What color should appear when a properly cleaned nichrome wire is introduced into the flame?.

When a solution of MgCl₂ and a solution of AgNO₃ are mixed, the net ionic equation obtained is:

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

In solution

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

AgNO₃(aq) —> Ag⁺(aq) + NO₃¯(aq)

The reaction proceeds as follow

MgCl₂(aq) + AgNO₃(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) —> 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Cancel out the spectator ions (i.e Mg²⁺ and NO₃¯) to obtain the net ionic equation

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

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When a solution of MgCl₂ and one of AgNO₃ are mixed, the net ionic equation is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

Net ionic reactions are those reactions in which each species are written in their respective ions form except the spectator ions.

Given chemical reaction is:

MgCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Mg(NO₃)₂(aq)

Ionic form of the given reaction will be written as

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) → 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Spectator ions are those which are commonly present on both side of the reaction and for this reaction they are Mg²⁺ and NO₃¯. So the net ionic reaction will be:

2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s)

Hence required net ionic reaction is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

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Answer:

A weak base is a base that, upon dissolution in water, does not dissociate completely, so that the resulting aqueous solution contains only a small proportion of hydroxide ions. PH 7-10

A strong base is a base that is completely dissociated in an aqueous solution. a PH of about 12-14

The mass of hydrogen atoms in the compound would be 2 grams.

The carbon atoms in the compound have a mass of 24 grams.

One carbon atom has a mass of 12 grams. Thus, there are two (12 x 2 = 24) carbon atoms in the compound.

This means that there are also two hydrogen atoms in the compound. One hydrogen atom weighs 1 gram. Hence, the mass of the hydrogen atoms in the compound will be 2 grams.

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Answer:

WHERES THE UNDER STORY! POST IT QUICK AND ILL HELP

Explanation:

All cell constituents are duplicated during cell division in a human cell i.e. mitosis and meiosis type of cell division.

During mitosis, a cell duplicates all of its internal parts and formed two identical daughter cells. During duplication, all parts have two sets which is equally distributed into two daughter cells in mitosis type of cell division.

While on the other hand, during meiosis, a cell divides into four daughter cells having haploid chromosomes i.e. half number of chromosomes.

So we can conclude that cell constituents are are duplicated during cell division in a human cell.

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Answer:

B.) –197.8 kJ

Balanced equation : 2SO₂(g) + O₂(g) → 2SO₃(g)

Given:

================================================================

products energy = reactant energy

-593.6 + O₂ = -791.4

O₂ = -791.4 - ( -593.6)

O₂ = –197.8 kJ

At STP

No of moles=13.7mol

Total volume:-

The volume of gas occupied by 13.7 moles at STP is 306.88L.

STP stands for standard temperature and pressure. STP refers to a specific pressure and temperature used to report on the properties of matter.

According to IUPAC( International Union of Pure and Applied Chemistry), it is defined as -

It is generally needed to test and compare physical and chemical processes where temperature and pressure plays an important role as they keep on varying from one place to another.

One mole of a gas under STP conditions occupies a volume of 22.4L.

Given,

Moles of carbon dioxide gas = 13.7 moles

We know that,

1 mole of a gas occupies 22.4 L of volume at STP.

Thus, 13.7 moles will occupy 13.7 × 22.4 L

                                              = 306.88 L

Therefore, the volume of gas occupied at STP is 306.88L.

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Answer:

forward and reverse reaction rates

Explanation:

meaning the equilibrium is reached faster. So if the reaction is already at equilibrium there will be no effect on a concentration-time or moles-time graph.

Addition of sodium carbonate is a way to soften water by removing calcium ions

Water can be softened by the addition of lime to precipitate the calcium as carbonate. Sodium carbonate is also added to remove the remaining calcium salts and to make the water soft.

So we can conclude that addition of lime or sodium carbonate is a way to soften water by removing calcium ions.

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A process based on ksp experiment to soften the water by removing calcium ions is by ion exchange resin process in which the calcium ion is substituted by a sodium ion.

The water containing a large number of calcium ions is called hard water.

Hard water is not suitable to use.

