Answer:
Here's the answer
Explanation:
since an electromagnet has a magnetic field, it will always follow the electromagnet.
The value of gravitational pull on the moon is 1.6m/s/s. what is the weight of a 85kg astronaut on the moon?
weight=
mass=
gravity=
formula:
substitution:
answer:
Explanation:
Gravity = 1.6 m/s^2
Mass = 85 kg
Full infomation needed your question is incomplete and BTW fomula : G Mm
R^2
An apple weighing 1 N fall a distance of 1 m how much work is done on the Apple by the force of gravity
Explanation:
work = Force×distance
Force in this question is equal to the weight (force of gravity)
work = 1 × 1 = 1 J
Jole is the unit of work
18. Students are discussing the magnitude of the electrostatic force that sphere B exerts on sphere A.
Eva states that sphere B exerts a larger electrostatic force on sphere A than sphere A does on sphere B.
. Taylor states that sphere B exerts the same electrostatic force on sphere A as sphere A does on sphere B.
• Jac states that sphere B exerts a smaller electrostatic force on sphere A than sphere A does on sphere B.
Which student is correct? Give scientific reasoning to support your decision.
she is k bads boy (into negative)
A weight of 200 n is hung from a spring with a spring constant of 2500 n/m and lowered slowly. How much will the spring stretch?
8n/m this is because 200×2500 all over 100 . 0's will cancile 0's living 200×2500×1 ,25 will go into 200 8 times ×1 =8n/m
The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.
What is spring force?The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is
F = kx
The given data in the problem is;
F is the spring force =200
K is the spring constant= 2500 N/m
x is the length by which spring got stretched =?
The stretch of the spring is found as;
[tex]\rm F=kx \\\\ x = \frac{F}{k} \\\\\ x= \frac{200}{2500} \\\\ x=0.08 \ m[/tex]
Hence the length by which the spring got stretched will be 0.08 m.
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A distant astronomical object (a quasar) is moving away from us at half the speed of light. what is the speed of the light we receive from this quasar?
For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar is mathematically given as c = 3x108 m/s
What is the speed of light?Generally, the equation for the is mathematically given as
The speed of light can be said to be measured to be approximately the value c = 3x108 m/s
.
In conclusion, An will not influence 3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to 3x108 m/s
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The change in momentum that occurs when a 1. 0 kg ball traveling at 4. 0 m/s strikes a wall and bounces back at 2. 0 m/s is.
Answer:
The change is momentum is given by ∆p=p(inital) - p(final) =4-2=2 kg.m/s
Explanation:
momentum is the product of mass and velocity (speed)
So it's initial momentum would be:
p=mv=(1)(4)=4 kg.m/s
It's final momentum is given by:
p=mv=(1)(2)=2 kg.m/s
How are physical descriptions and physical properties similar?
Answer:
A physical property and physical description are similar because the changes in a physical property of a system can be used to describe its changes between momentary states.
A physical property is is defined as any property that is measurable, and also whose value describes a state of a physical system.
Examples of physical properties include;
density,
hardness,
melting and boiling points, and
thermal conductivity
A physical description is observed physical properties usually represented by a specific class, compound or elements.
Both physical property and physical description are similar because the changes in a physical property of a system can be used to describe its changes between momentary states.
Answer:
A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.
this one too!! need just 1 answer about this system
Answer:
A
Explanation:
The endocrine system has all of the body's hormones it regulates the biological processes. For example it can help brain development, nervous system development, and it can regulate blood sugar. (This is the closest to A)
17. Suppose you attach the object with mass m to a vertical spring originally at rest, and let it bounce up and down. You release the object from rest at the spring’s original rest length. (a) Show that the spring exerts an upward force of 2.00mg on the object at its lowest point. (b) If the spring has a force constant of 10.0N/m and a 0.25-kg-mass object is set in motion as described, find the amplitude of the oscillations. (c) Find the maximum velocity.
Please show all of your work.
