ = p/3, we have:

p/3 = 12

p = 36

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The measure of m∠A in the triangle is:

m∠A = 38.44°

The cosine rule is used for solving triangles which are not right-angled in which two sides and the included angle are given. The following are cosine rule formula for angles:

cos(A) = (b² + c² − a²)/2bc

cos(B) = (c² + a² − b²)/ 2ac

cos(C) = (a² + b² − c²)/2ab

Where a, b and c are the length of the sides, and A, B, and C are the measures of the angles

We have:

a = BC = 20

b = AC = 23

c = AB = 32

Substituting into:

cos(A) = (b² + c² − a²)/2bc

cos(A) = (23² + 32² − 20²)/(2*23*32)

cos(A) = 0.7833

A = cos⁻¹(0.7833)

A = 38.44°

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The probability of drawing two yellow marbles is 0.015 to the nearest thousandth.

The probability of drawing two yellow marbles after drawing a yellow marble on the first draw and without replacement drawing another yellow marble is determined as follows:

Total number of marbles in the bag = 4 + 2 + 6

Total number of marbles in the bag = 12 marbles in the bag.

P(Yellow on first draw) = 2/12 or 1/6

P(Yellow on second draw | Yellow on first draw) = 1/11

The probability of both marbles being yellow will be:

P(Both marbles yellow) = (1/6) * (1/11)

P(Both marbles yellow)  = 1/66 or 0.015

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The model that represents the expression 87 - 42 is (d)

From the question, we have the following parameters that can be used in our computation:

87 - 42

Using their place values, we have

87 = 8 tens 7 units

42 = 4 tens 2 units

This means that

87 - 42 = 8 tens 7 units - 4 tens 2 units

Subtract the tens

87 - 42 = 4 tens 7 units - 2 units

Subtract the units

87 - 42 = 4 tens 5 units

The model that represents the expression 87 - 42 is 4 tens 5 units

This is represented by model (d) bottom right

Hence, the model that represents the expression 87 - 42 is (d)

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Answer:

They are both positive on (2, ∞)

Step-by-step explanation:

g(x) > 0

log(2x + 1) > 0

2x + 1 > 0

x > –1/2

(-1/2, ∞)

The area of the triangle is 6x³y⁵

The space enclosed by the boundary of a plane figure is called its area.

A triangle is a polygon with three sides having three vertices.

There are different types of triangle, scalene triangle, equailteral triangle, isosceles triangle, right triangle e.t.c

The area of a triangle is expressed as ;

A = 1/2 bh

where b is the base and h is the height of the of the triangle.

Base = 3x²y²

height = 4x4y³

A = 1/2 × 3x²y² × 4x4y³

A = 1/2 × 12x³y⁵

A = 6x³y⁵

Therefore the area of the triangle is 6x³y⁵

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The area of the Triangle is [tex]48x^{3} y^{4}[/tex]

Triangle is a two-dimensional  three-sided polygon, which has three vertices, three sides and three angles. It is a shape formed when three straight lines meet.

How to determine this

Area of triangle = 1/2 base * height as given

Where area of triangle = ?

Base = [tex]3x^{2} y2[/tex]

i.e 3 * 2 [tex]x^{2} y[/tex]

Base, b = [tex]6x^{2} y[/tex]

Height = [tex]4x4y^{3}[/tex]

i.e [tex]4x[/tex] * [tex]4y^{3}[/tex]

Height,b = [tex]16xy^{3}[/tex]

Area of triangle = 1/2 * [tex]6x^{2} y[/tex] * [tex]16xy^{3}[/tex]

Area = 1/2 * 96* [tex]x^{2+1}[/tex] * [tex]y^{1+3}[/tex]

Area = 1/2 * 96 * [tex]x^{3}[/tex] * [tex]y^{4}[/tex]

Area = 48 * [tex]x^{3} y^{4}[/tex]

Area of the triangle = [tex]48x^{3} y^{4}[/tex]

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We have two explicit functions of x for y:

[tex]y = -1/2 + \sqrt{(x^2 - x + 1/4)} \\or\\y = -1/2 - \sqrt{(x^2 - x + 1/4)}[/tex]

To define y as an explicit function of x, we need to solve for y in terms of x in the given equation:

[tex]x + y + y^2 = x^2[/tex]

First, let's simplify the equation by moving all the terms to one side:

[tex]y^2 + y + (x - x^2) = 0[/tex]

Now, we can use the quadratic formula to solve for y:

