The best use for a fume hood is: Removing toxic vapors. The correct option is b.
What is Fume Hood?
A fume hood is a specialized piece of laboratory equipment designed to protect the user and the environment from potentially harmful substances. It achieves this by capturing and removing toxic vapors, gases, and fumes from the air within the hood.
Removing toxic vapors is the primary purpose of a fume hood. It is equipped with an exhaust system that draws air and any hazardous substances away from the user and vents them out of the laboratory, ensuring the air in the workspace remains clean and safe.
Storing glassware (a) does not require the use of a fume hood, as it does not involve the handling or release of toxic substances. Covering volatile compounds (c) may benefit from a fume hood to control and capture any vapors that may be released, but it is not the primary use.
Mixing chemicals that release O₂ (d) does not necessarily require a fume hood unless those chemicals also release toxic vapors or fumes that need to be safely extracted.
In summary, the best use for a fume hood is to remove toxic vapors, safeguarding the health and safety of laboratory personnel and maintaining a controlled working environment. b. is the right option.
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Complete question:
Which is the best use for a fume hood?
a. Storing glassware
b. Removing toxic vapors
c. Covering volatile compounds
d. Mixing chemicals that release O₂
1. Determine the molecular formula of an oxide of iron in which the mass of iron and oxygen are 69.9% and 30% respectively given that the molar mass of the oxide 159.898/mol, find the empirical and molecular formula.
2. a crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%.
3. In three moles of Ethane calculate the following
1. calculate number of carbon atoms.
2. number of moles of hydrogen atoms
3. number of molecules of Ethane.
1a. The empirical formula of the compound is Fe₂O₃
1b. The molecular formula of the compound is Fe₂O₃
2a. The molecular formula of the anhydrous salt is MgSO₄
2b. The formula of the crystalline salt is MgSO₄.7H₂O
3i. The number of mole of carbon atoms in the compound is 6 moles
3ii. The number of mole of hydrogen atoms in the compound is 18 moles
3iii. The number of molecules in 3 moles of ethane is 1.806×10²⁴ molecules
1a. How to determine the empirical formulaFe = 69.9%O = 30%Empirical formula =?Divide by their molar mass
Fe = 69.9 / 56 = 1.248
O = 30 / 16 = 1.875
Divide by the smallest
Fe = 1.248 / 1.248 = 1
O = 1.875 / 1.248 = 3/2
Multiply by 2 to express in whole number
Fe = 1 × 2 = 2
O = 3/2 × 2 = 3
Thus, the empirical formula of the compound is Fe₂O₃
1b. How to determine the molecular formulaEmpirical formula = Fe₂O₃Molar mass of compound = 159.89 g/molMolecular formula = ?Molecular formula = empirical × n = molar mass
[Fe₂O₃]n = 159.89
[(56×2) + (16×3)]n = 159.89
160n = 159.89
n = 159.89 / 160
n = 1
Molecular formula = [Fe₂O₃]n
Molecular formula = [Fe₂O₃] × 1
Molecular formula = Fe₂O₃
2a. How to determine the molecual formula of the anhydrous saltWe'll begin by calculating the empirical formula
Mg = 20.0% S = 26.66% O = 53.33%Empirical formula =?Divide by their molar mass
Mg = 20.0 / 24 = 0.83
S = 26.66 / 32 = 0.83
O = 53.33 / 16 = 3.33
Divide by the smallest
Mg = 0.83 / 0.83 = 1
S = 0.83 / 0.83 = 1
O = 3.33 / 0.83 = 4
Thus, the empirical formula of the anhydrous salt is MgSO₄
The molecular formula of the anhydrous salt can be obtained as follow:
Empirical formula = MgSO₄Molar mass of compound = 120 g/molMolecular formula = ?Molecular formula = empirical × n = molar mass
[MgSO₄]n = 120
[24 + 32 + (16×4)]n = 159.89
120n = 120
n = 120 / 120
n = 1
Molecular formula = [MgSO₄]n
Molecular formula = [MgSO₄] × 1
Molecular formula = MgSO₄
2b. How to determine the formula of the crystalline saltWater (H₂O) = 51.2%Anhydrous salt (MgSO₄) = 100 - 51.2 = 48.8%Formula of crystalline salt =?Divide by their molar mass
MgSO₄ = 48.8 / 120 = 0.4
H₂O = 51.2 / 18 = 2.8
Divide by the smallest
MgSO₄ = 0.4 / 0.4 = 1
H₂O = 2.8 / 0.4 = 7
Thus, the formula of the crystalline salt is MgSO₄.7H₂O
3i. How to determine the mole of carbon atoms in 3 moles of C₂H₆1 mole of C₂H₆ contains 2 moles of carbon atoms.