To remove calcium ion or soften the water, there are various methods are used.

They are ion exchange resin, distillation, and sodium hydroxide.

Thus, a process based on ksp experiment to soften the water by removing calcium ions is by ion exchange resin process in which the calcium ion is substituted by a sodium ion.

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Answer: 6.7 kPa

Explanation:

Pressure Total = P(partial 1) + P(partial 2) + P(partial 3) →

94.5 kPa = 65.4 kPa + 22.4 kPa + P(partial 3) →

6.7 = P(partial 3) :)

According to the Dalton's law of partial pressures the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures exerted by each individual gas in the mixture.

So, P[tex]_o[/tex] = P[tex]_1[/tex]+ P[tex]_2[/tex]+ P[tex]_3[/tex]

[tex]\longrightarrow[/tex]94.5 = 65.4+ 22.4 + P[tex]_3[/tex]

[tex]\longrightarrow[/tex]94.5 = 87.8+ P[tex]_3[/tex]

[tex]\longrightarrow[/tex] P[tex]_3[/tex] = 94.5 - 87.8

[tex]\longrightarrow[/tex]P[tex]_3[/tex] = 6.7 kpa

Therefore, partial pressure of the 3rd gas of the mixture is 6.7 kpa .

Answer:

0.258 moles of Oxygen.

Explanation:

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Answer:

In a heavier nucleus, the repulsive force between the protons is very high. For stability, the nuclear force must dominate this electrostatic repulsive force. This is possible if the number of neutrons is greater than number of protons.

Answer: I believe the answer is surface tension :)

Answer:

D

Explanation:

because if a flea is on a dog that is a parisite to host relashionship

Answer:

for number 3 is D

Explanation:

but i am not 100% sure of that

After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

Given Data

Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

The remainder is 35ml

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If you dispense 40 ml of hexane, but it turns out you only need 5 ml, then we should have 35 mL of remained hexane.

Remaining volume of any liquid will be calucted as:

Remaining Volume = Total volume - Used volume

Given that, total volume of hexane = 40 mL

Used volume of hexane = 5 mL

On putting values in above equation, we get

Remaining volume = 40 - 5 = 35 mL

Hence required value of remaining volume is 3 mL.

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Answer:

AsF3:C2CI6

4:3

1.3618 moles: 1.02135 moles(1.3618÷4×3)

C2CI6 is the limting reagent

So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)

or

Balanced equation

4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4

Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.

Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.

Explanation:

Answer:

The air resistance is a special type of frictional force that acts upon objects as they travel through the air. The force of air resistance is often observed to oppose the motion of an object. This force will frequently be neglected due to its negligible magnitude (and due to the fact that it is mathematically difficult to predict its value). It is most noticeable for objects that travel at high speeds (e.g., a skydiver or a downhill skier) or for objects with large surface areas. Air resistance is a contact force.

The force of gravity is the force with which the earth, moon, or other massively large object attracts another object towards itself. By definition, this is the weight of the object. All objects upon earth experience a force of gravity that is directed "downward" towards the center of the earth. Gravitational force is considered to be a non-contact force because it is an attracting force which does not include contact between the objects to exert force

Answer:

Bison were saved through the combined efforts of conservationists, scientists, ranchers and ultimately the general public. As their comeback continues, I believe that they can teach us how to be better stewards of the land and provide a future for the Plains where ecosystems and human cultures thrive.

Explanation:

[tex]watch.some.anime[/tex]

Answer:

Because it is the hottest zone

Answer:

the non luminous flames are very hot. little light is produced by non luminous flames.

Answer:

The answer is Ka1

▬▬▬▬▬▬▬▬

When it comes to dissociation, Ka1 is fairly the most even-out level, classifying it as a Weak Acid.

They must be fully separable into ions. If that's the case, you are dealing with a Strong acid.

If this is not the case, that would make the acid Weak.

▬▬▬▬▬▬▬▬

In conclusion, I hope this helps you and I hope you have a great day!

 The coefficient tells you how many molecules of that substance there is. 

Answer: 373 mL

Explanation:

Since there is no change in pressure, the formula: V / T = V / T can be used.

