What is the value of mm in the equation m+6=43m+6=43?

Using right triangle relations, we will get:

We assume that bot triangles are equivalent, then the angle B will be the same as the angle Z.

Now remember the relations:

If we step on angle B, we have:

Replacing that, we get:

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The decomposition of the partial fraction is [tex]\frac{4ax-a^2}{(x+ 2a)(x-a)} = \frac{A}{x + 2a} + \frac{B}{x - a}[/tex]

The expression is given as:

[tex]\frac{4ax-a^2}{x^2+ax-2a^2}[/tex]

Expand the denominator

[tex]\frac{4ax-a^2}{x^2- ax+2ax-2a^2}[/tex]

Factorize

[tex]\frac{4ax-a^2}{x(x- a)+2a(x-a)}[/tex]

Factor out x - a

[tex]\frac{4ax-a^2}{(x+ 2a)(x-a)}[/tex]

The denominator of the partial fraction is a product of two linear factors.

So, the decomposition can be represented as:

[tex]\frac{4ax-a^2}{(x+ 2a)(x-a)} = \frac{A}{x + 2a} + \frac{B}{x - a}[/tex]

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Answer:

The correct awnser is A : )

Step-by-step explanation:

Step-by-step explanation:

If a stock's price falls all the way to zero, shareholders end up with worthless holdings. Once a stock falls below a certain threshold, stock exchanges will delist those shares.strong earning result in the stock price moving up and vice versa.

in the question you asked,the situation that will make stock price move from -$2.85 to zero means the stock, bond, or commodity market, or an index representing them, currently trades higher than it did at some specific point in the past.

The answer choice which explains that the three segments cannot be used to construct a triangle is; AC + CB < AB.

Since, It follows from the triangle inequalities theorem that sum of the side lengths of any two sides of a triangle is greater than the length of the third side.

Hence, since the sum of sides AC + CB is less than AB, it follows that the required inequality is; AC + CB < AB.

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Answer: Option 2 or B.  AC + CB < AB

Step-by-step explanation: Trust Me!  It is correct on Edge!

Q: Which inequality can be used to explain why these three segments cannot be used to construct a triangle?

A: AC + CB < AB

The inequality which shows all possible values of m is; m < 9.

It follows from the task content that the variable in discuss, m is described as less than 9.

On this note, the most appropriate inequality to represent the set of all possible values of m is; m < 9.

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In accordance with the function velocity, the car will have a complete stop after 6 seconds.

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

t² - 21 · t + 90 = 0

By the quadratic formula we get the following two roots: t₁ = 15, t₂ = 6. The stopping time is the least root of the quadratic equation, that is, the car will have a complete stop after 6 seconds.

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Answer:

the answer is congruent making d midpoint

The correct matching of the exponential form is given.

1: 13^-11 × 13^16 × 13^-3 × 13^-4 × 13^-5

= 13

2. 13^-21 × 13^-4 × 13^-5 × 13^14 × 13^-6

= 13^-22

3. 13^0 × 13^10 × 13^-12 × 13^5 × 13^4

= 13^7

This illustrates the exponential form.

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The graph that represents the given line with slope and y-intercept is as attached below.

We are given the equation;

x - y - 3 = 0

Now, the standard way we should put the equation would be in slope intercept form which is; y = mx + c

where;

m is slope

c is y-intercept

Thus, our equation can be rearranged to get;

y = x - 3

Thus, y-intercept is c = -3

The graph that represents the given line is as attached below.

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No, the average change in population is not the same as it was 50 years ago.

Reason in Support of the Answer:

In many important ways, the demographic future of the United States and the rest of the world is substantially different from the recent past. The world's average population approximately tripled between 1950 and 2010, and the U.S. population nearly doubled.

However, it is anticipated that between 2010 and 2050, both globally and in the United States, average population growth will be substantially slower and will disproportionately favor the oldest age groups. Hence it is seen that the average change in population is never constant. It depends on the demographic trends and conditions, whether the average change in population will be larger or comparatively trivial in the future. And, similarly, it can be said that the average change in population is not the same as it was 50 years ago.