Therefore,
3 moles of C₂H₆ will contain = 3 × 2 = 6 moles of carbon atoms
3ii. How to determine the mole of hydrogen atoms in 3 moles of C₂H₆1 mole of C₂H₆ contains 6 moles of hydrogen atoms.
Therefore,
3 moles of C₂H₆ will contain = 3 × 6 = 18 moles of hydrogen atoms
3iii. How to determine the number of moleculesFrom Avogadro's hypothesis,
1 mole of ethane = 6.02×10²³ molecules
Therefore,
3 moles of ethane = 3 × 6.02×10²³ molecules
3 moles of ethane = 1.806×10²⁴ molecules
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Complete question
2. A crystalline salt when heated becomes anhydrous and loses 51.2% of its weight the anhydrous salt analysis gave the percent composition as magnesium is equal to 20.0% and sulphur is equal to 26.66% and oxygen is equal to 53.33%. Ccalculate the molecular formula of the anhydrous and the crystalline salt. The molecular weight of the anhydrous salt is 120
A sample of neon gas in a bulb is at 149.05 °C and 349.84 kPa. If the pressure drops
to 103.45 kPa, what is the new temperature (in °C)? Provide your answer to two
decimals.
The new temperature (in °C) of the gas, given the data is –148.20 °C
Data obtained from the question Initial temperature (T₁) = 149.05 °C = 149.05 + 273 = 422.05 KInitial pressure (P₁) = 349.84 KPa Volume = constant New pressure (P₂) = 103.45 KPaNew temperature (T₂) =? How to determine the new temperatureThe new temperature of the gas can be obtained by using the combined gas equation as illustrated below:
P₁V₁ / T₁ = P₂V₂ / T₂
Since the volume is constant, we have:
P₁ / T₁ = P₂ / T₂
349.84 / 422.05 = 103.45 / T₂
Cross multiply
349.84 × T₂ = 103.45 × 422.05
Divide both side by 349.84
T₂ = (103.45 × 422.05) / 349.84
T₂ = 124.80 K
Subtract 273 from 124.80 K to express in degree celsius
T₂ = 124.80 – 273
T₂ = –148.20 °C
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The formula c₂H₄o can represent?
Answer:
Ethylene oxide
Explanation:
Ethylene oxide is an organic compound with the formula C2H4O. It is a cyclic either and the simplest epoxied: a three-membraned ring consisting of one oxygen atom and two carbon atoms!
How many atoms are in 76.15 grams of fe
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Answer:
See below
Explanation:
From periodic table
mole weight of Fe is 55.845 gm / mole
76.15 gm / 55.845 gm/mol * 6.022 x 10^23 atoms/mole =
8.212 x 10^23 atoms ( four signif. digits)
The half-life of silicon-32 is 710 years. If 40 grams is present now, how much will be present in 800 years
18 g of silicon-32 will be present in 800 years.