However, you must first convert the temperatures to Kelvin by adding 273 to them:

(19 + 273) = 292K and (90 + 273) = 363K.

Now, plug in: V / 292 = 464 / 363 → V = 373 mL :)

Answer:

2 KMnO4 + H2O2 → 2 MnO2 + 2 O2 + 2 KOH - Balanced equation

Answer:

This is a pretty straightforward example of how an ideal gas law problem looks like.

Your strategy here will be to use the ideal gas law to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant.

So, the ideal gas law equation looks like this

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

P

V

=

n

R

T

a

a

∣

∣

−−−−−−−−−−−−−−−

Here you have

P

- the pressure of the gas

V

- the volume it occupies

n

- the number of moles of gas

R

- the universal gas constant, usually given as

0.0821

atm

⋅

L

mol

⋅

K

T

- the absolute temperature of the gas

Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of

R

.

a

a

a

a

a

a

a

a

a

a

a

Need

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

Have

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

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a

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a

a

a

a

a

a

a

a

Liters, L

a

a

a

a

a

a

a

a

a

a

a

a

a

Liters, L

a

a

a

a

a

a

a

a

a

a

a

√

a

a

a

a

a

a

a

Kelvin, K

a

a

a

a

a

a

a

a

a

a

a

a

Celsius,

∘

C

a

a

a

a

a

a

a

a

a

×

Notice that the temperature of the gas must be expressed in Kelvin in order to work, so make sure that you convert it before plugging it into the ideal gas law equation

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

T

[

K

]

=

t

[

∘

C

]

+

273.15

a

a

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−

Rearrange the ideal gas law equation to solve for

P

P

V

=

n

R

T

⇒

P

=

n

R

T

V

Plug in your values to find

P

=

0.325

moles

⋅

0.0821

atm

⋅

L

mol

⋅

K

⋅

(

35

+

273.15

)

K

4.08

L

P

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

2.0 atm

a

a

∣

∣

−−−−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the temperature of the gas.

Answer:

[tex]\huge\boxed{\sf P = 1.68 \ atm}[/tex]

Explanation:

Given:

Moles = n = 0.6 mol

Volume = v = 9.13 L

Temperature = T = 38 °C + 273 = 311 K

Gas constant = R = 0.08206 L atm K⁻¹ mol⁻¹

Required:

Pressure = P = ?

Formula:

Pv = nRT

Solution:

Rearranging formula

[tex]\displaystyle P = \frac{nRT}{v} \\\\P = \frac{(0.6)(0.08206)(311)}{9.13} \\\\P = \frac{15.3}{9.13} \\\\P = 1.68 \ atm\\\\\rule[225]{225}{2}[/tex]

Long Answer:

Ionic: Cation is named first followed by the anion.

If it's an ionic compound with a transition metal, there are more than one possible ion. Molecular - named with the least electronegative ion first + prefixes are given to both ions to indicate number of atoms in each element.

Short Answer: Ionic compounds- Cation is named first, followed by the anion.

Answer:

Answer one:
Solute particles block some of the ability of liquid particles to evaporate. We can then conclude, solutions of solid solutes typically have a lower vapor pressure than pure solvents.

Answer two:
Solutions freezing points are lower than of the pure solvent or solute because freezing (becoming a solid) creates order and decreases entropy.

Answer three:
The presence of solute particles decreases the vapor pressure of the liquid solvent, this means a higher temperature is needed to reach the boiling point.

Explanation:

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Answer:

16.015668 M

Explanation:

Concentration is mols/L

nacl molar mass is 58.44277 g/mol

moles = mass/molar mass

moles = 4.00391699

4mol/0.250L = 16.015668 M solution

The term aldol condensation has to do with a reation in which a nucleophile attacks the carbonyl group of an aldehyde.

The term aldol condensation has to do with a reation in which a nucleophile attacks the carbonyl group of an aldehyde or a ketone to convert it to the enolate from which attacks another aldehyde or ketone at the carbonyl carbon to form the required product.

The structure of the organic product from the aldol condensation involving cyclopentanone is shown in the image attached to this answer.

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