Answer:
D . They are found in moist environments.
Explanation:
Nonvascular plants do not have a xylem or phloem, roots, stems, or leaves. Because these plants lack water-conducting tissues, they fail to achieve the structural complexity and size of most vascular plants and have evolved in habitats which allow their survival and reproduction.
The plant body that is most obvious in non-vascular plants are the the gametophyte generation. The gametophte gemeration is haploid.
The non-vascular plants grow in moist environments. It is due to lack of vascular tissue that requires to maintain close contact with water to prevent desiccation. Nonvascular plants are plants that do not have any special internal pipelines or channels to carry water and nutrients. Instead, nonvascular plants absorb water and minerals directly through their leaflike scales. Nonvascular plants are usually found growing close to the ground in damp, moist places. Non-vascular plants thrive in damp conditions since they don't need to rely on roots to acquire enough water.
Suppose you are provided with a 35.83 g sample of potassium chlorate to perform this experiment. What is the mass of potassium chloride you expect to release upon heating?
For a 35.83 g sample of potassium chlorate, the mass of potassium chloride is mathematically given as
M Kcl=21.62g
What is the mass of potassium chloride you expect to release upon heating?Generally, the equation for the Chemical Reaction is mathematically given as
2KClO_3----->2KCl+2O_2
Therefore
[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]
Mole of KCl=0.29mol
Mass of Kcl=0.29*74.55
Mass of Kcl=21.62g
In conclusion, Mass of Kcl
M Kcl=21.62g
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Determine which reaction has the highest activation energy.
A. Burning charcoal
B. Melting ice
C. Combusting gasoline
D. Reacting metal and acid
Answer:
A.
Explanation:
What is the first principle energy level called
Answer:
S orbital
Explanation:
no explanation, just a name you memorize
If a metal reacts violently with water, in which group is it likely to be found?
Answer:
Alkali metals (Li, Na, K, Rb, Cs, and Fr)
Explanation:
Answer:
Group 1
Explanation:
Alkali metals such as (Lithium, Sodium, Rubidium, Francium, Cesium, etc.) react violently with waterThey are termed "alkali" due to their nature of forming hydroxides on reacting with waterIdentifying My Interests
List five activities that you enjoy
Answer:
BIKE riding, Watching yt, Hanging with friends, Food,Dogs
based on the electron configuration of the two atoms predict the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound. hydrogen and fluorine
The metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.
What is a compound?A compound is madeup of two or more atoms that are chemically combined together. In this case, we have the atoms; hydrogen and fluorine.
The electronic configuration of the atoms are not shown here but the metal cationic (+) atom to nonmetal anionic (-) atom ratio in the compound formed between hydrogen and fluorine is 1:1.
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Which of the compounds below will dissociate in water? Check all that apply.
Ba(NO3)2
CaSO4
CO2
H2CO3
Mg3(PO4)2
those numbers are subscripts
An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.
What is a soluble compound?A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.
The compound that would dissolve in water among the list of compounds here is Ba(NO3)2.
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Answer:
A) Ba(NO3)2
B) CaSO4
C) CO2
D) H2CO3
E) Mg3(PO4)2
Explanation:
Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!
give the structure of chlorocyclohexane.
don't spam :)
thankyou ~
Answer:
Explanation:
This is not my photo. I got it from this website.
https://pubchem.ncbi.nlm.nih.gov/compound/Chlorocyclohexane#section=2D-Structure
write an equation to show the effect of heat on the nitrate of silver
Answer:
2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)
Explanation:
I used powers ³,²,²
So change them to be down
Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many
moles of ozone would be produced?
337.92 moles of Ozone will be produced
1 Oxygen atom is 8 g
1 mole of ozone, O3 = 8 * 3 = 24 g
7.92 * 1024 = 8110.08 g
1 mole = 24 g
? moles = 8110.08 g
? = 337.92 moles
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Hope it helps
Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.
What is molecular formula?Molecular formula is defined as an expression that defines a number of atoms of each element in one molecule of a compound.
It can also be defined as a chemical formula that gives the total number of atoms of each elements in each molecules of a substance.
Ozone is defined as a highly reactive gas composed of three oxygen atoms and form a layer above the earth surface called as ozone layer.