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and it's given by
[tex]N(t) = N_0 (\frac{1}{2}) ^\frac{t}{t_\frac{1}{2} }[/tex]
where,
[tex]N(t) =[/tex] quantity of the substance remaining
[tex]N_0 =[/tex] the initial quantity of the substance
[tex]t =[/tex] time elapsed
[tex]t_1_/_2 =[/tex] the half-life of the substance
From the given information we know:
The initial quantity of silicon-32 is 40 g.
The time elapsed is 800 years.
The half-life of silicone-32 is 710 years.
So, using the calculation above, we can determine how much silicon-32 is left.
[tex]N(t) = 40 (\frac{1}{2}) ^\frac{800}{710} \\N(t) = 40 (\frac{1}{2}) ^\frac{80}{71} \\\\N(t) = 18 g[/tex]
Therefore,18 g of silicon-32 will be present in 800 years.
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Based on their composition and structure list, CH2Cl2, CH3CH2CH3, and CH3CH2OH in order of: a. Increasing intermolecular forces b. Increasing viscosity c. Increasing surface tension
Based on their composition and structure list CH₂Cl₂, CH₃CH₂CH₃ and CH₃CH₂OH in order of (a) Increasing order of Intermolecular Forces are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (b) Increasing order of Viscosity are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (c) Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.
What is Intermolecular Forces ?Intermolecular forces often abbreviated to IMF (or Secondary force) are the forces that hold atoms together with in a molecule. These forces are electrostatic in nature and exist between molecules.
Increasing order of Intermolecular Forces are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.
How Intermolecular forces affect Viscosity ?Higher the intermolecular force then higher the viscosity. Stronger the intermolecular force then stronger the viscosity.
Increasing order of Viscosity are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.
How Intermolecular forces affect Surface tension ?Stronger the intermolecular forces of liquid have higher surface tension. Surface tension depend upon the intermolecular forces.
Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.
Thus from the above conclusion we can say that Based on their composition and structure list CH₂Cl₂, CH₃CH₂CH₃ and CH₃CH₂OH in order of (a) Increasing order of Intermolecular Forces are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (b) Increasing order of Viscosity are CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH. (c) Increasing order of Surface Tension are: CH₃CH₂CH₃ < CH₂Cl₂ < CH₃CH₂OH.
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Provide the organometallic reagent that is needed to perform the transformation shown below. The reagent should be formatted as LiR or BrMgR, where R is an alkyl group written as a Condensed Formula. Do not use subscripts.
The correct answer is [tex]LiCH_{3}CH(CH_{3} )CH_{3}[/tex] .
Organometallic reagentOrganometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.
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A 100 cc bottle of Amoxicillin 125 oral suspension requires addition of 61 ml of Purified Water to make 100 cc. What is the powder volume
A 100 cc bottle of Amoxicillin 125 oral suspension requires addition of 61 ml of Purified Water to make 100 cc. The powder volume is 76.25.
How do you calculate powder volume ?To calculate the powder volume use the expression
[tex]\frac{H}{Q} = \frac{D}{X}[/tex]
where,
H = Dose on hand
Q = Quantity on hand
D = Desired dose
X = Quantity desired
Now put the values in above expression we get
[tex]\frac{H}{Q} = \frac{D}{X}[/tex]
[tex]\frac{100}{61} = \frac{125}{X}[/tex]
[tex]X = \frac{125 \times 61}{100}[/tex]
X = 76.25
Thus from the above conclusion we can say that A 100 cc bottle of Amoxicillin 125 oral suspension requires addition of 61 ml of Purified Water to make 100 cc. The powder volume is 76.25.
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what is the color of phenolphthalein in weak base
Answer:
Pink
Explanation:
Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.
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Answer:
pink
Explanation:
Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.
{Mark as brainlest answer}When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is:_____.
When 3-methyl-2-butanone undergoes a baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.
The Baeyer-villiger oxidation would seem to be a chemical reaction that uses peroxy acids using peroxides as the oxidant to transform a ketone into an ester or a lactone from such a cyclic ketone.
