The chemical energy in food is converted into the mechanical energy of the person, enabling him to push the load.
When you eat, your system may use the chemical energy in the food to cause your muscle groups to move, enabling you to walk, run, lift objects, and perform all the other activities necessary for their continued existence.
The chemical energy in food is converted into the mechanical energy of moving muscles.
The metabolic rate is the rate at which the energy from food is used by the human body to maintain vitality and carry out different activities.
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A 1436. 32' line has an azimuth of 178 52 13. What is the latitiude and departure of the line?
Latitude of the line will be = 1436.033
Departure of the line will be = 28.152
Given
let line be = a = 1436. 32
azimuthal be = x = 178° 52' 13''
This line must have two components , one is horizontal component which is its latitude and other will be vertical component which is departure . Resolving both the components we get,
latitude = a*cos(178° 52' 13'')
= 1436. 32 * cos(178° 52' 13'')
= 1436. 32 * (- 0.9998)
latitude = 1436.033
departure = a * sin (178° 52' 13'')
= 1436. 32 * 0.0197
departure = 28.152
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The following figures show four positions (1-4) of a comet during its orbit of the Sun. Also shown is the orbit of the Earth around the Sun. Rank the positions of the comet from left to right based on the size of its tail, from shortest to longest. (Not to scale; tails not shown.)
3, 1, 2, 4 is the arrangement according to their comet's tail.
The length of a comet's tail depends primarily on the comet's distance from the sun. It is longer when the comet is closer to the sun and shorter or (Negligible) when the comet is farther from the sun.
Due to sunlight's radiation pressure, the comet's tail will always point away from the sun. Small dust particles are pushed away from the sun by sunlight with a stronger force than by gravity pulling them in the opposite direction. As a result, a comet's tail streams behind the nucleus during its inbound transit, but it streams in front of the nucleus during its outbound passage back to the outer solar system. Typically, gas jets produced by thawing frozen volatiles expel dust particles from a comet's surface.
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The north-pole end of a bar magnet is held near a stationary positively charged piece of plastic. How is the plastic affected?.
When the north-pole end of a bar magnet is held near a stationary positively charged piece of plastic, it remains unaffected.
What is a bar magnet?
A bar magnet is made of ferromagnetic substance that produces
magnetic field.
What are the properties of a bar magnet?
Magnets attract ferromagnetic materials like iron, cobalt and nickel.Like poles repel each other and unlike poles attract each other.The strength of both poles is always the same.When a magnetic material is kept in contact with a bar magnet it acquires the magnetic property.Some materials like gold, silver and water get repelled by magnets.Since plastic is not a ferromagnetic material or any other material like gold and silver ,they remain unaffected in the presence of magnetic field.
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I need to know how to solve: finding magnitudes of forces related to a sum of three vectors
The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.
What are the magnitudes of two vectors to get the zero vector by vector sum?
According to the definition of vector sum and vectors in rectangular form, we must solve the following vector equation:
(0, 0) = 205 · (cos 23°, - sin 23°) + v · (- cos 75°, sin 75°) + u · (- cos 55°, - sin 55°)
(0, 0) = (188.703, 80.100) + v · (- 0.259, 0.966) + u · (- 0.574, 0.819)
(- 188.703, - 80.100) = v · (- 0.259, 0.966) + u · (- 0.574, 0.819)
Then, we must solve the following system of linear equations:
- 0.259 · v - 0.574 · u = - 188.703
0.966 · v + 0.819 · u = - 80.100
The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.
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In the absence of a strong magnetic field), what is the chief factor that determines what type of electromagnetic radiation objects give off:____.
The chief factor that determines what type of electromagnetic radiation that objects give off in the absence of a strong magnetic field is their temperature.
What is the radioactive activity?The radioactive activity refers to the energy that a atomic nucleus can release in a given period of time due to the emission of different types of radiation.
This activity (radioactive activity) increases as temperature rises due to a higher collision of subatomic particles that form molecules.
In conclusion, the chief factor that determines what type of electromagnetic radiation in the absence of a magnetic field is temperature.
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A 0.10-m 3 0.20-m 3 0.30-m block is suspended from a wire and is completely under water. What buoyant force acts on the block
The buoyant force acting on the block is 58.8 N.