Answer:
See below ↓
Explanation:
Step 1 : Diagram
In attachmentStep 2
We choose the system to be the spring, the block, and the Earth and it is isolatedWe put all the data in the figure we have created and create a zero level (initial height) of the block to be yₓ = 0 and the final position, when it stops and moves upwards again, to be yₙ = -ANo external forces are exerted on the system and no energy comes in or out of the systemHence,⇒ ΔE = 0
⇒ Eₙ - Eₓ = 0
⇒ Eₙ = Eₓ
⇒ Kₙ + Uₙ + Pₙ = Kₓ + Uₓ + Pₓ
Final kinetic energy is 0 at the lowest point⇒ Uₙ + Pₙ = Uₓ + Pₓ
Step 3
Initial potential energy is 0 [zero level = initial height]⇒ Uₙ + Pₙ = Uₓ
And we know that spring was originally at normal length, so initial spring energy is also 0⇒ Uₙ + Pₙ = 0
⇒ 1/2kxₙ² + mgyₙ = 0
⇒ 1/2kxₙ² = -mgyₙ
We know xₙ = A and yₙ = -A from the diagram⇒ 1/2kA² = -mg(-A)
⇒ 1/2kA² = mgA
⇒ [1/2kA = mg]
Step 4
Spring force is given by : F = -kxNote : x = A⇒ F = kA
⇒ k = F/A
⇒ Plug 'k' into the equation found at the end of Step 3
⇒ 1/2(F/A)(A) = mg
⇒ 2F = mg
⇒ F = 2mg (a)
Step 5
We know the spring will stop oscillating and be at rest at the new equilibrium position of the system⇒ F - mg = 0
⇒ F = mg
We know that :⇒ F = -kx
In the case x = yₙ⇒ kyₙ = mg
⇒ yₙ = mg/k
⇒ yₙ = 0.25 x 9.8 / -10
⇒ yₙ = -0.245 m
⇒ yₙ = A
⇒ yₙ = 0.245 m (b)
Step 6
v(max) = Aωv(max) = A√k/mv(max) = 0.245 x √(10/0.25)v(max) = 1.55 m/s (c)sitting at rest on top of a spring with a spring constant of 10N /m. the spring is compressed 5m
Answer:
50N
Explanation:
this is because 5×10all over 100 ,0 will cancile 0 remaining 10 ,1 into 10 ,10times ,so 5×10 =50N
When a car is struck by lightning, the resulting electric field inside the car is.
Answer: When a car is struck by lightning, the resulting electric field inside the car is zero.
Explanation:
What is current of 12 ohm? help me pleasee
1. 0.25 A
2. 0.5 A
3. 1 A
4. 1.5 A
5. 2 A
please show solution.
Answer:
the current is 5.2 Amps
Scientists predict that in another 250 million years, the continents will be located in different positions. How is this possible? *
Answer:
The continents will be in different positions because tectonic plate boundaries are always moving.
How much work is done in lifting 30 kg of bricks to a height of 20 m?
Answer:
5,886 Joules or 5.886 KJ.
Explanation:
FORMULA IN FINDING WORK is
W = F x D
Where W is working;
F is force; and
D is distance
However, let us first discuss what work is.
When there is an object being moved by a force through a certain distance, the measure of energy transfer is what we call WORK.
One of the most common units used in work is JOULES (commonly used as a unit of energy). It is the work by which 1 Newton (1N = 1 kg.m/sec²) of force is used/expended through a distance of 1 meter (1m).
Refer to the problem.
It is said that the 30 kg set of bricks is to be raised to a height of 20 meters. As we see, there is no force given. But recall that force (F) is the product of the mass (m) of an object and its acceleration (a)
F = ma
However, in the formula, (g = 9.81 m/s²) or acceleration due to gravity is used in replacement of (a) because the object is moving upward.
So now we have
F = mg
Thus, we have the new work formula as
W = (mg)(D)
Substituting the given values, we have
W = (mg)(D)
W = (30kg)(9.81 m/s²)(20m)
W = 5,886 kg.m²/sec² or W = 5,886 Joules
The work done in lifting the bricks is 5,886 Joules or 5.886 KJ.
~hope this helps~
What is the wavelength of a light ray that has a frequency of 7.4 E12 Hz?
The wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.
Given the data in the question;
Frequency of the light ray; [tex]f = 7.4 * 10^{12}Hz[/tex]Wavelength; [tex]\lambda = \ ?[/tex]WavelengthWavelength can be simply defined as the spatial period of a periodic wave. When the shapes of waves are repeated, the distance over which they are repeated is called wavelength. Wavelength is expressed as;
[tex]\lambda = \frac{c}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and c is speed of light( [tex]c = 3*10^8m/s[/tex] )
We substitute our values into the expression above to determine the wavelength of the light ray.