1 oxygen atom = 8 g
1 mole of ozone = 8 x 3 = 24 g
7.92 x 10²⁴ = 8110.08 g
24 g = 1 mole
So, 8110.08 g = 337.92 moles
Thus, Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.
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#SPJ2
A 5.00 L flask at 25˚ C contains 0.200 mol of Cl2 . What is the pressure in the flask?
Answer:
Your answer would be:
0.98atm.
Explanation:
The pressure of a gas can be calculated by using the following expression:
PV = nRT
P = pressure
V = volume
-----------------------------------
n = number of moles
R = gas law constant
T = temperature
P × 5 = 0.2 × 0.0821 × 298
5P = 4.893
P = 4.893 ÷ 5 = 0.98atm
P = 0.98atm
In conclusion, the pressure of a 5.00 L flask at 25 degrees C. that contains 0.200 mol of Cl2 is 0.98atm.
Have a great rest of your day
#TheWizzer
Answer:
Hello, senzawahl SORRY IF I SPELLED YOUR NAME INCORRECT
Prime here ready to solve your question :)
so your correct answer is 0.98atm.
Explanation:
Stay safe
-prime
A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves. What is the solute in this scenario?
Answer:
The answer is the Sodium Chloride.
Explanation:
A solute is the minor component in a solution, dissolved in the solvent, and the sodium is being dissolved in water ( or the solvent).
A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves, in this scenario sodium chloride is solute.
What are solute?Those substance which are present in the solution relatively in less amount is known as solute.
In the question given that 36 grams of sodium chloride is added in the 200 grams of water. From this it is clear that sodium chloride is a solute and water is a solvent, which additionally makes a solution.
Hence, sodium chloride is a solute.
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If 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate, determine the molarity of the lead (II) nitrate solution. Note: First write the balance equation between potassium iodide and lead (II) nitrate.
The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.
How to calculate molarity?The molarity of a solution can be calculated using the following formula:
CaVa/CbVb = na/nb
Where;
Ca = concentration of acidCb = concentration of baseVa = volume of acidVb = volume of basena = number of moles of acidnb = number of moles of baseThe balanced equation of the reaction is as follows:
Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)
22 × 2/18 × Cb = 2/1
44/18Cb = 2
Cb = 44 ÷ 36
Cb = 1.2M
Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.
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When a sodium atom becomes an ion, the size of the atom
A
decreases by losing an electron,
B
decreases by gaining an electron,
с
increases by losing an electron,
D
increases by gaining an electron,
As you move from left to right in the third period of the periodic table…
A. Each group loses an outer electron
B. Each group gains an outer electron
C. Each group gains a neutron
D. The number of outer electrons remains constant across the period
Answer:
B
Explanation:
2.8.1 Na
2.8.2 Mg
and so on and so forth
Ignoring the contributions of wind, a baseball would be expected to travel farther in warm, humid air because: Select one: a. water vapor helps to lift the baseball even higher. b. water vapor sticks to baseballs. c. water vapor is less dense than dry air. d. none of these
Answer:
water vapor is less dense than dry air
what is safe storage of produced materials exlain long
Answer:
Stacking storage sacks/ bags by interlocking, and placing heavier object on lower shelves.
Explanation:
Not sure what you meant exactly, but this is my best guess.
Referring to your benzene model, explain why there is no directionality for a substituent group bonded directly to a benzene ring.
The benzene molecule is flat and planar. As a result of this planarity, the substituent is also in the plane of molecule and do not show any directionality.
What is the benzene moleculeThe benzene molecule is a flat and planar molecule owing to the fact that all the bond lengths and bond angles in the molecules are the same. This results from resonance in the molecule.
Hence, owing to the planarity of the molecule, the substituent is also in the plane of molecule and do not show any directionality.
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How much heat is required to raise the temperature of 1,500 g of water from 25°C to 52°C? The specific heat of water is 4.184 J/g-oC.
Apply thermodynamics
[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]
Q is heat[tex]\\ \rm\rightarrowtail Q=1500(4.184)(27)[/tex]
[tex]\\ \rm\rightarrowtail Q=169452J[/tex]
What is the isotope notation of selenium
Answer:
It is Se.
hope this helps.
When Thomas Edison first sold electricity, he used zinc coulometers to measure charge consumption. (In a coulometer the cathode is weighed before a current is passed through it, and then again after the passage of current. The weight increase is proportional to the amount of current that flows through the cathode.) If the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, how much charge had passed through it
When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.