Calculation:The dimensions of the block are given as 0.10 m, 0.20 m and 0.30 m.
The volume of the block will be = 0.10 × 0.20 × 0.30 m³
= 0.006 m³
We know that,
W = mg .....(1)
where,
W = weight of the block
m = mass of the block
g = acceleration due to gravity = 9.8 m/s²
We also know that mass is proportional to density and volume
m = ρ.V .....(2)
Substituting the equation (2) in (1)
W = ρ.V.g .....(3)
Density of water, ρ = 1000 kg/m³
Force is the net weight acting on the block
F = W = ρ.V.g
F = 1000 × 0.006 × 9.8
F = 58.8 N
Therefore, the buoyant force acting on the block is 58.8 N.
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Two 1-d waves of amplitude a and period t and constant phase 0 are superposed. If wave 1 travels 13. 5 wavelengths farther than wave 2, will the interference be:________
Two 1-d waves of amplitude a and period t and constant phase 0 are superposed. If wave 1 travels 13. 5 wavelengths farther than wave 2, the interference is 3/2π.
Interference of light is the phenomena of multiple light waves interfering with each other under certain circumstances, causing the mixed amplitudes of the waves to both boom or lower.one of the exceptional examples of interference is demonstrated by the light contemplated from a film of oil floating on water.
The phenomenon of addition or superposition of mild waves which produces an increase in intensity at some factors and a decrease in depth at a few other points are known as interference of light.
The intensities of light at exceptional factors of the medium are distinctive. At a few factors of the medium, depth is most and at a few different points intensity is maximum ( about 0) This phenomenon is called the interference of mild waves, the interference is known as negative interference.
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What relation can you state about the acceleration of the charge and it mass? Describe the mathematical relation, such as "directly proportional ", or "inversely proportional
Relation can you state about the acceleration of the charge and it mass is they are inversely proportional .
According to the question
Newton's second law :
Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
F = m * a
a = [tex]\frac{F}{m}[/tex]
Relation can you state about the acceleration of the charge and it mass is
According to Newton's second law of motion, acceleration is inversely proportional to the mass when the force is a constant.
The acceleration is directly proportional to the force when the mass remains constant.
Hence, Relation can you state about the acceleration of the charge and it mass is they are inversely proportional .
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How many watts of power are needed to exert a force of 30 n over a distance of 100 m for 1 minute?
Power require in Watts is 50 watts
Given:
Force = 30 N
Distance = 100m
Time for which force applied = 1 min = 60 sec
To Find:
Power
Solution: A watt is a unit of power. It is the amount of energy an item needs to function; the rate at which energy is consumed. One watt is equivalent to electricity flowing at a rate of one joule (unit of energy) per second
P = W/t
where W is work done by force and t is the time for which force is applied
W = F x d
W = 30 x 100 = 3000
P = 3000/60 = 50 watts
So Power require in Watts is 50 watts
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You're holding an open house for Brenda. Walt and Mary walk in and ask you for a flyer that gives details about the property. At this point, what's your relationship with Walt and Mary
Walt and Mary are my Customers at this point.
To construct proper client relationships you need to: greet clients and approach them in a way that is herbal and suits the character scenario. show customers that you recognize what their desires are. be given that a few humans may not want your merchandise and concentrate on constructing relationships with people who do.
Use the time period clients, with an apostrophe before the “s” to expose a possessive form for a single consumer. Use the time period clients', with an apostrophe after the “s” to show the possessive plural shape of a couple of patrons. Do now not use an apostrophe if there's no possessive indication needed.
The definition of a consumer is a person who buys services or products from a store, restaurant, or different retail vendor. An example of a patron is someone who is going to an electronics save and buys a tv. (Casual) a person, mainly one engaging in a few types of interaction with others.
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(10%) Problem 2: The frequency range for AM radio is 540 to 1600 kHz. The frequency range for FM radio is 88.0 to 108 MHz.
188m - 556m is the wavelength range for AM radio.
2.77 - 3.40m is the wavelength range for FM radio.