The main product produced by the Baeyer-Villiger oxidation of camphor using m-CPBA in buffer conditions could be created as a result of the migration of a tertiary bridgehead carbon as opposed to a methylene group.
By the reaction between 3-methyl-2-butanone with m-CPBA , will form isopropyl acetate and methyl isobutyrate.
It reaction can be shown as:
Therefore, when 3-methyl-2-butanone undergoes a Baeyer-villiger oxidation reaction, the product is isopropyl acetate and methyl isobutyrate.
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Gaseous nitrogen dioxide dissolved in warm liquid water to form hno3 and gaseous nitrogen monoxide enter a balanced equation for this reaction
Answer:
3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)
Explanation:
Gaseous nitrogen dioxide = NO₂ (g)
Liquid water = H₂O (l)
Because the reactants are dissolved = HNO₃ (aq)
Gaseous nitrogen monoxide = NO (g)
In order for a reaction to be balanced, there needs to be an equal amount of each type of atom on both sides of the equation. The equation can be balanced by adding coefficients to modify the quantities of certain compounds.
The unbalanced equation:
NO₂ (g) + H₂O (l) ---> HNO₃ (aq) + NO (g)
Reactants: 1 nitrogen, 3 oxygen, 2 hydrogen
Products: 2 nitrogen, 4 oxygen, 1 hydrogen
The balanced equation:
3 NO₂ (g) + H₂O (l) ---> 2 HNO₃ (aq) + NO (g)
Reactants: 3 nitrogen, 7 oxygen, 2 hydrogen
Products: 3 nitrogen, 7 oxygen, 2 hydrogen
Which compound has the lowest melting point?
CaCl2
K2Cr2O7
C6H12O6
K2O
Answer:
[tex]K2O[/tex]
Explanation:
If you use a melting point periodic table there is a listing of all the elements and their melting point.
Potassium (K) has a melting point of 63.25 degrees Celsius and oxygen (O) has a melting point of -218 degrees Celsius. Therefore, if you add those two values up
[tex](63.25x2)+-218 = -91.5 Degrees Celsius[/tex]
All the other compounds do not reach negatives.
Two-thirds of a bone's weight is composed of calcium phosphate which interacts with calcium hydroxide to form crystals of __________.
Two-thirds of a bone's weight is composed of calcium phosphate which interacts with calcium hydroxide to form crystals of hydroxyapatite
The two component of bones are 33% organic matter and 67% inorganic matter( Calcium phosphate and hydroxyapatite crystal).Calcium phosphate make up almost 2/3 of the bone's weight.Collagen fibers make up almost 1/3 of the bone's weight.The calcium phosphate interacts with calcium hydroxide to form crystals of hydroxyapatite, whose molecular formula is [tex]Ca_{10} (PO_{4} )_{6} (OH)_{2}[/tex]
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Determine the mass, in grams, of 0.350 moles of s (1 mol of s has a mass of 32.07 g).
Answer:
11.22 gm
Explanation:
32.07 gm / mole * .350 mole = 11.22 gm
The mass of 0.350 moles of Sulphur is equal to 11.22 g.
What is a mole?A mole is a standard unit which is used to calculate the huge number of quantities of atoms, molecules, ions, or other particular particles. The mass of the one mole of any element is called atomic mass and that of any compound is called molar mass.
The number of units present in one mole was found to be equal to 6.023 × 10 ²³ which is known as Avogadro’s constant or Avogadro’s number.
Given, the number of moles of sulphur = 0.350 moles
The mass of one mole of sulphur = 32.07 g
Then, the mass of 0.350 moles of Sulphur = 0.350 × 32.07
The mass of 0.350 moles of Sulphur (S) = 11.22 g
Therefore, 11.22 grams is the mass of 0.350 moles of Sulphur (S).