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Answer:

2=1289/17

Step-by-step explanation:

use the given functions to set up and simplify 2

The zeros of the given function are x = 2 and x = -1

From the question, we are to determine the zeros of the given function

The given function is

f(x) = (x - 2)(3x + 3)

To determine the zeros of a function, we will set the function equal to zero

That is,

(x - 2)(3x + 3) = 0

Then,

x - 2 = 0 OR 3x + 3 = 0

x = 2 OR 3x = -3

x = 2 OR x = -3/3

x = 2 OR x = -1

Hence, the zeros of the given function are x = 2 and x = -1

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Answer:

C

Step-by-step explanation:

y = (x - 2)² = x² - 4x + 4 → (1)

x + y - 2 = 0 → (2)

substitute y = x² - 4x + 4 into (2)

x + x² - 4x + 4 - 2 = 0

x² - 3x + 2 = 0

(x - 1)(x - 2) = 0

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 2 = 0 ⇒ x = 2

substitute these values into (2) and solve for y

x = 1 : 1 + y - 2 = 0 ⇒ y - 1 = 0 ⇒ y = 1 ⇒ (1, 1 )

x = 2 : 2 + y - 2 = 0 ⇒ y + 0 = 0 ⇒ y = 0 ⇒ (2, 0 )

the line intersects curve C at 2 points (1, 1 ) and (2, 0 )

Answer:

Line A

Step-by-step explanation:

Hello!

Given that the x-values is the time in minutes, and the y-axis is the number of dishes stacked, for every minute, the line should go up by 7.

This means, that the value of y when x is 1 should be 7. The line that follows this rule is Line A. For every minute, 7 dishes are stacked.

The answer is Line A.

Answer: [tex]\frac{9g}{4y}[/tex]

Step-by-step explanation:

[tex]\frac{6g}{2} \times \frac{3}{4y}=\frac{18g}{8y}=\frac{9g}{4y}[/tex]

Answer:

C. 0.12

Step-by-step explanation:

Let's use a sample number of 100

Out of 100 members, 50 are in the brass section

Out of those 50, 24% play the trombone. This means that 12 people total play the trombone.

12/100 is .12.. That is the final answer

Answer:  [tex]\frac{\sqrt{7}}{7}[/tex]

========================================================

Explanation:

The reciprocal of x is 1/x where x is nonzero. Multiplying x with 1/x leads to 1. For example, the numbers 9 and 1/9 are multiplicative inverses of each other.

We'll stick 1 over the given square root expression. Then follow these steps to rationalize the denominator.

[tex]\frac{1}{\sqrt{7}}\\\\\\\frac{1*\sqrt{7}}{\sqrt{7}*\sqrt{7}}\\\\\\\frac{\sqrt{7}}{(\sqrt{7})^2}\\\\\\\frac{\sqrt{7}}{7}\\\\[/tex]

In short, [tex]\frac{1}{\sqrt{7}}=\frac{\sqrt{7}}{7}[/tex]

The total number of snakes in the zoo is 10.

The number of snake can be found using ratio as follows:

The animals in the zoo are lions, tigers and snakes and he has them in the ratio of 5 : 3 : 2. The total animal is 50 animals.

Therefore,

total snakes = 2 / 10 × 50

total snakes = 100 / 10

total snakes = 10

Therefore, the total number of snakes in the zoo is 10.

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Using the law of cosines, it is found that the approximate length of side a is 3.99 units.

The law of cosines states that we can find the side c of a triangle as follows:

[tex]c^2 = a^2 + b^2 - 2ab\cos{C}[/tex]

in which:

In the context of this problem, we have that side a is opposite to the angle of 53º, hence:

[tex]a^2 = b^2 + c^2 - 2bc\cos{53^\circ}[/tex]

We are given that:

Then:

[tex]a^2 = 34 - 30\cos{53^\circ}[/tex]

a² = 15.95

[tex]a = \sqrt{15.95}[/tex]

a = 3.99.