1) For AM radio
f(max) = 1600 × 10³ Hz
f(min) = 540 ×10³Hz
c = fλ
λ = c/f where,
c = speed of light
f = frequency
λ= wavelength
So,
λ(min) = 3 × [tex]10^{8}[/tex] / 1600 × 10³ = 188 m
λ(max) = 3 × 10⁸/540 ×10³ = 556 m
So wavelength range of AM radio is 188 m - 556m
2) For FM radio
f(max) = 108 × 10⁶ Hz
f(min) = 88 × 10⁶ Hz
λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m
λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m
So wavelength range of FM radio is 2.77m - 3.40m
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Interstellar dust is effective at blocking visible light because Choose one: A. the dust is so dense. B. dust grains are so small. C. dust grains are so large. D. dust grains are so few.
Answer: Interstellar dust is effective at blocking visible light because dust grains are so small.
Explanation: To find the answer, we need to know more about the interstellar dust.
What is interstellar dust?Interstellar dust developed from dying stars as they burn out.This dust can block the visible light as well as UV emerging from the stars, because dust grains can block light at optical wavelengths.it absorbs and scatters blue light more than red. thus, red light can pass through it.If we place a star behind the dust, it will look more redder than its usual color. This is called interstellar reddening.Grains have a typical size of [tex]10^-6 m[/tex].Thus, we can conclude that, Interstellar dust is effective at blocking visible light because dust grains are so small.
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A laser is shone through a double slit and a particular interference pattern is observed on a screen some distance away. If the separation between the openings is increased, the distance between the fringes will
If the separation between the openings in a laser is increased, then the distance between the interference fringes decreases
What is Interference fringe ?Interference fringe refers to bands caused by different lights which can be found in phase or not each other.
Distances between laser fringes are short which is due to light wavelength.The interference fringes can be estimated by knowing slit separation and wavelength.In conclusion, if the separation between the openings in a laser is increased, then the distance between the interference fringe decreases
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A 65.0 kg skier slides down a
37.2° slope with uk = 0.107.
If the slope is 42.0 m long, and
the skier starts from rest, how
fast is she going at the bottom?
(Unit = m/s)
She is going at a velocity of 20.63m/s to the bottom.
Friction is a resistive force between a body and the surface it is moving over in mechanics. It is computed mathematically using the friction coefficient and normal force product.
The mass is: m = 65kg
The coefficient of friction is: μk = 0.107
The angle is: θ = 37.2°
W = mg
W₁ = W sin θ = mg sin θ
W = W cos θ = mg cos θ
[tex]F_{N} = W = mgcos[/tex]θ
[tex]F_{f} =[/tex] µ[tex]F_{N}[/tex] = µmg cosθ
[tex]F_{net} = W_{1} - F_{f}[/tex]
[tex]= mg sin[/tex]θ - µmg cosθ
[tex]F_{net} = ma[/tex]
[tex]ma =[/tex] mg sinθ - µmg cosθ
a = g sinθ - µmg cosθ
= 9.8 sin (37.2) - (0.107) 9.8 cos(37.2)
= 9.8 × 0.605 - 0.107 × 9.8 × 0.796
= 5.929 - 0.834
= 5.095 [tex]m^2/s[/tex]
∴ Δd = [tex]\frac{1}{2} a ([/tex][tex]t^2[/tex][tex])[/tex]
[tex]t^2[/tex] = 2Δd / a
[tex]t^2=[/tex] 2 × 42.0 / 5.095
[tex]t^2 =[/tex] 16.48
[tex]t=4.05[/tex]
∴ [tex]v_{2} = v_{1} + at[/tex]
[tex]= 0+ 5.095 (4.05)[/tex]
[tex]= 20.63 m/s[/tex]
Therefore, she is going at a velocity of 20.63m/s to the bottom.
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Medical applications of ultrasound use frequencies up to 2.00 × 10^7 hz. What is the wavelength of this frequency in 20 °c air?
The wavelength of the ultrasound wave in 20 °c air is 1.715 * 10⁻⁵ m.
What is the relationship between wavelength and frequency of a wave?The frequency of sound is the number of complete oscillations per second.
The wavelength is the distance between successive positions in the wave.
Velocity of sound is the distance covered per second.
