The following polluting gases do not directly create O3 in a combustion engine.
What three gases are present in your home?Therefore, either propane, butane, or a combination of the two is the type of gas used in dwellings. Natural gas (also known as mains gas) and compressed natural gas (CNG), both of which include methane, are the two types of gas used in homes. Hydrocarbon gases include propane, butane, and natural gas.
Which common gases are there?Common gases include oxygen, nitrogen, sulphur dioxide, argon, and a few more substances. See how these chemicals are used in daily life and how they assist us in the paragraphs below.
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Do the following statement describe physical or chemical property!
Uranium is a radioactive element
Name the functional group in the
following molecule:
A. alkene
C. aldehyde
O₂N
NO₂
-CH₂
NO₂
B. aromatic
D. alkyl halide
The functional group would be the aromatic ring.
What are functional groups?Functional groups in organic compounds are a group of atoms that gives the compound a distinctive chemical property or properties.
The major functional groups include Hydroxyl, sulfhydryl, carbonyl, carboxyl, amino, and phosphate groups. Aromatic rings are also considered a functional group.
Functional groups are made up of atoms of elements that are covalently linked to each other. The functional group as a whole is also covalently linked to the rest of the molecule.
Functional groups influence molecules to behave in a particular way when it comes to chemical reactions.
Looking at the image (see the attached), none of the side chains qualify as functional groups except the mother chain which is an aromatic ring.
Thus, the only functional group remains the aromatic ring.
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27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.
The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
How to find the mass of solute ?Mass of solute = Mass percent of solute x Mass of the solution
Here,
Mass percent of solute = 18.7 %
Mass of the solution = 27.2 kg
Now put the value in above formula we get
Mass of solute = Mass percent of solute x Mass of the solution
= [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]
= [tex]\frac{508.64}{100}[/tex]
= 5.086
Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
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The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compound.
[tex]K_{sp}[/tex] of the compound is found to be 5.04 ×[tex]10^{-10}[/tex].
Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.
Solubility equilibrium
Ksp = [tex][A^{+} ]^{a}[/tex] [tex][B^{-} ]^{b}[/tex]
Ksp = solubility product constant
A+ = cation in an aquious solution
B- = anion in an aqueous solution
a, b = relative concentrations of a and b
Given,
Solubility = s = 3.60 × [tex]10^{-2}[/tex] g/L
molar mass = 288 g/ mol
∴ s= 3.60 × [tex]10^{-2}[/tex] g/L ÷ 288 g/ mol = 1.25 ×[tex]10^{-4}[/tex] mol/ L
Reaction:
MX3 ⇄ M + 3X
s 3s
[tex]K_{sp}[/tex] =[ [tex]M^{+3}[/tex]] [ [tex]X^{-1}[/tex][tex]]^{3}[/tex] = solubility product
∴ [tex]K_{sp}[/tex] =[tex][s]^{} [3s]^{3}[/tex]
∴ [tex]K_{sp}[/tex] = 3 [tex]s^{4}[/tex]
∴ [tex]K_{sp}[/tex] = 3 × (3.60 × [tex]10^{-2}[/tex] [tex])^{4}[/tex]
∴ [tex]K_{sp}[/tex] = 503.8848 ×[tex]10^{-8}[/tex] = 5.04 ×[tex]10^{-10}[/tex]
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Can someone please help me with this question also explain the answers I am so confused thank you.
The theoretical yield of H₂S is 13.5 g.
The percent yield is 75.5 %.
What is the theoretical yield of H₂S from the reaction?The equation of the reaction is given below:
FeS + 2 HCl → FeCl₂+ H₂SMoles of FeS reacting = mass/molar mass
Molar mass of FeS = 88 g/mol
Moles of FeS reacting = 35/88 = 0.398 moles
Moles of H₂S produced = 0.398 moles
Molar mass of H₂S = 34 g/mol
Mass of H₂S produced = 0.398 * 34 = 13.5 g
Theoretical yield of H₂S is 13.5 g.
Percent yield = actual yield/theoretical yield * 100%Actual yield of H₂S = 10.2 g
Percent yield = 10.2/13.5 * 100%
Percent yield = 75.5 %
In conclusion, the actual yield is less than the theoretical yield.