[tex]\lambda = \frac{c}{f} \\\\\lambda = \frac{3*10^8m/s}{7.4*10^{12}s^{-1}}} \\\\\lambda = \frac{3*10^8ms/s}{7.4*10^{12}}}\\\\\lambda = 4.05*10^{-5}m\\\\\lambda = 4.05*10^{4}nm[/tex]
Therefore, the wavelength of the light ray with the given frequency is 4.05 × 10⁴nm.
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Can you hear the vibrations a tuning fork puts off when hit?
no
Explanation:
no not an vibration signal
22. What is the length of a pendulum that has a period of 0.500 s?
Please show all of your steps to find the solution.
6.21 cm
use the pendulum formula : [tex]\sf \bold{\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{L}}{\mathrm{g}}}}[/tex]where
T is time or periodπ is pie = 22/7L is pendulum lengthg is acceleration due to gravityGiven:
T = 0.500 sg = 9.8 m/s²solving step-wise:
[tex]\dashrightarrow \mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{g}}}[/tex]
[tex]\sf \dashrightarrow \mathrm{0.5}=2 \pi \sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]
[tex]\dashrightarrow \mathrm{\dfrac{0.5}{2 \pi } }=\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}[/tex]
[tex]\dashrightarrow\sqrt{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= \mathrm{\dfrac{0.5}{2 \pi } }[/tex]
[tex]\sf \dashrightarrow{\dfrac{\mathrm{L}}{\mathrm{9.8}}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2[/tex]
[tex]\sf \dashrightarrow{{\mathrm{L}}= (\mathrm{\dfrac{0.5}{2 \pi } })^2*9.8[/tex]
[tex]\sf \dashrightarrow{{\mathrm{L}}=0.06205922 \ m[/tex]
1 m → 100 cm[tex]\sf \dashrightarrow{{\mathrm{L}}=6.2059\ cm[/tex]
[tex]\sf \dashrightarrow{{\mathrm{L}}=6.21\ cm[/tex] { rounded to nearest hundredth }
Let's see
[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
[tex]\\ \rm\rightarrowtail 0.5=2\pi \sqrt{\dfrac{l}{9.8}}[/tex]
[tex]\\ \rm\rightarrowtail 0.783=\pi \sqrt{l}[/tex]
[tex]\\ \rm\rightarrowtail 0.2494=\sqrt{l}[/tex]
[tex]\\ \rm\rightarrowtail \ell=0.0622m[/tex]
A rollercoaster loop has a radius of 22.7 m. what is the minimum speed the coaster must have at the top of the loop to not fall off the track? (unit = m/s)
Answer:
v = 14.92 m/s
Explanation:
First, make a free body diagram and see the forces in the y-direction.
∑F_y = F_N - F_gUse Newton's 2nd Law F = ma to replace ∑F_y with m * a_y.
m * a_y = F_N - F_gThe acceleration in the y-direction is the centripetal acceleration, a_c = v^2/r.
m * v^2/r = F_N - mgThe normal force is 0 because this is where the rollercoaster is not falling off the track yet not touching the track.
m * v^2/r = - mgThe masses cancel out.
v^2/r = -gSolve for v to find the speed of the rollercoaster at the top of the loop.
v^2 = -(-9.81) * r v = √(9.81 * 22.7)v = 14.9227The minimum speed the coaster must have at the top of the loop to not fall off the track is 14.92 m/s.
If you were standing on the edge of a thunderstorm as it begins to form, would the wind be blowing into the storm or out of it? why?
hey guys can y’all help quickly?
how to induce a positive temporary charge on the right side of a metal ball
Answer:
Temporary? You have two options
If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).
If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).
Either way, the electron cloud will migrate towards the right side of the of your sphere.
Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.
Tuning a piano to tune middle c on a piano, a tuner hits the key and at the same time sounds a 261 hz tuning fork. if the turner hears 3 beats per second, what are the possible frequencies of the piano key?
This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.
How to compute the variation in frequencyThe beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.
Beat per second equals |f1 - f2| Where
ft = Frequency of the Tunning fork and
fp= Frequency of the Piano Key
Hence
3 = 261 - fp
Solving for fp,
fp = 261-3
= 258hz
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Two cities in the same climate zone must have the same climate and weather conditions. Why is this statement true or false?