The frequency and wavelength of a wave are related by the formula given below:
Velocity = frequency * wavelengthThe velocity of sound in 20°C air = 343 m/s
frequency of the sound wave = 2.00 × 10⁷ hz or 2.00 × 10⁷ s⁻¹
wavelength = velocity/frequency
wavelength = 343 / 2.00 × 10⁷
wavelength = 1.715 * 10⁻⁵ m
In conclusion, the wavelength of the ultrasound wave is determined from the ratio of the velocity and the frequency of the sound.
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How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 26.0 cm in diameter to produce an electric field of 1440 N/C just outside the surface of the sphere
a metaphor for generosity and joy and joy and joy and joy organised a large wedding guests had to choose their meal from beef chicken tikka and a kind young women in the streets of St
The number of excess electrons needed to be distributed uniformly in the sphere to produce the given electric field is 1.69*10^(10).
What is an electric field?
The electric force exerted on a unit charge is called the electric field.
For a sphere of uniform charge density, the magnitude of the electric field on its surface is given by,
E=k*q/r^2
where E is the magnitude of the electric field, k is the coulomb's constant which has a value of 9*10^9 N m^(2) C^(-2), and q is the total charge of the sphere, and r is the radius of the sphere.
The radius of the sphere is half of the diameter. Given the diameter of the sphere is 26.0 m, the radius of the sphere r=26.0/2 cm or r=13.0 cm.
It is given that E=1440 N/C, r=13.0 cm, and the value of k is 9*10^9 N m^(2) C^(-2). Substitute these values in the formula of the electric field and solve it to get the value of the total charge on the sphere.
Note: 1 cm = 0.01 m.
1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13 cm)^2
1440 (N/C)= (9*10^9 N m^(2) C^(-2))*q/( 13*0.01 m)^2
1440 ( N/C)= (532.54*10^(9) N C^(-2))*q
q=1440/(532.54*10^(9)) C
q=2.704*10^(-9) C
Since the charge is quantized, the total charge inside the sphere is the integral multiple of an elementary charge. In the given case, the value of that elementary charge is 1.6*10^(-19) C. The total charge is then given by,
q=ne
where q is the total charge, n is the number of elementary charges and e is the value of the elementary charge.
The value of q is 2.704*10^(-9) C and the value of e is 1.6*10^(-19) C.
Substitute these values in the formula of total charge and solve it to get the number of elementary charges.
2.704*10^(-9) C =n*1.6*10^(-19) C
n=2.704*10^(-9)/ 1.6*10^(-19)
n=1.69*10^(10)
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PLEASE HELP QUICK! Why does thermal energy increase on a roller coaster? Especially when it goes up the second hill?
5.1 What is the nucleus composed of ?
Answer:
5.1 The DNA double helix is the most recognizable nucleic acid structure, but these are ribozymes.
What is the energy of an electromagnetic wave that has a wavelength of
7.0 x 10-12 m? Use the equation E= hc where hc = 1.99 × 10-25 J-m.
OA. 2.8 × 10-14 J
OB. 1.4 x 10-36 J
OC. 9.0 x 10-37 J
OD. 7.2 x 1035 J
SUBMIT
Answer:
A: 2.8 * 10^(-14) J
Explanation:
Formula to find the energy is;
E = hc/λ
Where;
E is energy of a photon (E)
λ is wavelength of the light
c is speed of light
Thus;
E = (1.99 *10^(-25))/(7 * 10^(-12))
E = 2.8 * 10^(-14) J
An astronomer discovers a new star and wants to measure its temperature. She would typically do this by:____.
An astronomer that discovers a new star and wants to measure its temperature would typically do this by means of a blackbody curve to find the maximum wavelength.
What is the maximum wavelength peak?The maximum wavelength peak is the portion of the wave where a given chemical substance/object exhibits its maximum strongest value of photon absorption.
On the other hand, the blackbody curve of an object is the graphical diagram that shows the distribution of the radiation emitted by this particular substance.
In conclusion, An astronomer that discovers a new star and wants to measure its temperature would typically do this by means of a blackbody curve to find the maximum wavelength.
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A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. How far away is the reflecting object? (c = 3.0 × 10^8 m/s)
A radar receiver indicates that a pulse return as an echo in 20 μs after it was sent. The reflecting object would be 3000 m away .
Phenomenon of hearing back our own sound is called an echo. It is due to successive reflection of sound waves from the surfaces or obstacles of large size. To hear an echo, there must be a time gap of 0.1 second in original sound and the reflected sound.