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2NaN3 → 2Na + 3N2. Calculate the mass of sodium azide required to decompose and produce the number of moles of nitrogen you calculated to get 0.016
The mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.
How to calculate number of moles?The number of moles of a substance can be calculated stoichiometrically as follows:
According to this question, sodium azide decomposes to produce sodium and nitrogen gas as follows:
2NaN3 → 2Na + 3N2
2 moles of sodium azide produces 3 moles of N2
This means that 0.016 moles of N2 will be produced by 0.016 × 2/3 = 0.011moles of NaN3.
Therefore, the mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.
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4.50 moles of glucose in 3.50 L of a glucose solution
Answer:
Molarity = 1.28
Explanation:
[tex]m= n/v[/tex]
M = molar concentration
n = moles of solute
v = liters of solution
Molarity = moles of solute / litres of solution.
]
reference - https://www.wikihow.com
A soil test recommends applying 193 lbs N per acre. Using a 36-6-18 fertilizer, how much fertilizer is needed to meet the recommendation? Round your answer to nearest whole number.
The mass of 36-6-18 fertilizer fertilizer required is 536 lb.
What mass of nitrogen fertilizer is required for the acre of land?The mass of nitrogen fertilizer required for the acre of land is determined as follows:
Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.
Mass of Nitrogen required per acre = 193 lbs
Mass of fertilizer required = 193 * 100/36
Mass of fertilizer required = 536 lb of fertilizer.
In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.
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first law of thermodynamics with pressure volume equation
The first law of thermodynamics with pressure volume equation is written as E = Q - PΔV.
What is first law of thermodynamics?The first law of thermodynamics states that energy cannot be created or destroyed, but it can be transformed from one form to another.
It also states that the internal energy (E) is equal to the difference of the heat transfer (Q) into a system and the work (W) done by the system.
E = Q - W
The first law of thermodynamics with pressure volume equation is given as;
W = PΔV
E = Q - PΔV
Thus, the first law of thermodynamics with pressure volume equation is written as E = Q - PΔV.
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1. Consider the unbalanced equation:
Mg (s) + HCl (aq) ---> MgCl2 (s) + H2 (g)
If 4.59 mol of Mg and 4.59 mol of HCl are reacted, how many moles of MgCl2 are produced?
Hint: Write the balanced equation first.
Answer:
2.30 moles MgCl₂
Explanation:
First, you need to balance the chemical equation. An equation is balanced when there is an equal amount of each element on both sides of the reaction. These values can be modified by adding coefficients in front of the molecules.
The unbalanced equation:
Mg (s) + HCl (aq) ---> MgCl₂ (s) + H₂ (g)
Reactants: 1 magnesium, 1 hydrogen, 1 chlorine
Products: 1 magnesium, 2 hydrogen, 2 chlorine
The balanced equation:
Mg (s) + 2 HCl (aq) ---> MgCl₂ (s) + H₂ (g)
Reactants: 1 magnesium, 2 hydrogen, 2 chlorine
Products: 1 magnesium, 2 hydrogen, 2 chlorine
Now, you need to use the mole-to-mole ratios from the balanced equation to convert between moles. Since we were not given a limiting reactant, the easiest way to find the actual moles of MgCl₂ is to start from both reactants.
4.59 moles Mg 1 mole MgCl₂
------------------------- x ------------------------ = 4.59 moles MgCl₂
1 mole Mg
4.59 moles HCl 1 mole MgCl₂
------------------------- x ------------------------ = 2.30 moles MgCl₂
2 moles HCl
Since HCl produces the smaller amount of product, it must be the limiting reactant. In other words, HCl runs out before all of the Mg is completely used up. Therefore, the actual amount of MgCl₂ produced in 2.30 moles.
PLEASE HELP!!!
A sample of xenon occupies a volume of 715 mL at 8.01 atm and 67 °C. If the volume is changed to 963 mL and the temperature is changed to 52 °C, what will
be the new pressure?
Answer:
4.62 atm
Explanation:
To find the missing pressure, you need to use the Combined Gas Law equation:
P₁V₁ / T₁ = P₂V₂ / T₂
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.