[tex]y = (-b + \sqrt{(b^2 - 4ac)} ) / 2a[/tex]

where a = 1, b = 1, and [tex]c = x - x^2.[/tex]Substituting these values, we get:

[tex]y = (-1 + \sqrt{(1 - 4(x - x^2)} )) / 2[/tex]

Simplifying further:

[tex]y = (-1 + \sqrt{(1 - 4x + 4x^2)} ) / 2\\y = (-1 + \sqrt{(4x^2 - 4x + 1)} ) / 2\\y = (-1 + 2\sqrt{(x^2 - x + 1/4)} ) / 2\\y = -1/2 + \sqrt{(x^2 - x + 1/4)}[/tex]

Therefore, we have two explicit functions of x for y:

[tex]y = -1/2 + \sqrt{(x^2 - x + 1/4)} \\or\\y = -1/2 - \sqrt{(x^2 - x + 1/4)}[/tex]

Either of these expressions represents y as an explicit function of x.

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Mrs. Garcia invested $2240 in the 8.5% account and $4091 in the 8% account.

Let x be the amount invested in the 8.5% account, and y be the amount invested in the 8% account. Since the total investment is $6331, we have x + y = 6331.

The total interest received is $517.68, which can be expressed as 0.085x + 0.08y = 517.68, where 0.085 and 0.08 are the decimal equivalents of the interest rates.

We can now solve this system of equations to find x and y. One possible method is to use substitution, where we solve for one variable in terms of the other from one of the equations, and substitute it into the other equation. From x + y = 6331, we have y = 6331 - x. Substituting this into the second equation, we get:

0.085x + 0.08(6331 - x) = 517.68

Simplifying and solving for x, we get:

0.005x + 506.48 = 517.68

0.005x = 11.2

x = 2240

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Answer:

Step-by-step explanation:

The function you provided, f(x) = -2.5 + 7, represents a linear function rather than a radical function. A linear function has a constant slope and a constant y-intercept.

The end behavior of a linear function is determined by its slope. In this case, the slope of the function is 0 since there is no term involving x. When the slope is 0, it means the function is a horizontal line.

The function f(x) = -2.5 + 7 represents a horizontal line at y = 4.5. As x approaches positive infinity (∞) or negative infinity (-∞), the value of y remains constant at 4.5. Therefore, the end behavior of this linear function is that y approaches 4.5 as x approaches both positive and negative infinity.

In conclusion, the end behavior of the function f(x) = -2.5 + 7 is that y approaches 4.5 as x approaches positive and negative infinity.

ANSWER: 100% of 2000000000 is 2000000000

What is 100 Percent of 2000000000?

100 percent *2000000000

= (100/100)*2000000000

= (100*2000000000)/100

= 200000000000/100 = 2000000000

Now we have: 100 percent of 2000000000 = 2000000000

Question: What is 100 percent of 2000000000?

We need to determine 100% of 2000000000 now and the procedure explaining it as such

Step 1: In the given case Output Value is 2000000000.

Step 2: Let us consider the unknown value as x.

Step 3: Consider the output value of 2000000000 = 100%.

Step 4: In the Same way, x = 100%.

Step 5: On dividing the pair of simple equations we got the equation as under

2000000000 = 100% (1).

x = 100% (2).

(2000000000%)/(x%) = 100/100

Step 6: Reciprocal of both the sides results in the following equation

x%/2000000000% = 100/100

Step 7: Simplifying the above obtained equation further will tell what is 100% of 2000000000

x = 2000000000%

Therefore, 100% of 2000000000 is 2000000000

Answer: $71,400

Step-by-step explanation:

We will set up a proportion with income in the numerator and pounds in the denominator.

       [tex]\displaystyle \frac{\$12}{4.2\;lbs} =\frac{\$x}{24,990\;lbs}[/tex]

Then we will cross-multiply.

       4.2 * x = 12 * 24,990

       4.2x = 299,880

Lastly, we will divide both sides of the equation by 4.2.

       x = $71,400

The income from 24,990 pounds of strawberries would be approximately $71,690.14.

To find the income from 24,990 pounds of strawberries, we need to use a proportion:

4.2 pounds of strawberries sells for $12, so 1 pound of strawberries sells for $12/4.2 = $2.86 (rounded to two decimal places).

Therefore, 24,990 pounds of strawberries would sell for:

$2.86 x 24,990 = $71,690.14 (rounded to two decimal places).