Given
time = 20 μs = 20 * [tex]10^{-6}[/tex] s
let distance to the reflecting surface be = x
total distance travelled by pulse will be = 2x
speed = 3.0 × [tex]10^{8}[/tex] m/s
distance = speed * time
2x = 3.0 × [tex]10^{8}[/tex] * 20 * [tex]10^{-6}[/tex]
x = 3000 m
The reflecting object would be 3000 m away
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A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from the ground, which path would the bowling ball most closely follow after leaving the airplane?
The path the bowling ball would most closely follow after leaving the airplane is horizontal direction.
Path of the bowling ball
Based on the law of inertia, which is the reluctance of an object to stop moving once in motion or start moving when it is at rest.
The bowling ball will maintain the path of the airline in the first few seconds of fall, after which it will change its path to vertical direction.
Thus, the path the bowling ball would most closely follow after leaving the airplane is horizontal direction.
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A 1-oz bullet is traveling with a velocity of 1400 ft/s when it impacts and becomes embedded in a 5-lb wooden block. The block can move vertically without friction. Determine (a) the velocity of the bullet and block immediately after the impact, (b) the horizontal and vertical components of the impulse exerted by the block on the bullet.
After impact velocity = 14.968 ft/s
Weight and mass of Bullet and wooden block:
Bullet: w = 1oz = 1/16 lb m = 0.001941 lb
wooden block : W = 5lb M = 0.15528 lb
velocity of block and bullet immediately after impact:
Σmv1 + ΣImp = mv2
Resolving vertical component
( m× v₀cos30⁰) + 0 = ( m+M) v'
v' = ( m× v₀cos30⁰)/ (m+M)
v' = 14.968 ft/s
Horizontal and vertical component of the impulse exerted by block on the bullet:
Here we will apply the principle of impulse and momentum.
Horizontal component:
-mv₀ cos30⁰ + RxΔt =0
RxΔt = mv₀sin30⁰
= 0.001941 × 1400sin30⁰
RxΔt = 1.3587 lb.s
Vertical component:
-mv₀cos30⁰ + RyΔt = -mv'
RyΔt = m( v₀cos30⁰-v')
RyΔt = 0.001941(1400cos30⁰ - 14.968)
= 2.32 lb.s
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A box of mass 8 kg slides across a frictionless surface at an initial speed 1.5 m/s into a relaxed spring of spring constant 69 N/m.
Time for which box will remain in contact with spring is 1.1 sec
Given:
mass of box = 8 kg
initial speed of box = 1.5 m/s
spring constant = 69 N/m
To Find:
time for which box will remain in contact with spring
Solution: The time taken to complete one oscillation is called the time period. where m is the mass, and k is the spring constant.
Time period is given as
t = π √m/k
t = 3.14 √8/69
t = 1.1 sec
So time for which box will remain in contact with spring is 1.1 sec
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A car generator turns at 400 rpm (revolutions per minute) when the engine is idling. It has a rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm that rotates in an adjustable magnetic field. What is the field strength needed to produce a 24.0 V peak emf
The field strength needed to produce a 24.0 V peak emf is 0.73T.
To find the answer, we need to know about the expression of emf.
What's the expression of peak emf produced in a rotating rectangular loops?
The peak emf produced in a rotating loops= N×B×A×wN= no. of turns of the loop, B= magnetic field, A= area of loop and w= angular frequencySo, B = emf/(N×A×w)What's the magnetic field applied to the loop, when rectangular coil with 300 turns of dimensions 5.00 cm by 5.22 cm rotates at 400 rpm produce a 24.0 V peak emf?N= 300, A= 5cm × 5.22cm = 0.05m × 0.0522m = 0.00261 m²Emf= 24V, w= 2π×400 rpm= 2π×(400rps/60) = 42 rad/sNow, B= 24/(300×0.00261×42)B= 24/(300×0.00261×42) = 0.73T
Thus, we can conclude that the magnetic field is 0.73T.
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What is the radial distance between the 500 v equipotential surface and the 1000 v surface?.
Answer: the radial distance between the 500-v equipotential surface and the 1000 v surface will be 8.91*106 times the charge Q.
Explanation: To find the answer, we have to know more about the equipotential surfaces.