P₁ = 8.01 atm P₁ = ? atm
V₁ = 715 mL V₁ = 963 mL
T₁ = 67 °C T₁ = 52 °C
P₁V₁ / T₁ = P₂V₂ / T₂
(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C
85.47985 = P₂(963 mL) / 52 °C
4444.952 = P₂(936 mL)
4.62 atm = P₂
1. A 4.0-g sample of glass was heated from 274K to 314 K. a temperature increase of 40 K, and was
found to have absorbed 32J of energy as heat.
a. What is the specific heat of this type of glass?
b. How much energy will the same glass sample gain when it is heated from 314 K to 344 K?
Answer:
See below
Explanation:
Q = m c T c = specific heat T = temp change Q = heat joules
32 = 4 c 40 c = .2 J/g-C
314 to 344 k is a change of 30 K
Q = m c T
= 4 * .2 * 30 = 24 Joules
Answer:
(a) 0.2 J/g°K
(b) 24 J
Explanation:
(a)
To find the specific heat capacity, you need to use the following equation:
Q = mcΔT
In this formula,
-----> Q = heat energy (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°K)
-----> ΔT = change in temperature (K)
You can plug the given values into the equations and simplify to find the missing value.
Q = 32 J c = ? J/g°K
m = 4.0 g ΔT = 40 K
Q = mcΔT <----- Equation
32 J = (4.0 g) x c x (40 K) <----- Insert variables
32 J = (160) x c <----- Multiply 4.0 and 40
0.2 = c <----- Divide both sides by 160
(b)
To find the energy of the same sample, you can use the same equation. This time, you know the specific heat capacity, have a different change in temperature, and are solving for energy (Q).
Q = ? J c = 0.2 J/g°K
m = 4.0 g ΔT = 344 K - 314 K = 30 K
Q = mcΔT <----- Given equation
Q = (4.0 g)(0.2 J/g°K)(30 K) <----- Insert values
Q = 24 <----- Multiply
9. Predict the full Robinson Annulation product (including all intermediates) and 10. Show the stepwise mechanism for the following reaction.
I need help with my work
Answer:
2 the mass is greater than 10.0gram
Explanation:
2 the mass is greater than 10.0gram
What is the initial volume, in milliliters, needed to prepare each of the following diluted solutions? 330mL of 7.5% (m/v) HCl from 17% (m/v) HCl
Taking into account the definition of dilution, the initial volume needed to prepare each of the diluted solution is 145.59 mL.
DilutionWhen it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal volumeIn this case, you know:
Ci= 17% (m/v)Vi= ?Cf= 7.5% (m/v)Vf= 330 mLReplacing in the definition of dilution:
17% (m/v)× Vi= 7.5% (m/v)× 330 mL
Solving:
Vi= (7.5% (m/v)× 330 mL)÷ 17% (m/v)
Vi= 145.59 mL
In summary, the initial volume needed to prepare each of the diluted solution is 145.59 mL.
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pls help i need this ASAP
Answer:
a. 54 calories burnt
b. multiplied by 9
The volume of a sample of gas (4.32 g) was 752 mL at 1.98 ATM and 62°C. The gas is
Answer:
Bromine
Explanation:
To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol *K)
-----> T = temperature (K)
After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.
P = 1.98 atm R = 0.08206 atm*L/mol *K
V = 752 mL / 1,000 = 0.752 L T = 62 °C + 273.15 = 335.15 K
n = ? moles
PV = nRT
(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)
1.48896 = n(27.5024)
0.0541 = n
You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.
Molar Mass = mass / moles
Molar Mass = 4.32 g / 0.0541 moles
Molar Mass = 79.8 g/mol
This molar mass is closest to the molar mass of bromine (79.904 g/mol).
How much heat is required to raise the temperature of 67.0 g of water from its melting point to its boiling point?
When 67 g of water is heated from its melting point to its boiling point, it takes 28006 J of heat.
Relationship between heat production and temperature changeA way to numerically relate the quantity of thermal energy acquired (or lost) by a sample of any substance to that sample's mass and the temperature change that results from that is provided by specific heat capacity.The following formula is frequently used to describe the connection between these four values.
q = msΔT
where, q = the amount of heat emitted or absorbed by the thing
m = the object's mass = 67 gm
s = a specific heat capacity of the substance = 4.18 J/gC
ΔT = the resultant change in the object's temperature = 373.15 -273.15K= 100 k
q = 67 * 4.18 * 100 J
⇒q = 28006 J
Therefore it is concluded that 67 g of water takes 28006 J of heat from its melting point to reach its boiling point.