Ionization of zinc
The zinc metal will ionize as shown below;
Zn²₊ + 2e⁻ → Zn
The molar mass of zinc metal is given as 65.38 g/mol
Amount of charge passed through 65.38 g/molAmount of charge that will deposite the given mass of zinc is calculated as follows;
e⁻ = 96500 C
2e⁻ = 2 x 96500 C = 193,000 C
Amount of charge passed through 7.85 g65.38 g -------> 193,000 C
7.85 g -----------> ?
= (7.85 x 193,000)/(65.38)
= 23,173 C
Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.
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• Calculate the entropy change when 1.00 mol of
water at 0°C freezes to form ice. (AHfus for water
is +6.02 kJmoll)
1
Answer:
the enthalpy change of this is 5.02mol
When 20.4g of sodium metal are mixed with chlorine gas, are 52.0 g of sodium chloride
produced? Explain (use calculations to prove your answer.
.ves or no
-with amounts shown)
Answer: True
Explanation:
[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]
For Na
[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]
For NaCl
[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]
[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]
Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced
Explanation:
The answer: True
I explained the answer to your question in the submitted photo
2. The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?
3. When a 10L balloon is heated from 22.0°C to 97.0°C, to what volume does it inflate?
4. Calculate the pressure of a gas in a 205 mL container at 0.0°C when the container was initially at a volume of 300.0 mL and a pressure of 1.05 atm
Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?
Explanation:
According to Bohr's Model, which one is correct about a transition from n=2 to n=1 in a hydrogen atom?
When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.
What happen in transition from n= to n=1?During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.
So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.
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3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0
mL water initially. What is the density of this unknown metal if the final reading from
the graduate cylinder was 65.0 mL?
For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially, the density of this unknown meta is mathematically given as
D= 0.23 g/ml
What is the density of this unknown metal if the final reading from the graduate cylinder was 65.0 mL?Generally, the equation for the Volume of water is mathematically given as
Vw= Volume of water after metal addition - Volume of water initial
Therefore
Vw = 65 ml - 50 ml
Vw= 15 ml
In conclusion,
D= Mass of metal / Volume
D= 3.5 / 15
D= 0.23 g/ml
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A buffer was prepared containing 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). The Ka of formic acid is 1.7 x 10-4. What will be the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer
For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as
pH=3.95
What is the pH after 0.010 mol of NaOH(s) is added to 100.0 mL of the buffer?Generally, the equation for the Hendersons equation is mathematically given as
pH=pKa+log(SALT)/(ACID)
Where
moles of (NaCOOH)=100*0.05/1000
moles of (NaCOOH)=0.05moles
and formic acid
moles of formic acid=100*0.05/1000
moles of formic acid=0.05moles
Therefore
pKa=-logka
pKa=1.4*10*3.77
pH=3.77+log{0.06/0.04}
pH=3.95
In conclusion, the pH is
pH=3.95
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Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.
Calculate the pH.
Note: the answers should have three significant figures
The pOH is: Blank 1
The pH is: Blank 2
Answer:
Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.
Calculate the pH.
Note: the answers should have three significant figures
The pOH is: Blank 1
The pH is: Blank 2
Explanation:
How many grams of Na2S will be produced if you react 35.0g sodium
How much 1.75 M H3PO4, in mL, would you need to add to 50.00 mL of 3.50 M Ca(OH)2 in order to neutralize the solution
The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL
Balanced equation2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O
From the balanced equation above,
The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3How to determine the volume of H₃PO₄ Molarity of acid, H₃PO₄ (Ma) = 1.75 MVolume of base, Ca(OH)₂ (Vb) = 50 mLMolarity of base, Ca(OH)₂ (Mb) = 3.5 MVolume of acid, H₃PO₄ (Va) =?MaVa / MbVb = nA / nB
(1.75 × Va) / (3.5 × 50) = 2/3
(1.75 × Va) / 175= 2/3
Cross multiply
1.75 × 3 × Va = 175 × 2
5.25 × Va = 350
Divide both side by 5.25
Va = 350 / 5.25
Va = 66.67 mL
Thus, the volume of the H₃PO₄ solution needed is 66.67 mL
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