What are equipotential surfaces?An equipotential surface is the locus of all points which have the same potential due to the charge distribution.Any surface in an electric field, at every point of which, the direction of electric field is normal to the surface can be regarded as equipotential.We have the equation for electric potential as,[tex]V=\frac{Qk}{r}[/tex] , where k is equal to 1/(4π∈₀) =[tex]8.99*10^9[/tex] .
equation for radial distance will be,[tex]r_d=r_1-r_2[/tex]
How to solve the problem?For the first surface, we can write the equation of potential as,[tex]500V=\frac{Qk}{r_1} \\thus, r_1=\frac{Qk}{500V}= (1.79*10^7 *Q) m[/tex]
For the second surface, we can write the equation of potential as,[tex]1000V=\frac{Qk}{r_2}\\ r_2= \frac{Qk}{1000V} =(8.99*10^6*Q) m[/tex]
Thus, the radial distance will be,[tex]r_d=1.79*10^7Q-8.99*10^6Q=(8.91*10^6*Q)m[/tex]
Thus, we can conclude that, the radial distance between the equipotential surface of 500V and 1000V will be,8.91*106 times the charge Q.
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What are true statements that reflect why infants experience more fluid and electrolyte changes?
True statements that reflect why infants experience more fluid and electrolyte changes are that dehydration can upset the balance of electrolytes in an infant or child and the newborn is at risk of excessive water loss and hypernatremia as the result of high evaporative water loss through the skin.
As infants are not used to the environment around , they are more sensible towards problems such as Dehydration because of fast metabolism.
Dehydration can upset the balance of electrolytes in an infant or child. Children are especially vulnerable to dehydration due to their small size and fast metabolism, which causes them to replace water and electrolytes at a faster rate than adults.
Infants are particularly prone to the effects of dehydration because of their greater baseline fluid requirements (due to a higher metabolic rate), higher evaporative losses (due to a higher ratio of surface area to volume), and inability to communicate thirst or seek fluid.
The newborn is at risk of excessive water loss and hypernatremia as the result of high evaporative water loss through the skin, insensible water loss (IWL), as well as decreased capacity to concentrate the urine.
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An electron moving through an electric field is observed to have an acceleration of 1.20 1016 m/s2 in the x direction. What is the magnitude and the direction of the electric field that produces this acceleration
The magnitude is 5.69 × 10^4 N/C and the direction is opposite to the acceleration of electron.
Equation of force on a charge is -
F = ma
→ qE = ma
The acceleration of an electron is 1.201016 m/s².
→ E = ma/q
plug in the values
E = 9.11 × 10^-31 kg × 1×10^16 m/s² i / -1.6 × 10^-19 C
E = 5.69 × 10^4 N/C (-i)
so, magnitude is 5.69 × 10^4 N/C and field is along negative x-axis
Thus, it has opposite direction to the acceleration of electron.
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The light ray is now incident on a glass-air interface, with an angle of incidence in the glass of 45 degrees. What is the angle of light ray emerging from the glass into air
The ray will not emerge into the air medium from glass medium.
To find the answer, we need to know about the critical angle.
What's critical angle of glass?Critical angle of a medium can be determined from the relation as sinФ = 1/n, n = refractive index of that medium.As glass has refractive index of 1.5, so Critical angle = sin⁻¹(1/1.5) = 42 °Why does the light incident at 45° inside a glass not emerge to the air medium?As we got the critical angle of glass is 42°, so the light incident at 45° which is greater than 42° will reflect back into the glass medium instead of emergence into the air medium.Thus, we can conclude that the light will not emerge into air medium.
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A 2. 0mc charge in an external field of 20n/c, north (direction) will experience a force of: ___0. 04____________ newtons, the direction of the force is __north___________
2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
Force in an electric field = charge * electric field
given
charge = 2* [tex]10^{-3}[/tex] C
electric field = 20 N/C
Force in an electric field = 2* [tex]10^{-3}[/tex] * 20
= 0.04 N
since , external field is in north direction then the force must be in north direction because the direction of an electric field at a point is the same as the direction of the electric force acting on a positive test charge
hence, 2. 0 mc charge in an external field of 20n/c, north (direction) will experience a force of 0.4 newtons, the direction of the force is north
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