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What mass of water could be warmed from 21.4 degrees celsius to 43.4 degrees celsius by the pellet dropped inside it? Heat capacity of the pellet is 56 J/degrees celsius. the pellet is initially at 113 degrees celsius.
42.34 g of water could be warmed from 21.4°C to 43.4°C by the pellet dropped inside it
Heat loss by the pellet is equal to the Heat gained by the water.
[tex]q_{w} = -q_{p}[/tex] ….(1)
where, [tex]q_{w}[/tex] is the heat gained by water
[tex]q_{p}[/tex] is the heat loss by pellet
[tex]q_{w}[/tex] = mCΔT
where m = mass of water
C = specific heat capacity of water = 4.184 J/g-°C
ΔT = Increase in temperature
ΔT for water = 43.4 - 21.4 = 22°C
[tex]q_{w}[/tex] = m × 4.184 × 22 …. (2)
Now
[tex]q_{p}[/tex] = [tex]H_{c}[/tex] ×ΔT
where [tex]H_{c}[/tex] = Heat capacity of pellet = 56J/°C
Δ T for pellet = 43.4 - 113 =- 69.6°C
[tex]q_{p}[/tex] = 56 × -69.6 = -3897.6 J
From equation (1) and (2)
-m× 4.184 × 22 =-3897.6
m= 42.34 g
Hence, 42.34 g of water could be warmed from 21.4 degrees Celsius to 43.4 degrees Celsius by the pellet dropped inside it.
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Order the following chemicals from lowest to highest melting point.
Tungsten
Copper (II) chloride
• Caffeine
• Lead
• Sodium chloride
• Silver
Caffeine - Lead (Pb) - Copper (II) chloride (CuCl2) - Sodium chloride (NaCl) - Silver (Ag) - Tungsten
Which statement can best be concluded from the ideal gas law?
O The product of pressuré and volume of an ideal gas is proportional to the absolute temperature.
O All collisions between atoms or molecules
are perfectly elastic and are not the result of any attractive forces.
O The temperature, pressure, and volume of a gas are all related.
O The behavior of a gas
under real conditions does not obey the ideal gas law.
The product of pressuré and volume of an ideal gas is proportional to the absolute temperature.
What is an ideal gas?An ideal gas is a gas that is not real in nature. It is a hypothetical gas that obeys the ideal gas law.
Just like normal gas particles, the particles of an ideal gas also move randomly. However, unlike normal gas molecules, the molecules of an ideal gas do not interact with one another.
The ideal gas law states that the product of the pressure and the volume of a gas is proportional to the temperature of the gas.
Mathematically, the ideal gas equation is expressed as:
PV = nRT where n = number of mole of the gas and R = constant.
Thus, the best conclusion from the ideal gas law is the product of pressure and volume is directly proportional to the temperature.
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When ATP breaks down to ADP, potential energy stored in bonds is released. This energy stored in bonds is
7. An SDS sheet contains the abbreviations LC or LD. The L portion of these two-letter
combinations stands for
A. life.
O B. liquid.
C. lethal.
D. layered.
A student mixed two clear liquids together in a beaker. A solid and a new liquid formed. The student forgot to write down the mass of one of the reactants. The rest of the data are shown in the table below.
Mass (g)
liquid reactant A unknown
liquid reactant B 9.0
liquid product 8.0
solid product 12.0
What is the mass of liquid reactant A?
A. 1.0 g
B. 8.0 g
C. 9.0 g
D. 11.0 g
E. 20.0 g
9 / 15
8 of 15 Answered
Mass of liquid reactant A is 11g.
as we know that,
reactant = product
from conservation of mass
so, liquid reactant A + liquid reactant B = liquid product + solid product
substituting the values, we get,
liquid reactant A + 9 = 8 + 12
liquid reactant A + 9 = 20
liquid reactant A = 20 - 9
liquid reactant A = 11g
Hence, mass of the liquid reactant A is 11g.
what is a reactant ?
A reagent, also known as an analytical reagent, is a substance or compound that is added to a system in chemistry to bring about a chemical reaction or check to see whether one happens. Although the terms "reagent" and "reactant" are frequently used synonymously, "reactant" refers to a material that is consumed during a chemical reaction.