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one model that shows how energy passes from organism to organism is called? 1. an energy link 2. a food chain 3. a phytoplankton cycle
Given the balanced equation: 2KClO3 --> 2KCl 3O2 What type of reaction is represented by this equation
The correct option is (2) decomposition.
In the balanced equation 2KClO3==> 2KCl + 3O2, as there is a reduction of oxygen therefore it is decomposition reaction.
What is decomposition reaction?A chemical reaction that results in the breakdown of one reactant into two or more reactants is known as a decomposition reaction.
The general equation for decomposition is-
AB -> A + B
Where A & B are now the product molecules and AB is the parent (reactant) molecule.
Some key features of the decomposition reaction are-
A combination reaction is the opposite of the a decomposition reaction. In such reactions, a single product is created form two or even more reactants.Decomposition processes are not always endothermic. Both endothermic and exothermic reactions can take place during decomposition. This one is more typical than the former, though.Extraction of metal from their ores is a significant use of decomposition processes. For instance, by putting calamine through a breakdown reaction, zinc can be extracted. The same process can be used to make sodium form sodium chloride (NaCl).A type of decomposition reaction known to be a double decomposition reaction involves the exchange of positive and negative ions between two constituent reactants to create two new molecules.To know more about decomposition reaction, here
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The complete question is-
Given the balanced equation:
2KClO3==> 2KCl + 3O2
Which type of reaction is represented by this equation?
(1) synthesis
(2) decomposition
(3) single replacement
(4) double replacement
What is δs° for the reaction so2(s) no2(g) → so3(g) no(g)? substance s°(j/k • mol) so2(g) 248.5 so3(g) 256.2 no(g) 210.6 no2(g) 240.5
The value of ΔS° for reaction is - 22.2 J/K.mol
[tex]SO_{2}(s)+NO_{2} (g)[/tex] → [tex]SO_{3}(g)+NO(g)[/tex]
Calculation,
Given value of S°(J/K.mol) for
[tex]SO_{2}(s)[/tex] = 248.5
[tex]NO_{2} (g)[/tex] = 240.5
[tex]NO(g)[/tex] = 210.6
[tex]SO_{3}(g)[/tex] = 256.2
Formula used:
ΔS° (Reaction) = ∑S°(Product) - ∑S°(Reactant)
ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol
The change in stander entropy of reaction is - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.
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which of the following pairs would have a larger size? explain your answer.
K or K^(+)
Br or Br^(-)
Answer:
k ion is the largest size of the radius it is always smaller compared to the parent ion
Explanation:
An oxygen gas tank holds 1 mole of gas at 10.0 atm of pressure. In order to reduce the pressure of the tank to 2.5 atm, moles must be released. How many moles will be left
Answer:
0.25 moles
Explanation:
To find the number of moles, you need to use a variation of the Ideal gas Law. The manipulated equation looks like this:
P₁ / n₁ = P₂ / n₂
In this formula, "P₁" and "n₁" represent the initial pressure and number of moles. "P₂" and "n₂" represent the final pressure and number of moles. You can find the final amount of moles by plugging the given values into the equation and simplifying.
P₁ = 10.0 atm P₂ = 2.5 atm
n₁ = 1 mole n₂ = ? moles
P₁ / n₁ = P₂ / n₂ <----- Equation
(10.0 atm) / (1 mole) = (2.5 atm) / n₂ <----- Insert values
10.0 = (2.5 atm) / n₂ <----- Divide 1 from 10.0
(10.0) x n₂ = 2.5 atm <----- Multiply both sides by n₂
n₂ = 0.25 <----- Divide both sides by 10.0
How many sucrose molecules are in 3.0 moles of sucrose?
Answer: No of molecule of sucrose = 1.806 X 10^24
Explanation:
No. of molecules = No. of moles X NA
No. of molecule of sucrose = 3 moles X 6.02 X 10^23
No of molecule of sucrose =18.06 X 10^23
No of molecule of sucrose =1.806 X 10^24
Answer:
1.80 × 10²⁴ Molecules of Sucrose
For a phase change, H = 2 kJ/mol and S = 0.017 kJ/(K-mol). What are
G and the spontaneity of the phase change at 500 K?