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Al aplicar operaciones de aritmética básica, tenemos que la mitad de 980 es igual a 490.

En esta pregunta tenemos un número par de tres dígitos que termina en cero. De acuerdo con la teoría numérica, un número de base 10 de más de un dígito que tenga un número par relacionado con números impares como último dígito, tendrá un número impar si es dividido por 2.

Ahora bien, si tenemos un número par con más de un dígito que termina en cero, entonces tendrá un número par que termina en 0 si es dividido por 2.

Si dividimos 980 por 2, entonces tenemos 490 como resultado:

980/2 = 98/2 × 10 = 49 × 10 = 490

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Answer: A. x = 4

Step-by-step explanation:

Substituting 4 for x..

(4+7)^2 = 121

(11)^2 = 121

11 * 11 = 121

Using Green's Theorem to evaluate the given line integral with the given conditions and vertices gives us; -30

The line integral of a vector-valued function along the edges of a rectangle or any other closed curve can be found by converting the line integral into a double integral. We apply Green's theorem to do this. The resulting double integral is integrated over the two-dimensional region bounded by the same closed curve.

Green's Theorem can be applied as follows:

∮_c (P.dx + Q.dy) = ∫∫_R ((dQ/dx) - (dP/dy))dA

The vertices of the rectangle (1,1), (3,1), (1,4), and (3,4).

Applying Green's Theorem to the given function gives;

∮_c (ln x + y) dx - x² dy

= ∫14∫13 Dx(-x2) -Dy(ln(x) +y) dx dy

= ∫₁⁴∫₁³ (-2x - 1) dx dy

= -3·[x² +x]₁³

= -30

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The sum of the ten terms to the nearest whole number is 50857.

Using geometric sequence formula,

nth term = arⁿ⁻¹

where

r = 20 / 8 = 5 / 2

a = 8

Hence,

s₁₀ = a(rⁿ - 1) / r - 1

s₁₀ = 8((5 / 2)¹⁰ - 1) / 5 / 2 - 1

s₁₀ = 8(9535.74316406) / 1.5

s₁₀ = 50857.296875

s₁₀ = 50857

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This problem is about pension fund management. It is to be noted that the best Feasible Capital Allocation Line (CAL) is: 0.3162.

A graph's capital allocation line depicts all conceivable combinations of risky and risk-free assets, allowing investors to estimate future returns depending on risk.

It is to be noted that the optimal risky portfolio's stock percentage is determined by:

Weight of Stock = ((Return on Stock - Risk Free Rate) * Variance of bond) - ((Return on Bond - Risk Free Rate) * Co-Variance of bond & Stock)/ ((Return on Stock - Risk Free Rate) * Variance of bond + (Return on Bond - Risk Free Rate) * Variance of Stock - ((Return on Bond - Risk Free Rate + Return on Stock - Risk Free Rate + ) * Co-Variance of bond & Stock)

→ The weight of stock

= ((15% - 5.5%) * 529) - ((9% - 5.5%) * 110.40)/ ((15% - 5.5%) * 529) + (9% - 5.5%) * 1,024 - ((15% - 5.5% + 9% - 5.5%) * 110.40)

= [(50.255) * (3.864) /(50.255) + (46.08) - (14.352)]

Weight of Stock = 0.646628

Weight of  Bonds = 1 - 0.646628

Weight of  Bonds= 0.353372

Expected return of portfolio = 0.646628 * 15% + 0.353372 * 9%

= 12.88%

Standard Deviation of Portfolio (SDP)= (0.6466282² * 1,024 + 0.3533722² * 529 + 2 * 0.646628* 0.353372* 110.40)⁰·⁵

SDP = (544.67)⁰·⁵

SDP = 23.34%

Hence,

Best feasible CAL = (12.88% - 5.5%)/ 23.34%

Best feasible CAL = 0.3162

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Full Question

See the attached spread sheet for additional information related to the questions.

Answer:

Cinthia studied 2/3 of her time on Tuesday