Mass of liquid reactant A is 11g.
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For each pair of molecules given in the table below, identify the correct relationship.
For each pair of molecules given in the table below, the correct relationships are identified as follows.
The relationships between the molecules are given as?These are structural isomers. This is because, they have the same molecular formula (C₆H₁₂) but possess varying structures.The given pair of molecules posses similar formula (C₄H₁₀O) and can be superimposed on one another via rotation of the entire molecule, hence they are identical isomers.In this case the pair of molecules possess similar molecular formula (C₄H₁₀O) and similar arrangement of atoms. Hence, they are identical isomers.This case also features structural isomers. They both contain the same carbon chain with similar formula - C₃H₆BrClThese pair as identical isomers. They are also derived from C₃H₆BrCl.This pair are called stereoisomers isomers. This is because they contain the same about of molecules but are different in the position of the alcohol (-OH) group. But more importantly, the position of the bonding is the same.This set is a functional pair. This is because the composition of the molecules present in each case are different.This is also a functional pair.What is a molecules?A molecule is a bonded collection of atoms that represents the smallest fundamental unit of a chemical compound that may participate in a chemical process.
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You need to calculate the enthalpy change (AH) of the reaction A + 2B → C.
How can the enthalpies given for the reaction steps below be combined to
give the overall change in enthalpy?
D+B
D+3B
A. AH = AH2-A H₁
B. AH=2AH₁+AH²₂
OC. AH AH ₁ +AH²₂
D. AH = A H₁-AH₂
A
C
A
AH°,
A Hº
The enthalpy change of the reaction: A + 2B → C is determined as follows: ΔH = ΔH₁ + ΔH₂; option C
What is enthalpy change?Enthalpy change refers to the change in heat content as reactant molecules combine to form products.
The enthalpy change of a multistep reaction is calculated from by summing the enthalpy changes of the intermediate steps that leads to the overall reaction.
Thus, the enthalpy change of the reaction: A + 2B → C is determined as follows:
ΔH = ΔH₁ + ΔH₂
In conclusion, the enthalpy change of the reaction is determined from the summation of the enthalpy changes that occur in the intermediate steps.
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27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.
The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
How to find the mass of solute ?Mass of solute = Mass percent of solute x Mass of the solution
Here,
Mass percent of solute = 18.7 %
Mass of the solution = 27.2 kg
Now put the value in above formula we get
Mass of solute = Mass percent of solute x Mass of the solution
= [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]
= [tex]\frac{508.64}{100}[/tex]
= 5.086
Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
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Chemical reaction when chromium metal is immersed in an aqueous solution of cobalt(II)
The chemical equation for the reaction is [tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]
Chemical reactionChromium metal is higher in the reactivity series than cobalt. Thus, chromium will displace cobalt from solutions.
Therefore, the equation for the reaction between chromium metal and cobalt (II) chloride will be written as:
[tex]2Cr (s) + 3CoCl_2 (aq) --- > 2CrCl_3 (aq) + 3Co (s)[/tex]
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Chromium metal is immersed in an aqueous solution of cobalt(II) chloride. Express your answer as a chemical equation. Identify all of the phases in your answer. Enter no reaction if no reaction occurs.
which celsius temperature is equal to 298k
Answer:
298-273 = 25°C is correct answer!
What are the coefficients needed to balance this equation: NH3 +0₂ → N₂ + H₂O?
Answer:
4 NH₃ + 3 O₂ -----> 2 N₂ + 6 H₂O
Explanation:
An equation is balanced when there is an equal amount of each element on both sides of a reaction. To balance the elements, you can add coefficients to modify the amount of elements/molecules present. It is important to have the smallest coefficients possible.
The unbalanced equation:
NH₃ + O₂ -----> N₂ + H₂O
Reactants: 1 nitrogen, 3 hydrogen, 2 oxygen
Products: 2 nitrogen, 2 hydrogen, 1 oxygen
The balanced equation:
4 NH₃ + 3 O₂ -----> 2 N₂ + 6 H₂O
Reactants: 4 nitrogen, 12 hydrogen, 6 oxygen
Products: 4 nitrogen, 12 hydrogen, 6 oxygen