A. G=-6.5 kJ; nonspontaneous
B. G= 10.5 kJ; spontaneous
C. G= 10.5 kJ; nonspontaneous
D. G=-6.5 kJ; spontaneous
The reaction has a change in free energy of -6.5 kJ and is spontaneous Option D.
What is a spontaneous reaction?The term spontaneous reaction refers to a reaction that occurs with n external input of energy. We know that a spontaneous reaction is one in which the value of the change in free energy is negative. If the change in the free energy is positive then the reaction is nonspontaneous.
If the value of the change in free energy is zero then it follows that the reaction has attained equilibrium.
Now;
ΔG = ΔH - TΔS
ΔH = 2 kJ/mol
T = 500 K
ΔS = 0.017 kJ/(K-mol)
When we substitute values;
ΔG = 2 kJ/mol - (500 K * 0.017 kJ/(K-mol))
ΔG = -6.5 kJ
It the follows that the reaction has a change in free energy of -6.5 kJ and is spontaneous Option D.
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_____ in carbon dioxide in your red blood cells, which causes _____ in ph, causes your breathing to speed up.
Increase in carbon dioxide in your red blood cells, which causes a drop in pH, causes your breathing to speed up.
The presence of carbon dioxide in red blood cell will lower the pH because carbon dioxide combines with water to form [tex]H^{+}[/tex] and [tex]HCO_{3} ^{-}[/tex] .
About 70% of Carbon dioxide transported as bicarbonate ion in the plasma of the red blood cells .When carbon dioxide diffuses across the cell membrane of erythrocyte then it reacts with water to form carbonic acid.This carbonic acid breaks into bicarbonate ion and proton in the presence of carbonic anhydrase . this is because it is very unstable.This hydrogen ions binds to the hemoglobin and which results in initiation of bohr effect .So, as concentration of hydrogen ions increases pH of the blood decreases.learn about carbonic acid
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Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?.
Answer:
212 000 yrs
Explanation:
15/16 decay means 1/16 is left
how many halflives is this?
(1/2)^n = 1/16
n = 4 half lives
4 half lives * 53 000 yr/ half life = 212 000 yrs
Answer:
c. 212,000 years
Explanation:
got it right on edge:3
23
What is the mass of 3.01 x 10 atoms of neon?
Answer:
10.0 g
Explanation:
Avogadro's law states that there are 6.02 × 10²³ molcules in one mole of a substance, so we know that this sample has half a mole of neon.
The atomic mass of neon is 20.1797 g/mol, so 0.5 mol has a mass of about 10.0 g.
it is 10.09 g
According to Avogadro;
1 mole of neon would have 6.022 x 10^23 atoms
3.0 x 10^23 atoms of neon would have:
3.0 x 10^23/6.022 x 10^23
= 0.5 moles
mass of 0.5 moles neon = mole x molar mass
= 0.5 x 20.18
= 10.09 g
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Determine the number of oxygen atoms in 1.00 g of CaCO3
Answer:
1.81 x 10²² atoms O
Explanation:
To find the number of oxygen atoms, you need to (1) convert grams CaCO₃ to moles CaCO₃ (via molar mass), then (2) convert moles CaCO₃ to moles O (via mole-to-mole ratio from formula subscripts), and then (3) convert moles O to atoms O (via Avogadro's Number). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.