A. It is false because cities in the same climate zone must have different climates.
B. It is false because the two cities might differ in their proximity to water.
C. It is true because the two cities are at the same latitude.
D. It is true because the two cities will be closer to the equator.
Answer:
C
Explanation:
true because c is the best answer
Answer: The answer is C. It is true because the two cities are at the same latitude.
Explanation:
Hi I was doing the same test are u in flvs lol I am too if you are!
After a student shoves a book across a flat table, it begins to slow down. Why?
Answer:
The force of friction opposes the motion of an object, causing moving objects to lose energy and slow down. When objects move through a fluid, such as air or water, the fluid exerts a frictional force on the moving object. The frictional force from a fluid is called a drag force.
You’ll start by investigating how earth’s surface temperature varies. open my nasa data, and click on data set in the top left corner of the page. within the atmosphere category, select all data, then select temperature. now, select monthly air surface temperatures. after the new map appears on your screen, select the animate option near the top of the page, and then select ok to see the animation. set the time range on the animation for the most recent five years, and then click submit. you can control the speed of the animation with the controls beneath the map.
question 1
describe patterns you observe in earth’s surface temperature. how do these patterns change during the course of a year and from year to year? use lines of latitude and degrees celsius in your description.
Different patterns we observe in earth’s surface temperature due to angle, distance from the sun, latitude of the place and ocean currents.
Describe patterns you observe in earth’s surface temperature?The Earth's surface experiences a range of temperature due to different conditions such as angle of the sun, distance from the sun, the latitude of the place, distance from the sea, altitude of the place and ocean currents.
So we can conclude that different patterns we observe in earth’s surface temperature due to angle, distance from the sun, latitude of the place and ocean currents.
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13.
Jenny and her brother Tom sit on opposite ends of a seesaw. Jenny is
40 kg and her brother is 30 kg. If Jenny sits 1.5 meters from the pivot
point and Tom sits 1 meter from the pivot point, what is the net torque
on the seesaw?
The net torque on the seesaw is 294 Nm.
What is torque?Torque is the force that tends to rotate the body to which it was applied.
To calculate the net torque, we use the formula below
Formula:
τ = mgd-m'gd'........... Equation 1Where:
τ = Net torquem = Jenny's massm' = Tom's massd = Jenny's distance from the pivotd' = Tom's distance from the pivotg = acceleration due to gravityFrom the question,
Given:
m = 40 kgm' = 30 kgd = 1.5 md' = 1 mg = 9.8 m/s²Substitute these values into equation 1
τ = (40×1.5×9.8)-(30×1×9.8)τ = 588-294τ = 294 NmHence, The net torque on the seesaw is 294 Nm.
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Why doesn't mercury have an atmosphere?
Answer:
The main reasons are two. Mercury's atmosphere is hard to hold onto because it is small and does not have much gravity. As Mercury is close to the Sun, any atmosphere is blasted away by material being blown off the Sun.
Hope this helps friend!
Do tuning forks make sounds when hit from the vibrations? I'll give brainiest
Answer:
Yes
Explanation:
they make sound due to the fact that the vibration from the tuning fork itself interacts with the air around it. it's also worth mentioning that anything that vibrates creates sound waves as well.
While playing basketball in PE class, Logan lost his balance after making a lay-up and colliding with another student standing behind the basket. His 74-kg body decelerated from 7.6 m/s to 0 m/s, causing the 81-kg student to accelerate from 0 m/s. What is the final velocity of the other student?
PLEASE HELP
The final velocity of the other student after the elastic collision with Logan is 6.94 m/s.
Conservation of linear momentum
The final velocity of the other student will be determined by applying the principle of conservation of linear momentum for elastic collision.
let u represent initial velocitylet v represent final velocitym₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Substitute the given parameters and solve for final velocity of the other stsudent.
74(7.6) + 81(0) = 74(0) + 81(v₂)
562.4 = 81v₂
v₂ = 562.4/81
v₂ = 6.94 m/s
Thus, the final velocity of the other student after the elastic collision with Logan is 6.94 m/s.
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What is atmospheric pressure?
If a food has 200 calories and 7 grams of protein, and each gram of protein is 4 calories, what percent of the serving comes from protein?
Answer: 13%
Explanation: The reason this is 13 is because you can eat carlories and you can also be an amazing person 200 calories and 7 grams