The percentage of buyers is approximately 68.26% of buyers of new houses paid between [tex]$149,000[/tex] and [tex]$151,000[/tex] .

We are given that the prices of the new homes are normally distributed with a mean of [tex]$150,000[/tex] and a standard deviation of $1000.

Using the 68-95-99.7 rule, we know that: approximately 68% of the data falls within one standard deviation of the mean approximately 95% of the data falls within two standard deviations of the mean, approximately 99.7% of the data falls within three standard deviations of the mean.

In order to determine the proportion of customers who spent between $149,000 and , we must first determine the z-scores for these values:

z1 = (149,000 - 150,000) / 1000 = -1 z2 = (151,000 - 150,000) / 1000 = 1

Now, we can determine the proportion of data that falls between z1 and z2 using the z-table or a calculator. The region to the left of z1 is 0.1587, and the area to the left of z2 is 0.8413, according to the z-table. Thus, the region bounded by z1 and z2 is:

0.8413 - 0.1587 = 0.6826

We can get the percentage of consumers who spent between by multiplying this by 100% is  [tex]$149,000[/tex]  and [tex]$151,000[/tex]:

0.6826 x 100% = 68.26%

Therefore, the standard deviation of customers who paid between is [tex]$149,000[/tex] and [tex]$151,000[/tex]  for this model of new homes.

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The value of x from the given triangle with angle 55° and side 27 units is 15.5 units.

A) By using Pythagoras theorem,

x²=16²+6²

x²=292

x=17.1 units

B) By using Pythagoras theorem,

23²=x²+9²

x²=529-81

x²=448

x=21.2 units

C) By using Pythagoras theorem,

10²=x²+8.5²

x²=100-72.25

x²=27.75

x=5.3 units

D) By using Pythagoras theorem,

x²=12²+15²

x²=369

x=19.2 units

E) Here, cos60°=6√3/x

1/2=6√3/x

x=12√3 units

F) Here, cos45°=√10/x

1/√2=√10/x

x=10 units

G) Here, sin60°=30/x

2/√3=30/x

x=15√3 units

H) Here, cos30°=x/16

2/√3=x/16

x=32/√3 units

I) Here, sinx=25/26

x=74°

J) Here, sin45°=x/16√2

1/√2=x/16√2

x=16 units

K) tan34°=x/28

0.6745=x/28

x=18.886

L) tanx°=17/18.5

tanx°=0.9189

x=42.5°

M) Here, cosx=9/12

x=41.4°

N) Here, sin16°=4/x

0.2756=4/x

x=4/0.2756 units

x=14.5

O) Here, cos55°=x/27

0.5735=x/27

x=15.4845

Therefore, the value of x from the given triangle with angle 55° and side 27 units is 15.5 units.

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This is a ratio problem and Sophia is expected to simplify the ratio by finding the smallest possible values and not compounding them by multiplying them by some values.

We can represent the given ratio as 60:36,

60/36

We proceed to reduce the fraction by dividing both the numerator and the denominator by a common factor say 6,

10/6

We can further reduce this with a common factor of 2

5/2

Thus, the ratio we have 5:2

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The values of a and b are a = -3 and b = 42. The solutions for x can be written as:

x = -3 - √42

x = -3 + √42

To solve the quadratic equation 2x² + 12x = 66 by completing the square, we need to follow these steps:

Step 1: Move the constant term to the right side:

2x² + 12x - 66 = 0

Step 2: Divide the equation by the leading coefficient (2):

x² + 6x - 33 = 0

Step 3: To complete the square, we take half of the coefficient of x, square it, and add it to both sides of the equation:

x² + 6x + (6/2)² = 33 + (6/2)²

x² + 6x + 9 = 33 + 9

x² + 6x + 9 = 42

Step 4: Rewrite the left side as a perfect square:

(x + 3)² = 42

Step 5: Take the square root of both sides:

√(x + 3)² = ±√42

x + 3 = ±√42

Step 6: Solve for x:

x = -3 ± √42.

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The product of powers of exponents cannot be used to simplify the binomial expansion

Given data ,

Let the binomial expansion be represented as A

A = ( 3z + y )³

According to the property of products of powers, exponents can be multiplied when a power is increased to a higher power.

The product of powers characteristic cannot be applied to the equation (3z + y)³. This is due to the fact that (3z + y)³ is a binomial raised to the power of 3, not just a power of a single word.

These terms cannot be simplified further using the product of powers property because they involve different variables or variable combinations.

In this case, it is more appropriate to expand the expression using the binomial expansion

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