Molar Mass (CaCO₃): 40.078 g/mol + 12.011 g/mol + 3(15.998 g/mol)
Molar Mass (CaCO₃): 100.083 g/mol
1 CaCO₃ = 1 Ca and 1 C and 3 O
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
1.00 g CaCO₃ 1 mole 3 moles O 6.022 x 10²³ atoms
---------------------- x ------------------ x ---------------------- x ------------------------------ =
100.083 g 1 mole CaCO₃ 1 mole
= 1.81 x 10²² atoms O
Relative humidity is described as: Group of answer choices a basically unused concept when it comes to weather topics. the amount of water vapor in the air at a given temperature expressed as a percentage of the water vapor capacity of the air. the amount of water vapor in the air compared to the normal amount. the amount of moisture in the air relative to your own sensible feelings.
Correct answer:
The relative humidity is best described as the amount of water vapor in the air at a given temperature expressed as a percentage of the water vapor capacity of the air.
What is relative humidity?
The ratio of the current absolute humidity to the highest absolute humidity is known as relative humidity (which depends on the current air temperature).
Water vapor is also measured by relative humidity, which is stated as a percentage but RELATIVE to the air's temperature. In other words, it is a comparison between the amount of water vapor that is actually present in the air and the maximum amount of vapor that is possible for the air at the current temperature.
With the same quantity of absolute/specific humidity, air will have a HIGHER relative humidity if it is cooler and a LOWER relative humidity if it is warmer because warm air may contain more water vapor (moisture) than cold air. The actual amount of moisture (absolute humidity) in the air is what we "feel" outside.
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A short chain of monomer liquid not long enough to be considered a polymer is called a(n)?
a. methacrylate
b. acrylate
c. urethane
d. oligomer
Answer:
d. oligomer it is the correct answer also if you would just search that up it pops up
Blank + BaCl2 = BaSO4 + 2NaCl
How to complete this chemical reaction so that it is a Double displacement reaction
The blank is filled by Na₂SO₄, and the complete equation for the double displacement reaction is:
Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl
What is a double displacement reaction?It is a reaction in which both reactants exchange anions and cations.
Let's consider the following incomplete double displacement reaction.
_____ + BaCl₂ = BaSO₄ + 2 NaCl
If we compare the left and right sides, we can see that the missing ions in the left side are Na⁺ and SO₄²⁻. Thus, the missing compound is Na₂SO₄. The complete equation is:
Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl
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please help me with this question, and if u can do it on paper
1. O2 is the limiting reagent
2. Excess NH3 = 0.102 moles
3. 0.088 mol of NO is formed
4. 2.376 grams of H2O is formed
Stoichiometric problemFrom the equation: [tex]4NH_3 + 5O_2 --- > 4NO + 6H_2O[/tex]
Mole ratio of NH3 and O2 = 4:5
Mole of 3.25 g NH3 = 3.25/17 = 0.19 mol
Mole of 3.50 g O2 = 3.5/32 = 0.11 mol
Equivalent mole of O2 from NH3 = 5/4 x 0.19 = 0.24 mol
Equivalent mole of NH3 from O2 = 4/5 x 0.11 = 0.088 mol
Thus, O2 is the limiting reagent.
Excess NH3 = 0.19 - 0.088 = 0.102 moles
Mole ratio of O2 and NO = 5:4
Equivalent mole of NO = 4/5 x 0.11 = 0.088 mol
Mole ratio of O2 and H2O = 5:6
Equivalent mole of H2O = 6/5 x 0.11 = 0.132 mol
Mass of 0.132 mol H2O = 0.132 x 18 = 2.376 grams
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N analyst prepared a sucrose solution by weighing 1kg of water and add 1.5kg sucrose.estimate the concentration of the resultant solution in (i) mass percent (ii) degree brix
The concentration of the solution in mass percent is 60%.
What is the mass percent?The concentration of a substance can be expressed in mass percent. This refers to the percentage of the solute that is contained in the solution.
Thus we can write;
Mass percent = Mass of solute/ Mass of solution * 100/1
Mass percent = 1.5kg/1.5kg + 1 Kg * 100/1
Mass percent = 60%
Hence, the concentration of the solution in mass percent is 60%.
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